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24=2×2×2×3 is the prime factorization

Given, thickness of iron =3cm external diameter = 56cm Length of tube = 182cmWe know, volume of hollow cylinder = πh(R²−r²)∴ internal diameter = external diameter−2×thickness of iron= 56−2×3 = 56−6 = 50cm

=> Outer radius(R) = 56÷2 = 28cm inner radius(r) = 50÷2 = 25cm∴ Volume of hollow cylinder = πh(R²−r²) = 3.14×182(28²−25²) = 3.14×82×159 = 90865.32cm³ Answer

its not a right answer

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P(AUB)= p(a)+p(b)0.8= x+0.2x= 0.6

Complimentary angles when added equal 90 degrees. Let one angle be x. Then, the other angle will be x+20. x+x+20 = 90 2x+20= 90

2x= 90-20 2x=70 x= 70/2x=35 One angle is 35 and the other 55 degrees

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In isosceles right angle triangle, sum of all angles is 180° and one angle is 90°so sum of other two angles is 90° they must be equal( isosceles triangle)therefore each acute angle measure 90/2=45°

(i)-x=5.(ii)-x=10.(iii)-x=17.

This can be done by pythageorous theoram ok

Let the outer radius be Rand inner radius be r

total surface area = inner surface area + outer surface area + 2 ( area of thickness ) . = 2πrh + 2πRh + 2π(R² -r²)⇒338π = 20πr + 160π + 128π - 2πr²⇒2πr² - 20πr + 50π =0⇒r² -10r + 25 =0⇒r²-5r-5r+25=0⇒r(r-5)-5(r-5)=0⇒(r -5)²=0⇒r =5 cm

therefore thickness of the metal in cylinder = R- r = 8- 5 = 3 cm.

12100 is the answer...

option (c) 24200 is the correct answer

24200 is the following question answer

24200 is the correct answer of the given question

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Tncs so much

Two events areindependentif the result of the second event is not affected by the result of the first event. IfAAandBBare independent events, theprobabilityof both events occurring is the product of the probabilities of the individual events.Two events aredependentif the result of the first event affects the outcome of the second event so that the probability is changed. In the above example, if the first marble is not replaced, the sample space for the second event changes and so the events are dependent. The probability of both events occurring is the product of the probabilities of the individual events

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4m + 6n = 542m + 3n = 272m = 27 - 3nm = (27 - 3n)/2.....(1)

3m + 2n = 28.........(2)

Put value of n from eq(1) in eq(2), we get3*(27 - 3n)/2 + 2n = 2881 - 9n + 4n = 56-5n = -81 + 565n = 25n = 25/5 = 5

From eq(1)m = (27 - 3*5)/2 = (27-15)/2 = 12/2 = 6

LCM = (1242×138)÷HCF

.( 5 cos²60°+4 sec²30°-tan²45°) ÷ (sin²30° +cos²30°)

= {5*(1/2)^2+ 4 (√3/2)^2-(1)^2} ÷{ (1/2)^2+(√3/2)^2}

={ 5/4+4*(3/4)-1}÷ (1/4+3/4)

= 5/4-2 ÷ 1 = -3/2

price of 19 note book is 304.

128*8/19=304 is the quick answer for your question

16×19 =304 is correct answer

the cost of 19 notebook are Rs 304

Cost of 19 notebooks are rupees 304

cost of 8 note book = 128cost of 1 note book = 128/8=16cost of 19 note book = 19*16=304304 is the answer

cost of 19 notebook are Rs. 304

4 cos 60 + 4 tan²45 - sin²30

= 4*(1/2) + 4(1) - (1/2)²

= 2 + 4 - 1/4

= 6-1/4

= 24-1/4

= 23/4

3 is correct answers and express the this options is correct

option 3 is the right answer

option 3 is the right answer

option 3 is the right answer

option 3 is the right answer

1²+2²=3so 3 is the answer of the first

volume of two containers = 2(a^3) = 3456 cm^3a^3= 1728a=cube root of 1728a =12 cm

Modal value is the most repeated number.

146 - 2

134 - 1

143 - 1

144 - 1

138 - 3

145 - 1

153 - 1

140 - 1

135 - 1

So the modal value is 138

so the correct answer is 138

This is a graphical representation of data, pie chart

x+x =138 {vertically opposite angles are equal in measure}

=>2x =138=>x =69 degrees

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0.75= 75 percentage1/3= 33 percentage30 percentage then4/5x100= 20 percentagethanksplease like the solution 👍 ✔️

3 2/3 - 3/11 of 2 3/4 ÷ 1 1/4 × 1 2/3 + 1/3 = 11/3 - 3/11 of 11/4 ÷ 5/4 × 5/3 + 1/3 = 11/3 - 3/4 ÷ 25/12 + 1/3 = 11/3 - 3/4 × 12/25 + 1/3 = 11/3 - 9/25 + 1/3 = 12/3 - 9/25 = 4 - 9/25 = (100-9)/25 = 91/25 = 3 16/25

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full ans plzz

Ratios are 4:3 (4+3=7) and 2:3 (2+3=5). So LCM of 7, 5 is 35.

Now, for 35 litres mixture .

Let AC = Acid, W=water

Vessel A,

AC:W = 4:3 (4+3=7) means in 35 litres mixture. Acid is 4*35/7=20 litres and water is 3×35/7=15 litres.

Vessel B,

AC:W = 2:3(2+3=5) means in 35 litres mixture. Acid is 2×35/5 = 14 litres and water is 3×35/5 = 21 litres

For Vessel C,AC:W=1:1(required)

Let ratio of Vessel A=x and Vessel B=y.

In Vessel C , both acid and water will be in equal quantity. So,

Net quantity of acid = Net quantity of water

20x+14y=15x+21y

5x=7y

x/y=7/5

So, x:y=7 :5

Vessel A : Vessel B = 7:5

(a) is correct option

Right answer is a. 7:5.

is carcat answer 7:5

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one rational number between 6 and 8