This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Dark colour clothes keep us warm as :- a) they reflect heat , b) they absorb more heat , c) they scatter heat , d) they stick to our body |
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Answer» ONG>Answer: Step-by-step explanation: |
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| 2. |
11. Answer in one word6. Two angles forming a linear pairare |
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Answer» the ANSWER is SUPPLEMENTARY angles hope it HELPS.. |
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| 3. |
3. Answer the the following questions a) Calculate the value of a in Fig. 5. |
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Answer» ONG>ANSWER: sorry the pic is blurry can't SEE it :( Step-by-step EXPLANATION: send a proper pic pls |
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| 4. |
Which of the following angle can be measure of triangle given reson 105 |
Answer» ONG>Answer:
Step-by-step explanation: The angle MUST be obtuse angle |
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| 5. |
40percent of 1km is? |
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Answer» ong>Step-by-step explanation: |
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| 6. |
Find the missing term 2:21::15.... |
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Answer» ONG>Answer: 34 Step-by-step EXPLANATION: |
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| 7. |
I. Choose the correct answer. 1. The mode of 1,2,2, 3, 3, 4, 4, 4, is (A) 2 B) 3 C) 4 D) Noneof Ohservations) |
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Answer» Solution:- ━━━━━━━━━━━━━━━━━━━━━━━━━━
ANSWER:-⇨ Mode of the given data is 4. Thus, option C that is 4 is correct. GIVEN:-★ Data = 1, 2, 2, 3, 3, 4, 4, 4 TO FIND:-➝ Mode of given data = ? HOW TO SOLVE:-
SOLVING BY APPLYING THE FORMULA:-⇒ Data = 1, 2, 2, 3, 3, 4, 4, 4 ⇒ Arranging the data = 1, 2, 2, 3, 3, 4, 4, 4 ⇒ No. of times a number is repeated = ⬇ 1. 1 is repeated 1 time. 2. 2 is repeated 2 times. 3. 3 is repeated 2 times. 4. 4 is repeated 3 times ⇒ Maximum no. of times a number is repeated = 3 ⇒ Most frequent no. = 4 [As it is repeated 3 times.] Thus, we got the answer. So, the mode of the given data is 4. So, option C (4) is correct. ━━━━━━━━━━━━━━━━━━━━━━━━━━ |
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| 8. |
Simplify this problem please... |
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Answer» ONG>Answer: 512 / 125 Step-by-step explanation: (5/8)^-7 = (8/5)^7 (8/5)^7 × (8/5)^-4 = (8/5)^ 7-4 = (8/5)^3 = 8^3/5^3 = 512/125 |
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| 9. |
What sum will amount to ₹1300 in 5/2 years at 12% per annum at simple interest ? |
| Answer» ONG>Step-by-step EXPLANATION: | |
| 10. |
6. Convert the following temperatures into the other scale.(a) 80° C(b) 109° F |
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Answer» > SOLUTION, 80°C=176°F 109°C=42.778°C
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| 11. |
How many factors are there in the term 3xsquarey |
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Answer» ONG>Answer: 1 FACTOR is there only CARPEDIAM |
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| 12. |
Which of the following division gives the quotient t-1 |
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Answer» ONG>ANSWER: t-1 Step-by-step EXPLANATION: . . . .... ... . . . . .... |
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| 13. |
Dmas rule question 1 upon 3 into 5 upon 4 divide by 3 upon2 to + 1 upon 3 |
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Answer» ONG>Answer: hope it help |
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| 14. |
A trader bought 20 quintals of rubber sheets at 19850 rupees a quintal. He spent 3000 rupees totake the load to the shop. Since prices went down,he had to sell them at 18250 rupees a quintal. Howmuch money did he lose? |
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Answer» ution!! The concept of profit and LOSS has to be used here. Cost price (CP) of 1 QUINTAL = Rs 19,850 CP of 20 quintals = Rs 19,850 × 20 CP of 20 quintals = Rs 3,97,000 The trader also spent Rs 3000 for shipping purpose. Total CP of 20 quintals = Rs 3,97,000 + Rs 3,000 Total CP of 20 quintals = Rs 4,00,000 Selling price (SP) of 1 quintal = Rs 18,250 SP of 20 quintals = Rs 18250 × 20 SP of 20 quintals = Rs 3,65,000 Total CP > Total SP Loss = CP - SP Loss = Rs 4,00,000 - Rs 3,65,000 Loss = Rs 35,000 Hence, the trader LOST Rs 35,000. More INFORMATION:-If SP>CP, then it is profit. If CP>SP, then it is loss. Profit = SP - CP Loss = CP - SP Profit% = (Profit/CP) × 100 Loss% = (Loss/CP) × 100 CP → Cost Price SP → Selling Price 1 quintal = 100 kg |
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| 15. |
Write any decimal number and convert into fraction. |
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Answer» ONG>ANSWER: 0.15 = 15/100 is you answer |
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| 16. |
Division pl full solution of these |
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Answer» ong>Answer: (1) 169 (2) 12 (3) 2400 Step-by-step explanation: hope this is HELPFUL |
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| 17. |
A partical is moving along a circular path of radius 16m and it completes one revolution in 30sec. If total time of motion is 75sec, the displacement of the partical is ___ 1) 16m2) 54m3) 32m4) 75m |
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Answer» Given :-
To FIND :-
Solution :-
So, 75 seconds can be break down as
Thus,
As we KNOW that,
Thus,
Additional Information :-
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| 18. |
4. Which of the following i a positive 1stinal nanherd. |
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Answer» ONG>ANSWER: This QUESTION is dealing with RATIONALISATION of a fraction. Rationalisation is performed to eliminate irrational expression in the denominator. For this particular case we can do this by applying the following rule: (a−b)(a+b)=a2−b2.
Multiple both numerator and denominator by √ n+1 + √ n : √ n+1 + √ n ( √ n+1 − √ n )( √ n+1 + √ n )
= √ n+1 + √ n ( √ n+1 )2−( √ n )2)
= √ n+1 + √ n n+1−n
= √ n+1 + √ n . Step-by-step EXPLANATION: |
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| 19. |
A decrease of 20% in rupees 1000 will give :- a) rupees 800 , b) rupees 900 , c) rupees 1000 , d) rupees 200 |
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Answer» ong>Answer: Step-by-step EXPLANATION: pls makes me brainliest |
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| 20. |
Given that AB is a line segment and the angle a = 25°, work out the value of x .Given that AB is a line segment and the angle a = 25°, work out the value of x . |
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Answer» ER:ANSWER to your question ✍️ GIVEN that AB is a LINE segment and the angle a = 25°, work out the VALUE of x . Step-by-step explanation: |
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| 21. |
1) Construct a LMN right-angled at M, giventhat LN = 8.2cm and MN = 6.5cm |
| Answer» ONG>Step-by-step EXPLANATION: | |
| 22. |
Who is known as iron Man of India ?:(..take my points !!.. |
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Answer» ong>Answer: Sardar PATEL Step-by-step explanation: |
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| 23. |
Section 0.31 Solve any three of the following1) Data about the different modes of transported by students to1 studentMode of travellingPrivate carNumber of studentsPublic BusSchool BusCycleWalking |
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Answer» ONG>Answer: Step-by-step explanation: walking |
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| 24. |
An article is parched for Rs.520 and sold for Rs650 The pain percentage is a. 4520%4. 23% 4. 24 |
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Answer» ong>ANSWER: |
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| 25. |
biswa planned to deposit Rs. 20,000 each on 1st January and 1st July of that same year. if the bank offers 6% compound interest calculated on half -yearly basis. what amount he would have earned through interest by the end of year? |
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Answer» ong>Answer Biswa planed to deposited rs. 20000 on 1ST JANUARY and 2nd july of that same YEAR . Then total is 40000 Bank offers 6% 400 * 6 = 2400 40000 + 2400 = 42400 get on half year . by the end of year biswa get = 42400 + 42400 = 84800 |
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| 26. |
an equilateral triangle is described on the diagonal of a square what is the ratio of the area of the triangle to that of the square |
| Answer» ONG>Answer: | |
| 28. |
What is the smallest multiple of 45 90 and 180 |
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Answer» ong>Answer: What are the Multiples of 45? To get multiples of a number, we need to multiply natural numbers with integers. For example, 45 × 2 = 90, 90 is a multiple of 45 and ALSO a multiple of 5. Now let us consider the first 5 multiples of 45, 45 × 1 = 45 45 × 2 = 90 45 × 3 = 135 45 × 4 = 180 45 × 5 = 225 According to this, the first five multiples of 45 you just learned are 45, 90, 135, 180, 225. 5 Multiples of 45 List of First 20 Multiples of 45 The first 20 multiples of 45 will be the product of natural numbers from 1-20 with 45. In the above section, you have learned about the first 5 multiples of 45. In this section, you will be finding the next 15 multiples of 45 First 20 Multiples of 45 45 × 1 = 45 45 × 11 = 495 45 × 2 = 90 45 × 12 = 540 45 × 3 = 135 45 × 13 = 585 45 × 4 = 180 45 × 14 = 630 45 × 5 = 225 45 × 15 = 675 45 × 6 = 270 45 × 16 = 720 45 × 7 = 315 45 × 17 = 765 45 × 8 = 360 45 × 18 = 810 45 × 9 = 405 45 × 19 = 855 45 × 10 = 450 45 × 20 = 900 Hurray! In the end, you have a total of 20 multiples of 45 are 45, 90, 135, 180, 225, 270, 315, 360, 405, 450, 495, 540, 585, 630, 675, 720, 765, 810, 855, 900. To understand the concept of finding multiples, let us take a few more examples. Multiples of 30 - The first five multiples of 30 are 30, 60, 90, 120, 150 Multiples of 20 - The first five multiples of 20 are 20, 40, 60, 80 and 100 Multiples of 36 - The first five multiples of 36 are 36, 72, 108, 144, 180 Multiples of 13 - The first five multiples of 13 are 13, 26, 39, 52, 65 Multiples of 7 - The first five multiples of 7 are 7, 14, 21, 28, 35 |
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| 29. |
An article is parched for Rs. 0 and sold for Rs 0. The pain percentage is a. 4520%4. 23% 4. 24 |
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Answer» ONG>Step-by-step explanation: 45% |
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| 30. |
Ashepherd have 200 sheep with him. Find the number of Sheeps with him after 3 years if increase in number of sheep is 8% every year. |
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Answer» ONG>Step-by-step EXPLANATION: It is similar to the PROBLEM of simple interest SI= 100 PRT
= 100 200×8×3
= 48 sheeps. Total sheeps = 200+48 = 248 sheeps. |
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| 31. |
20 Pencils can be packed in one Packet.How many Packets will require toPack 400 Pencils |
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Answer» ONG>400÷20=20 Answer is 20 |
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| 32. |
Convert 1250 day into years and month . please explain how to solve it . no spam plz |
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Answer» ong>ANSWER: a year has 365 day so we will divide it by 1250 days whish is EQUAL to 3 years 5 months and 5 days |
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| 33. |
A track is in the form of ring whose inner and outer circumferences are 88m and 132m respectively find the width of the trackorA garden is 90m and 75m broad. A path 5m wide is to be built all around (outside)it along its border. Find the area of path. |
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Answer» Q2) A garden is 90 m long and 75 m BROAD. A PATH 5 m wide is to be BUILT outside and around it. Find the area of the path. Also find the area of the garden in a hectare. Length= 90m Breadth= 75m Area of the garden= =90m+75m=6750m^2=90m+75m=6750m
Length of the garden including path =90m+5m+5m=100m=90m+5m+5m=100m Breadth of the garden including path =75m+5m+5m=85m=75m+5m+5m=85m Area of the garden including path =l\times b=l×b =100m
Area of the path= 8500m^2-6750m^2=1750m^28500m
Hence, the required area of path= 1750m^21750m and area of the garden= =6750m^2=0.675=6750m =0.675 |
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| 35. |
Is 87 percent good in class VI |
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Answer» ong>Answer: it is CONSIDERED as A2 grade so it is good Step-by-step EXPLANATION: PLEASE make me as BRAINLIEST |
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| 36. |
Simplify (-4/3)3 ×(-1/8)2 |
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Answer» ong>ANSWER: your answer is 1 Step-by-step EXPLANATION: hope it will HELP you |
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| 37. |
(1) What is the number of basmati rice bags he must sell to have neither profit nor loss, if the number of bags of non-basmati rice sold is 6,400. |
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Answer» ong>Answer: If a merchant NEITHER earns profit nor loss, then we have to EQUATE both profit and loss he earns. It means if a merchant SELLS 3,200 number of bags of BASMATI rice and 6,400 number of bags of non-basmati rice, he neither earns profit nor loss. So, the correct answer is option B. |
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| 38. |
right angle triangle has the largest side as that in centimetres and one of the sides containing the right angle as 12 CM its area in centimetre square is |
| Answer» ONG>ANSWER: | |
| 39. |
What is consecutive number |
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Answer» ong>ANSWER: NUMBERS that follow each other continuously in the order from smallest to largest are called CONSECUTIVE numbers. For example: 1, 2, 3, 4, 5, 6, and so on are consecutive numbers. |
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| 40. |
Metre of cloth. What is کراIdents are coming by private carof transport maximum used ?more students coming to school by walking as compared toyre of cloth and Sai boughtys, if the numbers 1 kg : 40 |
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Answer» ONG>ANSWER: sorry I DONT know the answer ONLY LOVE TO PLAY FREE FIRE |
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| 41. |
80+[20×{15-(8÷4)}]____________________________please answer the question |
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Answer» ONG>Answer: 80+(20×{15-2}) 80+(20×13) 80+260 340 |
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| 43. |
Prepare a poster on A WORLD WITHOUT NUMBERS. |
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Answer» ONG>Answer: A World Without Numbers Numbers is a world's most important thing. We can't emazing the study about maths without numbers.
draw a SKETCH of any number. 2 ,4 ,6
Numbers make study more easier. |
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| 44. |
Biswa decided to save money for a trip. He was checking some investment options for saving, but his friend Kalia suggested to check if he is interested in compound interest. Biswa found a bank that offers 6% compound interest calculated on a half-yearly basis. To know in detail, Biswa planned to deposit Rs. 20000 each on 1st of January and 1st of July of that same year. But Biswa is not that great at Math! Can you help him know, what amount he would have gained through interest by the end of the year? |
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Answer» ong>Step-by-step explanation: Q).Write a letter to the younger brother advising him about his FUTURE career. Ans- 5, Rosewood, Four Bungalows, Andheri (W) Mumbai-400053 15th March 2013 Dear Ramesh, I am very happy for you. You have done EXTREMELY well in your board examination. Your hard work has been rewarded. Today you are standing at the THRESHOLD of your career. You have to take the right decision. Do not take up any stream blindly simply because of your friends or family pressure. Choose the stream of your own interest. Since you are GOOD in mathematics, I would advise you to take up science stream. This is my personal opinion. The final decision will be yours. Do inform me about your decision. With love and AFFECTION, Your brother XYZ |
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| 46. |
Fill in the messages multiple 16 24 32 |
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Answer» ong>ANSWER: multiple of 16 is 2*2*2*2 multiple of 24 is 2*2*2*3 multiple of 32 is 2*2*2*2*2 |
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| 47. |
Biswa decided to save money for a trip. He was checking some investment options for saving, but his friend Kalia suggested to check if he is interested in compound interest. Biswa found a bank that offers 6% compound interest calculated on a half-yearly basis. To know in detail, Biswa planned to deposit Rs. 20000 each on 1st of January and 1st of July of that same year. But Biswa is not that great at Math! Can you help him know, what amount he would have gained through interest by the end of the year? Your Answera) 1818b) 980c) 878d) 1586 |
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Answer» ONG>Answer: 20000×9.09/100=1818 ANS |
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| 48. |
Prepare a poster on A WORLD WITHOUT NUMBERS.plz send me fast its urjent |
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Answer» ong>Step-by-step EXPLANATION: Hope it helps you good luck |
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| 49. |
The diagram shows a cuboid. The width of the cuboid is 25 cm.The end face of the cuboid is a square.The volume of the cuboid is 1.25 m'.a Work out the length of the cuboid.b Work out the surface area of the cuboid. |
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Answer» Length (1) = 25 cm, BREADTH (b) = 20 cm, Height (h) = 5 cm ∵ The box is like a cuboid and TOTAL surface AREA of a cuboid = 2(lb + bh + hl) Area of a box = 2([25 × 20) + (20 × 5) + (5 × 25)] cm2 = 2[500 + 100 + 125] cm2 = 2[725] cm2 = 1450 cm2 Total surface area of 250 boxes = 250 × 1450 cm2 = 362500 cm2 For smaller box: l = 15 cm, b = 12 cm, h = 5 cm Total surface area of a box = 2[lb + bh + hl] = 2[(15 × 12) + (12 × 5) + (5 × 15)] cm2 = 2[180 + 60 + 75] cm2 = 2[315] cm2 = 630 cm2 ⇒ Total surface area of 250 boxes = 250 × 630 cm2 = 157500 cm2 Now, total surface area of both kinds of boxes = 362500 cm2 + 157500 cm2 = 5,20,000 cm2 Area for overlaps = 5% of [ total surface area] ∴ Total area of the cardboard required = [Total area of 250 boxes] + [5% of total surface area] = 520000 cm2 + 26000 cm2 = 546000 cm2 Cost of cardboard: ∵ Cost of 1000 cm2 = Rs. 4 |
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