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It will be zero.

ElectricFlux=(totalchargeenclosed)/(permittivityoffreespace)

Since net charge of a dipole is zero. Therefore, flux through the cube will be zero

We know thatf=1/T

Where f is the Frequency & T is the Time Period

Therefore , T=2π *√(L/g)————(1) Where L is the Initial length of the Pendulum

When L=4L,

T1=2π *√(4L/g)

=√4*(2π *√(L/g))

=2*(2π *√(L/g))

From(1) We get that , T1=2T

Therefore,f1=1/T1 =1/2T

So we get that f1 = 1/2f

So we can conclude that, When the length of the Simple Pendulum is increased 4 times of its initial length, its frequency will be reduced to half of the initial frequency.

Because he can produce sufficient torque by increasing the perpendicular distance between the line of action of force and axis of rotation i.e. the length of arm of see saw on the side of boy.

oscillation=40time taken=60secin 1sec = 40/60=2/3 Hz frequency = 1/time periodtime period = 1/frequencytime period = 1/2/3 =3/2 =1.5 sec

1.55 meters is the correct answer

1.55m is the correct answer

unable to understand

The Tyndall effect, also known as Willis–Tyndall scattering, is light scattering by particles in a colloid or in a very fine suspension. It is named after the 19th-century physicist John Tyndall.

Oscillationis the repetitive variation, typically intime, of some measure about a central value (often a point ofequilibrium) or between two or more different states. The termvibrationis precisely used to describe mechanical oscillation. Familiar examples of oscillation include a swingingpendulumandalternating current.

Oscillations occur not only in mechanical systems but also indynamic systemsin virtually every area of science: for example the beating of thehuman heart(for circulation),business cyclesineconomics,predator–preypopulation cycles inecology, geothermalgeysersingeology, vibration of strings inguitarand otherstring instruments, periodic firing ofnerve cellsin the brain, and the periodic swelling ofCepheid variablestars inastronomy.

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Time taken= 0.4sSpeed of sound= 340m/sDepth of water level=(speed * time)/2=(340m/s*0.4s)/2=136m/2=68m

D) is the correct answer

gravitationally bound systems, the orbital speed of an astronomical body or object is the speed at which it orbits around either the barycenter or, if the object is much less massive than the largest body in the system, its speed relative to that largest body.

gravitationally bound systems, the orbital speed of an astronomical body or object is the speed at which it orbits around either the barycenter or, if the object is much less massive than the largest body in the system, its speed relative to that largest body.

orbital velocity. noun. Thevelocityat which a body revolves about another body. The minimumvelocityrequired to place or maintain a satellite in a givenorbit.

Orbital velocity is defined as the velocity at which a body (satellite) revolves around the other body (earth).

The other ways to express orbital velocity are as follows:

The particle velocity due to wave motionProduction of orbital kinetic energy by the electron

Derivation of orbital velocity

Orbital velocity is derived in the following way:

Fg=GMm/r^2(gravitational force between the earth and the satellite) (eq.1)

Fc=mV^2/r(centripetal force acting upon the satellite) (eq.2)

Where,

M: mass of the earth

m: mass of the satellite

r: radius of uniform motion of the satellite around the earth

r=R+h

Where,

R: radius of the earth

h: height of the satellite

V: linear velocity of the satellite

Fc: centripetal force

Fg: gravitational force

Fg=Fc(from eq.1 and eq.2)

GMm/r^2=mV^2/r

V=[GM/r]^1/2(eq.3)

Therefore, this is the equation of orbital velocity.

orbital velocity. noun. Thevelocityat which a body revolves about another body. The minimumvelocityrequired to place or maintain a satellite in a givenorbit.

They are used by mobile phones (produced from a transmitter chip and antenna) as well as WiFi

They are also used in radar which is used by ships, aircraft and weather forecasters.

s=Q/m∆T Since boiling of water is an isothermal process => ∆T = 0

therefore s=Q/m×0= infinity

so option c

The SI derivedunitof quantity of electricchargeis the coulomb (symbol: C).

The amount ofchargein 1 electron (elementarycharge) is approximately1.6×10−19 C, and 1 coulomb corresponds to the amount ofchargefor about6.24×1018 electrons.

The symbol Q is often used to denote a quantity of electricity orcharge

By convention we refer to the electron has having a negative charge and a proton as having a positive charge.

From the definition of electric field in electrostatic chapter,we get that the word unit positive charge means a charge amount of +1 coulomb(S.I unit) charge.

2 is the following question answer.

2 is the right answer

Given data states the value of x and y and is asking the value of 2x – 2y,

Therefore putting the value of x and y into the equations,

Substituting x = 10.0 + -0.1 and y = 10.0 + -0.1 in 2x-2y = {2[10.0 +(-0.1)] – 2[10.0 + -(0.1)]}

Rearranging them, we get = {2[10.0-10.0] +2[(-0.1)+(-0.1)]} = {2 [0.0] + 2[-0.1-0.1]} ={0.0 + 2 x [-0.2]} =0.0- 0.4

Hence 2x -2y = -0.4 so answer Is 3

2 is the correct answer

the correct answer is 3

2 is the right answer

If a body gets positively charged then it means that it lost some electrons from its outer shell. Electrons are negatively charged sub atomic particles and protons are positively charged sub atomic particles.if a body is negatively charged, then it means that it gain some electrons and they are in majority. If a body is positively charged,then it means that it is loosing some electrons so the protons which are positively charged are in majority. Only electrons can move and protons can't coz electrons are loosely attracted to the nucleus and protons and neutrons are present in nucleus of an atom. The electrons present on the outermost shell can easily be loosed.

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Deriving the expression orformula #1

TheGravitational Forcebetween the earth and the satellite =Fg= (G.M.m)/r2 ……………… (1)

Thecentripetal forceacting on the satellite =Fc= mV2/r ……………………….. (2)

Here, M is the mass of earth and m is the mass of the satellite which is having a uniform circular motion in a circular track of radius r around the earth. V is the linear velocity of the satellite at a point on its circular track.

Now this r is the sum of the radius of the earth(R) and the height(h) of the satellite from the surface of the earth.

r = R + h

Now equating, equation 1 and 2 we get,

Fg= Fc

=> (G.M.m)/r2= mV2/r

V = [(GM)/r]1/2……………………………….. (3)

This is the first equation or expression of Orbital Velocity of a satellite. Herer = R +h

Deriving the expression orformula #2

For a mass of m on earth’s surface, the following is true:

mg = (GMm)/R2………………………. (4)

Note, on earth surface h=0 and r = R. Andgravitational forceon amassis equal to its weight on the surface.

From equation 4 we get this equation,GM = g. R2…………………….. (5)

Substituting this expression of GM in equation 3 (Orbital velocity), we get,

V = [(gR2)/r]1/2

V = R . (g/r)1/2……………………. (6)

This is the second expression of Orbital Velocityof a satellite.Here, as said earlier, r = R +h

The action which doesn't require brain to response and does it itself by the help of spinal cord is called reflex action.It is a quick sudden response to the stimuli. e.g. (1):lifting of hand when touched by a hot object, (2):closing of eyelids when an insect comes in front of our eye.

The pathway:Receptor >sensory neuron>spinal cord>motor neuron>Effector

A substance that provides nourishment essential for the maintenance of life and for growth.

A substance that provides nourishment essential for the maintenance of life and for growth .

a substance that is needed to keep a living thing alive and to help it grow

Nutrientsare molecules in food that all organisms need to make energy, grow, develop, and reproduce. There are two major types ofnutrientsthat we need to supply our bodies with energy, macronutrients and micronutrients. Macronutrients are carbohydrates, protein, and fat. ... Micronutrients are vitamins and minerals.

a substance that is needed to keep a living thing alive and to help to grow

nutrients are such a substance that is contained by food which gives a living organisms energy and helps to keep them strong

As n= 2 and l = 1 represents2 P orbitalsoAnswerOption c

theorbital velocityof an astronomical body or object (e.g.planet) is thespeedat which itorbits.V=√(GM÷R)

Theorbital speedcan be found using v = SQRT(G*M/R). The R value (radius oforbit) is theearth'sradius plus the height above theearth- in this case, 6.59 x 106m. Substituting and solving yields aspeedof 7780 m/s

Let a mass m be suspended with a string of length l and be displaced by a force F through a small angle θ.

From the FBD we see that the restoring force is mgsin(θ)

Since the displacing force F is acting opposite to the restoring force

F = ─mgsin(θ)

Now since θ is small

sinθ ≈ θ

Let the horizontal displacement bex

θ =x/l

Thus,

F = ─mgθ

=> F = -mgx/l

=>F = -(mg/l)x

=> F = -kx [since mg/l is a constant]

Restoring force is thus directly proportional to the displacement, hence the motion is SHM for small anglesθ.

F = -(mg/l)x

=> ma = -(mg/l)x

=> a = (g/l)x

The changingmagneticflux through the plateproduces a strong eddy current in the direction, which opposes the cause as theplate oscillates.

Barkhausen criterionare a set of two mathematical conditions which a linear electronic circuit must follow to act as an electronic oscillator. It also satisfies the following condition: The magnitude of the product of open loop gain of the amplifier and the magnitude of the feedback factor is unity.

An oscillator is anything that has a rhythmic periodic response. A damped oscillation means an oscillation that fades away with time. Examples include a swinging pendulum, a weight on a spring, and also a resistor - inductor - capacitor (RLC) circuit.

TheTyndall effectis the scattering of light as a light beam passes through a colloidThe visible beam of headlights in fog is caused by the Tyndall effect. Thewater dropletsscatter the light, making the headlight beams visible.

The Tyndall effect is used in commercial and lab settings to determine particle size of aerosols.

Opalescent glass displays the Tyndall effect. The glass appears blue, yet light that shines through it appears orange.

Blue eye coloris from Tyndall scattering through the translucent layer over the eye's iris.

T/15=2π√l/gT/18=2π√l-22/gdividing both the equations18/15=√l/l-226/5=√l/l-2236/25=l/l-2236(l-22)=25l36l-36*22=25l36*22=11ll=36*2=72cmSo second length=72-22=50cm

Resultant,R =√(a^2+b^2+2abcosx)

As, r = √{(3p)^2+(2p)^2+2×3p×2p×cosx}

or, r = √(9p^2+4p^2+12p^2cosx)

or, r = √(13p^2+12p^2cosx)

According to question;

2r = √{(6p)^2+(2p)^2+2×6p×2p×cosx}

or, 2r =√(36p^2+4p^2+24p^2cosx)

or, 2r = √(40p^2+24p^2cosx)

or, 2{√(13p^2+12p^2cosx)} = √(40p^2+24p^2cosx)

or, 4(13p^2+12p^2cosx) = (40p^2+24p^2cosx)

or, 52p^2 + 48p^2cosx= 40p^2 + 24p^2cosx

or, 12 p^2 = - 24 p^2cosx

or, cosx = - 1/2

or, x = cos^-1(-1/2)

or, x = 120°

So, angle between the forces is 120°.

bakchod

why we take a/√2

why we take a /√2

one more question why you take 1/2 for finding diagonal how to take 1/2? thanks in advance

why you take 1/2 pls answer

Diagonal = AC OC = (1/2) AC

thanks now I understand

distance=10 mu =0m/Sa= 10m/sPutting the formula v square _ u square / 2a =s v square =

An electric bell contains an electromagnet, consisting of coils of insulated wire wound round iron rods. When an electric current flows through the coils, the rods become magnetic and attract a piece of iron attached to a clapper. The clapper hits the bell and makes it ring.

(a) converts electrical energy to sound energy.(b) A converts sound energy to electrical energy.(c) A converts electrical energy into light energy and heat energy.(d) A converts electrical energy of the battery into light and heat energy.

Heating effect is not seen in (c) electric motor. Electric motor converts electric energy to mechanical energy.

A geographic meridian(orline of longitude) is the half of an imaginarygreat circleon the Earth's surface, terminated by theNorth Poleand theSouth Pole, connecting points of equallongitude, as measured in angular degrees east or west of the Prime Meridian.

Themagnetic meridianis an equivalent imaginary line connecting the magneticsouthandnorth polesand can be taken as the horizontalcomponentof magnetic force lines along the surface of the earth.