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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
by selling a bicycle for rupees1638 ishita losses 9%at what price should she sell it to make profit of 15%? |
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Answer» please like my answer if you find it useful |
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| 2. |
The angles of a quadrilateral are in the ratio 35:9313. Find the men of eachangle of the quadrilateral |
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Answer» 3x+5×+9×+13×=36030×=360×=360/30=123×12=365×12=609×12=10813×12=156 |
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| 3. |
4. 40% of the population of a town are men and 35%are women. What is the percentage of children?12 |
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Answer» total percentage is 100% men Are 40% women are 35%children are 100% - (40% + 35%) =100% - 75% =25% the percentage of children are 25% the percentage of children are 25% total 100%women =35%men=%100%_(35%+40%)100%_75%=25% answer |
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| 4. |
Aanors income increased by 20% and then decreased by 20%. What is the total percentageManoj's income? |
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Answer» Let manoj income is X Increased income= X+(20X/100)=6X/5 Now decreased income = 6X/5 - (20/100)6X/5 =(6X/5)[1-1/5] =24X/25 Change in income = |(24X/25)-X|=X/25 % change=(X/25)*100=4X% 4% of decrease write |
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| 5. |
Der is tirst increased by 10% and then decreased by 10%, then the numbera) Remains the sameb) Increased by 1%c) Decreased by 1%d) Increased by 0.1% |
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Answer» remains the same( increase 10° & decreased 10/° decrease by 1℅ is correct answer |
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| 6. |
800000/4500 |
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Answer» 800000÷4500=177.777778 is the correct answer. 177.7778 is the correct answer of the given question 177.777778 is the correct answer 800000/4500Thus, the correct answer is=177.777778 177.7778 is the correct answer of the given question 800000/4500=177.777778 is the right answer 177.777777778 is the only answer |
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| 7. |
137. If the height of a cylinder is in-creased by 15% and the radiusof its base is decreased by 10%then the percentage change inits curved surface area is :(a) 2.5% increased(b) 3.5% increased(c) 2.5% decreased(d) 3.5% decreased |
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Answer» 3.5℅ Increase in height = 15%=3/20=3/20 Decrease in base radius = 10%=1/10Required % increase in area =7/200×100=3.5% |
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| 8. |
1500 families were surveyed and following data was recorded about their maids ahomesType of maidsVumberof familiesOnly part timeOnly full time860370250A family is selected at random. Find the probability that the family selected has()Both ypes of maids(i)Part time maids (aipNo maids(ii) Part time maids(iii)No maids |
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Answer» total number of family=15001)250/1500=25/150=1/62)860/1500=86/150=43/753)(1500-250-370-860)/1500 =20/1500=1/75 |
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| 9. |
Manguram hired 35 men to reap his field,it took them 8 days. How many days willbe required by 10 men to reap it?12. |
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Answer» Total man x days = 35*8= 280now 280= 10 men x days= 28 days |
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| 10. |
e WIR20 days,2. Udit can complete his woin eight days?(a) Howplete his work in 10 days. What amount of work will be comple(b) WH |
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Answer» Work done in 10 days= 10/10 Work done in 8 days= 8/10 = 4/5 ∴ work done in 8 days is 4/5 |
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| 11. |
the second boy?25. A labourer is paid 114 for 4 days work. How much will he be paid for 30 days work? If he took 4 daysoff in a month of 30 days, how much should he be paid for that month?Ratio Pronortion And Unitary Method |
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Answer» 4 days=rs1141 day=114/4=28.5rsHe worked for 30-4 days=26daysSo,26 day=26*28.5=rs741 4 days = 114 rs1 day = 114/4 = 28.5 rs No of days he worked = 30 – 4 = 26 days= 26 * 28.5= 741 rs Answer = 741 rs 741 is the best answer |
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| 12. |
A and B under took to do a work for R 4500. Aalone can do it in 8 days and B alWith the help of C they finished the work in 4days. Then C's share of money isA) 2250c) 750one in 12 days.B) 1500D) 375 |
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Answer» thank you |
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| 13. |
1 5. Solve each of the following quaequations by factorvation(1) *-*-babb vaba |
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| 14. |
(a) Explain SCSI interface of Hard Disk. |
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Answer» A small computer systems interface (SCSI) is a standard interface for connecting peripheral devices to a PC. SCSI is used to increase performance, deliver faster data transfer transmission and provide larger expansion for devices such as CD-ROM drives, scanners, DVD drives and CD writers. |
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| 15. |
An artificial satellite is moving in a circular orbit of radipeed if it takes 24 hours to revolve around the earth. |
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Answer» Circumference of circular planet= 2*pi*radiius=2*(22/7)*42250 km=265571.43 km Speed= Distance/timeSpeed= 265571.43/24Speed= 11065.48 km/hr |
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| 16. |
A bike is sold at the loss of 10%. What is the selling price of the bike if it was bought for Rs. 24990? |
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| 17. |
the printed price of a book is rs 250. a shopkeeper sells 3 books for rs 697.50 after allowing a discount at a certain rate.find the rate of discount. |
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| 18. |
Two adjecent angle of parallelogram are 3x-4 degree and 3x+16 degree. Find the measure of its all sides |
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Answer» Adjacent angle in parallelogram have sum 180°So,3x - 4 + 3x + 16 = 180°6x + 12 = 180°6x = 180° - 12° = 168°x = 168°/6 = 28° So, 3x - 4 = 80, so two opposite angles are 80°.3x + 16 = 100, and two opposite angle are 100°. Given information is insufficient to find sides |
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| 19. |
Dadupie4COPILO.The number of sheets of paper available for making books is 65,000. Each sheet makenpages of a book. Each book contains 250 pages. How many books can be made from thepaper available? |
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Answer» 10 divided into 250. =25ans |
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| 20. |
The cost of a motorcycle is 49,137 and that of a car is * 2,15,000. How much more does the carcost than the motorcycle ? |
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Answer» Cost of motorcycle = Rs. 49,137Cost of car = Rs. 2,15,000 So cost of car more than the motorcycle is Rs. 2,15,000 - Rs. 49,137= Rs. 1,65,863 |
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| 21. |
9. A motorcycle costs 68925. How much will 567 motorcycles costwill be save ir |
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Answer» Given:cost price=Rs 68925cos price of 567 cycles= 567×68925=Rs 39080475 |
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| 22. |
A bike originally cost52,500. Its value has decreased by 12%. What is its value now? |
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Answer» now the value is 46,200. as 12% of 52500 = 6300 and 52500-6300 = 46200 |
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| 23. |
Area of the rectangle formed by y = -2,x=3y=3&x=5 is |
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Answer» the best answer is the area of a rectangle is 15 |
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| 24. |
25 square each of perimeter 8cm are place adjecent t each other to form a rectangle of length 50cm What is the area of rectangle formed |
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Answer» 25 squares are placed adjacent to each otherLet side od Square is sGiven Perimeter of Square = 8cm4*side = 8side = 2cm Reactangle length = 50cm, Breadth = 2 cmArea of Reactangle = length * breadth = 50*2 = 100 cm^2 |
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| 25. |
7. Two wires of length 42 cm are bent to form a square and a rectangle. The breadth of the rectangle formedis 5 cm. Which of the two figures, square and rectangle will have a greater area and by how much? |
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Answer» Please hit the like button if this helped you |
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| 26. |
ABCD is a rectangle formed by the pointsA(-1,-I). B(R and S are the mid-points of AB, BC, CD and DA respectively. Is the quadrilateralPQRS a square? a rectangle? or a rhombus? Justify your answer8.1.4), C(5' 4) and D(5,1). RO. |
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| 27. |
prove that parallelogram formed in circle is a rectangle. |
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| 28. |
oneA wire in the form of a rectangle 18.7 cm longand 14.3 cm wide is reshaped and a circle isformed. Find the radius of the circle hence formed.show3.5 mwer |
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| 29. |
Example 2 Romila went to a stationery shop and purchased 2 perfor ? 9.Her friend Sonali saw the new variety of pencils and erasers with Ronmshe also bought 4 pencils and 6 erasers of the same kind fort 18. Resituation algebraically and graphically.present this |
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Answer» Let the cost of one pencil = Rs. xLet the cost of one eraser = Rs. y Romila purchases 2 pencils and 3 erasers for Rs. 9 Cost of 2 pencils = 2xCost of 3 erasers = 3yTotal Cost = Rs. 9 So, we have: 2x + 3y = 9 ---(1) Sonali purchases 4 pencils and 6 erasers for Rs 18. Cost of 4 pencils = 4xCost of 6 erasers = 6y Total Cost = 18 So, we have: 4x + 6y = 18So, 2(2x + 3y) = 18So,2x + 3y = 9----(2) |
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| 30. |
(iv) 70, 60, 50, 40, . . .t1=?t2=?t3=?a=?d=? |
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| 31. |
If the radius of a circle be reduced by 50% its area is reduced by: |
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| 32. |
v reduced the price of an article by 5%. By how much% a retailer must increase the new price so as10. A company reduced the price of an artito sell the aritcle at the old price? |
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Answer» hi it is not hard i will send in within 5 hours Let original price be "x":After reduction: 0.95x------Solve:k(0.95x) = x0.95k = 1k = 1/0.95 = 1.0526-------Ans: Increase price by 5.26%============================= Step-by-step explanation: let initial price was 100 reduced price is 95. so.. we need to increase ₹5 to sell it at initial price and we can calculate the percentage value of ₹5 on the basis of 95.. it is.. 5×100/95=5.26% the correct answer is 5.26% suppose the original price is = Xafter reduction : 0.95X solutionk {0.95x}= X0.95k= 1k = 1/0.95 = 1.0526 so answer - increase price by 5.26% |
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| 33. |
motorcycle originally cost40,000. Its cost has decreasedoriginal price.An alloyof copp11. The price of a garment has been reduced by306. Find its original price15% inhas been reduced by 15% in a sale toloatic was stretched |
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Answer» Let the original price of the garment = Rs x Reduced percentage = d = 15 % Selling price of the garment = S.P = Rs 306 Selling price = original price × ( 100 - d ) / 100 Original price = ( selling price × 100 ) / ( 100 - d ) x = (306 × 100 ) / ( 100 - 15 ) x = ( 306 × 100 ) / 85 x = 360 Therefore original price of the garment = x = Rs 360 |
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| 34. |
3 दल! 1 lfi‘ R, 4के. ot e G T R T B B |
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Answer» This problem can be solved by rationalising the terms (1/2+root 5 x 2 - root 5 /2-root 5) + (1/root 5+root 6 x root 5 -root6/root 5 -root 6) + (1/root6 + root 7 x root 6 -root 7/root 6- root 7) + (1/root7 +root8 x root 7 - root 8 /root 7 - root 8) + (1/root 8 + root9 x root 8 - root 9 /root 8 - root 9) + = (2 - root 5/ -1 ) + ( root 5 - root 6 / -1) + (root 6 - root 7 / -1 ) + ( root 7 - root 8 / -1 ) + (root 8 - root 9/-1) = - 2 + root 5 - root 5 + root6 - root 6 + root 7 - root 7 + root 8 - root 8 + root 9 = - 2 + root 9 = - 2 + 3 = 1 |
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| 35. |
ON AREAIf the length of a rectangle is reduced by 5 units and its breadth is!increased by 2 units then the area of the rectangle is reduced by 80 squnits. However, if we increase its length by 10 units and decrease |
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Answer» please upload full question |
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| 36. |
the area of rectangle get reduced by 8unit if its length is reduced by 6unit and breadth is increased by 4unit if length is increase by 3unit and breadth by 5unit the area is increased by 119sq units find the di mentions of the rectangle |
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Answer» a-8 = (l-6)(b+4)a+119 = (l+3)(b+5)a=lba - 8 = lb +4l -6b -24 => 4l-6b = 16a+119 = lb + 5l +3b +15 => (5l +3b =104)x214l = 224l = 16b = 8 |
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| 37. |
The area of a rectangle remains the same if the length is increased by 7 metres and the breadth is decreased by 3 metres. The area remainsunaffected i the length is decreased by 7 meters and breadth is increased by 5 metres. Find the dimensions of the rectangle(22, 1 |
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| 38. |
The perimeter of a rectangular field is 84 metres. If the length of the field is increased by 2 metres andits breadth is decreased by 4 metres, the area is decreased by 32 sq m. Find the length and breadth of threctangular field.12. |
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Answer» suppose length and breadth is l and bso 2(l+b)=84so l+b=42 -> l=42-bnow l is increased by 2m and breadth is decreased by 4m, area is decreased by 32so (l+2)(b-4)=lb-32lb+2b-4l-8=(42-b)b-32(42-b)b+2b-4(42-b)=42b-b^2-2442b-b^2+2b-168+4b=42b-b^2-246b=144b=24so l=18b^2-48b+208=0 |
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| 39. |
- One side of a square is increased by 3 metresand other side is reduced by 3 metres. Theperimeter of the rectangle formed is 36 metres,find the side of the square. |
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| 40. |
.In the given figure, the boundarof shaded region consists of fouisemicircular arcs two smaller beingequal. If diameter of the largest is 14cm and that of the smallest is 3.5 cmcalculatc the area of the shaded regiorn(Use Ď = 22] A:06-62 dCBSE 2010] |
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Answer» Diameter of biggest semi circle = 14cm.Diameter to two small semi circle = 3.5cm.Diameter of other semi circle = 14-(2×3.5) = 7cm.Area of biggest semi circle = 1/2×(pi)×7^2 cm^2.Area of two small semi circle = (pi)×1.75^2 cm^2.Area of other semi circle = 1/2×(pi)×3.5^2 cm^2.Area of shaded region = (pi)×(24.5-3.0625+12.25) = (pi)×27.5625 cm^2= 86.59 cm^2. |
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| 41. |
13. The length of a rope is decreased by 12-%. What is the new, length if it was 150 metres? |
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Answer» where is the answere what is the meaning of candidates |
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| 42. |
3.Find in square metres, the area of a square of side 16.5 dam |
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| 43. |
The length of a rope is decreased by 12 1/2%. What is the new length if it was 150 metres? |
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| 44. |
: A table-top measures 3 m by 2 m 60 cm. What is its area in square metres? |
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Answer» Area = length x widthlength = 3m , width = 2.60mArea = 3m x 2.60 m = 7.80 m |
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| 45. |
3. The top of a table measures 2 m 25 cm by 1 m 20 cm. Find its area in square metres. |
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| 46. |
3.The length of a plot is four times its breadih. A playgrourdl measuring1200) square metres occupies a third of the total area of the plot. Whatis the length of the plol, in metres?a) 20(c) 60(Bank P.O. Exam, 1940)(b) 30(d) none of these |
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Answer» Area of the plot = (3 x 1200) m^2= 3600 m^2 Let breadth = y metersThen Length = 4y meters,Now area = 4y x y = 3600 m^2⇒ y^2= 900 m^2⇒ y = 30 m ∴ Length of plot = 4y m= (4 x 30) m=120 m..hence option d |
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| 47. |
09respectively arcs of two concentric circles of radii |
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Answer» Like if you find it useful |
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| 48. |
Find the circumference of a semicircular shape on a line of length 10 cm. |
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| 49. |
13. Three semicircdles each of diameter 3 cm, a circle of diameter 4.5 cm and a semicircle of radius 4.5 cm are drawn inthe given figure. Find the area of the shaded region. |
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Answer» Area of shaded region = Area of larger semicircle - Area of circle - 2(Area of small semicircle) + Area of small semicircle= Area of larger semicircle - Area of circle - Area of small semicircle= [π(4.5 cm)²/2] - π(4.5/2 cm)² - [π(3/2 cm)²/2]= π[(4.5)²/2 - (4.5/2)² - (3/2)²/2] cm²= 12.37 cm² Thanks for the answer |
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| 50. |
&. If the perimeter of a semicircular protractor of Nitish is 36 cm, find its diameter. |
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Answer» wrong answer perimeter of semicircle =πd/2=36d=36*2/π=72/3.14=22.9cm |
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