98971 + Interview Questions in Primary School in Math

1.	1. Following are the number of goals scored by a football team in 25 matches.6,8,7,7,6,5,3,2,5,6,5,4,3,6,6,5,4,6,7,3,2,3,5,4,1elements of mathematics class 8
Answer» Answer: your answer Step-by-step explanation: Mean =sum of observation/ no. of observations =2+3+4+5+0+1+3+3+4+3/10 =28/10 =2.8 mean = 2.8 median let us write given observatins in ascending ORDER = 0123333445 here no. of observations r 10 which is an even no. therefore observation at 5th and 6th PLACE is at MIDDLE position ile. 3 and 3 median = sum of observation at 5th and 6th place / 2 = 3+3/2 =6/2 =3 median = 3 mode= observation which repeated MAXIMUM time = 3 mode = 3 plz mark brain list

1.

1. Following are the number of goals scored by a football team in 25 matches.6,8,7,7,6,5,3,2,5,6,5,4,3,6,6,5,4,6,7,3,2,3,5,4,1elements of mathematics class 8

Answer»

Answer:

your answer

Step-by-step explanation:

Mean =sum of observation/ no. of observations

=2+3+4+5+0+1+3+3+4+3/10

=28/10

=2.8

mean = 2.8

median

let us write given observatins in ascending ORDER

= 0123333445

here no. of observations r 10 which is an even no.

therefore observation at 5th and 6th PLACE is at MIDDLE position ile. 3 and 3

median = sum of observation at 5th and 6th place / 2

= 3+3/2

=6/2

=3

median = 3

mode= observation which repeated MAXIMUM time

= 3

mode = 3

plz mark brain list

Discussion

2.	15. A sum of money is lent for 5 years at R% simple interest per annum. If the interestearned be one-fourth of the money lent, find the value of R.the simple interest earned on a certain sum in 5 years is 30% of the sum. Find the value of R
Answer» Step-by-step EXPLANATION: this ANSWER will HELP you

2.

15. A sum of money is lent for 5 years at R% simple interest per annum. If the interestearned be one-fourth of the money lent, find the value of R.the simple interest earned on a certain sum in 5 years is 30% of the sum. Find the value of R

Answer»

Step-by-step EXPLANATION:

this ANSWER will HELP you

Discussion

3.	In how many years does the sum of 1200 became 1800 at the rate of simple intrest of 5% per anumtake a pic and send
Answer» Answer: 10 years DEAR because it is increse 600 rs and 600 rs is 50 percent of 1200 and GIVEN interset is 5 percent so 5 × 10 = 50 plese like this trick sortcut ANS...

3.

In how many years does the sum of 1200 became 1800 at the rate of simple intrest of 5% per anumtake a pic and send

Answer»

Answer:

10 years DEAR because it is increse 600 rs

and 600 rs is 50 percent of 1200 and GIVEN interset is 5 percent

so 5 × 10 = 50 plese like this trick

sortcut ANS...

Discussion

4.	Abx+) 850nd the value of the following368 x 12 + 18 x 368 I want how to do problem
Answer» 368×12+18×368 368×(12+18) 368×30 11040

4.

Abx+) 850nd the value of the following368 x 12 + 18 x 368 I want how to do problem

Answer»

368×12+18×368

368×(12+18)

368×30

11040

Discussion

5.	The parallel sides of a trapezium measure 20 cm and 28 cm respectively and the distance between them is10 cm. Find the area of trapezium.
Answer» Answer: 240 cm. Step-by-step explanation: FORMULA of Area of Trapezium= Average of the SUM of two PARALLEL sides × height ∴ 1/2 (ONE side + Another side) × height = 1/2 (20 + 28) × 10 = 1/2 × 48 × 10 = 1/2 × 480 = 240 Answer: 240 cm

5.

The parallel sides of a trapezium measure 20 cm and 28 cm respectively and the distance between them is10 cm. Find the area of trapezium.

Answer»

Answer:

240 cm.

Step-by-step explanation:

FORMULA of Area of Trapezium= Average of the SUM of two PARALLEL sides × height

∴ 1/2 (ONE side + Another side) × height

= 1/2 (20 + 28) × 10

= 1/2 × 48 × 10

= 1/2 × 480

= 240

Answer: 240 cm

Discussion

6.	A man cycles at 12 km per hour. How much distance does he cover in 35 minutes?Option -30km20 km please explain step by step
Answer» Answer: answer is CORRECT GOOD job but I THINK the answer is 25

6.

A man cycles at 12 km per hour. How much distance does he cover in 35 minutes?Option -30km20 km please explain step by step

Answer»

Answer:

answer is CORRECT GOOD job but I THINK the answer is 25

Discussion

7.	Joseph deposited Rs 15000/- in a bank at the rate of 10% interest. Rafeekdeposited Rs 15000/- in another bank at the rate of 10% compound interest. a) After 29 years, how much amount would Joseph get back? b) After 2 years, how much amount would Rafeeq get back?
Answer» Answer: d) After 29 YEARS how much AMOUNT would RAFEEQ GET back

7.

Joseph deposited Rs 15000/- in a bank at the rate of 10% interest. Rafeekdeposited Rs 15000/- in another bank at the rate of 10% compound interest. a) After 29 years, how much amount would Joseph get back? b) After 2 years, how much amount would Rafeeq get back?

Answer»

Answer:

d) After 29 YEARS how much AMOUNT would RAFEEQ GET back

Discussion

8.	Mrcespl-threrfthmetthe1SW)Its )13.The side of a square field is 120 meters. The cost of preparing a grass lawn is 35 persquare meter. How much will it cost, if the entire field is converted into a lawn?
Answer» ANSWER: mr ces pl- t hrer fth met the 1S W) Its ) 13. The SIDE of a square field is 120 meters. The COST of preparing a grass lawn is 35 per square METER. How much will it cost, if the ENTIRE field is converted into a lawn?

8.

Mrcespl-threrfthmetthe1SW)Its )13.The side of a square field is 120 meters. The cost of preparing a grass lawn is 35 persquare meter. How much will it cost, if the entire field is converted into a lawn?

Answer»

ANSWER:

mr

ces

pl-

t

hrer

fth

met

the

1S

W)

Its )

13.

The SIDE of a square field is 120 meters. The COST of preparing a grass lawn is 35 per

square METER. How much will it cost, if the ENTIRE field is converted into a lawn?

Discussion

9.	A man cycles at 12 km per hour. How much distance does he cover in 35 minutes?Option -30km/hour 20 km/hour please explain step by step
Answer» Answer: THIS IS JUST AN example Time taken to COVER 20 km at SPEED 5 km/hr = 4 HOURS ∴ Fixed time = 4 HOUR - 40 minutes = 3 hour 20 min Time taken to cover 20 km at the speed 8 km/hr = 20/8 = 2 hours 30 minutes ∴ Required time = 3 hours 20 minutes - 2 hr 30 min =50 minutes

9.

A man cycles at 12 km per hour. How much distance does he cover in 35 minutes?Option -30km/hour 20 km/hour please explain step by step

Answer»

Answer:

THIS IS JUST AN example

Time taken to COVER 20 km at SPEED 5 km/hr = 4 HOURS

∴ Fixed time = 4 HOUR - 40 minutes = 3 hour 20 min

Time taken to cover 20 km at the speed 8 km/hr = 20/8 = 2 hours 30 minutes

∴ Required time = 3 hours 20 minutes - 2 hr 30 min

=50 minutes

Discussion

10.	Draw thegraph of given polynomial and find thezeroes. Justify the answerp(x)= x²+5x-5.plz give answer
Answer» Answer: This is the THING you are asking for(PLEASE MARK as BRAINLIEST.)

10.

Draw thegraph of given polynomial and find thezeroes. Justify the answerp(x)= x²+5x-5.plz give answer

Answer»

Answer:

This is the THING you are asking for(PLEASE MARK as BRAINLIEST.)

Discussion

11.	A perimiter of a circle is called its circumference. true or false(if you don't know the answer so don't answer pls)
Answer» Answer: The term is closely associated with the work of mathematician and meteorologist Edward Lorenz. He noted that butterfly effect is derived from the metaphorical example of the details of a tornado (the exact time of formation, the exact path taken) being influenced by minor perturbations such as a distant butterfly flapping its wings SEVERAL weeks earlier. Lorenz discovered the effect when he OBSERVED runs of his weather MODEL with initial condition data that were rounded in a SEEMINGLY inconsequential manner. He noted that the weather model would FAIL to reproduce the results of runs with the unrounded initial condition data. A very small change in initial conditions had

11.

A perimiter of a circle is called its circumference. true or false(if you don't know the answer so don't answer pls)

Answer»

Answer:

The term is closely associated with the work of mathematician and meteorologist Edward Lorenz. He noted that butterfly effect is derived from the metaphorical example of the details of a tornado (the exact time of formation, the exact path taken) being influenced by minor perturbations such as a distant butterfly flapping its wings SEVERAL weeks earlier. Lorenz discovered the effect when he OBSERVED runs of his weather MODEL with initial condition data that were rounded in a SEEMINGLY inconsequential manner. He noted that the weather model would FAIL to reproduce the results of runs with the unrounded initial condition data. A very small change in initial conditions had

Discussion

12.	A tank is in the form of a right circular cylinder. Its height is 48 m and the base area is 616 sq. m. Findthe lateral surface area and volume of the cylinders
Answer» Answer: The process by which green PLANTS and ANIMALS and WATER and the other organisms USE sunlight to synthesize nutrients from carbon dioxide and WATERS..

12.

A tank is in the form of a right circular cylinder. Its height is 48 m and the base area is 616 sq. m. Findthe lateral surface area and volume of the cylinders

Answer»

Answer:

The process by which green PLANTS and ANIMALS and WATER and the other organisms USE sunlight to synthesize nutrients from carbon dioxide and WATERS..

Discussion

13.	5= 0.01443) Square of 0.013 = (0.013)2= 0.013 x 0.013= 0.000169* Which of the following numbers can be3) 0.00161) 2.54) 14.4written as a square?2) 0.255) 1.44Aanbe
Answer» ANSWER: SORRY I don't KNOW the answer

13.

5= 0.01443) Square of 0.013 = (0.013)2= 0.013 x 0.013= 0.000169* Which of the following numbers can be3) 0.00161) 2.54) 14.4written as a square?2) 0.255) 1.44Aanbe

Answer»

ANSWER:

SORRY I don't KNOW the answer

Discussion

14.	3. In a circle with centre O, the measure of a minor arc is 110°. What is the measure ofthe major arc PYQ?
Answer» ANSWER: Suppose PQ is the minor arc and then m(arc PQ) = 110°. We KNOW that, measure of MAJOR arc = 360° − measure of corresponding minor arc. HENCE, the measure of major arc PYQ is 250°.

14.

3. In a circle with centre O, the measure of a minor arc is 110°. What is the measure ofthe major arc PYQ?

Answer»

ANSWER:

Suppose PQ is the minor arc and then m(arc PQ) = 110°. We KNOW that, measure of MAJOR arc = 360° − measure of corresponding minor arc. HENCE, the measure of major arc PYQ is 250°.

Discussion

15.	HAPPY HOLI IS ADVANCE TO ALL OF THEM WHO R VERY VERY EXITED FOR HOLI LIKE MEI AM SOO EXITED FOR HOLI,,,,,,,,,,,,,,
Answer» ANSWER: I Am also SOO exited for HOLI Step-by-step explanation: ADVANCED happy Holi

15.

HAPPY HOLI IS ADVANCE TO ALL OF THEM WHO R VERY VERY EXITED FOR HOLI LIKE MEI AM SOO EXITED FOR HOLI,,,,,,,,,,,,,,

Answer»

ANSWER:

I Am also SOO exited for HOLI

Step-by-step explanation:

ADVANCED happy Holi

Discussion

16.	17. Find the amount to be paid at the end of 3 years, if Principal is ₹2400 at 15p.a.
Answer» Solution:- ━━━━━━━━━━━━━━━━━━━━━━━━━━ $\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}$ ◍ Here, the question has given us the principal, rate of interest and time that is Rs. 2,400, 15% per ANNUM and for 3 years RESPECTIVELY. Now, the question has asked us to find the simple interest of it. So to get the amount FIRST of all we need to find out the simple interest for that we simply have to apply the formula of SI. After it we have to add the principal and the SI to get the amount. ANSWER:- ◈ Simple Interest = Rs. 1,080 ◈ Amount = Rs. 3,480 GIVEN:- ☆ Principal = Rs. 2,400 ☆ Rate of Interest = 15% per annum ☆ Time = 3 years TO FIND:- ↠Simple Interest= ? ↠Amount = ? FORMULA:- ➾ Simple Interest = P × R × T / 100 ➾ Amount = Principal + SI SOLVING BY APPLYING THE FORMULA:- ☆ Principal = Rs. 2,400 ☆ Rate of Interest = 15% per annum ☆ Time = 3 years ➾ Simple Interest = P × R × T / 100 ➾ Amount = Principal + SI Finding the SI:- ➢ SI = 2,400 × 15 × 3 / 100 ➢ SI = 2,400 × 45 / 100 ➢ Cancelling the zeros. ➢ SI = 24 × 45 / 1 ➢ SI = 24 × 45 ➢ SI = 24 × 45 = 1,080 ➢ SI = Rs. 1,080 The simple interest is of Rs. 1,080. Finding the amount:- ➢ Amount = 2,400 + 1,080 ➢ Amount = 2,400 + 1,080 = 3,480 ➢ Amount = Rs. 3,480 Thus, we got the answer. The amount is Rs. 3,480. ━━━━━━━━━━━━━━━━━━━━━━━━━━

16.

17. Find the amount to be paid at the end of 3 years, if Principal is ₹2400 at 15p.a.

Answer»

Solution:-

━━━━━━━━━━━━━━━━━━━━━━━━━━

$\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}$

◍ Here, the question has given us the principal, rate of interest and time that is Rs. 2,400, 15% per ANNUM and for 3 years RESPECTIVELY. Now, the question has asked us to find the simple interest of it. So to get the amount FIRST of all we need to find out the simple interest for that we simply have to apply the formula of SI. After it we have to add the principal and the SI to get the amount.

ANSWER:-

◈ Simple Interest = Rs. 1,080

◈ Amount = Rs. 3,480

GIVEN:-

☆ Principal = Rs. 2,400

☆ Rate of Interest = 15% per annum

☆ Time = 3 years

TO FIND:-

↠Simple Interest= ?

↠Amount = ?

FORMULA:-

➾ Simple Interest = P × R × T / 100

➾ Amount = Principal + SI

SOLVING BY APPLYING THE FORMULA:-

☆ Principal = Rs. 2,400

☆ Rate of Interest = 15% per annum

☆ Time = 3 years

➾ Simple Interest = P × R × T / 100

➾ Amount = Principal + SI

Finding the SI:-

➢ SI = 2,400 × 15 × 3 / 100

➢ SI = 2,400 × 45 / 100

➢ Cancelling the zeros.

➢ SI = 24 × 45 / 1

➢ SI = 24 × 45

➢ SI = 24 × 45 = 1,080

➢ SI = Rs. 1,080

The simple interest is of Rs. 1,080.

Finding the amount:-

➢ Amount = 2,400 + 1,080

➢ Amount = 2,400 + 1,080 = 3,480

➢ Amount = Rs. 3,480

Thus, we got the answer. The amount is Rs. 3,480.

━━━━━━━━━━━━━━━━━━━━━━━━━━

Discussion

17.	17. Find the amount to be paid at the end of 3 years, if Principal is ₹2400 at 15p.a plz tel step by step explanation
Answer» <P>Step-by-step EXPLANATION: Given; P = 2400 T = 3 years R = 15 % A = P (1+R/100)^T A = 2400 ( 1+ 15/100)^3 A = 2400 ( 115/100 ) ^3 A = 2400 × 115/100 × 115/100 × 115/100 A = 24×115×115×115/10000 A = 36501000/10000 A = 3650.1 Hope it helps!!

17.

17. Find the amount to be paid at the end of 3 years, if Principal is ₹2400 at 15p.a plz tel step by step explanation

Answer»

<P>Step-by-step EXPLANATION:

Given;

P = 2400

T = 3 years

R = 15 %

A = P (1+R/100)^T

A = 2400 ( 1+ 15/100)^3

A = 2400 ( 115/100 ) ^3

A = 2400 × 115/100 × 115/100 × 115/100

A = 24×115×115×115/10000

A = 36501000/10000

A = 3650.1

Hope it helps!!

Discussion

18.	How many bricks of length 25 cm, breadth15 cm and height 10 cm are required tobuild a wall of length 6 m, height 2.5 m andbreadth 0.5 m?
Answer» VOLUME of BRICK = 25×15×10 = 250×15 = 3750cm3 volume of WALL = 600×250×50 30000×250 7500000cm3 no of BRICKS = 7500000/3750 2000 bricks

18.

How many bricks of length 25 cm, breadth15 cm and height 10 cm are required tobuild a wall of length 6 m, height 2.5 m andbreadth 0.5 m?

Answer»

VOLUME of BRICK = 25×15×10 = 250×15 = 3750cm3

volume of WALL = 600×250×50

30000×250

7500000cm3

no of BRICKS = 7500000/3750

2000 bricks

Discussion

19.	1) 216 cm2) 108 cm2. The length of rectangular hall is 18 m and breadth is 12 m. How many squareof length 25 cm will fit in the hall ?1) 34002) 40004) 34563) 4456
Answer» ANSWER: dggdtgbcgjkfrhbxvjncdg

19.

1) 216 cm2) 108 cm2. The length of rectangular hall is 18 m and breadth is 12 m. How many squareof length 25 cm will fit in the hall ?1) 34002) 40004) 34563) 4456

Answer»

ANSWER:

dggdtgbcgjkfrhbxvjncdg

Discussion

20.	Find the maximum length of the rod that can be kept in cuboidical box of side 30 cm, 24 cm and 18cm.
Answer» Answer: just APPLY the FORMULA for diagonal of a cuboid Step-by-step EXPLANATION: U will get your answer

20.

Find the maximum length of the rod that can be kept in cuboidical box of side 30 cm, 24 cm and 18cm.

Answer»

Answer:

just APPLY the FORMULA for diagonal of a cuboid

Step-by-step EXPLANATION:

U will get your answer

Discussion

21.	प्रश्न. सही जोड़ी बनाइए।axa(2) वर्ग(3) त्रिभुज14 समांतर चतुर्भुज150bxhपाई।1/2bxhaxb
Answer» Answer: Step-by-step EXPLANATION: I don't know SORRY please MARK me as BRAINLEST

21.

प्रश्न. सही जोड़ी बनाइए।axa(2) वर्ग(3) त्रिभुज14 समांतर चतुर्भुज150bxhपाई।1/2bxhaxb

Answer»

Answer:

Step-by-step EXPLANATION:

I don't know SORRY please MARK me as BRAINLEST

Discussion

22.	Activity - 1Let's find out the pairs.You know the peculiarities of parallel lines. Identify the parallelpairs from the lines given below.PСD uNMKLХWrite the parallel lines in pairs.e.g.PQ, UVSAMAGRA SHIKSHA, KERALADEPARTMENT OF GENERAL EDUCATION
Answer» ANSWER: OK just WAIT I am ANSWERING

22.

Activity - 1Let's find out the pairs.You know the peculiarities of parallel lines. Identify the parallelpairs from the lines given below.PСD uNMKLХWrite the parallel lines in pairs.e.g.PQ, UVSAMAGRA SHIKSHA, KERALADEPARTMENT OF GENERAL EDUCATION

Answer»

ANSWER:

OK just WAIT I am ANSWERING

Discussion

23.	5. Sanju completes 12 rounds arounda square park every day. If oneside of the park is 120 m, find out inkilometres and metres the distance thatSanju covers daily.
Answer» ANSWER: CLICK on image.okkkkkkkk

23.

5. Sanju completes 12 rounds arounda square park every day. If oneside of the park is 120 m, find out inkilometres and metres the distance thatSanju covers daily.

Answer»

ANSWER:

CLICK on image.okkkkkkkk

Discussion

24.	A tree is broken at a height of 5 metre from the ground and its top touches the ground at adistance of 12 m from the base of the tree find the original height of the treeif the same
Answer» ANSWER: Let A'CB be the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled TRIANGLE, at B. Hence, the TOTAL HEIGHT of the tree(A'B) = A'C + CB = 13 + 5 = 18 m.

24.

A tree is broken at a height of 5 metre from the ground and its top touches the ground at adistance of 12 m from the base of the tree find the original height of the treeif the same

Answer»

ANSWER:

Let A'CB be the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled TRIANGLE, at B. Hence, the TOTAL HEIGHT of the tree(A'B) = A'C + CB = 13 + 5 = 18 m.

Discussion

25.	Biswa decided to save money for a trip. He waschecking some investment options for saving,but his friend Kalia suggested to check if he isinterested in compound interest. Biswa found abank that offers 6% compound interestcalculated on a half-yearly basis. To know indetail, Biswa planned to deposit Rs. 20000 eachon 1st of January and 1st of July of that sameyear. But Biswa is not that great at Math! Canyou help him know, what amount he would havegained through interest by the end of the year?
Answer» here P= 20000 r= 6% = 6/2= 3% half yearly t= 1/2 years N= 1/2×2 = 1 A= P(1+r/100)¹ = 20000(1+6/100)¹ =20000×1.03 =20600 Now after 6 months he deposited ANOTHER 20000 So P= 20600+20000 = 40600 r= 6%= 3% n= 1 A= 40600( 1+ r/100)¹ = 40600(1+0.03) = 40600×(1.03) = 41818 Amount gained(C.I)= 41818-40000= 1818 Also, you can do EM together by taking the first principle anually + second principle half yearly.

25.

Biswa decided to save money for a trip. He waschecking some investment options for saving,but his friend Kalia suggested to check if he isinterested in compound interest. Biswa found abank that offers 6% compound interestcalculated on a half-yearly basis. To know indetail, Biswa planned to deposit Rs. 20000 eachon 1st of January and 1st of July of that sameyear. But Biswa is not that great at Math! Canyou help him know, what amount he would havegained through interest by the end of the year?

Answer»

here

P= 20000

r= 6% = 6/2= 3% half yearly

t= 1/2 years

N= 1/2×2 = 1

A= P(1+r/100)¹

= 20000(1+6/100)¹

=20000×1.03

=20600

Now after 6 months he deposited ANOTHER 20000

So

P= 20600+20000

= 40600

r= 6%= 3%

n= 1

A= 40600( 1+ r/100)¹

= 40600(1+0.03)

= 40600×(1.03)

= 41818

Amount gained(C.I)= 41818-40000= 1818

Also, you can do EM together by taking the first principle anually + second principle half yearly.

Discussion

26.	The compound interest forRs.50,000 at 8% per annum for 2years, compounded annually is8340831083508320
Answer» ANSWER: 4) 8320 (answer) HOPE it will HELP you...

26.

The compound interest forRs.50,000 at 8% per annum for 2years, compounded annually is8340831083508320

Answer»

ANSWER:

4) 8320 (answer)

HOPE it will HELP you...

Discussion

27.	Info01) Which of the following is correct for 5 in 2a + 5 = b?1. O It is a fixed constant.2. O It is an unknown.3. O It is an arbitary constant. 4.t is a variable.
Answer» ANSWER: o is a fixed constant Step-by-step EXPLANATION: MARK it as BRAINILEST PLS

27.

Info01) Which of the following is correct for 5 in 2a + 5 = b?1. O It is a fixed constant.2. O It is an unknown.3. O It is an arbitary constant. 4.t is a variable.

Answer»

ANSWER:

o is a fixed constant

Step-by-step EXPLANATION:

MARK it as BRAINILEST PLS

Discussion

28.	Solve thisPlease help me do my homework
Answer» ANSWER: a.volume=4.75.97.4=205.202cm³ b.volume=9.43.04.1=115.62cm³ Step-by-step EXPLANATION:

28.

Solve thisPlease help me do my homework

Answer»

ANSWER:

a.volume=4.7*5.9*7.4=205.202cm³

b.volume=9.4*3.0*4.1=115.62cm³

Step-by-step EXPLANATION:

Discussion

29.	In a basket there are colorful balls from 1 to 10 what is the probability of getting even numberof composite number of numbers greater than 8whoever answers can be marked as brainliest
Answer» Step-by-step explanation: possible out COMES =10 p(getting an even number)=5/10 =1/2 p(getting composite number)=5/10 =1/2 p(getting number GREATER than 8) = 2/10 =1/5

29.

In a basket there are colorful balls from 1 to 10 what is the probability of getting even numberof composite number of numbers greater than 8whoever answers can be marked as brainliest

Answer»

Step-by-step explanation:

possible out COMES =10

p(getting an even number)=5/10

=1/2

p(getting composite number)=5/10

=1/2

p(getting number GREATER than 8)

= 2/10 =1/5

Discussion

30.	Q. 9Do as directed.1) Which type of angle is created by half rotation? straight angle2) Write the symbolic form of two perpendicular lines AB and CD?AB LED3) What is the measurement of an angle formed in the morning at 9 o'clock? Right an4) Where will the hand of a clock stop if kavya starts from 5 and makes % of a rotationanti-clock wise?8 o'chek5) Draw and write the types of triangle based on its sides.-IsoscelesTA
Answer» Answer: 90 ,perllogram,RIGHT angle,8,

30.

Q. 9Do as directed.1) Which type of angle is created by half rotation? straight angle2) Write the symbolic form of two perpendicular lines AB and CD?AB LED3) What is the measurement of an angle formed in the morning at 9 o'clock? Right an4) Where will the hand of a clock stop if kavya starts from 5 and makes % of a rotationanti-clock wise?8 o'chek5) Draw and write the types of triangle based on its sides.-IsoscelesTA

Answer»

Answer:

90 ,perllogram,RIGHT angle,8,

Discussion

31.	Dark colour clothes keep us warm as :- a) they reflect heat , b) they absorb more heat , c) they scatter heat ,d) they stick to our body
Answer» ANSWER: B) they ABSORB more heat Step-by-step EXPLANATION:

31.

Dark colour clothes keep us warm as :- a) they reflect heat , b) they absorb more heat , c) they scatter heat ,d) they stick to our body

Answer»

ANSWER:

B) they ABSORB more heat

Step-by-step EXPLANATION:

Discussion

32.	I. Choose the correct answer.1. The mode of 1,2,2, 3, 3, 4, 4, 4, is (A) 2 B) 3 C) 4 D) Noneof Ohservations)
Answer» Solution:- ━━━━━━━━━━━━━━━━━━━━━━━━━━ $\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}$ $\implies$ Here, the QUESTION has given us the data that is 1, 2, 2, 3, 3, 4, 4, 4. Now, the question has asked us to find the mode of the given data. So, in FINDING mode arrange the data and observe that the observation which is repeated frequent TIMES will be the mode. ANSWER:- ⇨ Mode of the given data is 4. Thus, option C that is 4 is correct. GIVEN:- ★ Data = 1, 2, 2, 3, 3, 4, 4, 4 TO FIND:- ➝ Mode of given data = ? HOW TO SOLVE:- Arrange the data. The most frequent number will be the mode. SOLVING BY APPLYING THE FORMULA:- ⇒ Data = 1, 2, 2, 3, 3, 4, 4, 4 ⇒ ARRANGING the data = 1, 2, 2, 3, 3, 4, 4, 4 ⇒ No. of times a number is repeated = ⬇ 1. 1 is repeated 1 time. 2. 2 is repeated 2 times. 3. 3 is repeated 2 times. 4. 4 is repeated 3 times ⇒ Maximum no. of times a number is repeated = 3 ⇒ Most frequent no. = 4 [As it is repeated 3 times.] Thus, we got the answer. So, the mode of the given data is 4. So, option C (4) is correct. ━━━━━━━━━━━━━━━━━━━━━━━━━━

32.

I. Choose the correct answer.1. The mode of 1,2,2, 3, 3, 4, 4, 4, is (A) 2 B) 3 C) 4 D) Noneof Ohservations)

Answer»

Solution:-

━━━━━━━━━━━━━━━━━━━━━━━━━━

$\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}$

$\implies$ Here, the QUESTION has given us the data that is 1, 2, 2, 3, 3, 4, 4, 4. Now, the question has asked us to find the mode of the given data. So, in FINDING mode arrange the data and observe that the observation which is repeated frequent TIMES will be the mode.

ANSWER:-

⇨ Mode of the given data is 4. Thus, option C that is 4 is correct.

GIVEN:-

★ Data = 1, 2, 2, 3, 3, 4, 4, 4

TO FIND:-

➝ Mode of given data = ?

HOW TO SOLVE:-

Arrange the data.
The most frequent number will be the mode.

SOLVING BY APPLYING THE FORMULA:-

⇒ Data = 1, 2, 2, 3, 3, 4, 4, 4

⇒ ARRANGING the data = 1, 2, 2, 3, 3, 4, 4, 4

⇒ No. of times a number is repeated = ⬇

1. 1 is repeated 1 time.

2. 2 is repeated 2 times.

3. 3 is repeated 2 times.

4. 4 is repeated 3 times

⇒ Maximum no. of times a number is repeated = 3

⇒ Most frequent no. = 4 [As it is repeated 3 times.]

Thus, we got the answer. So, the mode of the given data is 4. So, option C (4) is correct.

━━━━━━━━━━━━━━━━━━━━━━━━━━

Discussion

33.	A trader bought 20 quintals of rubber sheets at19850 rupees a quintal. He spent 3000 rupees totake the load to the shop. Since prices went down,he had to sell them at 18250 rupees a quintal. Howmuch money did he lose?
Answer» Solution!! The concept of profit and loss has to be USED here. COST price (CP) of 1 quintal = Rs 19,850 CP of 20 quintals = Rs 19,850 × 20 CP of 20 quintals = Rs 3,97,000 The trader also SPENT Rs 3000 for shipping purpose. Total CP of 20 quintals = Rs 3,97,000 + Rs 3,000 Total CP of 20 quintals = Rs 4,00,000 Selling price (SP) of 1 quintal = Rs 18,250 SP of 20 quintals = Rs 18250 × 20 SP of 20 quintals = Rs 3,65,000 Total CP > Total SP Loss = CP - SP Loss = Rs 4,00,000 - Rs 3,65,000 Loss = Rs 35,000 Hence, the trader lost Rs 35,000. More information:- If SP>CP, then it is profit. If CP>SP, then it is loss. Profit = SP - CP Loss = CP - SP Profit% = (Profit/CP) × 100 Loss% = (Loss/CP) × 100 CP → Cost Price SP → Selling Price 1 quintal = 100 kg

33.

A trader bought 20 quintals of rubber sheets at19850 rupees a quintal. He spent 3000 rupees totake the load to the shop. Since prices went down,he had to sell them at 18250 rupees a quintal. Howmuch money did he lose?

Answer»

Solution!!

The concept of profit and loss has to be USED here.

COST price (CP) of 1 quintal = Rs 19,850

CP of 20 quintals = Rs 19,850 × 20

CP of 20 quintals = Rs 3,97,000

The trader also SPENT Rs 3000 for shipping purpose.

Total CP of 20 quintals = Rs 3,97,000 + Rs 3,000

Total CP of 20 quintals = Rs 4,00,000

Selling price (SP) of 1 quintal = Rs 18,250

SP of 20 quintals = Rs 18250 × 20

SP of 20 quintals = Rs 3,65,000

Total CP > Total SP

Loss = CP - SP

Loss = Rs 4,00,000 - Rs 3,65,000

Loss = Rs 35,000

Hence, the trader lost Rs 35,000.

More information:-

If SP>CP, then it is profit.

If CP>SP, then it is loss.

Profit = SP - CP

Loss = CP - SP

Profit% = (Profit/CP) × 100

Loss% = (Loss/CP) × 100

CP → Cost Price

SP → Selling Price

1 quintal = 100 kg

Discussion

34.	A partical is moving along a circular path of radius 16m and it completes one revolution in 30sec. If total time of motion is 75sec, the displacement of the partical is ___1) 16m2) 54m3) 32m4) 75m
Answer» Given :- A PARTICAL is moving along a CIRCULAR path of radius 16m. It completes one revolution in 30 second. Total time of motion is 75 seconds. To Find :- The displacement of the particle. Solution :- In 30 seconds, a particle completes one revolution. So, 75 seconds can be break down as 75 seconds = 30 seconds + 30 seconds + 15 seconds Thus, In 75 seconds, a particle takes 2 complete revolution and one half revolution. As we know that, Displacement is the shortest distance between the INITIAL and final POSITION. Thus, Displacement, PQ = Diameter = 2 × radius = 32 m. $\overbrace{ \underline { \boxed { \rm \therefore \: The \: displacement \: of \: particle \: is \: 32 \: m)}}}$ $\boxed{ \sf \: Option \: (3) \: is \: correct}$ Additional Information :- Displacement is the shortest distance between the initial and final position. It is a vector quantity i.e. it has both magnitude and direction.

34.

A partical is moving along a circular path of radius 16m and it completes one revolution in 30sec. If total time of motion is 75sec, the displacement of the partical is ___1) 16m2) 54m3) 32m4) 75m

Answer»

Given :-

A PARTICAL is moving along a CIRCULAR path of radius 16m.

It completes one revolution in 30 second.

Total time of motion is 75 seconds.

To Find :-

The displacement of the particle.

Solution :-

In 30 seconds, a particle completes one revolution.

So,

75 seconds can be break down as

75 seconds = 30 seconds + 30 seconds + 15 seconds

Thus,

In 75 seconds, a particle takes 2 complete revolution and one half revolution.

As we know that,

Displacement is the shortest distance between the INITIAL and final POSITION.

Thus,

Displacement, PQ = Diameter = 2 × radius = 32 m.

$\overbrace{ \underline { \boxed { \rm \therefore \: The \: displacement \: of \: particle \: is \: 32 \: m)}}}$

$\boxed{ \sf \: Option \: (3) \: is \: correct}$

Additional Information :-

Displacement is the shortest distance between the initial and final position.

It is a vector quantity i.e. it has both magnitude and direction.

Discussion

35.	Given that AB is a line segment and the anglea= 25°, work out the value of x.Given that AB is a line segment and the angle a= 25°, work out the value of x.
Answer» Answer:answer to your question ✍️ GIVEN that AB is a line SEGMENT and the ANGLE a = 25°, work out the VALUE of x . Step-by-step EXPLANATION:

35.

Given that AB is a line segment and the anglea= 25°, work out the value of x.Given that AB is a line segment and the angle a= 25°, work out the value of x.

Answer»

Answer:answer to your question ✍️ GIVEN that AB is a line SEGMENT and the ANGLE a = 25°, work out the VALUE of x .

Step-by-step EXPLANATION:

Discussion

36.	Section0.31 Solve any three of the following1) Data about the different modes of transported by students to1 studentMode of travellingPrivate carNumber of studentsPublic BusSchool BusCycleWalking
Answer» ANSWER: School bus, CYCLE, Step-by-step EXPLANATION: WALKING

36.

Section0.31 Solve any three of the following1) Data about the different modes of transported by students to1 studentMode of travellingPrivate carNumber of studentsPublic BusSchool BusCycleWalking

Answer»

ANSWER:

School bus, CYCLE,

Step-by-step EXPLANATION:

WALKING

Discussion

37.	An article is parched for Rs.520 and sold for Rs650 The pain percentage isa. 4520%4. 23% 4. 24
Answer» ANSWER: the GAIN PERCENTAGE is 20%.

37.

An article is parched for Rs.520 and sold for Rs650 The pain percentage isa. 4520%4. 23% 4. 24

Answer»

ANSWER:

the GAIN PERCENTAGE is 20%.

Discussion

38.	An article is parched for Rs. 0 and sold for Rs 0. The pain percentage isa. 4520%4. 23% 4. 24
Answer» Step-by-step explanation: 45% IAM not SURE with ANSWER

38.

An article is parched for Rs. 0 and sold for Rs 0. The pain percentage isa. 4520%4. 23% 4. 24

Answer»

Step-by-step explanation:

45%

IAM not SURE with ANSWER

Discussion

39.	Ashepherd have 200 sheep with him. Find the numberof Sheeps with him after 3 years if increase in number of sheep is 8% every year.
Answer» Step-by-step EXPLANATION: It is SIMILAR to the problem of SIMPLE interest SI= 100 PRT = 100 200×8×3 = 48 sheeps. Total sheeps = 200+48 = 248 sheeps.

39.

Ashepherd have 200 sheep with him. Find the numberof Sheeps with him after 3 years if increase in number of sheep is 8% every year.

Answer»

Step-by-step EXPLANATION:

It is SIMILAR to the problem of SIMPLE interest

SI=

100

PRT

=

100

200×8×3

= 48 sheeps.

Total sheeps = 200+48

= 248 sheeps.

Discussion

40.	A track is in the form of ring whose inner and outer circumferences are 88m and132m respectively find the width of the trackorA garden is 90m and 75m broad. A path 5m wide is to be built all around (outside)it along its border. Find the area of path.
Answer» Q2) A garden is 90 m long and 75 m broad. A path 5 m WIDE is to be BUILT outside and around it. Find the area of the path. Also find the area of the garden in a hectare. Length= 90m Breadth= 75m Area of the garden= $l\times bl×b$ =90m+75m=6750m^2=90m+75m=6750m Length of the garden INCLUDING path =90m+5m+5m=100m=90m+5m+5m=100m Breadth of the garden including path =75m+5m+5m=85m=75m+5m+5m=85m Area of the garden including path =l\times b=l×b =100m $\times85m=8500m^2=100m×85m=8500m$ Area of the path= 8500m^2-6750m^2=1750m^28500m Hence, the required area of path= 1750m^21750m and area of the garden= =6750m^2=0.675=6750m =0.675

40.

A track is in the form of ring whose inner and outer circumferences are 88m and132m respectively find the width of the trackorA garden is 90m and 75m broad. A path 5m wide is to be built all around (outside)it along its border. Find the area of path.

Answer»

Q2) A garden is 90 m long and 75 m broad. A path 5 m WIDE is to be BUILT outside and around it. Find the area of the path. Also find the area of the garden in a hectare.

Length= 90m

Breadth= 75m

Area of the garden= $l\times bl×b$

=90m+75m=6750m^2=90m+75m=6750m

Length of the garden INCLUDING path

=90m+5m+5m=100m=90m+5m+5m=100m

Breadth of the garden including path

=75m+5m+5m=85m=75m+5m+5m=85m

Area of the garden including path

=l\times b=l×b

=100m $\times85m=8500m^2=100m×85m=8500m$

Area of the path= 8500m^2-6750m^2=1750m^28500m

Hence, the required area of path= 1750m^21750m

and area of the garden= =6750m^2=0.675=6750m

=0.675

Discussion

41.	(1) What is the number of basmati rice bags he must sell to have neither profit nor loss, ifthe number of bags of non-basmati rice sold is 6,400.
Answer» Answer: If a merchant NEITHER earns profit nor loss, then we have to equate both profit and loss he earns. It means if a merchant sells 3,200 number of BAGS of BASMATI rice and 6,400 number of bags of non-basmati rice, he neither earns profit nor loss. So, the CORRECT answer is option B.

41.

(1) What is the number of basmati rice bags he must sell to have neither profit nor loss, ifthe number of bags of non-basmati rice sold is 6,400.

Answer»

Answer:

If a merchant NEITHER earns profit nor loss, then we have to equate both profit and loss he earns. It means if a merchant sells 3,200 number of BAGS of BASMATI rice and 6,400 number of bags of non-basmati rice, he neither earns profit nor loss. So, the CORRECT answer is option B.

Discussion

42.	Metre of cloth. What isکراIdents are coming by private carof transport maximum used ?more students coming to school by walking as compared toyre of cloth and Sai boughtys, if the numbers 1 kg : 40
Answer» Answer: SORRY I dont KNOW the answer ONLY LOVE TO PLAY FREE FIRE

42.

Metre of cloth. What isکراIdents are coming by private carof transport maximum used ?more students coming to school by walking as compared toyre of cloth and Sai boughtys, if the numbers 1 kg : 40

Answer»

Answer:

SORRY I dont KNOW the answer

ONLY LOVE TO PLAY

FREE FIRE

Discussion

43.	Biswa decided to save money for a trip. He was checking some investment options for saving, but his friend Kalia suggested to check if he is interested in compound interest. Biswa found a bank that offers 6% compound interest calculated on a half-yearly basis. To know in detail, Biswa planned to deposit Rs. 20000 each on 1st of January and 1st of July of that same year. But Biswa is not that great at Math! Can you help him know, what amount he would have gained through interest by the end of the year?Your Answera) 1818b) 980c) 878d) 1586
Answer» Answer: 20000×9.09/100=1818 ANS

43.

Biswa decided to save money for a trip. He was checking some investment options for saving, but his friend Kalia suggested to check if he is interested in compound interest. Biswa found a bank that offers 6% compound interest calculated on a half-yearly basis. To know in detail, Biswa planned to deposit Rs. 20000 each on 1st of January and 1st of July of that same year. But Biswa is not that great at Math! Can you help him know, what amount he would have gained through interest by the end of the year?Your Answera) 1818b) 980c) 878d) 1586

Answer»

Answer:

20000×9.09/100=1818 ANS

Discussion

44.	The diagram shows a cuboid.The width of the cuboid is 25 cm.The end face of the cuboid is a square.The volume of the cuboid is 1.25 m'.a Work out the length of the cuboid.b Work out the surface area of the cuboid.
Answer» Length (1) = 25 cm, Breadth (b) = 20 cm, Height (h) = 5 cm ∵ The box is like a cuboid and total SURFACE area of a cuboid = 2(LB + bh + hl) Area of a box = 2([25 × 20) + (20 × 5) + (5 × 25)] cm2 = 2[500 + 100 + 125] cm2 = 2[725] cm2 = 1450 cm2 Total surface area of 250 boxes = 250 × 1450 cm2 = 362500 cm2 For smaller box: l = 15 cm, b = 12 cm, h = 5 cm Total surface area of a box = 2[lb + bh + hl] = 2[(15 × 12) + (12 × 5) + (5 × 15)] cm2 = 2[180 + 60 + 75] cm2 = 2[315] cm2 = 630 cm2 ⇒ Total surface area of 250 boxes = 250 × 630 cm2 = 157500 cm2 Now, total surface area of both kinds of boxes = 362500 cm2 + 157500 cm2 = 5,20,000 cm2 Area for overlaps = 5% of [ total surface area] ∴ Total area of the cardboard required = [Total area of 250 boxes] + [5% of total surface area] = 520000 cm2 + 26000 cm2 = 546000 cm2 Cost of cardboard: ∵ Cost of 1000 cm2 = Rs. 4

44.

The diagram shows a cuboid.The width of the cuboid is 25 cm.The end face of the cuboid is a square.The volume of the cuboid is 1.25 m'.a Work out the length of the cuboid.b Work out the surface area of the cuboid.

Answer»

Length (1) = 25 cm, Breadth (b) = 20 cm, Height (h) = 5 cm

∵ The box is like a cuboid and total SURFACE area of a cuboid = 2(LB + bh + hl)

Area of a box = 2([25 × 20) + (20 × 5) + (5 × 25)] cm2 = 2[500 + 100 + 125] cm2 = 2[725] cm2 = 1450 cm2

Total surface area of 250 boxes = 250 × 1450 cm2 = 362500 cm2

For smaller box: l = 15 cm, b = 12 cm, h = 5 cm

Total surface area of a box = 2[lb + bh + hl]

= 2[(15 × 12) + (12 × 5) + (5 × 15)] cm2

= 2[180 + 60 + 75] cm2

= 2[315] cm2 = 630 cm2

⇒ Total surface area of 250 boxes = 250 × 630 cm2

= 157500 cm2

Now, total surface area of both kinds of boxes

= 362500 cm2 + 157500 cm2

= 5,20,000 cm2

Area for overlaps = 5% of [ total surface area]

∴ Total area of the cardboard required = [Total area of 250 boxes] + [5% of total surface area]

= 520000 cm2 + 26000 cm2

= 546000 cm2

Cost of cardboard:

∵ Cost of 1000 cm2 = Rs. 4

Discussion

45.	If the circumference of a circular park is 36 cm. Find its diameterIf the circumference of a circular park is 36 cm. Find its diameter
Answer» Answer: circumference of CIRCLE = 2πr 36CM = 2πr 36/2 = πr πr = 18 cm R = 18/π cm diameter = 2r d = 2 × 18/π d = 36/π cm

45.

If the circumference of a circular park is 36 cm. Find its diameterIf the circumference of a circular park is 36 cm. Find its diameter

Answer»

Answer:

circumference of CIRCLE = 2πr

36CM = 2πr

36/2 = πr

πr = 18 cm

R = 18/π cm

diameter = 2r

d = 2 × 18/π

d = 36/π cm

Discussion

46.	3. The denominator of a rational number is2 more than its numerator. If thenumerator is increased 4 times and 8is added to the denominator, the new no.would be 4/3. Find the original number.
Answer» ANSWER: I have MENTIONED the answer in the PIC.. HOPE it HELPS..

46.

3. The denominator of a rational number is2 more than its numerator. If thenumerator is increased 4 times and 8is added to the denominator, the new no.would be 4/3. Find the original number.

Answer»

ANSWER:

I have MENTIONED the answer in the PIC..

HOPE it HELPS..

Discussion

47.	RATIO AND PROPORTIONQ1) Solve the following: 1)If (x+15): (x+7)=(x-1): (x+2), find the value of x
Answer» Answer: 29 Step-by-step explanation: U should ADD all the numbers and X MARK it as BRAINILEST

47.

RATIO AND PROPORTIONQ1) Solve the following: 1)If (x+15): (x+7)=(x-1): (x+2), find the value of x

Answer»

Answer:

29

Step-by-step explanation:

U should ADD all the numbers and X

MARK it as BRAINILEST

Discussion

48.	14, Calculate the area of the shaded region in each of the figures given below:10 m0$200712m43 m40 m()3
Answer» ANSWER: SORRY, PLEASE SPECIFY the QUESTION.

48.

14, Calculate the area of the shaded region in each of the figures given below:10 m0$200712m43 m40 m()3

Answer»

ANSWER:

SORRY, PLEASE SPECIFY the QUESTION.

Discussion

49.	1. Complete the following table:(4)RevolutionaryOrganizationAbhinvan BharatBarindra kumar GhoshChandrashekhar Azad
Answer» ANSWER: REVOLUTIONARY, ORGANIZATION,Abhinvan BHARAT,chsndrashekhar AZAD

49.

1. Complete the following table:(4)RevolutionaryOrganizationAbhinvan BharatBarindra kumar GhoshChandrashekhar Azad

Answer»

ANSWER:

REVOLUTIONARY, ORGANIZATION,Abhinvan BHARAT,chsndrashekhar AZAD

Discussion

50.	A box contains 50 packets of biscuits each weighing 120g, Howmany such boxes can be loaded in a van which cannot carry beyond900kg?
Answer» Answer: 19 Step-by-step EXPLANATION: Its EASY do it yourself

50.

A box contains 50 packets of biscuits each weighing 120g, Howmany such boxes can be loaded in a van which cannot carry beyond900kg?

Answer»

Answer:

19

Step-by-step EXPLANATION:

Its EASY do it yourself

Discussion

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Solution:-

ANSWER:-

GIVEN:-

TO FIND:-

FORMULA:-

SOLVING BY APPLYING THE FORMULA:-

17. Find the amount to be paid at the end of 3 years, if Principal is ₹2400 at 15p.a plz tel step by step explanation

A = P (1+R/100)^T

A = 3650.1

Hope it helps!!

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Solution:-

ANSWER:-

GIVEN:-

TO FIND:-

HOW TO SOLVE:-

SOLVING BY APPLYING THE FORMULA:-

A trader bought 20 quintals of rubber sheets at19850 rupees a quintal. He spent 3000 rupees totake the load to the shop. Since prices went down,he had to sell them at 18250 rupees a quintal. Howmuch money did he lose?​

Solution!!

More information:-

A partical is moving along a circular path of radius 16m and it completes one revolution in 30sec. If total time of motion is 75sec, the displacement of the partical is ___1) 16m2) 54m3) 32m4) 75m​

Given :-

To Find :-

Solution :-

Additional Information :-

Given that AB is a line segment and the anglea= 25°, work out the value of x.Given that AB is a line segment and the angle a= 25°, work out the value of x.

Section0.31 Solve any three of the following1) Data about the different modes of transported by students to1 studentMode of travellingPrivate carNumber of studentsPublic BusSchool BusCycleWalking​

An article is parched for Rs.520 and sold for Rs650 The pain percentage isa. 4520%4. 23% 4. 24​

An article is parched for Rs. 0 and sold for Rs 0. The pain percentage isa. 4520%4. 23% 4. 24​

Ashepherd have 200 sheep with him. Find the numberof Sheeps with him after 3 years if increase in number of sheep is 8% every year.​

A track is in the form of ring whose inner and outer circumferences are 88m and132m respectively find the width of the trackorA garden is 90m and 75m broad. A path 5m wide is to be built all around (outside)it along its border. Find the area of path.​

(1) What is the number of basmati rice bags he must sell to have neither profit nor loss, ifthe number of bags of non-basmati rice sold is 6,400.​

Metre of cloth. What isکراIdents are coming by private carof transport maximum used ?more students coming to school by walking as compared toyre of cloth and Sai boughtys, if the numbers 1 kg : 40​

The diagram shows a cuboid.The width of the cuboid is 25 cm.The end face of the cuboid is a square.The volume of the cuboid is 1.25 m'.a Work out the length of the cuboid.b Work out the surface area of the cuboid.​​

If the circumference of a circular park is 36 cm. Find its diameterIf the circumference of a circular park is 36 cm. Find its diameter​

3. The denominator of a rational number is2 more than its numerator. If thenumerator is increased 4 times and 8is added to the denominator, the new no.would be 4/3. Find the original number.​

RATIO AND PROPORTIONQ1) Solve the following: ﻿ 1)If (x+15): (x+7)=(x-1): (x+2), find the value of x​

14, Calculate the area of the shaded region in each of the figures given below:10 m0$200712m43 m40 m()3​

1. Complete the following table:(4)RevolutionaryOrganizationAbhinvan BharatBarindra kumar GhoshChandrashekhar Azad​

A box contains 50 packets of biscuits each weighing 120g, Howmany such boxes can be loaded in a van which cannot carry beyond900kg?​

1. Following are the number of goals scored by a football team in 25 matches.6,8,7,7,6,5,3,2,5,6,5,4,3,6,6,5,4,6,7,3,2,3,5,4,1elements of mathematics class 8

15. A sum of money is lent for 5 years at R% simple interest per annum. If the interestearned be one-fourth of the money lent, find the value of R.the simple interest earned on a certain sum in 5 years is 30% of the sum. Find the value of R

In how many years does the sum of 1200 became 1800 at the rate of simple intrest of 5% per anumtake a pic and send

Abx+) 850nd the value of the following368 x 12 + 18 x 368 I want how to do problem

The parallel sides of a trapezium measure 20 cm and 28 cm respectively and the distance between them is10 cm. Find the area of trapezium.

A man cycles at 12 km per hour. How much distance does he cover in 35 minutes?Option -30km20 km please explain step by step

Joseph deposited Rs 15000/- in a bank at the rate of 10% interest. Rafeekdeposited Rs 15000/- in another bank at the rate of 10% compound interest. a) After 29 years, how much amount would Joseph get back? b) After 2 years, how much amount would Rafeeq get back?

Mrcespl-threrfthmetthe1SW)Its )13.The side of a square field is 120 meters. The cost of preparing a grass lawn is 35 persquare meter. How much will it cost, if the entire field is converted into a lawn?

A man cycles at 12 km per hour. How much distance does he cover in 35 minutes?Option -30km/hour 20 km/hour please explain step by step

Draw thegraph of given polynomial and find thezeroes. Justify the answerp(x)= x²+5x-5.plz give answer

A perimiter of a circle is called its circumference. true or false(if you don't know the answer so don't answer pls)

A tank is in the form of a right circular cylinder. Its height is 48 m and the base area is 616 sq. m. Findthe lateral surface area and volume of the cylinders

5= 0.01443) Square of 0.013 = (0.013)2= 0.013 x 0.013= 0.000169* Which of the following numbers can be3) 0.00161) 2.54) 14.4written as a square?2) 0.255) 1.44Aanbe

3. In a circle with centre O, the measure of a minor arc is 110°. What is the measure ofthe major arc PYQ?

HAPPY HOLI IS ADVANCE TO ALL OF THEM WHO R VERY VERY EXITED FOR HOLI LIKE MEI AM SOO EXITED FOR HOLI,,,,,,,,,,,,,,

How many bricks of length 25 cm, breadth15 cm and height 10 cm are required tobuild a wall of length 6 m, height 2.5 m andbreadth 0.5 m?

1) 216 cm2) 108 cm2. The length of rectangular hall is 18 m and breadth is 12 m. How many squareof length 25 cm will fit in the hall ?1) 34002) 40004) 34563) 4456

Find the maximum length of the rod that can be kept in cuboidical box of side 30 cm, 24 cm and 18cm.

प्रश्न. सही जोड़ी बनाइए।axa(2) वर्ग(3) त्रिभुज14 समांतर चतुर्भुज150bxhपाई।1/2bxhaxb

Activity - 1Let's find out the pairs.You know the peculiarities of parallel lines. Identify the parallelpairs from the lines given below.PСD uNMKLХWrite the parallel lines in pairs.e.g.PQ, UVSAMAGRA SHIKSHA, KERALADEPARTMENT OF GENERAL EDUCATION

5. Sanju completes 12 rounds arounda square park every day. If oneside of the park is 120 m, find out inkilometres and metres the distance thatSanju covers daily.

A tree is broken at a height of 5 metre from the ground and its top touches the ground at adistance of 12 m from the base of the tree find the original height of the treeif the same

The compound interest forRs.50,000 at 8% per annum for 2years, compounded annually is8340831083508320

Info01) Which of the following is correct for 5 in 2a + 5 = b?1. O It is a fixed constant.2. O It is an unknown.3. O It is an arbitary constant. 4.t is a variable.

In a basket there are colorful balls from 1 to 10 what is the probability of getting even numberof composite number of numbers greater than 8whoever answers can be marked as brainliest

Dark colour clothes keep us warm as :- a) they reflect heat , b) they absorb more heat , c) they scatter heat ,d) they stick to our body

I. Choose the correct answer.1. The mode of 1,2,2, 3, 3, 4, 4, 4, is (A) 2 B) 3 C) 4 D) Noneof Ohservations)

A trader bought 20 quintals of rubber sheets at19850 rupees a quintal. He spent 3000 rupees totake the load to the shop. Since prices went down,he had to sell them at 18250 rupees a quintal. Howmuch money did he lose?

A partical is moving along a circular path of radius 16m and it completes one revolution in 30sec. If total time of motion is 75sec, the displacement of the partical is ___1) 16m2) 54m3) 32m4) 75m

Section0.31 Solve any three of the following1) Data about the different modes of transported by students to1 studentMode of travellingPrivate carNumber of studentsPublic BusSchool BusCycleWalking

An article is parched for Rs.520 and sold for Rs650 The pain percentage isa. 4520%4. 23% 4. 24

An article is parched for Rs. 0 and sold for Rs 0. The pain percentage isa. 4520%4. 23% 4. 24

Ashepherd have 200 sheep with him. Find the numberof Sheeps with him after 3 years if increase in number of sheep is 8% every year.

A track is in the form of ring whose inner and outer circumferences are 88m and132m respectively find the width of the trackorA garden is 90m and 75m broad. A path 5m wide is to be built all around (outside)it along its border. Find the area of path.

(1) What is the number of basmati rice bags he must sell to have neither profit nor loss, ifthe number of bags of non-basmati rice sold is 6,400.

Metre of cloth. What isکراIdents are coming by private carof transport maximum used ?more students coming to school by walking as compared toyre of cloth and Sai boughtys, if the numbers 1 kg : 40

The diagram shows a cuboid.The width of the cuboid is 25 cm.The end face of the cuboid is a square.The volume of the cuboid is 1.25 m'.a Work out the length of the cuboid.b Work out the surface area of the cuboid.

If the circumference of a circular park is 36 cm. Find its diameterIf the circumference of a circular park is 36 cm. Find its diameter

3. The denominator of a rational number is2 more than its numerator. If thenumerator is increased 4 times and 8is added to the denominator, the new no.would be 4/3. Find the original number.

RATIO AND PROPORTIONQ1) Solve the following: 1)If (x+15): (x+7)=(x-1): (x+2), find the value of x

14, Calculate the area of the shaded region in each of the figures given below:10 m0$200712m43 m40 m()3

1. Complete the following table:(4)RevolutionaryOrganizationAbhinvan BharatBarindra kumar GhoshChandrashekhar Azad

A box contains 50 packets of biscuits each weighing 120g, Howmany such boxes can be loaded in a van which cannot carry beyond900kg?