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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
HCF of 15 and5 |
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| 2. |
e 2 ig i1 1 1z [3 + 5 + डे + जन =?il |
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Answer» 3 is the right answer of following questions 3 is correct answer for question 3 is the correct answer |
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| 3. |
Find the value of aand b, il-3154+3/5 - a+b 5. |
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Answer» A= 61/29B=24/29is the best answer |
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| 4. |
1.2 \log 5+\frac{1}{2} \log 9-\log 3=\log x |
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| 5. |
9.-site-5 बराबर है :०) log-3)+ca) log (x -1) -2)/५८(d) log |(x-1) (-2)+C |
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Answer» x/( x-1)(x-2)=A/( x-1) + b/( x-2); x/( x-1)( x-2)=A( x-2)+B( x-1)/( x-1)( x-2); by cancelling denomater x=A(x-2)+B(x-1), putting x=1in (1); 1=A(1-2)+B(1-1)=1=A(-1); A=-1, similarly x=2 in (1); x=A(x-2)+B(x-1); 2=A(.2-2)+B( 2-1); 2=B; B=2. (b) |
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| 6. |
x^2 %2B 10*x %2B 16 |
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| 7. |
x^2 %2B 10*x - 120 |
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Answer» it is a wrong question that's incorrect questions |
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| 8. |
Il %fi/ ’ QQ. S SR Pl ora ] न की e5 OI’VLQ/ 4/ \ 5 3 |
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Answer» there can be infinitely many rationals between number 3 and 4, one way is to take them3=21/6+1, 4= 28/6+1therefore six rational numbers are:-22/7,23/7,24/7 ,25/7 , 26/7, 27/7 . |
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| 9. |
3*x^2 %2B 10*x %2B 3 |
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Answer» answer of this question is (x+3)(3x+1) 3x²+10x+3=0. 3x²+9x+x+3=0. 3x(x+3)+1(x+3)=0. (x+3)(3x+1)=0. x=3orx=-1/3 |
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| 10. |
3*x^2 %2B 10*x - 8 |
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Answer» 3x^2 + 10x - 8 = 03x^2 + 12x - 2x - 8 = 03x(x + 4) - 2(x + 4) = 0(3x - 2)(x + 4) = 0x = 2/3, - 4 |
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| 11. |
( IL05396285 |
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Answer» Yes it is correct. One is an integer and other has decimals. |
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| 12. |
Write the quadrant in which the following points lie?v) (0, 8)v) (3, 0)vi) (-4,0) |
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| 13. |
Which of the following points lie on the line y 2x +3a) (2, 8)b) (3, 9)c) (4, 12) |
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Answer» tq |
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| 14. |
x2+5x+4 |
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Answer» x²+5x+4=0=> x²+4x+X+4=0=> X(X+4)+1(X+4)=0=> (X+4)(X+1)=0=> X = -1, -4. Please hit the like button if this helped you |
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| 15. |
7. Prove that the points A(1, 4), B(3, -2) and C(4,-5) are collinear. Also bsthe equation of the line on which these points lie. |
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| 16. |
1.Write the quadrant in which the following points lie?iv) (vii)v) (0, 8)vi) (3, 0)vii) (-4, 0) |
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Answer» i) 2 quadrantii) 3 quadrantiii) 1 st quadrantv) y axisvi) x axisvii) negitive x axis |
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| 17. |
\left.\begin{array}{ccc}{3} & {-3} & {4} \\ {2} & {-3} & {4} \\ {0} & {-1} & {1}\end{array}\right] \text { and } B=\left[ \begin{array}{ccc}{3} & {1} & {2} \\ {2} & {0} & {5} \\ {1} & {2} & {0}\end{array}\right], \text { find } A B |
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Answer» determinant ki help se aayega answer vvvvvveasssy |
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| 18. |
\frac \cosec ^ 2 63 ^ \circ %2B \tan ^ 2 24 ^ \circ \cot ^ 2 66 ^ \circ %2B \sec ^ 2 27 ^ \circ %2B \frac \sin ^ 2 63 ^ \circ %2B \cos 63 ^ \circ \sin 27 ^ \circ %2B \sin 27 ^ \circ 2 ( \cosec ^ 2 65 ^ \circ - \tan ^ 2 25 ^ \circ ) |
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| 19. |
41 %2B 36 %2B 33 %2B 27 %2B 30 |
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Answer» So after addingwe will get60+30+7890+70+7167thanks 168 is the correct answer 168 is the right answer 167 is the correct answer of the given question The right answer is 167 27+30+33+36+41 = 167 this is your answer 167 please like me 167 is the most correct answer 167 is the right answer 27+30+33+36+41=167. by adding these numbers we get answer 167 |
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| 20. |
\frac { \log x } { \log 5 } = \frac { \log y ^ { 2 } } { \log 2 } = \frac { \log 9 } { \log \frac { 1 } { 3 } } , \text { find } x \text { and } y |
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Answer» log(x) log(9) log(3²) 2 log(3)-------- = -------------- = ------------ = --------------log(5) log (1/3) log(3^(-1)) (-1) log(3) log(x) = -2 log(5) log (x) = log (5^(-2)) x = 1/25 log(y²) log(9) log(3²) 2 log(3)-------- = -------------- = ------------ = --------------log(2) log (1/3) log(3^(-1)) (-1) log(3) 2 log(y)------------- = -2log(2) log(y) = - log (2) = log(1/2)y = 1/2 it's wrong |
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| 21. |
66.If α + β = 90° then cosa + cos2ß equals to:02(C) 2(D) 1Space for Rough Work |
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| 22. |
((64*a^3)/((27*x^(-3))))^(-2/3)*(8*a^3 %2B 27*x^(-3))^(2/3) |
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| 23. |
sqrt(5 %2B 2*sqrt(19) %2B 27) |
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Answer» V27+V76 +V25=V9x3 + V4x19+V5x5=3V3+19V2+5=57V6+5 3V3 +2V19+5( wrong answer 3V3+19V2+5) |
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| 24. |
-x %2B 10*x %2B 9 - 27=x %2B 10*(-x %2B 9) |
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Answer» 10x +9 - x - 27 = 10(9-x) + x9x - 18 = 90 - 10x + x18x = 108x = 6 |
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| 25. |
a^3 %2B 27 |
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Answer» =a^3+27=a^3+3^3=(a+3) ^3+(a^2+3^2-3a) =(a+3) ^3+(a^2+9-3a) |
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| 26. |
Findthe ngles in the figure |
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Answer» 2x + 3x = 180 ( staright line) 5x = 180 x = 36 2x = 72° 3x = 108° |
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| 27. |
3. What is the value of the determinant(A) 8(C) 12(B) 10(D) 14CE FOR ROUGH WORK |
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| 28. |
63. The sum of all real values of x satisfying 6the equation2+4 60x2 5x +51 is:(2) 4(3) 6(4) 5E/Page 28SPACE FOR ROUGH WORK |
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Answer» (3) 6... When you substitute x=6, your index becomes 0. And anything raised to 0 is 1. |
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| 29. |
A farsighted person's least distance of distinct vision is 0.5 m. The power of the lens that shouldbe prescribed to enable him to read a book held at 0.25m is + x diopter. Find the value of x.Space for Rough Work |
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Answer» A long sighted person means that he can see distant object clearly but he cannot see objects near to him .This defect is also known as Hypermetropia. Given :v=-50cmu=-25cm(normal near point)focal length=?Lens formula:1/f=1/v-1/u1/f=1/-50 -1/-25=1/25-1/50=2-1/50=1/50f=50cmHence convex lens of focal length 50cm should be advised or used to correct this defect. |
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| 30. |
Prove an four\frac{\log _{a}\left(\log _{5} x\right)}{\log _{b}\left(\log _{2} b\right)}=-\log _{a}^{b} |
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| 31. |
4Rita had enough money to buy 15 books for30 each. If the price of each book increasesresulting in a total cost increase of 45, howmany books can she buy now? How muchmoney will be left with her? |
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Answer» Money rita have= 15*30= Rupees 450Now,Rita Can buy, 450/45 books which is equal to 10 books. |
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| 32. |
\log _{a} b \times \log _{c} a \times \log _{b} c |
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| 33. |
2. If a? + b2 = 7ab then show that 2 log (a+b) = log a + log b + 2 log 34 |
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| 34. |
log(a*log(b*log(c, a), c), b)^3 |
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| 35. |
Findthe diutancome |
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Answer» Distance from P (x, y) to origin Points of origin Q (0,0) By applying distance formula √(x2 - x1)² + (y2 - y1)² √(0 - x)² + (0 - y) ² √x² + y² |
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| 36. |
$ 3 x+4(1)=7 $$ 3 x+4=7 $$ x= $ |
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Answer» tq so much bro 3x + 4(1) = 73x = 7 - 43x = 3x = 3/3x = 1 |
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| 37. |
=(a-b)(b- c) (c- a)bc ca ab |
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Answer» thanks |
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| 38. |
, If , b, c are all non-zero and a + b + c 0,then prove that+3.bc ca ab |
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Answer» When a + b + c = 0 then a³ + b³ + c³ = 3abc Divide by abc (a³ + b³ + c³) = 3abc ----------------- ---------- abc abc a² b² c²------ + ------ + ------- = 3 bc ac ab |
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| 39. |
is equal tolog, ab 'log, ab |
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| 40. |
If log, abx, then value of log, ab is |
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| 41. |
IF loga (ab)- x, then find the value of log, (ab). |
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| 42. |
5. Show that the sequence log a, log (a b), log (ab2), log (ab) is an A.P. Find its commondifference |
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| 43. |
33.The zeroes of the quadratic polynomíaIx" + 99χ +127 are(a) both positive(c)both equal(b) both negative(d) one positive and one negative |
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Answer» another method |
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| 44. |
\frac { a } { 3 } = \frac { b } { 4 } = \frac { c } { 7 } \text { then } \frac { a + b + c } { c } = ? |
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| 45. |
\frac { a } { 3 } = \frac { b } { 4 } = \frac { c } { 7 } , \text { then the value of } \frac { a + b + c } { c } |
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| 46. |
\frac{a}{3}=\frac{b}{4}=\frac{c}{7}, \text { then } \frac{a+b+c}{c}=? |
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Answer» 1 2 |
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| 47. |
a+b+c=0, \text { then }\left(\frac{a^{2}}{b c}+\frac{b^{2}}{c a}+\frac{c^{2}}{a b}\right)=? |
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| 48. |
of the path. Calculate thĂŠ cust urA tablhanging all around the table, find the area of the table top.of the table coverisgolutecover 5 m x 3 m, is spread on a meeting table. If 25 cm of the tablet has an inside path of uniform width 3.5m |
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Answer» 5m=500cmand 3m=300cmso (500-50)cm=450cm, (300-50)cm=250cmso the new length and breadth are 4.5m and 2.5marea =l*b =4.5m*2.5m =1125m^2 |
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| 49. |
BC, such29. In an equilateral triangle ABC, D is a point on side2that BD BC. Prove that 9AD2 7AB3 |
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| 50. |
on the side BC of an equilateral triangle ABC such that DC BC.29. A point D isProve that ADs13 CD4 |
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