Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Divided (5×-6×) by 3× solve math q​

Answer»

ANSWER:

answer is -10X

I HOPE you GET it CORRECT

2.

Please answer this question all the questions I need you help​

Answer»

Answer:

1. 4a2+4ab+b2

2. a2-4ab+4b2

3. a2+1+1/4a2

4. 4a2+4+1/a

5. a2+b2+c2+2ab-2bc-2ac

6. a2+b2+c2-2ab-2bc+2ac

7. +1 SQ

8. -1 sq

3.

If the length is taken as 20cm, which of the following will representfor width?a) 23 cm b) 17 cm c) 30 cm​

Answer»

ANSWER:

the WIDTH is SEVENTEEN CM

4.

Find the common factor of the following monomial.The person who will give the correct step-by-step solution will be marked as a BRAINLIEST ​

Answer»

ANSWER:

The COMMON FACTOR is

3pq

5.

The angle that cannot be constructed using rularand camposses is​

Answer»

Answer:

60 degrees,120degrees, ETC.

6.

Inside a square garden of side 15m, aroad 4 meter wide is built all around. what is the area of the remaining part of the garden?

Answer»

See the ATTACHED file.
side of SQUARE GARDEN = 15m
width of road = 4m

for the remaining PART;
side = 15-(2×4) = 15-8 = 7m
area = side² = 7² = 49m²

7.

Time difference between india japan

Answer» JAPAN currently is 3 hours and also some 30 mins ahead of India.
8.

How to find the side of a square , if area is given?

Answer»

If the SIDE of a SQUARE is 'a'
then
AREA=a²
a=√area

example:  if area is 100 cm²
side =√100=10 CM

9.

Add : 0.888 and 8.0000 and 10.01 . plz its very important 85 points for it plzzzzzzz fast !!!!!!!!!

Answer»

8.00000+0.8880+10.0100
8.8880+10.0100
=18.8980

10.

Convert farenhite to celcius f=9/5*c+32

Answer» <klux>F</klux> =  \frac{9}{5}\ C+32

 is the formula to CONVERT temperature from CELSIUS to fahrenheit where C is the temperature in celsius and F is the temperature in Fahrenheit.
11.

I want herons formula

Answer» area=√s(s-a)(s-b)(s-c). it is the HERONS FORMULA.
12.

Which is greater 3/11 or 4/11

Answer»

4/11 is greater because by CROSS MULTIPLICATION 44 is greater than 33 and hence 4/11 is greater than3/11.

13.

I WANT WORD PROBLEM FOR 4TH STD DHELI CBS? ADD,MULTI,SUBSTRT,DIVISION.

Answer»

1.There were 180 apples in a box. 15 of them were rotten and the rest packed into PACKETS of 8.How many packets of apples were there in the end?
2.Sarah bought 6 boxes of muffins.There were a dozen muffins in each box.Her friends ate some and there were 5 muffins left.How many muffins were eaten by her friends?
3.Of his COLLECTION of books,Sandeep gave 350 books to the local LIBRARY and 25 books ot each of his grand children.How many books did Sandeep had in his collection?
4.Ajay buys a piggy bank.He has 52 one rupee coins,26 fifty PAISE coins and 32 twenty-five paise coins.How MUCH money does he have?

14.

I WANT SIMPLE WORD PROBLEMS WITH ANSWER FOR 4TH STD CBS ?

Answer»

I didnt UNDERSTAND the WORD CBS

15.

there are some chocolate in box.each gets 7 chocolates when these chocolates are distributed equally among the students of class. if there were 5 more students in the class ,then each would get 1 chocolate less. find the number of students in class?

Answer»

Earlier the number of STUDENTS were 49.each ONE of them can get 7 CHOCOLATES each.then 5 students were added to the class then each one of them can get 6 chocolates eachTotal students=54

16.

A baker bought 7,500 grams of flour for $19.20.how much did each kilogram cost?

Answer»

This QUESTION can be solved by the UNITARY method.
7500 GRAMS = 7.5 KG
7.5 Kg costs $19.20
1 Kg costs $19.20/7.5 = $2.56

17.

What is 123 times 800?

Answer» 123*800=98400Hope this is what U MEANT :)
18.

Plese do it , this is trigonometri lesson, so you if you want to do it use trigonometri ok

Answer» PLEASE SEE the ATTACHMENT ....the ANSWER is 

h=2.94mm
19.

How to give explanation on percentage of 545 out of 600 marks

Answer»

100% = 600x% = 545see left hand side are of same UNITS and RIGHT hand side of same units so we can do like THIS100%/X% = 600/545we can multiply X on both SIDES we get100 = 1.1091743119 × XX = 100/1.1091743119X = 90.8333333333now we have 545 is 90.8333333333% of 600

20.

Find the fraction such that,if its numerator is diminished by unity,it reduces to 1/2and becomes equal to 2 when the numerator is increased by 5 and the denominator is diminished by 6.

Answer»

Let the FRACTION be x/y.
Here,
x-1/y = 1/2
or, 2x - 2 = y
x+5/y-6 = 2
or, x + 5 = 2Y -12
Thus, x + 5 = 2(2x - 2) - 12
or, x + 5 = 4X - 16
3x = 21
x = 7
and y = 14 - 2 = 12
Thus, the fraction is 7/12.

21.

X/8-2x-8/3-x/4+2-x/24+3=0Then find value of x.

Answer»

x=16/13 is the ANSWER


22.

Is 2003 a prime no how to find out prime or composite for large digits any tricks

Answer»

Mainly the PRIME no. End with odd no only 2 is the even prime no.1st see last digit of the no.If it is odd than there is possibility of prime no.2nd add all digit with each other3nd than TRY to multiple it by 3 if it does not MULTIPLY by 3THE composite even no. is always divide by 2Odd by 3 and many more......

23.

Can someone please help?? Write three different improper fractions that equal 4 1/2. So far we found 9/2 but having a hard time with the other two?

Answer» \frac{18}{4} \\  \\ 
 \frac{36}{8}  \\  \\  \frac{72}{16}
24.

Express the first quantity as a percent of the second quantity

Answer»

Assume the 1st QUANTITY is 120, and the 2nd quantity is 240. So FIRST, we have to FORM a fraction with them = 120/240. Then we MULTIPLY the fraction with 100 = 120/240 x 100= 50. This means that 120 is 50% of 240. Let us try another one. Assume the 1st quantity is 73, and the SECOND quantity is 365. We form a fraction = 73/365. We multiply it by 100 = 73/365 x 100= 20%. Hence, 73 is 20% of 365. Now, one more... Assume the 1st quantity to be 500, and the 2nd quantity to be 10,000. So let us form a fraction = 500/10000. We multiply by 100 = 500/10000 x 100 = 5. Thus, 500 is 5% of 10,000.

25.

What is mean of the data?

Answer» MEAN REFERS to AVERAGE of the DATA
26.

Find sum of three odd numbers is 30

Answer»

It is not POSSIBLE . because SUM of two odd NUMBERS is a  EVEN   number.
   even   number + odd number will be a  odd  number .But 30 is a  even    number

27.

What is the highest common factor of 120 and 32

Answer»

Factors of 32=1,2,4,8,32
factors of 120=1,2 ,3,4,5,6,8,12,15,................120
the COMMON factors between 32 and 120 are 1,2,4,8
the HIGHEST is 8 , THEREFORE HCF of32 and 120 is 8

28.

Prove that:[anyone genius there?]

Answer» let\ tan^{-1}3=A,\ Tan\ A=3\\\\let\ Tan^{-1}\frac{1}{3}=B\\\\Cot(A+B)=\frac{1 - Tan\ A \ Tan\ B}{Tan\ A\ +Tan\ B}=\frac{1 - 3*\frac{1}{3}}{3+\frac{1}{3}}=0\\A+B=\frac{\pi}{2}\\
========================
Let\ Tan\ A=3,\ \ Tan\ B=\frac{1}{3}\\\\Sec\ A=\sqrt{1+3^2}=\sqrt{10},\ Sec\ B=\sqrt{1+(\frac{1}{3})^2}=\frac{\sqrt{10}}{3}\\\\Cos\ A=\frac{1}{\sqrt{10}},\ \ \ Cos\ B=\frac{3}{\sqrt{10}}\\\\Sin\ A=tan\ A*Cos\ A=\frac{3}{\sqrt{10}}\\\\Sin\ B=\frac{1}{\sqrt{10}}\\\\Sin(A+B)=\frac{3}{\sqrt{10}}*\frac{3}{\sqrt{10}}+\frac{1}{\sqrt{10}}*\frac{1}{\sqrt{10}}\\\\=1\\\\A+B=\frac{\pi}{2}
29.

What is a circle and how does it look like?

Answer»

A ROUND PLANE FIGURE WHOSE BOUNDARY CONSISTS OF POINTS EQUIDISTANT FROM A FIXED POINT IS CALLED A CIRCLE

30.

The first angle of the triangle is double its second angle. the third angle is 18 degree more than the sum of first two angles. Find the three angles of the triangle

Answer» SECOND angle=x
first angle=2x
sum=2x+x=3x
third angle=3x+18
total angle=180
3x+18+2x+x=180
6x+18=180
6x=162
x=162/6=27
angles= 27,54,99
31.

Prove that:(its urgent plz help someone who's intelligent enough !!)=0

Answer» LHS=tan(2*Cot^{-1}\sqrt{\frac{1-Cos\ x}{1+Cos\ x}})+Tan\ x\\\\1-Cos\ x=2\ Sin^2(\frac{x}{2})\\\\1+Cos\ x=2\ Cos^2(\frac{x}{2})\\\\LHS=Tan(2*Cot^{-1}\sqrt{Tan^2(\frac{x}{2})})+Tan\ x\\\\We\ know\ Tan\frac{x}{2}= Cot(\frac{\pi}{2}-\frac{x}{2})\\\\LHS=Tan(2*(\frac{\pi-x}{2}))+Tan\ x\\\\=Tan(\pi-x)+Tan\ x=-Tan\ x + Tan\ x = 0
32.

Prove that:(its urgent plz help someone who's intelligent enough !!)

Answer» LET x = TAN A    ,     y = Tan B      ,   z = Tan C

(x - y)/(1+x y) = tan (A-B)
(y-z)//(1+y z) = tan (B-C)
(z-x)/(1+z x) = tan (C - A)

LHS = (A-B) + (B-C) + (C-A) = 0

RHS is also similar to LHS.
If we assume x³ = tan P ,    y³ = tan Q   ,   z³ = tan R
RHS = tan⁻¹ (tan (P-Q) ) + tan⁻¹ [tan (Q-R) ] + tan⁻¹ [ tan (R-P) ] = 0

LHS = RHS

33.

If the HCF of x²+x-12 and 2x² -kx-9 is x-k , find the value of 'k'.

Answer»

HCF of x²+x-12 and 2x² -kx-9 is x-k so (x-k) is a FACTOR of both the polynomials. So x=k is a zero of both the polynomials. So F(k)=0 in both cases. thus

k² + k - 12 = 0    --------------(1)
2k² - k² - 9 = 0    --------------(2)

from EQUATION 1, k = 3,-4
from equation 2, k = +3, -3
+3 is common to both the SOLUTIONS
So value of k is 3.

34.

How to add three fractions by cross-multiplying ?

Answer»

Doing first two PROBLEMS first ,then do the THIRD one. Also it would HELP if u put the problems you are having issues up on the this help BOARD.

35.

What is Sn-1 in AP ?Explain.

Answer» S_n = the\ sum\ of\ first\ n\ terms\ of\ the\ series.\\\\Series:\ a,\ a+d,\ a+2d,\ a+3d,...\\\\T_n=n^{th}\ term=a+(n-1)d\\\\S_n=a+a+a+...n\ times\ + d*[1+2+3+....(n-1)\ terms]\\S_n=n*a+d*n(n-1)/2=[2a+(n-1)d]*n/2\\\\S_{n-1}=sum\ of\ the\ first\ (n-1)\ terms\\\\S_n-1=[2a+(n-2)d](n-1)/2
36.

How many 0 are there in 1crore

Answer» There are  SEVEN ZERO  in 1 CRORE  ( 1,00,00,000 ) . 
37.

A solid cubical bock of fine wood costs RS 256 at RS 500 per metre square. Find its volume and the length of each side.

Answer»

Let the SIDES be of length be a 

so 1 m² = Rs 500

so Rs 1 = 1/500 m²

so Rs 256 = 256/500 m² = 0.512 m²


 so a² = 0.512 m² ⇒ a = 1.6√0.2 m

so VOLUME = (1.6√0.2)³ = 0.366 m³

38.

Write two more decimals equivalent to given decimals (a)71.3 (b)94.500

Answer»
39.

The students in a school are having a cup stacking contest. John has a pyramid 9 layers high. How many cups will he need to add to his pyramid to increase the number of layers to 12?

Answer»

Please see the DOCUMENT enclosed.
If the stacking is done as per that method, then we need, for a stack of L LEVELS,

  total number of CUPS at level  L = L
  total number of cups for all levels from 1 to L :  1 + 2 + 3 + ... + L
             = L ( L + 1)/2
  So the number of cups needed to increase the number of LAYERS to 12 from 9 is:

         12(12+1)/2 - 9 (9+1)/2 =  78 - 45 = 33
====================

Another method is:
  We need L more cups to increase the number of layers from L - 1 to  L.  Hence, we need, to go from level 9 to level 12:  10+11+12 = 33 cups more.


40.

Find area of rectangle whose length is 12m and breadth 12 ?

Answer» 12x12= 144 SQ CM .

WOULD be the AREA if you use the shortcut WAY.
41.

For what value of n are the nth terms of two A.P's 63 , 56 , 67 , ....... and 3 , 10 , 17 .......equal?===============================================The diameter of a roller 120cm long is 84cm . If it takes 500 complete revolutions to level a playground , determine the cost of levelling it at the rate of 30 paise per square metre.

Answer»

I think there is a typing mistake : it is 65 INSTEAD of 56.

1st series:  63, 65, 67 ... :    common diff = d = 2       a = 63
      Tn = 63 + (n-1) 2 = 2 n + 61
2nd series :  3, 10 , 17,..    : d = 7   a = 3
 Tn = 3 + (n-1) 7 =  7 n - 4
 
       so  2 n + 61 = 7n  - 4 
              5n = 65          =>   n = 13
 
================================

 S = curved surface area of the cylinder = 2 π R L 
       radius =   R = 84/2 = 42 cm            L = length = 120 cm
 
   S = 2 π 0.42 m * 1.20 m = 3.166 m²
    500 complete turns =>  area rolled = 500 * S = 1583.36  m²
       Cost = 1583.36 * 30/100 = RS 475  

42.

How do you find the distance between San Jose and Brisbane on a map with a scale of 1 in : 8 mi if they are actually 48 mi apart.

Answer» SCALE USED in map is 1 INCH = 8 MILES.
actual distance = 48 miles.
if 8 miles is REPRESENTED in 1 inch,
1 mile will be represented in = \frac{1}{8}\ inch
48 miles will be represented in = 48 \times  \frac{1}{8}=\boxed{6\ inch}
43.

If the root of x² + px + 12 = 0 are in the ratio 1:3 then what is the value of p ?=====================================================Find the distance between the points ( l + m , n - p ) and ( l - m , n + p )===================================================If are the roots of the equation x² + x√ + = 0 , then find

Answer» x^{2} + px + 12 = 0
so let the ROOTS be 1 d and 3 d
We know that sum of the roots = -b/a
and product of the roots = c/a
1d+3d = - p / 1

1d * 3d = 12
3d^{2} = 12
d = 2
So substituting, 1(2) + 3 (2) = - p
2+6 = - p
p = - 8 or +8 (since root can be both positive and negative)
==================================================
\sqrt{(x1-x2)^{2}+ (y1-y2)^{2}  }DISTANCE between the points = 

\sqrt{ (l+m-(l-m))^{2} +(n-p-(n+p)) ^{2} }=

\sqrt{ (2m)^{2} + (-2p) ^{2} }=

\sqrt{4m+4p}=

2 \sqrt{m+p}= units
=====================================================
\alpha + \beta = -\frac{ \sqrt{\alpha } }{1}

\alpha  \beta =  \frac{ \beta }{1}

\alpha =1

sub alpha value,

1+ \beta = -  \sqrt{1}

1+ \beta =-1

\beta  = - 2


44.

Plz solve this my frnds its quite urgent

Answer»

I dont know the BEST way of solving this.  I am able to solve it in the following manner.

        y - x  y'  =  x + y  y'
         (x + y)  y' =  y - x       --- equation (1)

Let  y = g x          =>            y' = g + x g'

    Substitute in equation (1), 
          x g + x² g' + x g² + x² g g' =  g x - x 
             x g' (1 + g) = - (g² + 1) 

               - 1/x = (g + 1) g' / (g² + 1)
            -1/ x  =  g g' / (g² + 1)  +  g' / (g² + 1)
 Integrating we get, 
       LN 1/x  + Ln K  =  1/2 Ln (1 + g²)  +  tan⁻¹ g
 Substitute g = y/x, and simplify.

Ln\ \frac{K}{x\sqrt{1+g^2}} = tan^{-1}g\\\\Ln\ \frac{Kx}{x^2+y^2}=tan^{-1}\frac{y}{x}\\\\Or,\ x^2+y^2=K_1\ e^{-2\ tan^{-1}\frac{y}{x}}\\

You may verify the SOLUTION, by DIFFERENTIATING this equation and OBTAINING the expression for y'.

45.

How much soil is there in a circular hole ,2 m deep and 1 m across?

Answer» H= 2 m
r= 0.5 m
v= πr²h
=0.25*2*π
 22/7*0.5
v=11/7 m³
46.

A wall 24 m long 5 m high and 0.25 m rhick is to be constructed using bricks measuring 25cm X 12.5 cm × 7.5 cm.Find the no. of bricks required, if 5% of the wall is occupied by cement and sand mixture.

Answer» VOLUME of WALL=24×5×0.25=30m³
volume of CEMENT and BRICKS=5% of wall=5/100×30=1.5m³
volume of wall that CONTAIN only bricks=30-1.5=28.5m³
volume of brick=25×12.5×7.5=3/1280
no of bricks=28.5/3/1280=285×128  /3=12160 bricks
47.

If D , E (7 , 3) and F are the mid-points of the sides of triangle ABC , then find the area of the triangle ABC.

Answer»

First to find the area we need to find the VERTICES of the triangle.

MIDPOINT D = x1+x2 = -1........(1)

y1+y2 = 5.............................(4)

Midpoint E = x1+x3 = 14.........(2)

y1+y3 = 6...............................(5)

Midpoint F = x2+x3 = 7............(3)

y2+y3 = 7...............................(6)

Now let us find the x terms first.

(1) ........ x1 = -1-x2
Sub in (2) ........ -1-x2 + x3 = 14........(7)
Now subtracting (7)  and (3)
we get, 2x3 = 22
x3 = 11
Sub x3 in (2) ........x1+11 = 14
x1 = 3
and so x2 = -4

now let us find y terms.

(3) ............y1 = 5 - y2
sub in (5).........5-y2+y3 = 6.........(8)
Now subtracting (8) and (6) we get,
y3 = 4
now sub y3 in (5)...... y1 = 2
and so
y2 = 3

now the vertices are (3,2) (-4,3) (11,4)

Area of the triangle = (3(3-4) + (-4) (4-2) + 11(2-3))/2
= (-3 -8 -11)2
= - 11

Remove the negative SIGN (-) from the number -11. 

The area of the triangle is 11 sq.units.

Because the formula calls for absolute value, you SIMPLY remove the negative sign.

48.

The value of 'a' so that the point ( 3 , a ) lies on the line 2x - 3y = 5 is :a)12 b) 3 c) 1/2 d)1/3

Answer»

So (3,a) will satisfy the line 2X - 3y = 5

so 2x3 - 3A = 5

3a = 6 - 5

a = 1/3 

so OPTION (d) is the answer

49.

The length of the minute hand of a clock is 6cm . Find the area swept by the minute hand during the time period 8:05 AM and 8:45 AM.

Answer» RADIUS of SECTOR=6 cm
/alpha=240 degree
area of sector=/alpha/360*/PI*r^2
area of sector= 240/360*22/7*6*6
=75.42. ANS...........
50.

What is Base/Perpendicular ?

Answer» PERPENDICULAR = OPPOSITE SIDE to Ф

Base = ADJACENT side to Ф

Tan Ф = \frac{perpendicular}{base}

\frac{1}{tan} teta =  \frac{base}{perpendicular}

CotФ = \frac{base}{perpendicular}