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Sum of the exterior angle other than 90= 180therefore no. of side = 180/60 = 3 = 3 +2 = 5

option A is the correct answerA=7-1=6B=12-5=7hence, A+B=6+7=13

x+y=50; x-y=14; x+y=50; x-y=14/ / 2y=36; y=18; x=50-18=32

Milk elephant drink in 1 day=12LMilk elephant drink in (365*2 days) 2 years=12*365*2=8760L

let 1st no be X x(12.6)=253.134x=253.134/12.6x=20.09

X×y= 253.134; x = 254.134/12.6=20.09

Let rate upstream = x km/h and rate downstream = y km/hThen,(24/x) + (36/y) = 36 ------(i)and (36/x) + (24/y) = 13/2 -------(ii)Adding (i) and (ii),60((1/x) + (1/y)) = 25/2=> (1/x) + (1/y) = 5/24 -------(iii)Subtracting (i) from (ii)12((1/x) - (1/y)) = 1/2=> (1/x) - (1/y) = 1/24 --------(iv)Adding (iii) and (iv)2/x = 6/24=> x = 8So (1/8) + (1/y) = 5/24=> y = 12Speed Upstream = 8 km/h andSpeed Downstream = 12 km/hSo,Velocity of Current = (1/2) * (12-8)= 2 km/h

Let the speed of the boat

in still water = x kmph

Speed of the stream = y kmph

i ) relative speed of the boat in downstream= ( x + y ) kmphDistance travelled = d1 = 36Time = t1 hrt1 = d1 / s1t1 = 36/ ( x + y )

ii) relative speed of the boat in upstream = ( x - y ) kmphDistance = d2 = 32 kmTime = t2 t2 = 32/ ( x - y )Therefore ,Total time = 7 hrt1 + t2 = 7hr36 / ( x + y ) + 32/ ( x - y ) = 7 ----( 1 )

iii) second time ,Relativespeed of the boat indownstream = ( x + y ) kmphd3 = 48 kmTime = t3t3 = 48/ ( x + y )

iv ) in upstream

Relative speed of the boat = ( x - y ) kmph

time = t4 hrd4 = 40kmt4 = 40/ ( x - y )

Total time = 9 hr48 / ( x + y ) + 40/ ( x - y ) = 9 ---( 2 )

Let 1 / ( x + y ) = a ,1 / ( x - y ) = b

Then rewrite ( 1 ) and ( 2 ) we get 36 a + 32 b = 7 -----( 3 )48a + 40b = 9 ------( 4 )

Multiply ( 4 ) with 4 and equation ( 3 ) with 5 and

192a + 160b = 36 ---( 5 )

180a + 160b = 35 -----( 6 )

Subtract ( 6 ) from ( 5 )

we get

a = 1/ 12

put a = 1/ 12 in ( 3 )we get ,b = 1/ 8Now 1/ ( x + y ) = 1/ 12 1/ ( x - y ) = 1/ 8

Therefore ,

x + y = 12 ----( 7 )x - y = 8 ----- ( 8 )add ( 7 ) and ( 8 )2x = 20x = 10put x = 10 in ( 7 ) we get y = 2

Speed of the boat in still water = x = 10 kmphspeed of the stream= y = 2kmph

very good

Let present age of varun be m and swati be n

Seven years agom-7 = 5(n-7)^2...... (1)

3 years hencen +3 = 2/5(m+3)5n + 15 = 2m + 6m = (5n + 9)/2.......(2)

Put Value of eq(2) in eq(1)

5n+9 - 14 = 10(n-7)^2 n-1 = 2(n^2 + 49 - 14n)2n^2 - 29n +99=02n^2 - 18n - 11n +99 =02n(n-9) - 11(n-9)=0n = 9, 11/2

m = (5x9 + 9)/2m =54/2 = 27

Present age of varun is 27 years and swati is 9 years

Thanks

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S={1,2,3,4,5,......,96,97,98,99,100}n(S)=100

EVENT AA={80,81,82,83,84,85,86,87,89,90,91,92,93,94,95,96,97,98,100}n(A)=20P(A)=n(A)÷n(S)=20÷100=2/10=1/5

EVENT BB={5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95,100}n(B)=20P(B)=20÷100=1/5

5+8=13 so the probability is 1/13

An eight sided polygon is a octagon.

it is 10 20 15 30 20 40 25 50

n-1 sided Polygon DATASize of each exterior angle = 360/(n-1)Size of each interior angle = 180-[360/(n-1)]==========================================n+1 sided Polygon DATASize of each exterior angle = 360/(n+1)Size of each interior angle = 180-[360/(n+1)]===========================================Equation: Difference = 9 degrees180-[360/(n+1)] - [180-[360/(n-1)] = 15°-(360/(n+1) + 360/(n-1) = 15°-1/(n+1) + 1/(n-1) = 1/24-----24(n-1)+24(n+1) = (n+1)(n-1)48= n^2-1n^2 = 49n = 7

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Unlike permanent magnets, temporary magnetscannot remain magnetizedon their own. They are usually made up of soft materials. They require an external force i.e. electric current to stay magnetized. As electric current is removed,they are demagnetized so far.

hence, option (c) is correct.

3) Increases or decreases depending upon the original dimensions

(3) Increase or decreases depending upon the original dimensions

total outcome=150(i) P(an odd number)=(25+15+32)/150

(i)p(an odd number)=(25+15+32)/150=72/150=36/75=12/25(ii)p(a multiple of 4)=28/150=14/75

Odd numbers are the numbers which can't be completely divuded by 2.

13+12+5=30

your answer is wrong

falsebecause if x is odd and then 1 is added in it, it become even. that means it does not remain odd no.

Let total amount required for car = xSaving every month should be equal to x/12

To buy car in 9 months saving should be x/9

So % increase in saving should be = [(x/9 - x/12)/(x/12)]*100= [(4x - 3x)/36/(x/12)]*100= (12/36)*100= (1/4)*100= 25%

33.3

Solution:-Let the natural number be 'x'.Therefore, according to the question.x² - 84 = 3(x+8)x² - 84 = 3x + 24x² - 3x - 84 - 24 = 0x² - 3x - 108 = 0x² - 12x + 9x - 108 = 0x(x - 12) + 9(x - 12) = 0(x + 9) (x - 12)⇒ x = -9 and x = 12we have to take the positive value because natural numbers cannot be negative.Therefore, the number is 12.Answer.

Let the natural number be 'x'.Therefore, according to the question.x² - 84 = 3(x+8)x² - 84 = 3x + 24x² - 3x - 84 - 24 = 0x² - 3x - 108 = 0x² - 12x + 9x - 108 = 0x(x - 12) + 9(x - 12) = 0(x + 9) (x - 12)⇒ x = -9 and x = 12we have to take the positive value because natural numbers cannot be negative.Therefore, the number is 12.

Solution:-Let the natural number be 'x'.Therefore, according to the question.x² - 84 = 3(x+8)x² - 84 = 3x + 24x² - 3x - 84 - 24 = 0x² - 3x - 108 = 0x² - 12x + 9x - 108 = 0x(x - 12) + 9(x - 12) = 0(x + 9) (x - 12)⇒ x = -9 and x = 12

since, natural numbers cannot be negative so the required number is 12.

Two packs of candies weigh 12/5 kg and 9/10 kg

Total weight of the packs= 12/5 + 9/10= (24 + 9)/10= 33/10= 3.3 kg

Given:- a company fax chocolate powder in cylindrical judge of radius 7 cm and height 20 cm.The label of the company is placed around the surface of jar with a 2 cm space from the top and bottom.

=>Height of the label=20 cm - 4cm=16 cm=>Radius of the label=7 cm.Area of the label=2πrh=(2×3.14×7×16) cm²=703.36 cm²

THE ANSWER OF THIS QUISTION IS 352cm

where is the figure