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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Exam47. 18, 23. 21.26. 2SSC Stenographer Exam 2014(a) 23(b) 31(c) 33(d) 2448. 7. 10, 8, 11, 9, 12, ?, ?ISSC (10 + 2) Level Exam 2012!(a) 7 11 (b) 10.13(c) 2. 15 (d) 13, 14Exams |
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Answer» 24 This is a double series.The numbers in odd positions increase in difference of 3. The numbers in even positions increase in difference of 3.18 + 3 = 2123 + 3 = 26 10, 13 This is also two different series.The numbers in odd positions differ by 1. The numbers in even positions differ by 1.7 + 1 = 810 + 1 = 11 |
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| 2. |
﹂g/ A point moves such that its distance from the point (3,4) is three times its d(0rom the point (-3,-4). Find the locus of that point. |
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| 3. |
the circumference of a circle is 44cm then find the area of its semi circle |
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Answer» Circumference of circle =2 π r = 44cmso π×r=44/2π×r= 22cmr=22cm×7/22r=7cmarea of semi circle=22/7×7×7=154/2= 77cm^2 |
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| 4. |
What is the circumference of the semi circle. |
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Answer» 2πr/2πr will be the answer |
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| 5. |
Find the perimeter and area of a semi-circle of radius 10.5 cm. |
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Answer» Perimeter of semi - circular park=(pi×r)+(2r)=(22/7×10.5)+(2×10.5)=33cm+21cm=54cm |
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16. In the below figure, ABCD is a quadrant of a circle of radius 28 cm and a semi circle BEC isフフdrawn wah BC as diameter. Find the area of the shaded region. [Use |
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Answer» 1 2 |
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| 7. |
The radius of a semi circle is 6.3 cm then its perimeter is? |
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| 8. |
is a diameter of the circle and C, D, E are any three points on the semi-circle, then find theIf ABvalue of ZACDLBED.Ahetween their centres is 4 |
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Answer» AOB is a diameter of the circle, C, E, D are three points on the circle To find:∠ACD +∠BED Construction: Join CO, DO and EO Assume AC = CD = AO Assume DE = EB So inΔACO It is an equilateraltriangle∠ACO = 60° InΔCDO It is an equilateral triangle, hence∠DCO = 60° ∠DOE =∠EOB As∠AOB = 180° So 180° =∠AOC +∠COD +∠DOE +∠EOB And∠AOC =∠COD = 60° And∠DOE =∠EOB Hence 2∠DOE = 180° - 60° - 60° ∠DOE= 30° InΔODE ∠ODE =∠OED (isoscelestriangle) And∠ODE +∠OED +∠DOE = 180° So 2∠ODE = 180° - 30° = 150° So∠ODE = 75° InΔOEB ∠OEB =∠OBE (isosceles triangle) And∠OEB +∠OEB +∠BOE = 180° So 2∠OEB = 180° - 30° = 150° So∠OEB = 75° So∠ACD +∠BED =∠ACO +∠DCO +∠DEO +∠BEO = 60° + 60° + 75° + 75° = 270° |
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| 9. |
6. Find the area of largest triangle that can be inscribed in asemi-circle of radiusr |
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| 10. |
13 cmis isosceles with PQ PR 7.5 cm and QR -9 cm. The height PS from PoOAPQRis 6 cm. Find the area ofΔPQR. What will be the height from R to PQie.RT? |
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Answer» Base QR is 9 cmheight PS is 6 cmarea of triangle PQR =1/2×base ×height= 1/2 × 9 ×6=9 ×3=27 |
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| 11. |
The area of a circle with centre 'O' is 308 cm2. Find the perimeter of theshaded semi-circle from the following figure.(1),72 cm(3) 108 cm(2) 58 cm(4) 36√2 cm |
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Answer» option (1) is correct. |
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| 12. |
6.) Find the area of largest triangle that can be inscribed in a semi-circle of radius r |
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| 13. |
tan P. cot R का मान ज्ञात करे PAR =PQ 12 cm or PR =13 Cm h EX =8.1 |
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| 14. |
A mirror that is 5ft wide is to be centered on wall that is 21ft longHow far from each end of the wall the mirror's ends should beplaced? |
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Answer» Out of 21ft, 5ft covered.remaining is= 21-5=16ftthus 16ft/2 should be left on each side.Which is 8ft thank you |
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| 15. |
f a rectangle is 5 cm and its diagonal is 13 cmperimeter?30°, APQR and ASQR are isosaelesQR and ZPRQx70QRand ZSRQFig. 8.23OR is sosceles with pr = PB LM is parallel to QB with L on PQ and |
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| 16. |
EXERCISE 10.21. Construct a triangle ABC in which BC7cm, ZB75° and AB + AC-13 cm2. /Construct a triangle ABC in which BC = 8cm, <B = 45° and AB-AC = 3.5 cm3. Construct a triangle PQR in which QR = 6cm, 2 Q-60 and PR-PQ=2cm.,/ |
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| 17. |
(13) PQRS is a rectangle with sides PS = 5 cm andPQ = 12 cm. Find the length of QR, SR and thetwo diagonals PR and QS12 cm |
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| 18. |
24:In two concentric circles with centre O, PQ is thediameter of outer circle and QS is the tangent lineto the inner circle touching it in R and outer circle inS. Find the length of PR, if radii of two circles are13 cm and 8 cm. |
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| 19. |
16. In two concentric circles with centre O, PQis the diameter of outer circle and QS isthe tangent line to the inner circle touchingit in R and outer circle in S. Find the lengthof PR, if radii of two circles are 13 cm and8 cm |
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| 20. |
46. एक वस्तु पर छ्पा हुआ मूल्य 900 रु. है लेकिन एक खुदरा व्यापारीइसको 40% बड़े पर खरीदकर इसे 900 रु. में बेच देता है । खुदरा 5५व्यापारी का प्रतिशत लाभ है -- [SSC-CPO] |
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| 21. |
Pis a mid-point of side AB to aIlgm ABCD. A line through Bparallel to PD meets DC at Qand AD produced at R. Then BRis equal to :АРв(a) BQ(b) BQ(c) 2BQ(d) of these |
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| 22. |
13. A train travelling with uniform speedcrosses two bridges of lengths 300 m and240 m in 21 sand 18 s, respectively. Findthe speed of the train. [SSC CPO 2011] |
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Answer» Let length of the train = L According to the question, L+30021=L+24018L+30021=L+24018 =>L+307=L+2406L+307=L+2406 => 6L + 1800 = 7L + 1680 Therefore, L = 120 m Taking the length of the 2nd bridge into consideration, Speed of train =L+24018=120+24018m/sL+24018=120+24018m/s =36018×185km/h36018×185km/h = 72 km/h |
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| 23. |
V687 what is the degree of08 I 6X2+2% is a polynomthalдаділо и о аmid 2x+ LOр длөфаолота Раб) p (2) Ден наarent's SignatureTeacher's Signature |
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Answer» Q7 |
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| 24. |
EXERCISK 9.1Which or the following Mures lie on the same base and between the sameparallels. In such a case write the common base and the two parallelsAPBNO PCSRSCS0в Р А воCS DCR(vi)(iv)hr same ParallelsNY |
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| 25. |
CISE 5C3.А+ А+ АВА |
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Answer» 5+5+5=15A=5B=1this is right answer |
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| 26. |
c— аa - b- с|c-a(ix)b-cсаa-bа -b- с |
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| 27. |
$28. In trabes um HARE, EP and RP.Tare bisector of LE and CR respectivelyfind the measure of CHAR. |
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Answer» the answer of this question is ८HAR= 90° |
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| 28. |
4. Punctuate the following:() tare you annoyed because they are still refusing to pay you an extra tworupees a month he asked nathu |
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Answer» 'Are you annoyed because they are still refusing to pay you an extra two rupees a month?', he asked Nathu. |
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oftare22. An arithmetic progression consists of 21 terms, the sumterms in the middle is 129 & the last three 237. Find the AP |
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Answer» Given total number of terms in an AP = 21. Given that the sum of three terms in the middle is 129. = > T10 + T11 + T12 = 129 = > a + 9d + a + 10d + a + 11d = 129 = > 3a + 30d = 129 = > a + 10d = 43 ----- (1) ----------------------------------------------------------------------------------------------------------- Given that sum of last three terms is 237. = > T19 + T20 + T21 = 237 = > a + 18d + a + 19d + a + 20d = 237 = > 3a + 57d = 237 = > a + 19d = 79 ----- (2) ---------------------------------------------------------------------------------------------------------------- On solving (1) & (2), we get = > a + 10d = 43 = > a + 19d = 79 --------------------- -9d = -36 d = 4. substitute d = 4 in (1), we get = > a + 10d = 43 = > a + 10(4) = 43 = > a + 40 = 43 = > a = 43 - 40 = > a = 3. Therefore, The first term is 3 and Common difference = 4. The required AP is 3,7,11.... |
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| 30. |
50.3. किसी संख्या के ३, 64 है, तो उस संख्या का आधा| कितना होगा ?(1) 32 (2) 40(3) 80(4) इनमें से कोई नहीं[P.0.1991, CPO 2008] |
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Answer» So4/5*x= 64x= 64*5/4= 16*5= 80 4÷5×x=64x =64×5 ÷4=16 ×5= 80= 80 answer The correct answer is 80 |
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। एक संख्या पहले 20% कम की जाती है। फिर इस कम की हुई संख्या में 20% वृद्धि की जाती ।है। परिणामी संख्या मूल संख्या से 20 कम है, तो मूल संख्या हैं-{) 40)(c) 5()();(d) 000(SSC, 2.11.2014)(a) 2008 |
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Answer» 2 is the right answer |
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| 32. |
.Raju lent 400 to Ajay for 2 yr and 100to Manoj for 4 yr and received from both60 as collective interest. Find the rate ofinterest, simple interest being calculated.[SSC CGL 2008](a) 5%(b) 6%(c) 8%(d) 9% |
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Answer» Let rate is R%. According to the question, [400*2*R/100] + [100*4*R/100] = 60;8R+4R = 60;Hence, R = 5%. Like my answer if you find it useful! |
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| 33. |
a)Draw rough diagrams to illustrate the following:(a) Open curve (b) Closed curve.2. |
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Answer» thanks |
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| 34. |
SALI1. Draw rough diagrams to illustrate the following:(i) Open curve(ii) Closed curve |
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| 35. |
6.A, B, C are any three points in a plane. Join them in pairs. How many linesyou get if-(a) A, B, C are collinear?(b) A, B, C are not collinear? |
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Answer» the answer is abc are collinear 3 is the correct answer add the line segments and diagonals you will get the answer a boy wants to distribute 25 trophy between has two friends Ram and Shyam in such a way that Ram get 5 rupees more than what Sham get how many toffee will it get ramsis five year older than Shyam and Shami strir younger than Mohan age is 30 how old is Mohan A, B, C Are Collinear a) A, B, C are collinear the sentence question the travellers stopped several times to take refreshment 6.(a) One (b) Three The write ans is 1st ka 2 and 2nd ka 3 A,B,C are collinear. a.A,B,C are collinear? a................a...... b is right answer and there are three line form from this points Answer is .a.b.c are collinear A,B,C are collinear ,6 lines A, B, C are collinear collinear , when .3 points joining together,it is known collinear A,B,C ARE NOT COLLINEAR 3 is the correct answer there is only 1(one)line yes a,b,c, is a collinear point The points A, B, C are collinear b is the correct answer a)A,B,C are collinesr a is the option which is correct a.three lines we will get B IS THE CORRECT ANSWER PLEASE LIKE ME EVERYONEBECAUSE I AM NEW I HAVE MOT A SINGLE LIKE OR FOLLOW (a) 1 line(b) 3 lines ans --Aplease like and accepts as best A B and C are Collinear Sir. Hope you could understand sir. Stay safe and Stay Happy.. A, B, C are collinear one and only one 111111111111 (b) this is a correct answer a) 1 line possible if points are collinearb) 0 lines possible if points are non-collinear 6. (a) one (b) three answer (a) A,B,C are collinear (a) we get only one line if all the points are join pair wise then it is collinear as they lies on the same plane a,b,c are collinear is right answer a, B, C are vollinear (b) is the correct answer because collinear means point on same line but if the A-B-C are any point in plane then it can't be a collinear (a) triangle(b) pyarllar line (a) one (b) three (a) A,B,C are collinear (a) A.B.C are collinear 3 Answer is the corret add the line in segments and diagonals you will got the answer b answer because they are not collinear A, B, C, are collinear 3 is correct answerline segment and diagonal get Option (a) A, B, C are collinear b is correct answer and there are three lines |
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| 36. |
Do three collinear points A,B and C form a triangle? |
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Answer» but its answer is six |
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| 37. |
Do three collinear points A, B and C form a triangle ? |
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Answer» no hii can you give me your no. sorry iam student so I cannot give My no. No, it is not possible as three collinear points lies in same line therefore ot contradicts the need of three sides to form a triangle. you're right |
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| 38. |
Two angles with two points in common |
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| 39. |
EXERCISE 11.31. () Given three non collinear points, then the number of circles wlich can bedrawn through these three points are(a) one(b) zero |
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Answer» a) one because choose any three arbitrary points A,B,C and find their circumcentre so we get centrer which is equidistant from all given points that we can draw locus that will be circle. |
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| 40. |
o three collinear points A, B and C form a triangle? |
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| 41. |
What will be the locus of three non-collinear points A, B and C? Justiftanswer. |
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| 42. |
In the given figure A, B, C andD, E, F are two sets of collinearpoints. Prove that AD |CF.2 |
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Answer» In this figure, ABED is a cyclic quadrilateral. ∠DAB = ∠ BED ( as opposite angles of a cyclic quadrilateral are supplementary) ...(1) BCFE is also a cyclic Quad. ∴ ∠BCF = ∠ BEF(as opposite angles of a cyclic quadrilateral are supplementary)…(2) when we add these angles ∠DAB + ∠ BED + ∠BCF + ∠ BEF = 360°…(1) ∠BED + ∠ BEF = 180° ⇒ ∠ DAB + ∠ BCF = 180° But they are co-interior angles and if co-interior angles sum up to 180° they are parallel. So AD parallel to CF. |
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| 43. |
Coefficient of variation of two distributions are 60 and 70, and their standarddeviations are 21 and 16, respectively. What are their arithmetic means?cito ond veights of the |
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| 44. |
Define principle of linearmomentum |
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Answer» The Principle of the Conservation of Momentum states that: if objects collide, the total momentum before the collision is the same as the total momentum after the collision (provided that no external forces - for example, friction - act on the system). Thelaw of conservation of linear momentumstates that if no external forces act on the system of two colliding objects, then the vector sum of the linear momentum of each body remains constant and is not affected by their mutual interaction. |
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| 45. |
n points in a plane in which no three of them lies is a straight except p of them.find the numbers of triangles and straight lines which can be formed |
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| 46. |
Find the number of points on the straight line between points (4, 11) to (16,-1) whosecoordinates are positive integer |
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Answer» only 3 points mentioned below ,are there. thnx |
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| 47. |
. Let Aand B be two fxed points then the locus of a point C which moves so that22(D) Straight line(A) Circle(B) pair of straight line (C) A point |
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| 48. |
A-7.Let A and B be two fixed points then the locus of a point C which moves so that22(A) Circle(B) pair of straight line (C) A point(D) Straight line |
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Answer» The answer is a Circle. pls post a clear image |
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| 49. |
The equation of the straight line through the points (3,3) and (7,6) is |
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Answer» Thanks |
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| 50. |
right bisector of the line segment joining the points (3,4the line6 Find the equation of theand (- 1, 2).th ation of the straight line passing through (3,-2) andma |
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