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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Pactorise each of the followii) 8 a^3 + b^3 + 12 a^2 b + 6 ab^2 |
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| 2. |
2. Express the followithe following complex numbers in polar form[NCERT](İİ.一1-1--(0)-1+ i[NCERT Exemplar)coS+ i sin |
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Answer» please solve any other method |
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| 3. |
The population of a town has increased from 60000 to 65000, what is the increased percentage |
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Answer» Initial Population=60000Final Population=65000 Population increased=65000-60000=5000 Percentage increase=(5000/60000)*100%=50/6%=8.33% |
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| 4. |
he following is not35. In the given figure, if AB = AC then which of the followitrue ?(a) ABEA = ACFA(c) ADBC is equilateral(b) ADBC is isosceles(d) NOTA |
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Answer» yes it is true it is an equilateral triangle ∆ DBC is not a equilateral because angle FDC=180° angleFDB+BDC=180 20+x =180 x=180-20 x=160° in equilateral triangle each angle should be 60° hence it is not equilateral ∆ DBC is not a equilateral and the angle of FDC is 180 |
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| 5. |
Ex. Solve the followi(1) m + 3 = 5 |
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Answer» m +3=5 m=5-3m=2 is the answer by simple method no need to do by comp. method m+3=5m=5-3m=2 is the answer m=2 is the answer of this m+3=5m=5-3m=2this is answer for your answer 2 is the answer for this question given m=2 your answer is 2 m+3= 5m=3-2m = 2the value of m is 2 m+3=5=>m=5-3 [Transposing 3 to right side]=>m=2 Answer M+3=5 THEN, M=5-3M=2Hence, the value of M is equal to 2 |
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| 6. |
WEMO6.1TA23552412341MN57 03-G3 x 4337 57 -46153475 x7345R5.2A 23.56-87-9.7875+43-345-78 -c /45+56+67476-7L108 x6 =672 x 7 =7632 x 5 =6 547 65425 43 4M5623 x 7 = |
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Answer» The real answer is 2479 |
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| 7. |
1. Write the number names for the followi(a) 7,86,143 |
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Answer» 7,86,143Seven Lakh Eighty-six Thousand One Hundred and Forty-three. the correct answer of 7,86,143 is- seven lakhs Eighty six thousand one-hundred forty Three |
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| 8. |
2 find the discriminant of each of the followi2x2 + 4x +5= 0 |
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Answer» discriminant -4*4-4*2*5 =-24 |
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| 9. |
What number when increased by25% becomes 150 ? |
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| 10. |
The government plans to develop a new industrialzone in an unused portion of land in a city.The shaded portion of the map shown on theright, indicates the area of the new industrial zone.Find the area of the new industrial zone.KKambanStreetNe14 km 1.0 kmIndustrialZone |
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Answer» green color on a map indicates plains |
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| 11. |
An ink container of cylindrical shape isfilled with ink upto 91%.Ballpen refills oflength 12cm and inner diameter 2mm arefilled upto 84%.If the height and the radiusof the ink container are 14cm and 6cmrespectively. Find the number of refills thatcan be filled with this ink. |
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Answer» Given:Length of the refill = 12 cmInner diameter of the refill = 2 mm∴ Inner radius of refill =22mm = 1 mm = 0.1 cmNow,Volume of one refill =πr2h=227×(0.1)2×12= 0.377 cm3Because the refills are filled up to 84%, the volume of the ink filled in each refill is:84100×0.377cm3= 0.3166 cm3Also,Height of the container = 14 cmRadius of the container = 6 cmNow,Volume of the container =πr2h=227×62×14= 1584 cm3Because the container is filled with ink up to 91%, the volume of the ink filled in the container is:91100×1584 = 1441.44 cm3Thus, we have:Number of refills that can be filled =VolumeoftheinkfilledinthecontainerVolumeoftheinkfilledineachrefill=1441.44.3166 = 4552.87 Hence, the number of refills that can be filled is 4552. volume ink in container=22/7×6×6x14×91/100=1440.1296; volume of ink one refill=22/7×0.1×0.1×12×84/100=0.316512cm,; number of refill can be filled =volume of ink in container/ vol. of ink in one refill=1440.1296/0.316512=4550.refill can be filled are =4550 |
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| 12. |
The time for half-life period of a certain reaction, A--> Products is 1 h. When the initialconcentration of the reactant A is 2.0 mol L-1, how much time does it take for itsconcentration to come from 0.50 to 0.25 mol L-1, if it is a zero order reaction? [AIEEE 2010]a. 4 hc. 0.25 hb. 0.5 hd. 1 h |
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| 13. |
The sum of the digits of a 2-digit number is 12. The number is 6 times the units der Find the met |
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Answer» Let the unit digit be x then ten digit = (12-x) Then,Number = 10*(12 - x) + x= 120 - 9x As per given condition120 - 9x = 6x9x + 6x = 12015x = 120x = 120/15 = 8 Therefore,Number = 120 - 9*8= 120 - 72= 48 |
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| 14. |
(situation) & Frog is there in a 12 mder well. The Frog want 10sumes out of well. Every timehe dumps 3m and falls backby Im |
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| 15. |
Find the argument of the complex no. 3- i |
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Answer» the argument of complex number -x-iy is given as ∅ =-π +tan-¹(y/x) = -π+tan-¹(1/√3) = -π+π/6 = -5π/6. |
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| 16. |
6. Find the argument of the complex no.-3 i |
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Answer» the argument of this complex number is ∅ = -π+tan-¹(y/x) = -π+tan-¹(1/√3) = -π+π/6 = -5π/6 |
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| 17. |
12, if the price of sugar rises by25%, by how much percent should one reduce his/herconsumption so that his/her expenditure on sugar may remain the same |
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Answer» Let original price be Rs.100. Then, increased price = Rs.125 Therefore, Reduction in consumption =(125−100/125*100)=(25/125×100)% = 20% |
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| 18. |
समर्थ कुल |5+2 +5-8+6 | 6+5 +5-8+6-8 = |
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Answer» A = 6+4-8+3+2 = 15-8 = 7B = 2+9-1-8+3 = 5+9-9 = 5C = 3+8-1-8+2 = 13-9 = 4D = 5+5-8+6-4 = 16-12 = 4E = 6+5-8+6-8 = 17-16 = 1 A . 6+4-8+3+2=7B. 2+9-1-8+3=5C. 3+8-1-8+2=4D. 5+5-8+6-4=4E. 6+5-8+6-8=1 |
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| 19. |
12. If the letters of the word "ALGORITHM" are arranged at random in a row, what is theprobability that the letters G, O and R must remain together? |
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Answer» Required probability =Number of favorable outcomesTotal number of outcomesNumber of favorable outcomesTotal number of outcomes Step 1: Given word ALGORITHM Number of letters in the word =9 The word is arranged randomly. ∴∴Total number of outcomes n(S)=9! Given GOR have to remain together Thereby considering GOR as a single letter ∴∴No of letter=7 Number of favorable outcomes n(E) =7! Step 2: ∴∴Required probability =n(E)/n(S) ⇒7!/9!⇒ 1/9×8 ⇒172 |
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| 20. |
40<θ<π,then θ =1)2'4' 4 '6' 68' 8 8 8 '3' 34) |
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| 21. |
. Two new cars were valued at 23 96 000 and 25 96 000 respectively. After 6 months, themarket value of each fell by 96 000. Find the ratio of their values (i) in the beginning and(1i) 6 months later. |
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| 22. |
Ifa : b-5:7and b : cIfa : b-4:5and b : clfx : у 2.7and y : z14:15,find a : c12:18 find a : c9:11find x : y : z |
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Answer» 1) a:b = 5:7=10:14 and b:c = 14:15 so a :c = 10:15 =2:3 2) a:b = 4:5 = 12:15 and b:c = 12:18 so a:c =( 12/15)*(12/18) = 8:15. 3) x:y = 2:7 = 18:63 and y:z = 9:11 =63:77so x:y:z = 18:63:77 samajh mai nhi aya plese detail |
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| 23. |
/6Find a, + b. ifa-bt 10and ab |
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| 24. |
Ifa= } - v. find the value of (1-) |
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Answer» -1 is correct answer. |
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| 25. |
Question mumbers 1 to 6 carry 1 mark each.1. Find thre value of a, or which point Pis the mid-point of the line segment joining the pointsQ(-5,4) and R (-1,0). |
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Answer» Coordinate of mid point (x,y)x = (x1 +x2)/2y =(y1 +y2)/2A/qx =(-5 + (-1))/2 = -3 ⇒a/3 = -3⇒a =-9y = (4+0)/2 = 2coordinate of mid point = (-3,2)so, a= -9 Like my answer if you find it useful! |
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| 26. |
1. Find the ratio of each of the following in 4simplest form:(i) 30 minutes to 2 hours(ii) 1.2 kg to 60 g(ii) 4 months to 1 year 6 months(iv) 75 paise to 1.2534 |
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Answer» thanks |
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| 27. |
1. At the rate of 9%p.a. simple interest, a sum of 5,400will earn how much interest in 1 year 6 months? |
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Answer» The right answer is is 729 he will earn 729 rupees interest.please like my answer 729 is the following question answer. 729 is the answer of the following 729****,,,**,,7,,,*************, the right answer is 729 |
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| 28. |
İIİ J 30, 26, 909 |
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| 29. |
The ratio of the volume of two spheres is 8:27. If r and R are the radii of spheres respectively then find (R-r)/r |
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| 30. |
yrite down a pair of integersSum is -6 |
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Answer» –8+2 ok fine ok fine -8,2 is the correct answer of the given question |
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| 31. |
(iii) sin”30°—2cos’ 60° + 3tan* 45° |
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Answer» sin30° = 1/2cos60°= 1/2tan45°= 11/4-2(1/8)+3=3 is the answer to this question |
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| 32. |
^{56} \mathrm{P}_{r+6} :^{54} \mathrm{P}_{r+3}=30800 : 1, \text { find } r |
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| 33. |
Given that f: R → R defined by f(x) = 3x-2 and g : R → R defined by g(r) =rs. Find(gof) (x).1. |
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Answer» what is power of x in g(x) x power 5 thank you |
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| 34. |
A vector r is inclined at equal angles to the three axes. If the magnitude of r is 2root3, find r. |
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| 35. |
Find the inverse of f :R -R definerd by f(x)r 13 |
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Answer» Can you help with these questions ? ask one by one.. again in the community , and not in the answer section. |
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| 36. |
Oerle conloSolutionExamples |
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Answer» d)47/3 divide7/447/3*4/7188/21 8+20/21 ansh)88/5 divide 11/488/5*4/118/5*432/56+2/5 ans if u satisfied with the ans then like or cmmt ✌️ 47/3 * 7/447*4/3*7 =178/21 47/3*7/447*4/7=178/21 |
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| 37. |
19. For what value of k does (k-12) x + 2(k-12) x + 2 0 have equal roots? |
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Answer» Equal roots exist if DIscriminant = 0=> [2(k-12)]^2 - 4(k-12)(2) = 0=> 4*( k-12)^2 - 8( k -12) = 0=> 4k^2 + 576 - 96k - 8k + 96 = 0=> 4k^2 - 104k + 672 = 0=> k^2 - 26k + 168 = 0=> k^2 - 12k - 14k + 168 = 0=> k(k-12) - 14(k - 12) = 0=> k = 12, 14 |
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| 38. |
angle of sides 4 cm, 5 cm and 6 cem and then a triangle similar to it whornof Pseps of Cones 4 cm, 5 cm and 6 cm and then a triangle similar to it whose Jt ofMATHEMATsides areof the corresponding sides of the first triangle.3. ConstruntJoin PO andJaking M as |
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| 39. |
11. Find the difference between simple interest and compound interest on 6400for 2 years at 6 14% p. a. compounded annually. |
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| 40. |
Tour, which is divisible by 10, 24 athat least number must be added to 5555 to make the sum &to 3555 to make the sum a perfect square?find the perfect square and its square root.The students of a class afransaranged a picnic. Each student contributed as manyes as the number of students in class. If the total conrupees as the neass. If the total contribution is Rs 5041, findthe strength of the class.decimal number is multiplied by itself. If the product is 4A decimtself. If the product is 251953.8025. Find the10.number. |
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Answer» 2519523.8025 is the square of the number so √ this no will give us the number which is 1587.3007914 |
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| 41. |
CoN13 |
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Answer» Post question in English |
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| 42. |
(Simplify)32CON |
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Answer» 32/8=4is the right answer 4 is the right answer 32/8=4so 4 is the answer 32 / 4 = 8 32/8 = 4 so 4 is correct answer for this question 4 is the right answer right answer is the 4 32/8=4so 4 is correct answer for this question 4 is the answer of this question so 4 is the right answer |
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| 43. |
am conat-the |
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Answer» Thanks |
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| 44. |
he maximCon aine |
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Answer» To find the maximum capacity of the container that can measure the diesel of three tankers we have to take their HCF Factors of 403 = 1, 13, 31, 403 Factors of 434 = 1, 2, 7, 14, 31, 62, 217, 434 Factors of 465 = 1, 3, 5, 15, 31, 93, 155, 465 Highest common factor of 403, 434 and 465 is 31. Hence the maximum capacity of the container should be 31 litres. |
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| 45. |
5¡1a) A sum ofă25,000 accumulated to? 55,000 after 12 years. Find the ratesimple interest p.a., which was effective in this situation. |
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Answer» Simple interest = PTR/100P= 25000Amount = 55000Rate= ?Simple interest= 30000Now30,000*100/25000*12= RR= 10 percentagePlease like the solution 👍 ✔️ Tysm |
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| 46. |
12 x 2-con |
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Answer» the answer will be 31 1/2 answer for this question is equal to 31.5 |
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| 47. |
5. (a) A sum of25,000 accumulated to? 55,000 after 12 years. Find the ratesimple interest p.a., which was effective in this situation |
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Answer» Interest=55000-25000= 30000Time= 12yearAmount= 55000Principal= 25000SI= PRT/10030,000*100/25000*12= R= 10 percentagePlease like the solution 👍 ✔️👍And check previous Answer as well and like them |
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| 48. |
An5. (a) A sum of? 25,000 accumulated to R 55,000 after 12 years. Find the rate dsimple interest p.a., which was effective in this situation. |
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Answer» Simple interest = PTR/100P= 25000Amount = 55000Rate= ?Simple interest= 30000Now30,000*100/25000*12= RR= 10 percentagePlease like the solution 👍 ✔️ |
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| 49. |
7.The price of a scooter depreciates by 3,000 in firstyear, and thereafter at the rate of 1,200 per year. Ifthe original price of the scooter was 48,000, find theprice of the scooter after 6 years. |
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Answer» 48000-3000-(5×1200) =39000 |
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| 50. |
Payal took loan of Rs. 12,000 for parlour from a nationalized bank. Howmuch amount she will repay after 2 years 6 months at annual rate of 8%When interest is accumulated annually100% when |
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Answer» interest=p×r×t/1002years 6months = 30monthsinterest = 8 × 12000 × 30/100it will cancelled8×120 × 30= 1460×30=43800 |
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