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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
4. Ramon caIf his brother caught F amount of fish, write anexpression that shows how many fish Ramonught twice as many fish as his brother.caught. |
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Answer» according to question Ramon caught 2 times as his brother caught. let Ramon caught R number of fishes Therefore we get equationR= 2F I'm confused please specify what you not understand |
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| 2. |
60 per m.9. A square lawn is surrounded by a path 2.5 m wide. If the area of the path is 165 m2, findthe area of the lawnti 5.A 5-m-wide path |
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| 3. |
13. In supplementary angles, one is twicethe other. Find the angles.The 1: |
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Answer» Supplement = 180 - angle measure. Supplementary angles add to 180 degrees. So of the measure of the angle is x, the measure of its supplement is 2x. x + 2x = 180 3x = 180 x = 60 Angle = 60, supplement = 120 |
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| 4. |
1. In Fig. 9.29, identify the following:a) any one pair of corresponding anglesb) any one pair of alternate interior anglesc) any one pair of angles on the same sideof the transversald) any two pairs of vertically opposite angles3746 5B /DFig. 9.29 |
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| 5. |
(7)Write the ratio of first quantity to second quantity in the reduced form.(i) 1024 MB, 1.2 GB [(1024 MB = 1 GB)](ii) 17 Rupees, 25 Rupees 60 paise (iii) 5 dozen, 120 units(iv) 4 sq.m, 800 sq.cm(v) 1.5 kg, 2500 gm |
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Answer» 17 rupis 25 rupis 60 paise 17 Rupees 25 Rupees 60 paise 17 rupees 25 rupees 60 paise 17 Rupees, 25 Rupees 60 paise 17 rupees . 25 rupees 60 paise i- 5:6ii-85:128iii-1:2iv-1:200v- 3:5 17 rupees 25 rupees 60 paisa 17rupees 25 rupees 60 paise 17 rupees, 25rupees,60paise 4sq. m,800,sq.cm this is the quantity RS 17 , RS 25. 60paise 17 rupis 25 rupis 60 rupis 17 Rupees, 25 Rupees 60 paise 4th one answer is correct answers 1024 mb ,1.2 GB (1024mb=1gb answer number 1 right kyouki 1024 MB se 1GB banti h 4 sq. m , 800 sq. cm sab koi ****** ..nobody is understanding the question just commenting the question.. ridiculous... how dumb of you all... 🤦♂️ scamming everyone.. how did you even get a mobile phone!! i wud really appreciate if someone could properly criticize these idiots trying to fool others .... 17 rupees 25rupees 60 paisa 17 Rupees,25Rupees 60paise (ii)17Rupees,25rupees 60paisa 17rupies 25 rupies 60 paise (iv) ithu than answer 1024mb, 1.2gb (1024mb=1 gb) iv) 1:24 sq.m×100:800 sq.cm400:800 sq.cm1:2 4square meater, 800square meater Q.1 5:6Q.2 17:26Q.3 1:2Q.4 1:2Q.5 3:5 17 rupees 25rupis 60 paise 17rupye. 25rupue 60 paise 17rupees,25 rupees60paise i is your answer ok 4sq.m,800sq.cm the answer is a second 17 rupis 25 rupis 60 paisa ,sorry.Don't know.... 17 Rupees. 25 Rupees 60 paise 17Rupees, 25Rupees60paisa 1st convert Meter into cmthen the ratio will be 1:2 4sq. m , 800 sq. cm. 800sq. meter is a answer (i) 1024 MB,1.2GB[(1024-1GB)]= 24 MB (1)- 5:6(2)-85:128(3)-1:2(4)1:200(5)-3:5 and 17rules 25rules60paise 4 sw.m,800 sq.cm sjnsjilua The answer is 800sq. cm (i) 1024mb 1.2gb (1024mb=1gb) (iv) 4 sq.m, 800 sq.cm 17 rupees 25 rupees 60 paisa is the correct answer iv=1:2 i=1:1.2iii=1:2vi=3:5ii=17:25.6 17 rupees, 25 rupees 60 paise 17 rupees , 25 rupees 60 paise first answer is write 17rupees; 25rupee,60paise This question answer is 4 17 rupees.25rupees 60 paisa 17 Rupees'. 25 Rupees 60 paise ans (1)=1228. ans (2)=4260. ans (4)=1m. = 100cm. ans (5)=4kg 17 rupees , 25 rupees 60 paise 17 RS 25 RS 60 paise |
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| 6. |
s Ot the thove angles of a tsungle one is twice the semaillest and anoherone is theice the smallest Find the angles |
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Answer» Let the angles be x,2x & 3x respectively so,x+2x+3x=180 6x=180 x=30 so,1st angle=x=30 2nd angle=2x=2*30=60 3rd angle=3x=3*30=90 Like if you find it useful |
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| 7. |
6.In a model of a ship, the mast is 9 cm high, while themast of the actual ship is 12 m high. If the length ofthe ship is 28 m, how long is the model ship? |
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Answer» thanks |
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| 8. |
In a model of a ship, the mast is 9 cm high, while themast of the actual ship is 12 m high. If the length ofthe ship is 28 m, how long is the model ship?6. |
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Answer» Height of model ship = 9 cmHeight of actual ship = 12 m= 1200 cm Let height of model ship is x % of actual ship height Then,(x/100)*1200 = 9x = 9/12 = 3/4 =.75 % If length of actual ship is 28 m= 2800 cm Length of model ship=(.75/100)*2800=.75*28 = 21 cm |
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| 9. |
9. In a model of a ship, the mast (flagstaff) is 6 cm high, while the mast of the actis 9 m high. If the length of the ship is 33 m, how long is the model of the ship? |
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| 10. |
\left(a^{\frac{1}{x-y}}\right)^{\frac{1}{x-z}} \times\left(a^{\frac{1}{y-z}}\right)^{\frac{1}{y-x}} \times\left(a^{\frac{1}{2-x}}\right)^{\frac{1}{z-y}}=1 |
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Answer» a^(1/(x-y)(x-z))×a^(1/(y-z)(y-x))×a^(1/(z-x)(z-y))=a^(1/(x-y)(x-z) + (y-z)(y-x) + (z-x)(z-y))=a^((y-z-x+z+x-y)/(x-y)(y-z)(x-z))=a^0=1 |
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| 11. |
\quad \sqrt { 0.09 \times 0.09 \times x } = 0.09 \times 0.09 \times \sqrt { z } |
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| 12. |
A5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same timeC) the length of the shadow cast by another pole 10 m 50 cm high (ii) the height of apole which casts a shadow 5m long.9. |
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| 13. |
Gb—,D& Q "_b 0 |
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Answer» a^4 - b^4/a^2 - ab = (a^2 - b^2)(a^2 + b^2)/ a(a - b) = (a - b)(a + b)(a^2 + b^2)/ a(a - b) = (a + b)(a^2 + b^2)/a |
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| 14. |
3a-gb to t6dbc |
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| 15. |
Findita gbJT - 57, a b 577di + 7 |
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Answer» V11 - V7/ V11 + V7= V11-V7( V11+ 7)/ (V11+V7)( V11+V7)=11-7/(V11+V7)^2=4/11+7+2V77=4/18+2V77=4/2(9+V77)=2/8+V77 |
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| 16. |
lLbb hite blhprLARh le â442 4f LD H Bie gb Inapalh L |
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Answer» please give question in English. |
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| 17. |
U pot) 91 +41+5 - DU| 8] The sum Ęthe plane at thx +produit|tgi iespectively the sand a gb|Indutto the pluie axby. + |
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Answer» For equation p(x) = ax^2 + bx + 1 Sum of roots = - b/a4 = - b/ab = - 4a......(1) Product of roots = 1/a1 = 1/aa = 1 Put value of a in eq(1)b = - 4*1 = - 4 |
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| 18. |
13 L2 b फारूक ॥विकि: विरिजुरि कला () |
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Answer» Ya..Every Irrational number be a real number..... प्रत्येक अपरिमेय संख्या वास्तविक संख्याएं होती है |
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| 19. |
君1in figure, AFECΔGDB and 4L2. Prove that ΔADE ~AABC.2 |
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Answer» Solution: [FIGURE IS IN THE ATTACHMENT] Given: ∆FEC ∆FEC ≅ ∆GDB EC= BD ( by CPCT)..........(1) Given: ∠1= ∠2 AE AD ………….. …… ..(2)(Sides opposite to equal angles are equal)From eq 1 and 2AE/EC = AD/BADDE || BC(Converse of Basic proportionality Theorem)∠1 = ∠3 and ∠2 = ∠4[ Corresponding angles] In ∆ADE and ∆ABC∠A = ∠A (Common)∠1 = ∠3 (proved above)∠2 = ∠4 (proved above) ∆ADE ~ ∆ABC [ by AAA similarity criterion] Like if you find it useful! |
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| 20. |
) What is the domain of the function cosec-l2 |
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Answer» cosec^-1(–x) = –cosec^–1x, x < –1 or x > 1 Odd function |
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\times v \times v \times z \times \varepsilon ( q ) |
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Answer» In exponent form 3 × 2 × a × a × a 6 a³ |
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| 22. |
19. Are angles 1 and 2vertically opposite?Why?42 |
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Answer» no, because , line segment are different for 1 and 2 |
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| 23. |
12.The digit in the tens place of a two-digit number is three times that in the units place. fheееdigits are reversed, the new number will be 36 less than the original number. Find theoriginal number. Check your solution. |
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| 24. |
Find an angle if three times the angle is equal to the sum of its complement and its supplement. |
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| 25. |
A rectangular plot of land measures 95 m by 72 m. Inside the plot, a path of uniforis to be constructed all around. The rest of the plot is to be laid with grass. Find the total expensinvolved in constructing the path at t46.50 per m2 and laying the grass at 3.75 per m2m width 3.5m |
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| 26. |
and 33 m wide in order to coverbreadth. li le purlits length and breadth.quare 3.4 cm long.ctangle 11.2 cm long and 7.5 cm13. How much would it cost to lay a wall-to-wall carpetin a room 8 m long and 6 m wide, with a carpet thatcosts 125 per m2?dcohhlestone path 8 m wide is to be laid along the |
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Answer» Area of room = 8*6 = 48 sq mCost = 48*125= Rs. 6000 |
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| 27. |
EXERCISE 20BA rectangular grassy plot is 75 m long and 60 m broad. It has a path of width 2 m all aroundit on the inside. Find the area of the path and the cost of constructing it at 125 per m1.oclond measures 95 m by 72 m. Inside the plot, a path of uniform width |
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| 28. |
2. A rectangular plot of land measures 95 m by 72 m. Inside the plot, a path of uniform widthof 3.5 m is to be constructed all around. The rest of the plot is to be laid with grass. Find thetotal expenses involved in constructing the path at R 80 per m2 and laying the grass at R 40per m. |
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Answer» lenght = 95mbreadth= 72m |
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| 29. |
SURFACE AREAS AND VOLUMES571a A classroom is 7 m long, 6.5 m wide and 4 m high. It has one door 3 m x 1.4 m and three windowseach measuring 2 m Ă 1 m. The interior wall is to be colour washed. Find the cost of colorwashing at the rate ofm2 is R 17550 and the cost of papering the walls at t 140 per m is R 24080. Find the dimensionsof the room.An open box is made of wood 3 cm thick. Its external dim3.50 per m2ICBSE 2012]13. Length of a room is one and a half time of its breadth. The cost of carpeting the room at ? 325 perCBSE 2016]14. |
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Answer» 12)Area of four walls=(2h(l+b))=(2x4(7+6.5))=(8x13. 5)=108m squarearea of one window =3mx1. 4m=4.2m squarearea of three window =3(2mx1m)=6m squaretotal area of windows =(4.2+6)m square=10.2m squareArea for whitewashing =(108-10.2)m square=97.8m square cost of 1 m square white washing = 3.50rupeecost of 97.8m square white washing=3.50x97.8=342.3 rupees 13)Solution :- Let the breadth of the room be b .Then, length of the room l = 1.5 bArea carpeted by Rs 3.25 = 1m²area carpeted with Rs 175.50 is the area of the floor.the area of the floor = 1 / 3.25 × 175.50 = 54 m²therefore lb=54(1.5b) × b=541.5b²= 54b² = 54/ 1.5 = 36b = 6m.therefore, the breadth of the room is 6 m.length of the room =1.5× 6= 9 mlet the height of the room be h m.area of the walls = 2h ( l + b ) = 2h ( 9+6) = 30hm²since 1 door and 2 windows occupy 8 meter square.therefore area of papering =30h-8 meter square......(1)cost of papering the walls at Rs. 1.40 per m2 is Rs. 240.80.therefore area of papering = 240.80/ 1.40 = 172m²Now, from the eqn 1 ...........30h - 8 = 17230h = 180 h= 180/ 30= 6m.therefore, the height of the room is 6 m.hence the dimensions of the room is 9× 6 ×6. |
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| 30. |
The dining-hall of a hotel is 75 m long, 60 m5.broad and 16 m high. It has five-doors 4 m by3 m each and four windows 3 m by 1.6 m each.Find the cost of:(i) papering its walls at the rate of2.12 per m-(ii) carpeting its floor at the rate of725 per m2. |
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| 31. |
D (\ ],,‘L :L2 |
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Answer» we have 2 multiply croosly and then subtract u will get the answer like -3 because (1×1)-(2×2)= -3 (1×1)-(2×2)=1-4=-3 this is the answer 1(1) - 2(2) =1-4=-3 1^1=1; (2×2)=(4); 4-1=3 |
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| 32. |
AL2bx = |
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Answer» 5 × 7 = 35 6 × 3 = 18 4 × 2 = 8 |
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| 33. |
2 L2ax-by = a,b- |
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Answer» hit like if you find it useful |
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| 34. |
Ex. 3. Find the cost of carpeting a room 13 m long and 9 m broad with a care75 cm wide at the rate of Rs. 12.40 per square metre.ALL annat Arog of the room = (13 x 9 m2 = 117 m2 |
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| 35. |
ty divided into 'n'sectors in such a way that the angles at the centre of circle are inA.P. If the smallest angle is 8 and the largest is 72', caleulate n and the angle of the 3"d sector taking thesmallest angle as first. |
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Answer» First angle, a = 8°nth angle, an = 72°let the common difference = d sum of angles = 360°⇒ (n/2)[a + an] = 360⇒(n/2)[8+72] = 360⇒(n/2)[80] = 360⇒ 40n = 360⇒ n = 360/40⇒ n = 9 72 = 8+(n-1)d⇒ 72 - 8= (9-1)d⇒ 64 = 8d⇒ d = 64/8⇒ d = 8° a₃ = a + (n-1)d⇒a₃ = 8 + (3-1)×8⇒a₃ = 24 n = 9angle of third sector = 24° |
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| 36. |
angle, then hnd the() In a triangle one of the three angles is twice of the smallest angle and other is thre(iv(vtimes the smallest angle. Find the angles. |
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| 37. |
142 X 5 =382 X 3 =2 X 175 =4 X 206 = |
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| 38. |
Out of the three angles of a triangle, the second angle is 45" more than the smallest angThe third angle is three times the smallest angle. Find all the angles of the triangle. |
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Answer» suppose x is the smallest anglethen x+x+45°+3x= 180( y= x+45,z= 3x)x=27y= 27+45= 72z= 3*27= 81 |
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| 39. |
4. The measure of one of the angles of a triangle istwice the measure of its smallest angle and themeasure of the other is thrice the measure of thesmallest angle. Find the measures of the threeangles. |
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Answer» Thanks. That's wr |
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| 40. |
Oe anale i&s hwice the smallest angleandl anoher anale &s three times fhesmalleit angle |
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| 41. |
18. Find the measures of all the angles ofa parallelogram, if one angle is 24° lessthan twice the smallest angle. |
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| 42. |
2. Find the measure ofall the angles ofa parallelogram, if one angle is 24° less than the twiceof the smallest angle. |
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| 43. |
Q.7: Using (a-b)(atb)-a-bfind 194 x 206 |
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Answer» (a - b)(a + b) = a^2 - b^2 Then, 194* 206 = (200 - 6)(200 +6)= (200*200) - (6*6)= 40000 - 36= 39964 ans |
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| 44. |
के. <2 १३९ ov book o Rehem रण थे 240 /-VR o रण कपः 2 कद सैफAo bovk तप B - |
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| 45. |
6668 (1)2 202E L Ip9pA2 RER P 122 b ReR Le [कह ? 67Sy ()0५ (६)29 ()8y (1)¢ 3 Ik PRYE 1 8527 '99 'SE 'OV 82oot (v)& 00z (€)£ 09t 3 08 (1))1 45513 12p 2९ P 3 LRकस OV 2b 2120 O 4 %O0v % Lok e L226652 (¥) |
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Answer» 4) 100 ( 100×40/100) = 40 |
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| 46. |
€OV d puy 9५ =x/x}= PN 3 wUE=x/x} बभ्ण g |
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| 47. |
b /i) 981स3 / (५2 5६123 / 2R} 0813 / 0५2] 07८ ॥८० 20: 29० छवि एट12 102 1०2 8 219१० (५ 128/%] 021 [52 Lftte) OV T Ritke26 है 202५० (कु 128/lhe} 0L 1 5 L (2) 099 धन |
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Answer» ओसत चाल=ओसत दूरी/ओसत समय=800/100=80kmphPlease like the solution 👍 ✔️ 40 km / hour he would travel 560+240=800km800/100=80km/1h |
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| 48. |
10A. 10Write the fractions as sum of equal fractions in 2 different ways44B. |
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Answer» A ) 10/10 = 2/4 + 2/4 10/10 = 3/6 + 3/6 B) 4/4 = 5/10 + 5/10 4/4 = 4/8 + 4/8 |
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| 49. |
206 + 96* - 86 - 120 के गुणनखण्ड हैं |
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Answer» you have to use id. (a+b)square and then take out common ~(2a+3b)sq.-8a-12b =(2a+3b)sq.-4(2a-3b) taking (2a+3b) common =(2a+3b)[(2a+3b) -4] |
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| 50. |
15X102+20645x8+74 |
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Answer» 4 is the right answer of this question 4 is the best answer 4 is the correct answer. 1311/4 is the correct answer answer is 04 |
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