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height=time*velocitytime=height/velocitytime=400m/196ms^-1 =2.04s

option b

ohh iconfused of it being cancelled by opposite sides. thank u

Theshadowis longer as you come nearer the north and south poles. thesun is directly overheadat noon you don't have a shadow.

Given: let radius of the wire initially : r1 radius of the wire after it decreases by 0.1% : r2= r1- (1/1000 )r1 = r1- (1/1000)r1 = (999/1000)r1= 0.999 r1 Area of the wire initially : A1 Area of the wire after it is stretched becomes : A2 Resistance initially of the wire : R1 Resistance after it is stretched : R2 lenght of the wire initially,l1lenght after it is stretched ,l2 Now, the most important thing to be kept in mind while solving this problem is that volume of the wire remains constant.Hence, l1A1= l2A2 l1×π r12= l2×π r22 l2= l1× r12/ r22= l1/0.99801We know that resistance( R) is given by the following equation: R = ρ(l/A)Where ‘ρ’ is the resistivity of the wire which will remain the same throughout as it is the property of the material of which the wire is made up.Taking the ratio of the resistances: R1/R2= (l1/A1)/(l2/A2) R1/R2= (l1A2)/(A1l2)Substituting the values of l2and A1in the above equation we get:R1/R2= (l1π r22)/( l2×π r22)R1/R2= l1/l2× ( r2/ r1)2R1= 0.9960 R2Or the percentage increase in the resistance of the wire is =(R2- R1)/R1×100 = 0.004×100 = 0.4 = 0.4% increase in resistance

Given :

Distance 1 = 30 km

Distance 2 = 70 km

We know that speed = distance/time

and, Average speed = total distance/total time taken

When the train acquired a speed of 30 km/hr, the time taken = 30/30 = 1 hour

Average speed = (distance 1 + distance 2)/(time 1 + time 2)

AS time 2 or t2 is time taken for the second part of the journey of 70 km

⇒ 40 = 100/(1 + t2)

⇒ 40 + 40t2 = 100

⇒ 40t2 = 100 - 40

⇒ 40t2 = 60

⇒ t2 = 60/40

t2 = 1.5

So, t2 or time taken to travel the second part of the journey is 1.5 hours.

Speed of the second part of the journey = distance 2/time 2

⇒ 70/1.5

⇒ 46.666 km/hr or 46.7 km/hr

average speed=9distance 1+distance2here I don't understand

its distance 1+distance2/time 1+time 2for average speed

40=100/1+t2here I don't understand

Your answer is couldn't show

The portion of space near a magnetic body or current carrying body in which the magnetic forces due to body or current can be detected

A magnetic field is a vector field that describes the magnetic influence of electric charges in relative motion and magnetized materials. ... Magnetic fields surround and are created by magnetized material and by moving electric charges (electric currents) such as those used in electromagnets.

Advantages of WindPower. It's a clean fuel source. Wind energy doesn't pollute the air likepowerplants that rely on combustion of fossil fuels, such as coal or natural gas. Wind turbines don't produce atmosphericemissionsthat cause acid rain or greenhouse gasses.

Let P2 = 1.004 P1 ..... A 0.4% increase in PLet T2 = T1 + 1 ........... See note below

P1V1/T1 = P2V2/T2 ..... combined gas lawP1/T1 = P2/T2 ............... Assume V remains constant.T1 = P1T2 / P2 .............. solve for T1T1 = P1(T1+1) / (1.004P1)T1 = (T1+1) / 1.0041.004T1 = T1 + 11.004T1 - T1 = 10.004T1 = 1T1 = 1 / 0.004T1 = 250K

Note: A 1 degree increase on the Celsius scale is a 1 degree increase on the Kelvin scale. Temperatures used in the combined gas law must be in Kelvin.

how P2=0.004

Magnesium is the powerhouse behind the photosynthesis in plants. Magnesium in plants is located in the enzymes, in the heart of chlorophyll molecule.

magnesium is the powerhouse behind the photosynthesis in plant. magnesium in plants is located in the enzymes, in the heart chlorophyll molecule

is located in enzymes

(i) Anticlockwise moment= 10gf × 50 cm = 500gf cm (ii) From the principle of moments, Anticlockwise moment = Clockwise moment 10gf × 50 cm = W × 100cm So, W = 10gf x 50cm/100cm = 5gf By applying a force 5 gf upwards at the 100 cm mark, rule can be made horizontal

Max acceleration =CMin acceleration =A

1-Moment of force =magnitude of force X perpendicular distance of the line of action of force from the axis of rotation= 50cm X 10gf = 500 gf cm (ans)2-To apply the least force we obviously have to make the perpendicular distance highest. Hence, the least force should be applied at 100cm mark.Thus, by principle of moments500 gf cm = 100cm X force=> force = 5 gfThe force should be 5 gf upwards at the 100 xm mark

Transpiration is the process of water movement through a plant and its evaporation from aerial parts, such as leaves, stems and flowers.

Water comes out of leaves in the form of vapour. This is called transpiration.

let the angle between the lines of action of their equal forces F be 2θ

F = 20 N

resultant force in the vertical direction upwards = 2F cosθ

=> 30 = 2(20) cos θ

=> cosθ = 3/4 or θ = 41.410°

=> 2θ = 41.410° x 2 = 82.819°

Ans: angle b/w their arms = 82.819°

c) is correct answer

a) is the correct answer

Option (b) is the correct answer.

Explanation:The possible energy of a photon is given by the difference between the two energy levels. The only 11.1eV is not possible.

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b)Ifthe cricketer moves his hands backwardswhile catchingtheball, he is giving more time totheball in changingitsmomentum. So when you takeyour hand backwardsthat is inthedirection of whichtheball is coming to you, it slowly reducesthemomentum and hence reducestheimpact to be safe.

c)The force applied to move a body depends upon effective force applied on it including its weight. As effective weight in the case ofpullingis lessthanin thepushing, less force is required inpulling.

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It is the best product for the dress iron....

It is the one of the top brand home appliance to use

The LG is a dry iron specially designed to get the best ironing results. The Teflon Classic PTFE coated soleplate of this dry iron has a gliding effect on the fabric and ensures the safety of your clothes.

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Given, r = 2.5 ohms, T1 = 0°C, Temperature coefficient, a= 4000/(°C)Resistance,R at T2= 70°C is given by

R = r{1+a(T2-T1)} = 2.5{1+4000(70-0)}= 2.5{1+28000}=2.5*(28001)=70002.5 ohms Ans. The value of resistance at 70°C is 70kiloohms

Net displacement will be 2+6+6= 14m

Refractive Index = Speed of light in Air / Speed of light in medium

Speed of light in medium = Speed of light in air / Refractive index

=> Speed of light in medium = 3 × 10⁸ / 1.5

=> Speed of light in medium = 2 × 10⁸ m/s

So, Percentage Change = ( Change in Speed / Speed of light in air ) * 100

=> Change in Speed = 3 × 10⁸ - 2 × 10⁸

=> Change in speed = 10⁸ ( 3 - 2 ) = 10⁸

=> Percentage change = ( 10⁸ / 3 × 10⁸ ) * 100

=> Percentage change = ( 1 / 3 ) * 100

=> Percentage change = 33.34 %

Velocity of the water = √2gh = √2*9.8*5 = √98 = 7√2m/s

now when radius of hole = 2mm A = π(0.002)² m²

rate of flow Q = A.v = π *4*7√2 × 10^-6 = 0.000124 m³/s = 1.24 × 10-⁴ m³/s

A) Ketoneketone is C=O functional group hence hydrogen is absent.

ketone is the ribht answer because its functional group is co

Thanks

Kindly tell ne the full questionthanks

Example of composite redicals are......methyl,methane

Centripetal Force. If an object moving in a circle and experiences an outward force, than this force is called as the centrifugal force. If the object travels in a uniform speed in a circular path is called centripetal force.

Option DThe total kinetic energy (KE) of an object is given by:

KE=1/2mv2+1/2Iω2KE=1/2mv2+1/2Iω2

whereIIis the moment of inertia of the object andits angular momentum.

option B is correct

option (A)

thanku

A circular wire behaves like a ring M.I. about its diameter = (MR²)/2.

The moment of inertia of remaining disk = Moment of inertia of whole disc - Moment of inertia of removed small disc

moment of inertia of any disk about its own central axis = 1/2 mr^2

Moment of inertia of total disk of mass 9M and radius R = (1/2) 9M R^2

Iwhole= (1/2) 9M R^2

-

Let us calculate the mass of the removed disk and the location of its centre of mass

mass density = 9M / area of disk = 9M/ piR^2

mass of small disk of radius R/3 = area of small disk x mass density = pi(R/3)^2x 9M/ piR^2

We get the mass of the removed small disk = M

-

Its centre of mass is located at R - R/3 = 2R/3 from the main axis

its moment of inertia can be calculated using parallel axis theorem

moment of inertia of removed disk = moment of inertia of small disk about its own axis + moment of inerita of its centre of mass about the main axis

Iremoved= (1/2) M (R/3)^2+ M (2R/3)^2

= MR^2/18 + 4MR^2/9

Iremoved= MR^2/2

-

hence the moment of inertia of remaining disk = Iwhole-Iremoved

=(1/2) 9M R^2-MR^2/2

= 4MR2

B. MR^2/2

Yes

R-X + 2Na +X-R ——-> R - R + 2NaX.

Example:-

2CH3 -CH-CH3 -Cl + 2Na —-> CH3-CH2-CH2--CH3 +2 NaCl.

option D is correct

F = qE + qv × B.q is chargeB is Magnetic forceE is electric forcev is velocity

When a charge Q moves with a velocity V inside a magnetic field B, then force on he charge is given as,F=Q( V×B)It is called MAGNETIC LORENTZ FORCE on the charge due to its motion inside the magnetic field.

If an electric field E also acts ,the TOTAL LORENTZ FORCE is given as

F= QE + Q( V×B).

Maxwell's corkscrew rule imagine a corkscrew held by your hand rotate. the screw head such that its tip advances in the direction of the current in a conductor as shown. the direction in which the thumb or the head of the screw rotates gives the direction of the magnetic lines of force a magnet.