98971 + Interview Questions in Primary School in Math

1.	The angles of a triangle are in the rotio 1:2:3. Find the measure of each one of the angles.
Answer» ong>Answer: 30 , 60 , 90 Step-by-step EXPLANATION: PLEASE mark it BRAINLIESST

1.

The angles of a triangle are in the rotio 1:2:3. Find the measure of each one of the angles.

Answer»

ong>Answer:

30 , 60 , 90

Step-by-step EXPLANATION:

PLEASE mark it BRAINLIESST

Discussion

2.	Add: 7ab-2bc+3ca,4a(3b-2c) and 7c (4a-2b)
Answer» ONG>Answer: 19ab-16bc+23ca Step-by-step EXPLANATION: $7ab-2bc+3ca\\12ab- <klux>0</klux> - 8ca\\ \\$ 0- 14bc + 28ca = 19ab-16bc+23ca

2.

Add: 7ab-2bc+3ca,4a(3b-2c) and 7c (4a-2b)

Answer» ONG>Answer:

19ab-16bc+23ca

Step-by-step EXPLANATION:

$7ab-2bc+3ca\\12ab- <klux>0</klux> - 8ca\\ \\$

0- 14bc + 28ca

= 19ab-16bc+23ca

Discussion

3.	In the following figure, pll q and m is a transversal. The value of x is :
Answer» ONG>Answer: where is the FIGURE bro Step-by-step EXPLANATION: Mark me as brainlieat

3.

In the following figure, pll q and m is a transversal. The value of x is :

Answer» ONG>Answer:

where is the FIGURE bro

Step-by-step EXPLANATION:

Mark me as brainlieat

Discussion

4.	The population of a suburb is 16000. Find the rate of increase in the population if the population after two years is 17640.In ho
Answer» ONG>Step-by-step EXPLANATION: plz make me as BRAINLILIST

Discussion

5.	Please solve it I will mark you as brainlist
Answer» *Perimeter of the PARK = SUM of the lengths of FOUR sides of the park = 460 m* *Hence, distance COVERED by Meera is 460 m.* *hope* *its* *helpful* *PLS* *thanks* *and* *follow*

5.

Please solve it I will mark you as brainlist

Answer»

Perimeter of the PARK = SUM of the lengths of FOUR sides of the park = 460 m

Hence, distance COVERED by Meera is 460 m.

hope its helpful

PLS thanks and follow

Discussion

6.	If 5 x + 7 is equal to 42 the value of x is
Answer» ONG>Step-by-step explanation: 5x+7=42 5x=42-7 5x=35 X=7

6.

If 5 x + 7 is equal to 42 the value of x is

Answer» ONG>Step-by-step explanation:

5x+7=42

5x=42-7

5x=35

X=7

Discussion

7.	10+10+10+10+10+10+10+10+10+10+10+10+10+10+10+10+10=
Answer» ONG>Answer: = 170 THIS is the CORRECT answer of your QUESTION.

7.

10+10+10+10+10+10+10+10+10+10+10+10+10+10+10+10+10=

Answer» ONG>Answer:

= 170

THIS is the CORRECT answer of your QUESTION.

Discussion

8.	64.86 x 80% = 98.84 x 80% =2995 x 80% =31.7 x 80%27.8 x 80%88.73 - 80% =64.09 - 80% =43.2 - 80% =6451 - 80% =98.49 - 80% =
Answer» ONG>Answer: 51.888 79.072 2396 25.36 22.24 17.746 12.818 8.64 1290.2 19.864 Step-by-step EXPLANATION:

8.

64.86 x 80% = 98.84 x 80% =2995 x 80% =31.7 x 80%27.8 x 80%88.73 - 80% =64.09 - 80% =43.2 - 80% =6451 - 80% =98.49 - 80% =

Answer» ONG>Answer:

51.888
79.072
2396
25.36
22.24
17.746
12.818
8.64
1290.2
19.864

Step-by-step EXPLANATION:

Discussion

9.	Solve it guys. And good evening ❤❤❤❤❤❤❤ all of you. Love uhh all.
Answer» ong>Answer: the answer are (8+10) ×15 is GREATER {(-3) -4}×(-5) is greater

9.

Solve it guys. And good evening ❤❤❤❤❤❤❤ all of you. Love uhh all.

Answer»

ong>Answer:

the answer are

(8+10) ×15 is GREATER
{(-3) -4}×(-5) is greater

Discussion

10.	a shopkeeper buys 75 articles for ₹2250 and sell them at a profit of 20%.find the selling price of an article
Answer» UTION!! The concept of profit and LOSS has to be used here. Profit% = 20 CP of 75 ARTICLES = Rs 2250 Profit% = (Profit/CP) × 100 20 = (Profit/2250) × 100 20 = (Profit/225) × 10 20 ÷ 10 = Profit/225 2 = Profit/225 Profit = Rs 450 Profit = SP - CP Rs 450 = SP - Rs 2250 SP = Rs 2250 + Rs 450 SP of 75 articles = Rs 2700 SP of 1 article = Rs 2700 ÷ 75 SP of 1 article = Rs 36 More information:- If SP>CP, then it is profit. If CP>SP, then it is loss. Profit = SP - CP Loss = CP - SP Profit% = (Profit/CP) × 100 Loss% = (Loss/CP) × 100 CP → Cost Price SP → SELLING Price

10.

a shopkeeper buys 75 articles for ₹2250 and sell them at a profit of 20%.find the selling price of an article

Answer» UTION!!

The concept of profit and LOSS has to be used here.

Profit% = 20

CP of 75 ARTICLES = Rs 2250

Profit% = (Profit/CP) × 100

20 = (Profit/2250) × 100

20 = (Profit/225) × 10

20 ÷ 10 = Profit/225

2 = Profit/225

Profit = Rs 450

Profit = SP - CP

Rs 450 = SP - Rs 2250

SP = Rs 2250 + Rs 450

SP of 75 articles = Rs 2700

SP of 1 article = Rs 2700 ÷ 75

SP of 1 article = Rs 36

More information:-

If SP>CP, then it is profit.

If CP>SP, then it is loss.

Profit = SP - CP

Loss = CP - SP

Profit% = (Profit/CP) × 100

Loss% = (Loss/CP) × 100

CP → Cost Price

SP → SELLING Price

Discussion

11.	312 x 584 = 257 x 481 =496 x 597 =389 x 226 =256 x 932 =305 x 428 =406 x 398 =348 x 162 =786 x 543 =254 x 698 =
Answer» ONG>Answer: 1. 182208 2. 123617 3 . 296112 4. 87914 5. 238592

11.

312 x 584 = 257 x 481 =496 x 597 =389 x 226 =256 x 932 =305 x 428 =406 x 398 =348 x 162 =786 x 543 =254 x 698 =

Answer» ONG>Answer:

1. 182208

2. 123617

3 . 296112

4. 87914

5. 238592

Discussion

12.	1. A ABC in which AB 2. A PQR in which PQ=5.5 cm, QR = 6.5 cm, RP = 5 cm.3. A XYZ in which XZ = 8.4 cm, XY = 6.8 cm, YZ = 7.5 cm.4. A DEF in which DE = 8 cm, DF = 7.2 cm, EF = 6.3 cm.5. A LMN in which LN = 7 cm, NM=5.5 cm, LM= 6.4 cm
Answer» ABC is a triangle in which AB = Ac and D is a point on the side AC such that BC2 = AC × CD. Prove that BD = BC. ABC is a triangle in which AB = Ac and D is a point on the side AC such that BC2 = AC × CD 2. taking P as centre and measure 5cm , cut an arc . taking Q as centre and measure 6.5 cm , cut an arc name the point meeting as R . PQR is the required triangle . 3. Draw a LINE segment which is sufficiently long using ruler. (ii) LOCATE points X and Z on it such that XZ=9.5cm. (iii) With X as centre and RADIUS 7.8cm, draw an arc(see figure) (iv) With Z as centre and radius 4.5cm , draw another arc cutting the previous arc at C. (v) Join XY and YZ 4 Step 1: Draw DE=8cm Step 2: With D as centre and radius =7.2cm, draw an arc at F. Step 3: With E as centre, and radius =6.3cm, draw an arc at F. Step 4: Join DF and EF. Hence, ΔDEF is the required triangle. 5 . Construct ΔLMN in which LN=7 cm, NM=5.5 cm, LM=6.4 cm. 6 0.04 metre

12.

1. A ABC in which AB 2. A PQR in which PQ=5.5 cm, QR = 6.5 cm, RP = 5 cm.3. A XYZ in which XZ = 8.4 cm, XY = 6.8 cm, YZ = 7.5 cm.4. A DEF in which DE = 8 cm, DF = 7.2 cm, EF = 6.3 cm.5. A LMN in which LN = 7 cm, NM=5.5 cm, LM= 6.4 cm

Answer»

ABC is a triangle in which AB = Ac and D is a point on the side AC such that BC2 = AC × CD. Prove that BD = BC. ABC is a triangle in which AB = Ac and D is a point on the side AC such that BC2 = AC × CD

2. taking P as centre and measure 5cm , cut an arc . taking Q as centre and measure 6.5 cm , cut an arc name the point meeting as R . PQR is the required triangle .

3. Draw a LINE segment which is sufficiently long using ruler.

(ii) LOCATE points X and Z on it such that XZ=9.5cm.

(iii) With X as centre and RADIUS 7.8cm, draw an arc(see figure)

(iv) With Z as centre and radius 4.5cm , draw another arc cutting the previous arc at C.

(v) Join XY and YZ

4

Step 1: Draw DE=8cm

Step 2: With D as centre and radius =7.2cm, draw an arc at F.

Step 3: With E as centre, and radius =6.3cm, draw an arc at F.

Step 4: Join DF and EF.

Hence, ΔDEF is the required triangle.

5 . Construct ΔLMN in which LN=7 cm, NM=5.5 cm, LM=6.4 cm.

6 0.04 metre

Discussion

13.	A²+b²-2ab if a=5 b=3
Answer» ONG>ANSWER: a²+b²-2ab = 5²+3²-2×5×3 = 25+9-30 = 34-30 = 4 Answer: 4

13.

A²+b²-2ab if a=5 b=3

Answer» ONG>ANSWER:

a²+b²-2ab

= 5²+3²-2×5×3

= 25+9-30

= 34-30

= 4

Answer: 4

Discussion

14.	What is expansion of (m +2)^2
Answer» WER : ) m² + 2M + 2m + 4 m²+4m+4 $\sf{ \red{ɧơ℘ɛ \: ɬɧıʂ \: ɧɛƖ℘ʂ \: ყơų}}$

14.

What is expansion of (m +2)^2

Answer» WER : )

m² + 2M + 2m + 4

m²+4m+4

$\sf{ \red{ɧơ℘ɛ \: ɬɧıʂ \: ɧɛƖ℘ʂ \: ყơų}}$

Discussion

15.	708 x 59 = 43 x 708 =391 x 75 =631 x 7483 x 605 =396 x 832 =694 x 147 =451 x 517 =573 x 391 =146 x 963 =
Answer» ONG>Answer: 1.)41,772 2.)30,444 3.)29,395 4.)5,528

15.

708 x 59 = 43 x 708 =391 x 75 =631 x 7483 x 605 =396 x 832 =694 x 147 =451 x 517 =573 x 391 =146 x 963 =

Answer» ONG>Answer:

1.)41,772

2.)30,444

3.)29,395

4.)5,528

Discussion

16.	Simplyfy please give correct answer now
Answer» ANSWER is 36. $2 \times 3 {}^{2} \times 2 = 2 {}^{2} \times 3 {}^{2} = 36$

16.

Simplyfy please give correct answer now

Answer» ANSWER is 36.

$2 \times 3 {}^{2} \times 2 = 2 {}^{2} \times 3 {}^{2} = 36$

Discussion

17.	किसी वर्गाकार मैदान का परिमाप याद प्रत्येक भुजा 5.5 मीटर है इसका वर्गाकार मैदान का परिमाप याद कीजिए
Answer» ा गया है भुजा - 5.5 मीटर ज्ञात करना है वर्ग का परिमाप हल - सूत्र : वर्ग का परिमाप - 4 X भुजा =4 x 5.5 =22 मीटर अत: वर्ग का परिमाप है 22 मीटर ।,,,,,,धन्यवाद ,,,,,,।

17.

किसी वर्गाकार मैदान का परिमाप याद प्रत्येक भुजा 5.5 मीटर है इसका वर्गाकार मैदान का परिमाप याद कीजिए

Answer»

ा गया है

भुजा - 5.5 मीटर

ज्ञात करना है

वर्ग का परिमाप

हल -

सूत्र : वर्ग का परिमाप - 4 X भुजा

=4 x 5.5

=22 मीटर

अत: वर्ग का परिमाप है 22 मीटर

।,,,,,,धन्यवाद ,,,,,,।

Discussion

18.	Side to the other of1. Simplify (3x - lly)(1) 7x - 12 )(ii)2. The product of (23
Answer» SE WRITE FULL QUESTION

Discussion

19.	Let's write the value of pq by calculation if (2p-3q) = 10 and (8p³- 27q³) =100
Answer» u6567392837383836382

Discussion

20.	There is an equal chance of getting heads or tails when flipping a coin. 1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1=
Answer» ONG>Answer: 92 IS A *ANSWER* 1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1= 92 *HOPE* IT HELPS YOU

20.

There is an equal chance of getting heads or tails when flipping a coin. 1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1=

Answer» ONG>Answer:

92 IS A ANSWER

1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1= 92

HOPE IT HELPS YOU

Discussion

21.	Let's write the value of 27x³- 1/27x³ if x- 1/9x= 1
Answer» 18 PLEASE CHECK this ANSWER

Discussion

22.	195 men working 10 hours a day can finish a job in 20 days. how many men are employed to finish the job in 15 days. if they work 13 hours a day?
Answer» align="absmiddle" alt="\sf\small\underline\green{Given:-}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Csf%5Csmall%5Cunderline%5Cgreen%7BGiven%3A-%7D" title="\sf\small\underline\green{Given:-}"> $\sf{\implies Case\:_{(1)}\:<klux>WORK</klux>\: finished}$ $\sf{\implies No\:of\:men=195}$ $\sf{\implies No\:of\:days=<klux>20</klux>}$ $\sf{\implies work\:done\:by\:man\:_{(each\:days)}=10\: hours}$ $\sf{\implies Case\:_{(2)}\:work\: finished}$ $\sf{\implies No\:of\:men=m}$ $\sf{\implies No\:of\:days=15}$ $\sf{\implies work\:done\:by\:man\:_{(each\:days)}=13\: hours}$ $\sf\small\underline\green{To\: Find:-}$ $\sf{\implies No\:of\:men\:_{(as\:per\:case\:_{(2)}}=?}$ $\sf\small\underline\green{Solution:-}$ To calculate the number of men as per the QUESTION ,at first we have to set up equation with the help of given clue in the question. In question, given that 195 men working 10 hours a day can finish a job in 20 days. how many men are employed to finish the job in 15 days. if they work 13 hours a day? $\tt{\implies work\:finished\:_{(Case\:_{(1)})}=work\: finished\:_{(Case\:_{(2)})}}$ $\tt{\implies M\:_{(1)}\times\:D\:_{(1)}\times\:T\:_{(1)}=M\:_{(2)}\times\:D\:_{(2)}\times\:T\:_{(2)}}$ $\tt{\implies 195\times\:20\times\:10=M\:_{(2)}\times\:15\times\:13}$ $\tt{\implies 15\times\:20\times\:10=M\:_{(2)}\times\:15}$ $\tt{\implies 20\times\:10=M\:_{(2)}}$ $\tt{\implies M\:_{(2)}=200}$ $\sf\large{Hence,}$ $\sf{\implies No\:of\:men\:_{(as\:per\:case\:_{(2)}}=200}$

22.

195 men working 10 hours a day can finish a job in 20 days. how many men are employed to finish the job in 15 days. if they work 13 hours a day?

Answer»

align="absmiddle" alt="\sf\small\underline\green{Given:-}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Csf%5Csmall%5Cunderline%5Cgreen%7BGiven%3A-%7D" title="\sf\small\underline\green{Given:-}">

$\sf{\implies Case\:_{(1)}\:<klux>WORK</klux>\: finished}$

$\sf{\implies No\:of\:men=195}$

$\sf{\implies No\:of\:days=<klux>20</klux>}$

$\sf{\implies work\:done\:by\:man\:_{(each\:days)}=10\: hours}$

$\sf{\implies Case\:_{(2)}\:work\: finished}$

$\sf{\implies No\:of\:men=m}$

$\sf{\implies No\:of\:days=15}$

$\sf{\implies work\:done\:by\:man\:_{(each\:days)}=13\: hours}$

$\sf\small\underline\green{To\: Find:-}$

$\sf{\implies No\:of\:men\:_{(as\:per\:case\:_{(2)}}=?}$

$\sf\small\underline\green{Solution:-}$

To calculate the number of men as per the QUESTION ,at first we have to set up equation with the help of given clue in the question. In question, given that 195 men working 10 hours a day can finish a job in 20 days. how many men are employed to finish the job in 15 days. if they work 13 hours a day?

$\tt{\implies work\:finished\:_{(Case\:_{(1)})}=work\: finished\:_{(Case\:_{(2)})}}$

$\tt{\implies M\:_{(1)}\times\:D\:_{(1)}\times\:T\:_{(1)}=M\:_{(2)}\times\:D\:_{(2)}\times\:T\:_{(2)}}$

$\tt{\implies 195\times\:20\times\:10=M\:_{(2)}\times\:15\times\:13}$

$\tt{\implies 15\times\:20\times\:10=M\:_{(2)}\times\:15}$

$\tt{\implies 20\times\:10=M\:_{(2)}}$

$\tt{\implies M\:_{(2)}=200}$

$\sf\large{Hence,}$

$\sf{\implies No\:of\:men\:_{(as\:per\:case\:_{(2)}}=200}$

Discussion

23.	3 रूट में 8 की पावर माइनस वन अपऑन 2
Answer» ong>Answer: √2/24 Ans. Step-by-step EXPLANATION: HOPE it's HELPFUL :) :)

23.

3 रूट में 8 की पावर माइनस वन अपऑन 2

Answer»

ong>Answer:

√2/24 Ans.

Step-by-step EXPLANATION:

HOPE it's HELPFUL :) :)

Discussion

24.	My qustaion is whwt is mean by maths
Answer» ONG>ANSWER: The study of numbers, shapes, and SPACE using reason and usually a special system of symbols and rules for organizing them. For EXAMPLE: algebra, arithmetic ETC.

24.

My qustaion is whwt is mean by maths

Answer» ONG>ANSWER:

The study of numbers, shapes, and SPACE using reason and usually a special system of symbols and rules for organizing them. For EXAMPLE: algebra, arithmetic ETC.

Discussion

25.	Find the sum of 981 and 982
Answer» ONG>Answer: 981+982=1963 PLZ HIT LIKE

25.

Find the sum of 981 and 982

Answer» ONG>Answer:

981+982=1963

PLZ HIT LIKE

Discussion

26.	10. find 1/5 of 875. math
Answer» ONG>Answer: 175 Ans. Step-by-step explanation: 1/5 of 875 => 1/5 × 875 => 175 Ans. Hope it's HELPFUL :) :)

26.

10. find 1/5 of 875. math

Answer» ONG>Answer:

175 Ans.

Step-by-step explanation:

1/5 of 875

=> 1/5 × 875

=> 175 Ans.

Hope it's HELPFUL :) :)

Discussion

27.	Are 6cm, 2cm, 8cm be possible length of sides of a triangle .
Answer» ong>ANSWER: No Step-by-step EXPLANATION: because sum of 2 sides of TRAINGLE should EQUAL to third therefore 6+2=8 not6+2>8

27.

Are 6cm, 2cm, 8cm be possible length of sides of a triangle .

Answer»

ong>ANSWER:

No

Step-by-step EXPLANATION:

because sum of 2 sides of TRAINGLE should EQUAL to third

therefore 6+2=8 not6+2>8

Discussion

28.	Wo R PARO 1- 2CPCRAZESR10) व पाना+ 432 - sees हे सिद्ध करण्यासाठी पुढील ती पूर्व कापूर्णभा(त्रिकोणमितीय नित्यसमानता-इजही बाजू
Answer» सतदँँणँरछभछमतबघठमरम

Discussion

29.	The number that and with 2,3, 7 and 8aresquare
Answer» number having 2, 3, 7 or 8 at UNIT's place is never a perfect square. In other words, no square number ENDS in 2, 3, 7 or 8. Property 2: The number of zeros at the end of a perfect square is always even. hope it helps U:)

29.

The number that and with 2,3, 7 and 8aresquare

Answer»

number having 2, 3, 7 or 8 at UNIT's place is never a perfect square. In other words, no square number ENDS in 2, 3, 7 or 8. Property 2: The number of zeros at the end of a perfect square is always even.

hope it helps U:)

Discussion

30.	46. A room is 12 metres long, 8 metres wide and 4 metres high. What is the area of itsfour walls?(A) 80 sq. metres(B) 160 sq. metres(C) 284 sq. metres (D)144 sq. metres
Answer» ONG>Answer: (B) 160 SQ. METRES

30.

46. A room is 12 metres long, 8 metres wide and 4 metres high. What is the area of itsfour walls?(A) 80 sq. metres(B) 160 sq. metres(C) 284 sq. metres (D)144 sq. metres

Answer» ONG>Answer:

(B) 160 SQ. METRES

Discussion

31.	Find the leap year in the following years.2013, 2016, 2019, 2022
Answer» ONG>Answer: 2016 Step-by-step EXPLANATION: because only this is DIVISIBLE by 4....

31.

Find the leap year in the following years.2013, 2016, 2019, 2022

Answer» ONG>Answer:

2016

Step-by-step EXPLANATION:

because only this is DIVISIBLE by 4....

Discussion

32.	659 x 337 = 113 x 886 =296 x 704 =560 x 489 =312 x 946 =7,559 x 281,667 x 898,662 x 15 =2,694 x 643,852 x 47
Answer» ONG>Step-by-step explanation: 659×337=222083 113×886=100118 296×704=208384 560×489=273840 312×946=295152 7559×28=211652 1667×89=148363 8662×15=129930 2694×64=172416 3852×47=181044

32.

659 x 337 = 113 x 886 =296 x 704 =560 x 489 =312 x 946 =7,559 x 281,667 x 898,662 x 15 =2,694 x 643,852 x 47

Answer» ONG>Step-by-step explanation:

659×337=222083

113×886=100118

296×704=208384

560×489=273840

312×946=295152

7559×28=211652

1667×89=148363

8662×15=129930

2694×64=172416

3852×47=181044

Discussion

33.	I) a² + b2 - 2ab if a=5 b=3
Answer» ong>Answer: SIMPLIFY the expression and FIND its value when a = 5 and b =-3. 2(a + ab) + 3- ab 2(a? + ab) + 3-ab = 2a? + 2ab + 3- ab = 2a? + 3 + ab (2 - 1) = 2a? + 3 + ab (1) = 2a? + 3 + ab = 2a? + ab + 3 Putting a = 5, b = -3 = 2(5)? + (5) (-3) + 3 = 2 (25) - 15 + 3 = 50 - 12 = 38

33.

I) a² + b2 - 2ab if a=5 b=3

Answer»

ong>Answer:

SIMPLIFY the expression and FIND its value when a = 5 and b =-3. 2(a + ab) + 3- ab

2(a? + ab) + 3-ab

= 2a? + 2ab + 3- ab

= 2a? + 3 + ab (2 - 1)

= 2a? + 3 + ab (1)

= 2a? + 3 + ab

= 2a? + ab + 3

Putting a = 5, b = -3

= 2(5)? + (5) (-3) + 3

= 2 (25) - 15 + 3

= 50 - 12 = 38

Discussion

34.	If 37:22 then 42:? options : 1. 24 2. 12 3. 09 4. 20
Answer» ONG>ANSWER: gshsbshsjnshssnsjsnhs

Discussion

35.	Write three pairs of the prime number less than 20 whose sum is divisible by 5
Answer» ONG>Answer: 3+7=10 which is DIVISIBLE by 5 13+2=15 which is divisible by 5 17+3=20 which is divisible by 5

35.

Write three pairs of the prime number less than 20 whose sum is divisible by 5

Answer» ONG>Answer:

3+7=10 which is DIVISIBLE by 5

13+2=15 which is divisible by 5

17+3=20 which is divisible by 5

Discussion

36.	The interest on a sum of rupees 500 is equal to 500 years what is the rate of interest
Answer» what is your question I can't UNDERSTAND

36.

The interest on a sum of rupees 500 is equal to 500 years what is the rate of interest

Answer»

what is your question

I can't UNDERSTAND

Discussion

37.	If (-3)⁴× (-3)⁶ = (-3)? then ? =
Answer» ong>Answer: -3¹⁰ Step-by-step EXPLANATION: add both the powers of -3 as the base is same. hope it'll help you and you UNDERSTOOD.

37.

If (-3)⁴× (-3)⁶ = (-3)? then ? =

Answer»

ong>Answer:

-3¹⁰

Step-by-step EXPLANATION:

add both the powers of -3 as the base is same.

hope it'll help you and you UNDERSTOOD.

Discussion

38.	4. In a class of 40 students, 24 like black colour and 18 like white colour while 5 like neither. Find the number of students who like both black and white colours. Draw aVenn diagram to represent it.5. Meena gets a certain amount as pocket money. She spends one-fourth of it onstationery and one-third in the school canteen. If she saves 340, using Venn diagramfind the amount of pocket money she received.
Answer» ONG>ANSWER: A∩B=7 Step-by-step EXPLANATION: A∩B=24+18+5-40 A∩B=7

38.

4. In a class of 40 students, 24 like black colour and 18 like white colour while 5 like neither. Find the number of students who like both black and white colours. Draw aVenn diagram to represent it.5. Meena gets a certain amount as pocket money. She spends one-fourth of it onstationery and one-third in the school canteen. If she saves 340, using Venn diagramfind the amount of pocket money she received.

Answer» ONG>ANSWER:

A∩B=7

Step-by-step EXPLANATION:

A∩B=24+18+5-40

A∩B=7

Discussion

39.	Using suitable properties, evaluate the following (i) (-8) ×(-2)×3×(-5)
Answer» ONG>Answer: here is your answer PLEASE mark me as BRILLIANT STUDENT

39.

Using suitable properties, evaluate the following (i) (-8) ×(-2)×3×(-5)

Answer» ONG>Answer:

here is your answer PLEASE mark me as BRILLIANT STUDENT

Discussion

40.	Please solve this question with full process
Answer» ONG>ANSWER: $\frac{5}{ \sqrt[3]{9} - \sqrt[3]{6} + \sqrt[3]{4} } = \frac{5}{2 - \sqrt[3]{6} - \sqrt[3]{4} }$

40.

Please solve this question with full process

Answer» ONG>ANSWER:

$\frac{5}{ \sqrt[3]{9} - \sqrt[3]{6} + \sqrt[3]{4} } = \frac{5}{2 - \sqrt[3]{6} - \sqrt[3]{4} }$

Discussion

41.	Divide the fractions:() 3/8 by 5/9(ii) 7/12 by 3/4(iii) 1/2 by 2/5(iv) 3/4 by 2/3
Answer» ong>ANSWER:P> p(X) = x2-3x+2,q(x) = 3x+1.(i) find p(x)+q(x). (ii) what NUMBER is p(x)+ 2(x)

41.

Divide the fractions:() 3/8 by 5/9(ii) 7/12 by 3/4(iii) 1/2 by 2/5(iv) 3/4 by 2/3

Answer»

ong>ANSWER:P>

p(X) = x2-3x+2,q(x) = 3x+1.(i) find p(x)+q(x). (ii) what NUMBER is p(x)+ 2(x)

Discussion

42.	A company distributed half kg of Sweats toeach at its to employees on the occasion ofDi wali. If the sweets were purechased atthe rate ₹ 320 per kg, then what was theexpenditure made by the company?
Answer» ONG>ANSWER: TOTAL INVEST =9600 is the answer

Discussion

43.	What is the ratio of 5:60
Answer» ONG>Step-by-step explanation: 5:60 1:12 5/60 512 = 60 1/12 So, RATIO* of 5:60 = 1:12

Discussion

44.	If a=5 and b=3 findi) a? + b² + 2ab
Answer» ong>Step-by-step EXPLANATION: a^2 + b^2 + 2ab = (5)^2 + (3)^2 + 2(5)(3) = 25 + 9 + 30 = 64

44.

If a=5 and b=3 findi) a? + b² + 2ab

Answer»

ong>Step-by-step EXPLANATION:

a^2 + b^2 + 2ab

= (5)^2 + (3)^2 + 2*(5)*(3)

= 25 + 9 + 30

= 64

Discussion

45.	The measure of the two angles of a triangle are 67° and 69°. find the measure of the third angle.
Answer» ONG>ANSWER: *PLEASE* *MARK* ME AS BRAINLIEST

Discussion

46.	Please help!(Vieta's Formulas) Let , , and be solutions to the equation . Find . Please include an explanation as well :)
Answer» ong>Solution :- comparing 2x³ - 3x² + 4X - 1 = 0 with ax³ + bx² + cx + d = 0 we get, a = 2 b = (-3) c = 4 d = (-1) since roots are r, s and t , r + s + t = (-b/a) = -(-3/2) = 3/2 rs + st + rt = c/a = 4/2 = 2 rst = - d/a = -(-1)/2 = (1/2) . we know that, (a + b + c)² = a² + b² + c² + 2(ab + bc + CA) then, → (r + s + t)² = r² + s² + t² + 2(rs + st + rt) → r² + s² + t² = (r + s + t)² - 2(rs + st + rt) PUTTING all values we get, → r² + s² + t² = (3/2)² - 2(2) → r² + s² + t² = (9/4) - 4 → r² + s² + t² = (9 - 16)/4 → r² + s² + t² = (-7/4) (Ans.)

46.

Please help!(Vieta's Formulas) Let , , and be solutions to the equation . Find . Please include an explanation as well :)

Answer»

ong>Solution :-

comparing 2x³ - 3x² + 4X - 1 = 0 with ax³ + bx² + cx + d = 0 we get,

a = 2
b = (-3)
c = 4
d = (-1)

since roots are r, s and t ,

r + s + t = (-b/a) = -(-3/2) = 3/2
rs + st + rt = c/a = 4/2 = 2
rst = - d/a = -(-1)/2 = (1/2) .

we know that,

(a + b + c)² = a² + b² + c² + 2(ab + bc + CA)

then,

→ (r + s + t)² = r² + s² + t² + 2(rs + st + rt)

→ r² + s² + t² = (r + s + t)² - 2(rs + st + rt)

PUTTING all values we get,

→ r² + s² + t² = (3/2)² - 2(2)

→ r² + s² + t² = (9/4) - 4

→ r² + s² + t² = (9 - 16)/4

→ r² + s² + t² = (-7/4) (Ans.)

Discussion

47.	3. In a survey of 50 students of a school, it was found that 30 read newspaper A, 2014 newspaper B and 5 read both the newspapers. Using Venn diagram, finda. Number of students who read only newspaper A.b. Number of students who read only newspaper B.c. Number of students who read none of the newspapers.
Answer» ONG>Answer:P> We have S=120 i) The number of people who read exactly one NEWSPAPER ⇒P(H)+P(T)+P(I)−2((H∩T)+P(T∩I)+P(I∩H))+3P(H∩T∩I) =50+52+52−2(18+22+16)+3(6)=60 ii) The number of people who read exactly two newspapers ⇒((H∩T)+P(T∩I)+P(I∩H))−3P(H∩T∩I) =(18+22+16)−3(6)=38 iii) the number of people who read at least one of the newspapers ⇒P(H∪T∪I∪)=P(H)+P(T)+P(I)−((H∩T)+P(T∩I)+P(I∩H))+P(H∩T∩I) =50+52+52−(18+22+16)+(6)=104

47.

3. In a survey of 50 students of a school, it was found that 30 read newspaper A, 2014 newspaper B and 5 read both the newspapers. Using Venn diagram, finda. Number of students who read only newspaper A.b. Number of students who read only newspaper B.c. Number of students who read none of the newspapers.

Answer» ONG>Answer:P>

We have S=120

i) The number of people who read exactly one NEWSPAPER

⇒P(H)+P(T)+P(I)−2((H∩T)+P(T∩I)+P(I∩H))+3P(H∩T∩I)

=50+52+52−2(18+22+16)+3(6)=60

ii) The number of people who read exactly two newspapers

⇒((H∩T)+P(T∩I)+P(I∩H))−3P(H∩T∩I)

=(18+22+16)−3(6)=38

iii) the number of people who read at least one of the newspapers

⇒P(H∪T∪I∪)=P(H)+P(T)+P(I)−((H∩T)+P(T∩I)+P(I∩H))+P(H∩T∩I)

=50+52+52−(18+22+16)+(6)=104

Discussion

48.	Write the 0ppsite of each integer of +1
Answer» ong>Answer: Antonyms: SEQUESTERED, segregated, lily-white, divided, inorganic, nonintegrated, white, quarantined, isolated, SEPARATE, unintegrated. SYNONYMS: structured, INCORPORATE, unified, incorporated, merged. integrated, structured(adj)

48.

Write the 0ppsite of each integer of +1

Answer»

ong>Answer:

Antonyms: SEQUESTERED, segregated, lily-white, divided, inorganic, nonintegrated, white, quarantined, isolated, SEPARATE, unintegrated. SYNONYMS: structured, INCORPORATE, unified, incorporated, merged. integrated, structured(adj)

Discussion

49.	Let's write the value of pq by calculation if (2p - 3q ) = 10 and (8p³ - 27q³) = 100
Answer» ong>ANSWER: -5 Step-by-step explanation: (2P-3q)=10 (Given) A/Q (2p)³-(3q)³=100 (2p-3q)(4p²+9q²+6pq)=100 4p²+9q²+6pq=10 (2p-3q)²+18pq=10 100+18pq=10 18pq=-90 pq= -5

49.

Let's write the value of pq by calculation if (2p - 3q ) = 10 and (8p³ - 27q³) = 100

Answer»

ong>ANSWER:

-5

Step-by-step explanation:

(2P-3q)=10 (Given)

A/Q

(2p)³-(3q)³=100

(2p-3q)(4p²+9q²+6pq)=100

4p²+9q²+6pq=10

(2p-3q)²+18pq=10

100+18pq=10

18pq=-90

pq= -5

Discussion

50.	2 X 3X 7X a Xa X a X b XbX c are the factors of whichalgebraic term?
Answer» ONG>ANSWER: hope it is HELPFUL to you ok

Discussion

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