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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
(a) What is the probability of getting one head13](b) A man is known to speak the truth 3 out of4 times. He throws a die and reports that itis an ace. Find the probability that it isre2]in six tossings of a coin?13]actually an ace. |
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| 2. |
9. Volume of a cube is 512 cm3. Its surfacearea is |
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| 3. |
,. If the volume of a cube is 512 cm3, find its surface area. |
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| 4. |
volumeI. The volume of scbe is 512 miA 64 cm2560 512 |
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Answer» Answer:C 384 cm 2Explanation: Volume of cube=512cm^3a^3=512a=8 cm So,Surface area of cube = 6a^2=6*8^2=6*64=384 cm sq |
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| 5. |
From a solid cube of edge 14 cm, a sphere of largest volume is cut. Appvolume is cut.Approximate volume of sphereiS(A) 359 cm3(C) 2874 cm3(B) 1437 cm3(D) of these |
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Answer» Edge length of cube = 14 cm maximum diameter of sphere = edge length of cube diameter of sphere = 14 cm let radius of sphere = r then ,2r = 14 cm r = 7 cm volume of sphere = 4/3πr³= 4/3× 22/7 × 7 × 7 × 7 cm³=4/3× 22× 7 × 7 cm ³=88× 49/3 =1437. 333 cm³ |
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| 6. |
38. The volume of a cube is 512 cm 3 then its total surface area is(a) 384 cm(b) 512 cm2(c) 256 cm |
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| 7. |
IntegratePirn622 +2dat |
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Answer» please accepted as best please |
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| 8. |
धहु का एक पाइप 77 0 लम्बा है। इसके एक अनुप्रस्थकाटशा ऑतरिक व्यास 4 ८ है और बाहरी व्यास 4.4 om है |
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Answer» isme malum kya karna hai bro who is wrote is biology |
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| 9. |
Water flows out through a circular pipe whoseinternal diameter is 2cm., at the rate of 6 metres persecond into a cylindrical tank. The radius of whosebase is 60cm. Find the rise in level of water in 30minutes. |
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| 10. |
ORWater flows out through a circular pipe whose internal diameter is 2 cm, at the rate of 6metres per second into a cylindrical tank the radius of whose base is 60 cm. Find the rise inthe level of water in 30 minutes |
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| 11. |
Water flows out through a circular pipe whose internaldiameter is 2 cm, at the rate of 6 meters per secondinto a cylindrical tank, the radius of whose base is 60cm. Find the rise in the level of water in 30 minutes? |
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| 12. |
33+77 |
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Answer» 33+77 = 110(basic additon) |
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| 13. |
ORt the rate of 6Water flows out through a circular pipe whose internal diameter is 2 cm, ametres per second into athe level of water in 30 minutescylindrical tank the radius of whose base is 60 cm Find the rise in |
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| 14. |
water flows out through a circular pipe whose internal diameter is 2 cm at the rate of 6 m per second into a cylindrical tank the radius of whose base is 6 0 CM by how much will the level of water rise in 30 minutes |
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| 15. |
81S22. Water is flowing at the rate of 7m per sec nd through a circular pipe whose internal diameter isin to a cylindrica! tank the radius of v hose base is 40cm. Determine the increase in the waterlevel in i hour2cm |
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| 16. |
।(D) या तो तर्क 1 या ॥ मजबूत हैएक लडकी घडी को देखती है, तब उसके सुबह के 3 am बजे कासमय होता है। घडी हर रोज 16 min पीछे होती जाती है। जब वहचौथे दिन वह घडी देखती है तो घड़ी में रात के 8 pm बजे होते हैं।तब सही समय क्या होगा?(A) 9:00 pm(C) 9:30 pm(B) 9:15 pm(D) 8:30 pmमें आग लग गौ केवल एक जनक द्वारा** *१३ |
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Answer» 9.15 answer the question |
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| 17. |
Two stations A and B are 110 Kms apart on a straight line.One train starts from A at 7 a.m. and travels towards B at20 km per hour speed. Another train starts from B at 8amand travels towards A at a speed of 25 km per hour. Atwhat time will they meet? |
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Answer» dist between two places = 110 kmA cover 20 km till 8am now distance left = 110-20=90 kmnow both coming oppositelyso speed = 20+25= 45 km/h45 km coming in 1 hr 1 km coming in 1/45 hr90 km coming in 90/45= 2hrthey will meet at 8+2= 10am Suppose they meetxhours after 7 a.m.Distance covered by A inxhours = 20xkm.Distance covered by B in (x- 1) hours = 25(x- 1) km.20x+ 25(x- 1) = 11045x= 135x= 3.So, they meet at 10 a.m. |
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| 18. |
8. Vikas can cover a distance of 20 km in 7 hours on foot. How many km per hour doeshe walk? |
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| 19. |
55. A train starts from a station at 11:30 amand runs with the speed of 112 km/h. Atwhat time will the train reach otherstation at a distance of 308 km?1. 2:45 pm 2. 2:15 pm3. 2:00 pm 4. 3:00 pm |
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Answer» We know,Distance = speed * time Given,Speed = 112 km/h, Distance = 308 km Time = Distance / speed = 308/112 = 11/4 = 2 3/4 Time = 2 hrs 45 min As train starts at 11:30 am and will reach station at 2:15 pm (2) is correct option 2:15 pm is the. correct answer. for the. given. question 2:15 pm is the. correct answer. for the. given. question |
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| 20. |
8. Vikas can cover a distance of 20in 7 hours on foot. How many km per hour doeshe walk? |
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Answer» Distance covered by Vikas in734734h =20232023km∴ Distance covered by him in 1 h =(2023÷734)2023÷734km =(623÷314)623÷314km =(623×431)623×431km =(2×43)2×43km =(83)83km =223223km Hence, the distance covered by Vikas in 1 h is223223km. |
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| 21. |
.5 Give the time.a) 1 hour ifter 12:00pmb) 1 hour before 8:45 amc) 2 hours after 10:05 amd) 2 hours after 2:30 pm |
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Answer» a) 1:00 amb) 7: 45 amc) 12: 05 pmd) 4: 30 pm |
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| 22. |
The collection of all prime numbers. |
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Answer» The first fewprime numbersare 2, 3, 5, 7, 11, 13, 17, 19, 23 and 29. Numbers that have more than two factors are called compositenumbers. The number1 is neitherprimenor composite. Forevery prime numberp, there exists aprime numberp' such that p' is greater than p. |
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| 23. |
Which of the following are sets ? Justify your answe)The collection of all prime numbers. |
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Answer» It is a set.As the collection of all prime numbers is known and can be counted, it represents a set. which of the following are sets |
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| 24. |
7. The mean of four numbers is 32. If one morenumber is added to the collection, the new averageof the five numbers becomes 31. Find the meanvalue of fifth observation. |
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Answer» Since the mean of four numbers is 32. Therefore, the sum of all four numbers is (4×32)=128 Now,one more number is added then, The mean becomes 31. So,new sum of 5 numbers (5×31)=155 Therefore,the new number=155-128 =27 |
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| 25. |
Do This1 -33 4770Consider the following collection ofnumbers 1, , 0.5, 40.3 , 22,-5, iO, 0.125. Write these numbers under the appropriate category[A' 19number can be written in more than one group]i Natural numbers(i) Whole numbersili) Integers(iv) Rational numbers |
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Answer» 1)12)0,13)-2,-5,0,1 |
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| 26. |
The total surface area of a cube is 96 cm2. What is the length of its sides? |
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Answer» Let the length of the side of a cube = a cm Total surface area of the cube = 6a² cm² ----( 1 ) Total surface area of the cube = 96 cm² ----( 2 ) ( 1 ) = ( 2) 6a² = 96 a² = 96 / 6 a² = 16 a =√16 a = 4 cm |
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| 27. |
Multiple Choice Questions (MCQs)10. The perimeter of one face of a cube is 20 cmIts total surface area is:(a) 2400 cm2(c) 120 cm2(b) 150 cm2(d) 96 cm2 |
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Answer» Face of cube is square so ,4 × side = 20 cmside = 5 cm So,Total surface area of cube = 6 × (side)²Total surface area of cube = 6 × (5)²= 150 So, b) 150 cm² is correct |
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| 28. |
The total surface area of a cube is 96 cm2. What is the length of its sides?3. |
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Answer» Total surface area of cube is 6a^296=6a^2a^2=16a=4 |
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| 29. |
and height of a triangle are in the ratio 3:4 and its area is 96 cm2. Find its base and height. |
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Answer» Base: height=3:4Let base 3x and height=4x Area =(1/2)base*height96=(1/2)3x*4x96*2=12x²48/12=x²x²=4x=2 Base=3*2=6 cmAltitude=4*2=8 cm |
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| 30. |
. 2. The area of a rhombus is 96 cm2. If one of itdiagonals is 16 cm, then find out the length of itssides |
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Answer» Area of a rhombus = 1/2 × (Product of the diagonals) Given: Length of one diagonal = 16 cm Area of the rhombus = 96 cm2 ∴ Length of the other diagonal = 96*2/16 cm = 12cm ------------------------------------------- |
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| 31. |
. Area of a rhombus is 96 cm2 and one of its diagonals is 16 cm. Find the length of the otherdiagonal of the rhombus. |
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Answer» Given, Let us consider d1 = 16 Area of a Rhombus = 1/2 * d1 * d2 = 96 0.5 * 16 * d2 = 96 d2 = 96 / 8 = 12 Perimeter of a Rhombus when d1 and d2 are given p = √ ( d1² + d2² ) = √ ( 16² + 12² ) = √ ( 256 + 144 ) p = √ 400 p = 200cm |
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| 32. |
[If the sum to n terms of a sequence be 2n2 + 4, find its n th term.this sequence in A. P. ?1 |
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| 33. |
6. If nth term of the sequence is a, (-1)1-1.5 1. Find a |
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Answer» We will put n= 3then it will be-1*(-1)*(5^4)= 124+1= 125please like the solution 👍 ✔️👍 |
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| 34. |
9 m 85 cm +2 m 35 cm |
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Answer» 9 m 85 cm + 2 m 35 cm= 11 m 120 cmBut 120 cm = 1 m 20 cmSo, 11 m 120 cm = 11 m + 1m 20 cm= 12 m 20 cm PLEASE HIT THE LIKE BUTTON |
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| 35. |
8. A spherical glass vessel has a cylindrical neck 8 cm long, 2 cm in diameter, the diamof the spherical part is 85 cm. By measuring the amount of water it holds, a child finvolume to be 345 cm'. Check whether she is correct, taking the above as the inmeasurements, and π = 3.14. |
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Answer» 1 2 |
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| 36. |
The dimensions of a rectangular water tank are 2 m 20 cm by 1 m 85 cm by 1 m 10 cm. Find thevolume of the water tank. |
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| 37. |
From a cloth 6 Cm long a piece of lengh 2 m 85 cm is cut off what is the length of fhe reamaining |
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Answer» 2m =200cm (100cm×2)200cm+85cm =285cmLength of remaining = 600cm-285cm=315cmOr 3m 15cm |
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| 38. |
25. From a cloth 5 m long, a piece of length 2 m 85 cm is cut off. What is the length of theremaining piece? |
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| 39. |
(3+6-7+9+4578+1358+85318+134)0 |
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Answer» 0 is the right answer 0 is the right answer 0 is the correct ans 0 is the right answer correct answer is the 0 0 is the correct answer 0 right answer following question |
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| 40. |
How many terms of the sequence 1,4,7,10....... should be taken so that their sum is 176. |
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| 41. |
-4ABC-ADEF if BC = 3 cm and EF = 4 cm and area of AABC - 54cm? then area of ADEF is:(A) 90 cm2(B) 96 cm2(C) 100 cm(D) 85 cm |
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Answer» the answer of these is 96 cm^2 |
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| 42. |
bur and Breadth of the room.19 A wooden bookshelf has external dimensions as follows: Height 110 cm,Depth = 25 cm, Breadth-85 cm (See Fig. 18.5). The thickness of the plank is5ăeverywhere. The external faces are to be polished and the inner faces are to be painted.If the rate of polishing is 20 paise per cm2 and the rate of painting is 10 paise per cm2Find the total expenses required for polishing and painting the surface of theNCERTbookshelf.110 cm |
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| 43. |
5. Find the cost of painting of cubical box of 6 em edge at the rate of 10 paise per |
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Answer» answer is in point 21.60paise It must be 21.60 Rs. Because 100 paise=1 rupee. So, 2160 paise=21.6 Rs. thanks |
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| 44. |
front compound walp uch spheres are used for thisose cvlinder of radius 1.5 cm and heightem, placedecor ed on small supports as shown in13.32. Eighthy wooden spheres ofd on small supports as shown in Figof a house isdiameter 21and are to be painted silver. Eachupporbe painted black. Find the costsupport is aof paint reof Pam and black paint costs 5 paise per cm2em and is touired if silver paint costs 25 paiseFig |
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| 45. |
Aforaldegul&UT&liaU8SPismadeupof 16 tiles which are triangular. The sides of the triangular tiesand 10 cm. The tiles are polished at the rate of 20 paise per cm2. Find the cost ofcm, 20 cmtiles10are 26Find the cost of polishing the26 cm0 cm |
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Answer» We have lengths of the sides of 1 triangular tile are a = 20 cm, b = 26 cm, c = 10cm. ∴ s = a +b +c/ 2 = 20 +26+10 /2 cm = 28 cmarea of triangle = √ 28(28-26) (28-20)(28-10)√28*2*8*18√56*8*18= 89.7cm^2area of 16 such tiles = 16*89.7 Cost of polishing 1 cm2= 50 p = Re 0.50 ∴ Total cost of polishing the floral design = Rs 16 × 89.7 × 0.50 = Rs 718.3 |
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| 46. |
C) 134nese9.1 yy |
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| 47. |
- findICA to') & CA-A") when2A - To a 61Lab COD |
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| 48. |
if(100)^2×(10)3=(1000)^y then y is equal to |
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Answer» meku answer nai maaloom bhai I don't know what you think about it is not going to be a (100)²x(10)³=(1000)^y10⁴x10³=10^3y10^7=10^3y so 3y=7y=7/3 y=5because ,a^m×a^n=a^m+n |
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| 49. |
1 + i ^ { 10 } + i ^ { 100 } + i ^ { 1000 } = 2 |
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Answer» 1+ i^10+i^100+i^1000=1+i²+1+1= 1-1+1+1=2 |
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| 50. |
Period of f(x)-ecos/リ+sín π[s] is (目and denote the greatest integerfunction and fractional part functionrespectively) |
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Answer» since sin(nπ) is always 0. so, it will always be sinπ[x] 0 now for e^cos{x} , {x} will decide the periodicity of the function.. and it is periodic with the period 1. so the periodic is 1.. or after all integers I , graph will repeat itself. |
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