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Using BODMAShence13*5+9+12-19=65+9+12-19=86-19=67option d

thank

C) option is correct,

The meaning of that statement is

there exists x belongs to A such that x + 2 < 9 , which is true for all elements of A

x=2 and y=2 please hit the 👍👍👍👍👍👍👍👍👍👍👍👍

x/3 +1=5/3x/3=5/3-1x/3=5-3/3x/3=2/3x=2y-2/3=1/3y=1/3+2/3y=2+1/3y=3/3y=1x=2, y= 1

inasquare ABCD ,AB (2x+3)cm and BC (3x_5)cmfind BD Hint BD2 AB2 + AS2by Pythagoras theorem isand AD BC.)

RPQ = 180°- 135° = 45°RQP = 180° -110° = 70soangle Q + angle P + angle R = 180°45°+70° + angle R = 180°angle PRQ = 180° - 115° = 65°

(9x²+5x)+(6x²-2x)= (9+6)x²+(5-2)X= 15x²+3x

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<p=<r=110. opposite angles of a parallelogram is equal

<s=180°-<p<s=180°-110°=70°. adjacent angles of a parallelogram are 180°

Answer is 45.70.65

Angle R = 180-(180-135)-(180-110) = 180-(45)-(70) = 180-115 = 65°

9000*5=10000*6/400........….

not possible once explain clearly

p= 9000Rs n=1yr r=5%

SI=PNR/100

=9000*1*5/100

=450Rs

A=p+i

=9000+450=Rs9450

A child friendly bank announces a savings scheme for school children

bhai apke is question ke answer- 448 hoga

=6x²-7x-3=6x²+2x-9x-3=2x(3x+1)-3(3x+1)=(2x-3)(3x+1)⇒2x-3=0 ⇒3x+1=0⇒x=3/2 ⇒ x= - 1/3α=3/2 ,β= - 1/3⇒α+β= -b/a⇒3/2+(-1/3)= - (-3)/6⇒3/2-1/3=1/2⇒7/6 =1/2⇒αβ=c/a⇒3/2(-1/3)= -7/6⇒-1/2= -7/6⇒1/2=7/6

Answer:

Step-by-step explanation:

P=15000

SI=21000-15000

=6000

T=(13-5)yrs

=8yrs

R=100×SI/P×T

R=100×6000/15000×8

=600000/120000

=5%p.a

P= 15,000T= (13-5) 8 yearsR = ?A = 21,000SI = A - P = 21,000 - 15,000 = 6,000R =SI×100/P×T =6,000×100/15,000×8 =6×100/15×8 =2×50/5×4 =1×10/1×2 =10/2 =5R= 5% p.a.Rate of interest should be 5% p.a.

5%=R. please like as best

1 day=120Rs25days=120*25=3000 Rs36 children=3000Rs1 child=3000/36=83.34Rs40 children=83.34*40=3333.34 Rs 100Rs=1 day3333.34Rs=3333.34/100=33 days

3600 revolution in 3 minutes

No: of revolution in 3 min=20*60*3=3600Linear distance covered during 1 revolution=2π*35=220 cmTherefore linear distance covered in 3600 revolution=220*3600=792000cm=7.92km

If x<1, 1/x > 1 (Reciprocals' sign get inversed)Therefore, Sum of x and 1/x equals to a number greater than one.

If x>1, 1/x < 1 Sum of x and 1/x equal to a number greater than 1.If x>-1, 1/x < -1Therefore, sum of x and 1/x is less than -1.If x< -1, 1/x > -1Therefore the sum of x and 1/x equals to a number less than -1.

But the range of cosine is between -1 and +1.According to the above obtained results, the range of cosine does not satisfy the given expression x + (1/x).Therefore, it is impossible for cos a to equal x + (1/x).

6x² - 7x + 2 = 0

Divide by 6 through:

x² - 7/6 x + 1/3 = 0

Subtract 1/3 from both sides:

x² - 7/6 x = - 1/3

Add (b/2)² to both sides:

x² - 7/6 x + (7/12)² = - 1/3 + (7/12)²

Complete the square:

(x - 7/12)² = 1/144

Square root both sides:

x - 7/12 = ±√1/144

x - 7/12 = ±1/12

x = 1/12 + 7/12 or x = - 1/12 + 7/12

x = 2/3 or 1/2

Answer: It has 2 real roots at x = 2/3 and x = 1/2

48000 = 40000(1+r/100)^2 ( The formula is a(1+r/100)^n

(1+r/100)^2 = 484/400

(1+r/100)^2 = (22/20)^2

1 + r/100 = 22/20

r/100 = 22/20 - 1

= 1/10

r = 100/10

= 10.

The rate of growth per annum = 10%.

a) y = 2xb) 3x + 4y = 24c) (i) 3x - 2y -2 = 0 (ii) 2x + 3y -23 = 0

this is only in example

can u explain me how this answer came

x-1/x is the correct answer of the given question is

X square -1/X. is the correct answer

The given relations are

l – 5m + 3n = 0⇒l = 5m – 3n……(1)

and 7l^2+ 5m^2– 3n^2= 0 ……(2)

Putting the value of l from (1) in (2), we get

7(5m – 3n)^2+ 5m^2– 3n^2= 0

or, 180m^2– 210mn + 60n^2= 0

or, (2m – n)(3m – 2n) = 0

∴m/n = 1/2 or 2/3

whenm/n = 1/2 i.e. n = 2m

∴l = 5m – 3n = –m or1/m = –1

Hence, we have l/–1 = m/1 = n/2 = √ (l^2+ m^2+ n^2) /√ {(–1)^2+ l^2+ 22} = 1/√6

So, direction cosines of one line are –1/√6,1/√6,2/√6

Again whenm/n = 2/3 or n = 3m/2

∴l = 5m – 3.3m/2 = m/2or 1/m = 1/2

Thus, m/n = 2/3and l/m = 1/2giving l/1 = m/2 = n/3 = 1/√1^2+ 2^2+ 3^2= 1/√14

The direction cosines of the other line are1/√14, 2/√14, 3/√14.

Thanku so much

I have a small doubt

& by the way thanks a lot 😊

22 /21 is the answer to your question I hope that my answer helped u in doing ur work

22/21 is the right answer

plz like my answer and accepted as best plz

1 2 3 4 5 6 7 8 98.1,8.2 ,8.3 ,8.5 ,8.6 ,8.7,8.8 answer is ^

Steps:

1.First, we draw a line OA of length 1

2.Now, we draw a perpendicular of length 1 on point A as AB

3.From, Pythagoras Theorem, OB =√2

4.Now, take an arc of length OB, and draw it on the number line which meets as E.

So, at E, we can represent √2 as shown in the figure.

multiplying by 100000, we get

= 12365/100000

= 2473/20000

Let parking charge of car be x and parking charge of scooter be y

Then,15x + 7y = 89....... (1)

10 y = 56y = 56/10 = 28/5.....(2)

Put value of y in eq(1), we get15x + 7*28/5 = 8975x = 445 - 196x = 249/75 = 3.32

y = 28/5 = 5.6

Parking charge of car = Rs 3.32Parking charge of scooter = Rs 5.6

Let the parking charge for car be x and scooter be y15x + 7y = 89........(1)10x + 3y = 56........(2)(1)×2;30x + 14y = 178......(3)(2)×3;30x + 9y = 168........(4)(3)-(4);5y = 10y=Rs 2then x =Rs 5

55℅are used45% are left45 /100×X=700X=70000/45X=2000

1200 is monthly income

55% are used45% are left.45/100×X=700X=70000/45X=2000

20x/100 ; 30x/100; 15x/100; x - (20x/100 + 30x/100 +15x/100) = 7 0 0; 100x - 65x = 7 0000; 35x = 7 0000; x= 7 0000/35=2000; 2 x 12 x 1000=24 × 1000=24000

24000 is the correct answer

20x/100; 30x/100; 15x/100;x-(20x/100+30x/100+15x/100) =700;100x-65x=70000;x=70000/35=2000;1000=24×1000=24000

Let the fixed charge=₹xLet charges per km=₹y

x+6y=58x+10y=90

Subtracting 2nd equation from first,-4y=-32y=8x=10

Therefore, the fixed charge=₹10The charges per km=₹8

2500630 produce in 365 day