This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A massless inextensible string in the form of a loopis placed on a horizontal film of soap solution ofsurface tension T. If film is pierced inside the loopand it convert into a circular loop of diameter d, thenthe tension produced in string is |
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| 2. |
84. A wire of length 0-26 m is bent to form a circular loop. If 2 A of current isflowing through this loop, calculate the magnetic field due to this loop at apoint P, which is at a distance of 0-15 m from its centre on its axis. |
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Answer» We are given a circular current carrying conducting loop. Need to find the magnetic field B (flux density) at a distance d from the center of the loop along the axis of the loop. Using Biot-Savart's law for magnetic field we can derive the formula. Current through the loop = i B = 54 * 10⁻⁶ T d = 4 cm = 0.04 m radius = a = 3 cm = 0.03 m B =μ i a² / [2 (d² + a²)³/² ] 54 * 10⁻⁶ = 4π * 10⁻⁷ * i * 0.03² / [2 * 0.05³] T => i = 1.193 Amp Magnetic field at the center of the loop is given by B = μ i / (2 a) = 4 π * 10⁻⁷ * 1.193 /(2 * 0.03) T = 2.50 * 10⁻⁵ T Like my answer if you find it useful! |
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| 3. |
Q.39.A wire of resistance R bent in form of closed circle, what is the resistance across diameter of thecircle. |
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Answer» Given, resistance of wire is R when, it is bend in a form of circle then the resistance across its diameter is --- 1/R' = 1/R/2 + 1/R/2 => 1/R' = 2/R + 2/R => 1/R' = 4/R => R' = R/4 hence, the resistance across the diameter of circle is R/4. |
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| 4. |
Q.27. A wire of resistance R is bent in form of a closed circle, what is the resistance across adiameter of the circle?28 Acharge of oir maud |
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Answer» As we can see the points A and B divides the circle in two equal arcs hence if we flow a current from point A to B it will pass from AOB and ACB where O and B are points on two arcs therefore the connection will look like this i.e parallel that is parallel connection hence effective or net resistance between any two point will be 1/Rn = 1/r0 + 1/r1 1/R/2 + 1/R/2 = 2/R+ 2/R = 1/Rn 4/R = 1/Rn =R/4 |
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| 5. |
Write the energy convesion thstiake place is ahydpoer pa |
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Answer» The power station where electricity is produced by using the energy of flowing water to drive generators is called hydro power plant or hydroelectric power station.The energy conservation that take place in hydro power plant are as follows:1.The water is collected in a large reservoir or manmade Lake behind the dam. In this process the kinetic energy of flowing water gets transformed into potential energy of water stored behind the dam.2. The water falls from a high level of the dam it flows at a very high speed. The potential energy of water gets converted into kinetic energy.3. The kinetic energy of flowing water rotates the Blades of the turbine. Here the kinetic energy of flowing water is converted into mechanical energy of the turbine.4. The moving armature of the generator in the magnetic field generate electricity. Here the mechanical energy of the turbine is converted into electrical energy in the generator. |
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| 6. |
An incompressible liquid of density p is contained in a vessel of uniform cross-sectional area A. Ifthe atmosphercpressure is p, then the force acting on a horizontal plane of area a situated at a depth d in liquid is given byP+pgd(D) a(pgd+ p)(A) Ap + apgdA a |
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| 7. |
State and explain law of parallelogram of vectors. |
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| 8. |
State and explain law of conservation of mass. |
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Answer» The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. |
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| 9. |
)Define:-a) linear charge densityb) volume charge density |
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Answer» Charge densityis a measure of electricchargeper unit volume of space, in one, two or three dimensions. More specifically: thelinear, surface, or volumecharge densityis the amount of electricchargeper unit length, surface area, or volume, respectively. The respective SI units are C. |
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| 10. |
Unit of surface charge density is- |
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Answer» In electromagnetism, charge density is the amount of electric charge per unit length, surface area, or volume. Volume charge density (symbolized by the Greek letter ρ) is the quantity of charge per unit volume, measured in the SI system incoulombspercubicmeter (C |
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| 11. |
(a) Define¡g, and G'. Also establish a relation between the two.(b) Write the units of 'g' and 'G(c) Which force accelerates a body in free fall?Q23 |
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Answer» c. gravitational force will act on free fall body. |
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| 12. |
. A 10 g bullet travelling at 200 m/s strikes and remains embeddedina2kgtargetwhichisoriginallyatibut free to move. At what spèed does the target move off |
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| 13. |
A beaker containing a liquid of density p moveswith an acceleration 'a'. The pressure due toliquid at a depth h below free surface of the liquids(1) hpgthe(2) hp (g -a)(4) 2hpg1 tag +(3) hp (g + a) |
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Answer» As the beaker is moving up with acceleration, so we have to consider pseudo force on the pressure element. Or simply in P= hdg , g will change to its apparent value g'=(g+a) So pressure at depth h will be, P= h d (g+a) |
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| 14. |
11. (a) The diameter of neck and bottom of a bottleare 2 cm and 10 cm respectively. The bottleis completely filled with oil. If the cork in theneck is pressed in with a force of 1-2 kgf, whatforce is exerted on the bottom of the bottle ? |
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| 15. |
a) 2b) 2c) 2-1EAM-92]d) 2-1 |
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| 16. |
Exploring Forces |
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Answer» Exploring Forces- Gravity" is a hands on activity in which visitors discover that it's easy to pour water out of a regular-sized cup, but not out of a miniature cup. They learn that size can affect the way materials like water behave. |
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| 17. |
5. Gravitational force between two masses at a distanced apart is 6N. If these masses are taken to moon andkeptat same separation, then the force between themwill be :-(1)1N (1) N (3) 36 N (4) 6 N6 |
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Answer» it will be the same 6Nit is because the G value is constant throughout the universe and the masses do not change from place to place |
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| 18. |
POTENTIAL DUE TO AN ELECTRIC DIPOLE |
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| 19. |
1. The rockets work on the principle of conservation of:(a) mass(b) energy(c) momentum(d) velocity |
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| 20. |
25. Why are space rockets usually launched from west to east in the equatorial plane? |
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Answer» It takes a certain velocity to put a satellite in orbit. By launching eastward about 5% of that velocity is provided by the rotating Earth, free of charge. Earth rotates eastwards, and that’s why the sun ‘rises’ in the east. Of course every point on the surface of the planet rotates once a day, but the circle with the largest circumference is the equator, so there the rotating Earth takes you farthest in 24hrs, so that’s where your ‘free velocity package’ is the biggest. And getting out of that plane is costing fuel too, so any given rocket puts the most mass into orbit when launched from the equator, in the equatorial plane, and eastward. |
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| 21. |
The clectrie potential in equatorial positigon of an electric dipole is- |
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Answer» Consider an electric dipole consisting of 2 point charges−q−qand+q+qseparated by a distance2l2l. Let p be a point on a perpendicular bisector of a dipole at distance r from center O.VQq+=14π∈0qBQVQq+=14π∈0qBQVQq−=14π∈0−qAQVQq−=14π∈0−qAQ$V_Q= V_{P_{q+}}+V_{p_{q-}}V_Q= \large\frac{q}{4 \pi \in_0} \bigg[ \large\frac{1}{BQ}-\frac{1}{AQ} \bigg]V_Q=0BQ=AQ$The net electrostatic potential at a point in the electric field due to an electric dipole at any point on the equatorial line is zero. |
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| 22. |
Eocample 2.2 A man wishes to estimatethe distance of a nearby tower from himHe stands at a point A in front of the towerC and spots a very distant objeet O in linewith AC. He then walks perpendicular toAC up to B, a distance of 100 m, andlooksat O and C again. Since O is very distant.the direction BO is practically the same asAO: but he finds the line of sight of Cshiftedfrom the original line of sight by an angle-40 (0 iS known as 'parallax) estimatethe distance of the tower C from hisoriginalposition A. |
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| 23. |
Example 2.2 A man wishes to estimatethe distance of a nearby tower from hinmHe stands at a point A in front of the towerC and spots a very distant objeet O in linewith AC. He then walks perpendicular toAC up to B, a distance of 100 m, and looksat O and C again. Since O is very distantthe direction BO is practically the same asAO: but he finds the line of sight of C shiftedrom the original line of sight by an angle- 40° (0 is known as 'parallax) estimatethe distance of the tower C from his originalposition A |
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| 24. |
the distance of a nearby tower from himHe stands at a point A in front of the towerC and spots a very distant objeet O in linewith AC. He then walks perpendicular toAC up to B, a distance of 100 m, and looksat O and C again. Since O is very distantthe direction BO is practically the same asAO: but he finds the line of sight of C shiftedfrom the original line of sight by an angle θ40 (0 is known as 'parallax') estimatethe distance of the tower C from his originalposition A |
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| 25. |
Eocample 2.2 A man wishes to estimatethe distance of a nearby tower from himHe stands at a point A in front of the towerC and spots a very distant objeet O in linewith AC. He then walks perpendicular toAC up to B, a distance of 100 m, andlooksat O and C again. Since O is very distant.the direction BO is practically the same asAO: but he finds the line of sight of Cshiftedfrom the original line of sight by an angle-40 (0 is Known as parallax) estimatethe distance of the tower C from hisoriginalposition A |
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| 26. |
\int _ { R } ^ { \infty } \frac { G M m } { x ^ { 2 } } d x |
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| 27. |
Three charges +q, -q, and + 2q are placed at the vertices of a right angledtriangle (isosceles triangle) as shown. The net electrostatic energy of theconfiguration is:4.Kq+a(C Kaiv1)(D) of these |
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| 28. |
c)What is over loading?OD |
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Answer» A large amount of current is withdrawn from the circuit when a large number of electrical appliances of high power-rating are switched on at the same time or connected in a single multi-plug. This situation is called overloading. |
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| 29. |
8·The vector P=ai + aj + 3k and Q = ai-2-kareperpendicular to each other. The positive value ofa is:EAMCET 1998, AIIMS 2002](2) 2(4) zero(3) 1 |
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Answer» If two vectors are perpendicular , their dot product will be Zero. It's a condition P= ai + aj+3k Q=ai -2j-k P.Q= (ai+aj+3k).(ai-2j-k)=0 mulitply their equal components a^2 -2a -3 =0 Factorisation of a^2-2a -3 is (a+1)(a-3)So, a+1=0. a-3=0 a=-1. a=3In positive value ,Here positive value is 3 So the answer is 3 |
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| 30. |
what is the meaning of quantisation |
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Answer» Considering for example quatisation of chargeQuantization of chargemeans that when we say something has a givencharge, we mean that that is how many times thechargeof a single electron it has. Because allchargesare associated with a whole electron, this is possible. So electrons have a a negativecharge, negativecharge. |
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| 31. |
6. Show that the vectors 2i-3j+ 4k and -6i 9j-12k are parallel to eacn U |
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Answer» Kindly repost a proper picture. The last part seems cropped |
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| 32. |
4. A train increases its speed from 80 km/h to 100 km/h in 4 S.the train. [Ans. 0.89 m/s)Sis speed from 80 km/h to 100 km/h in 4 s. Find the acceleration of |
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| 33. |
4. An object of height 1.2m is placed before a concavemiroroffocallength20mso2that a real image is formed at a distance of 60cm from it. Find the position of anobject. What will be the height of the image formed?of eneroy? Give two |
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Answer» Focal length (f) = -20 cm (concave mirror) Image distance (v) = -60cm (real image) Height of the object (h1)= 1.2 m = 120 cm Mirror Formula1/v + 1/u = 1/f(-1/60)+(1/u) = (-1/20)1/u= -1/20 + 1/601/u = (-3+1)/60= -2/60= -1/301/u= -1/30u = -30Object distance(u) = -30 cm Magnification (m) = -v/um = - (-60) /-30= 60/-30= -2m = h2/h1-2 = h2/120-2×120 = h2h2 = - 240 cmHeight of real image (h2)= -240 cm Real image is formed below the axis. So the height of a real image is negative. Hence, the position of an object is -30 cm(to the left of mirror) & the height of the real image formed is -240 cm or 2.4 m |
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| 34. |
Explain the meaning of "quantisation of charge"and "conservation of charge"[2003 (I) |
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| 35. |
Calculate the ratio of the de-Broglie wavelengthassociated with a proton and an alpha particle if thetwo have been accelerated through the same potentialdifference. |
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| 36. |
(a) Green(b) Yellow(c) Redi) de Broglie wavelength associated with an electron moving undera potential difference of 150 volts will be:(a) 12.27 A (b) 1 AThe inization eneroy ofhydrogen atom is(c) 1.227 A(d) 1 m |
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Answer» Wavelength=h/√V=12.27A° |
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| 37. |
A 80 Ω galvanometer shows a deflection of 1division per mA. It has 50 divisions on its scale. Ifa shunt of 2.5 Ω be attached to the galvanometer,what maximum current will this galvanometermeasure?Ans. 1.65 A. |
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| 38. |
The coil of a galvanometer has a resistance of100 Ω. It shows full-scale deflection for a current ofow will you convert it into a voltmeterto read a maximum PD of 5 V?Ans. By adding 9900 Ω resistance in series. |
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| 39. |
WTTWhat is the momentum of a photon from ultravioletlight of wavelength A 332 nm?(h 6.63 x 10 Js)2(ISC 2003)27 |
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| 40. |
80If the deflection in the galvanometer is zero, then the current flowing through the 512 resistor isA) 0.5 AIBYB) 06 AC09 AD) 15 A2.1 AoNs |
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Answer» it is. 1.5A. plz like and accept as best |
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| 41. |
httaterrRT Tq1 จี,relat 융 ? what is called the capability of doing work ?(a)สุส (force)(b) arf (work) (c)(power) (d) af (energy) |
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Answer» कार्य करने की क्षमता को ऊर्जा कहते हैं energy is the right answer |
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| 42. |
WORK, POWERAND ENERGY |
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Answer» Work is related to the amount of energy transferred to or from a system by a force. It is a scalar-valued quantity with SI units ofJoule. Power is defined to be the rate at which work is performed, or the derivative of work over time. The SI unit for power is thewatt. Energy is stored work. It has the same units as work, the Joule (J). |
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| 43. |
9. Aball is thrown up with a velocity of 20 m st. It takesto come back down. g10 ms1(A)4 s(B) 6 s(C) 8 s(D) 10 s |
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| 44. |
PHYSICSdy moving alonWORK POWER ENERGYor the cweThe work done by a force of IN in moving a body through a distance of Im in the direction of the forcea ito the circle whisYSICS C3 PART IId) 9.8 ergc) 9.8 Jb) I erga) 1 Tnt speed of 20 m/s over a tictionless surface. The workdone |
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Answer» Answer: a) JExplanation:Force: 1N, Displacement: 1m Formula W=force*distancew=1N*1m=1Nm=1J |
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| 45. |
A worker lives at a distance of 1.32 km from the factory. If the speed of the sound in air is 3.36m/s, how much time will the sound of factory siren take to reach the worker ? |
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Answer» Time=distance/speed 1.32km = 1320 m (1km = 1000m then 1.32km = 1320m) Speed of sounf in air = 330 m/s time = 1320 / 330 time = 4 second Thus it would take 4 second for the sound of the factory siren to reach the worker. |
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| 46. |
A police in a siren car moving witha velocity 20 ms1 chases a thief whois moving in a car with a velocityvm. The police car sounds atfrequency 300Hz, and both of themmove towards a stationary sirenof frequency 400Hz. Calculate thespeed in which thief is moving.= 10 ms.!or.1, |
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Answer» ◆ Solution-Frequency of police car horn heard by motorcyclist is -f1 = 400(330-v)/(330-20)f1 = 40(330-v)/31 Frequency of the siren heard by motorcyclist is -f2 = 300(330+v)/330f2 = 30(330+v)/33 As no beats are observed,f1 = f240(330-v)/31 = 30(330+v)/33435600 - 1320v = 306900 + 930v128700 = 390vv = 330 m/s Therefore, velocity of the thief is 330 m/s. please like the solution 👍 ✔️👍 |
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| 47. |
ABCD is a square whose side is a; taking AB and AD as axes, prove that the equation of thecircle circumscribing the square is x2 + y2-a (x-w)-0ing the square is a+y -a (x+y 0 |
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| 48. |
7. (tan-1 x cot1x)dx2 |
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Answer» It will be 0and tan inverse x+ cot inverse x = π/2 and d/DX of constant is 0 |
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| 49. |
the apparent depth of an object at the bottom of tank filled with a liquid of refractive index 1.3 is 7.7 cm. what is the actual depth of the liquid in the tank? |
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| 50. |
4. What is the relationship between Kp and Kc ? |
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Answer» KcandKpare the equilibrium constants of gaseous mixtures. However, the difference between the two constants is thatKcis defined by molar concentrations, whereasKpis defined by the partial pressures of the gasses inside a closed system. The equilibrium constants do not include the concentrations of single components such as liquids and solid, and they do not have any units. Relationship between Kp and Kc Consider the following reversible reaction:aA + bB ⇌ cC + dD The equilibrium constant for the reaction expressed in terms of the concentration (mol / litre) may be expressed as:K c = [C] c [D] d / [A] a [B] b If the equilibrium involves gaseous species, then the concentrations may be expressed in terms of partial pressures of the gaseous substance. The equilibrium constant in terms of partial pressures may be given as:K p = pcC pdD / paA pbBWhere pA, pB, pC and pD represents the partial pressures of the substance A, B, C and D respectively. If gases are assumed to be ideal, then according to ideal gas equation:pV = nRTp = nRT / VWhere p ———-> pressure in Pan ——————–> amount of gas in molV ——————–> Volume in m3T ———————> temperature in Kelvinn/V = concentration, Corp = CRT or [gas] RT If C is in mol dm-3 and p is in bar, then R = 0.0831 bar dm3 mol-1 K-1 Therefore, at constant temperature, pressure of the gas P is proportional to its concentration C, i.e.Let us suppose a general reaction:aA + bB↔ cC + dDThe equilibrium constant will be given as:Kp = (pC) c (pD) d /(pA) a (pB) b ……. (1)Now, p = CRTHence,pA = [A] RTwhere [A] is the molar concentration of ASimilarly,pB = [B] RTpC = [C] RTpD = [D] RTwhere [B], [C] and [D] are the molar concentration of B, C and D respectively. Substituting these values in expression for Kp i.e. in equation (1) Kp = [([C] RT) c ([D] RT) d]/[([A] RT) a ([B] RT) b] = [C] c [D] d (RT) c+d/[A] a [B] b (RT) a+b= [C] c [D] d (RT) c+d – a+b/[A] a [B] b= Kc (RT) c+d – a+b= Kc (RT) ∆n Where ∆n = (c + d) – (a + b) i.e. number of moles of gaseous products – number of moles of gaseous reactants in the balanced chemical reaction. Hence relation between Kp and Kc is given as:Kp = Kc (RT) ∆n thnx |
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