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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
x^(1/7)=(4/5)*(x %2B 10) |
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Answer» x=4/5(x+10)5x=4x+405x-4x=40x=40 |
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| 2. |
\frac { 3 x + 7 } { x ^ { 2 } - 3 x + 2 } = \frac { A } { x - 2 } - \frac { 10 } { x - 1 } , |
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| 3. |
O. Use the given number line to find the sign of thequotient a-babb)[Hint. a is +ve, b is --ve] |
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Answer» The sign of the quotient is "Negative " (-ve).. .... Please like my answer...... Choose the Best.... It's sign is negative .... sign is negative........ answer is positive because b is negative so a--b =positive positive-------------. ==positivepositive it's sign is negative is the correct answer of the given question |
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| 4. |
NVoQcoseeI sin A1sin A(0CONCosecA-cot A1 cosA |
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| 5. |
nvIS2 (0, 1) is equidistant from P (5, -3) and R (x, 6), find the value of x. |
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| 6. |
24. Sumita bought 12 notebooks for 168. Find the cost of f notebooks. |
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Answer» If you like the solution, Please give it a 👍 |
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| 7. |
Nandlal bought 20 dozen notebooks at 156 per dozen. He sold 8 dozens of them at 10%gain andthe remaining 12 dozens at 20%gain, what is his gain per cent in the whole transaction? |
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| 8. |
1. Sameera bought 8 notebooks for 96.00. Her teacher told her that sheneeded 15 notebooks. How much money does she need? |
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Answer» she needs rupees 180 |
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| 9. |
Q3. Calculate the value of 100 x 8 +10 x 17 |
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Answer» blank answer O sorry thanks |
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| 10. |
29. Ramesh and Govind are two friends of a class.Ramesh wants to buy 5 pens and 7 notebooks,Govind wants to buy 3 pens and 10 notebooks. Bothof them went to a shop. The price of one pen andone notebook which they have selected was Rs 5 and Rs12. Using matrix multiplication, find the amountrequired for each one of them. |
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Answer» 1 2 luv you helped a lot |
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| 11. |
s. Rao bought notebooks at the rate of 4 for35 and sold them at the rate oCalculate0) his gain percentage.(i) the number of notebooks he should sell to earn a profit of 171. |
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| 12. |
25. Solve by elimination method:2 (ix - by)+ a +4b 0,2 (bx +ay) +b-4a 0. |
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Answer» hit like if you find it useful |
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| 13. |
1. Solve the following pair of linear equations by the elimination method and the substitutionmethod:0 x+y=5 and 2x - 3y = 4(W) 3x + 4y - 10 and 2x - 2y = 2(iii) 3x - 5y-4=0 and 9x +2y +7-1 and xw |
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| 14. |
। दो संख्याओं का अन्तर 1365 है। बड़ी संख्या कोसंख्या से भाग देने पर भागफल 6 तथा शेषफल ।आँप्त होता है। छोटी संख्या क्या है ?1 2403 2954 3602:270 } |
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Answer» right anawer is; (2).please like my answer (2) is the right answer (2) is the correct answer 2 is correct answer of this question. 270 is the correct answer to this question. |
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| 15. |
0(c) _ 6%.of 800of2121% of 400 m(g)(k),-896 of(h)183%224a ton(1)80%0litresof 1000 |
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Answer» 1 ton = 1000kg hence 8% of a ton is8/100 x 1000 kg = 80kg |
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| 16. |
0fart 8.39 |
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| 17. |
lena made 90$for 5hours of work at the same rate how many hours would she have to work to make 324 |
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Answer» 90is to 5 hour then 1 is to 1/18 hour in same 324 is to 1/18 .324=18 |
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| 18. |
= 2 71 tan? Ogpot? 6 F W T कीजिए । ००१९८व... कक_ टी यंदि 11 07 ००. |
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Answer» Tana + cota =2take square both sides(tana + cota)² = 2²tan²a + cot²a +2tana.cota =4 we Know,tana =1/cotaso,tan² a + cot²a +2 = 4tan²a + cot² a = 4 -2 = 2 |
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| 19. |
125 is related to 17 1821 in theSame way as 458 is related toa 27 28 31 6 29 32 330 30 31 35 228 29 32 |
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Answer» c is the correct answer sorry a is the correct answer Opti on A as it can be made from 458just like17,18,21 are made from 125 |
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| 20. |
kculate coeficient of correlation for the ges of husbands and the rspeceir respectiveCalculate coefficient of cwives:3.Age ofhusbandsAge of wives23 27 28 29 30 31 33 35 36 3918 22 23 24 25 26 28 29 30 32 |
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Answer» gamma =0.99 |
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| 21. |
\frac { 2 ^ { 30 } + 2 ^ { 29 } + 2 ^ { 28 } } { 2 ^ { 31 } + 2 ^ { 30 } - 2 ^ { 29 } } = \frac { 7 } { 10 } |
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Answer» Will you Please tell me this question is taken from which book? |
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| 22. |
The total weight of 4 boxes is 74.5 kg. The weightof box A is 2.5 kg less than box B and weight of boxC is 2.5 kg more than box B. The weight of box D is2 kg more than box C. Find the weight of each box. |
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| 23. |
If 3 of a box of apples weighs 3 kg and 225 gm, how much does afull box of apples weigh?71:... TC 11 |
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Answer» let the weight of full box is X kg.. ER. RAVI KUMAR ROY A/Q3/4 of X = 3kg 225g = 3225g X = (3225*4)/3X = 4300g = 4kg 300g. ANS... 3kg225g=3225g,X=3225*4/3=4kg300g 4kg 300 GM is the correct answer of the given question |
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| 24. |
5. If- of a box of apples weighs 3 kg and 225 gm, how much does afull box of apples weigh?It she is another |
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Answer» Classify the following as rational or irrational number? (a) -25 4 kg 700gm is thw right answer.... the answer is four kgs seven hundred grams |
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| 25. |
3. 2 litres of juice is to be eqain each.4. The total weight of a box with contents is 8.25 kg. If the weight of the empty box is1.4 kg, find the weight of its contents |
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Answer» Weight of the contents= Total weight - Weight of empty box =>Weight of the contents= 8.25-1.4=6.85 kg |
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| 26. |
3. spet LuxUS dl 2 uuzens of such peris?4. A box of chocolates weighs 1.75 kg. Find the weight of each chocolate, if the boxcontains 35 chocolates. |
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Answer» 35 chocolate =1.75kg1 chocolate =1.75/35=0.05kg 35 chocolate =1.75 kg1 chocolate= 1.75/35=0.05 kg |
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| 27. |
3. The weight of 18 boxes is 12 kg. Find the weight of 1 box |
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Answer» 18 box=64/5kg1box=64/5*18=64/90=.71kg Plz mark me best and like If18 boxes = 64/5 kg1 box = 64/5 *1/18 kg= 0.711111 kg Answer 0.711111kg 0.711111kg is the weight of one box |
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| 28. |
A camp of 1000 soldiers has enough foodfor 180 days. If 600 more soldiers jointhe camp after 20 days. how long willthe remaining good fast ? |
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Answer» Remaining food for 100 days 100 day is the right answer remaining food for 100 days Given that 1000 soldiers have enough food for 180 days. Hence After 20 days, the remaining food is sufficient for 180 - 20 = 160 days. Given Remaining soldiers after 20 days = 1000 + 600 = 1600. Let the remaining food be x. 1000 : 1600 :: x : 160 1000 * 160 = 1600x 160000 = 1600x x = 100 days. The remaining food lasts for 100 days Given that 1000 soldiers have enough food for 180 days. Hence After 20 days, the remaining food is sufficient for 180 - 20 = 160 days. Given Remaining soldiers after 20 days = 1000 + 600 = 1600. Let the remaining food be x. 1000 : 1600 :: x : 160 1000 * 160 = 1600x 160000 = 1600x x = 100 days. The remaining food lasts for 100 days. Plz like my answer and accepted as bestPlz |
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| 29. |
9. Mona walked 7 km to the north from a restaurant to reach a petrol pump. From the petrol pump she went 5 km to the south to the next petrol pump. What is the distance between the restaurant and the second petrol pump? |
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Answer» She walked 5km on a same path dude... So it is 7-5=2kmHope you got it please like my answer and do comment for any queries |
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| 30. |
232 x 5 +3 (222/111) +3 |
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| 31. |
232-5 |
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Answer» 227 is the right answer of your question |
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| 32. |
6. 232-5x+3 |
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Answer» 2sqroot (3)x^2 - 5x + sqroot (3)= 2sqroot (3)x^2 - 3x - 2x + sqroot (3)= sqroot (3)x(2x - sqroot(3)) - 5x + sqroot (3) |
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| 33. |
If two third of A is four fifth of B, then A:B ? |
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Answer» 2/3 A = 4/5 BA/B = (4/5)(3/2)=6/5A:B =6:5 |
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| 34. |
money id se getaA shopkeeper sells glasses at180 per dozen and cups at60 per dozen. Smita has270. She spends one-third of the money on glasses and the remaining two-thirdon cups. How many glasses and cups did she buy? |
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Answer» glasses are of 180 per dozennow among 270 Smita spends 1/3 = 90 on glasses so she will get half dozen=6 glassescups are of 60 per dozennow among 270 Smita spends 180 on cups so she will get 36 cupsso total she will get 6 glasses and 36 cups. i am not proper understand |
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| 35. |
orpEApian travels one-third of the total distance by foot. He rides in a bus and covers two-third of the distance byus. If the distance covered by bus was 100 km, what was the total distance travelled by him?93w Age Mathematics-7 |
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Answer» let the distance travelled by man=x2/3 of the distance is covered by bus=2/3*xdistance travelled by bus=100 kmso, total distance travelled by man will be,2/3x=100 |
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| 36. |
PE1 the sum of threenumbers in G.P. is 38 and their product is 1728, find themhe su |
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| 37. |
2: On corresponding |
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| 38. |
Find the quotient in each of the following(6) 459(iv) 1728 (12)(0)729 รท9 |
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Answer» 45÷(-9) = -5 -243÷9 = -27 1728÷(-12) = -144 729÷9 = 81 main kitne mein padhti hoon |
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| 39. |
If the sum of three numbers in G.P. is 38their product is 1728, Find the numbers.and |
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| 40. |
12(8If the sum of three numbers in G.P. is 38their product is 1728, Find the numbersand |
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Answer» thank u |
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| 41. |
find the length of an edge of a cube, if its volume is 1728 cm3. |
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Answer» Volume of cube = 1728 cm ( Side)³ = 1728 Side = ³✓1728 Side = 12 cm thanks |
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| 42. |
Find the cube root of the following numbers.a. 1728e. 421875d. 2,62,144b, 39,304c. 50,653 |
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Answer» a. 12b. 34c. 37d. 64e. 75 |
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| 43. |
37.A godown building is in the form as shown in the following figure. The verticalsection parallel to the width side of the building is a rectangle 7 m x3 m, moustedbsemi-circle of radius 3-5 m. The inner measurements of the cuboidalare 10 m x 7 m x 3 m. Find the volume of the godown and the total surface area edligthe floor (base). |
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| 44. |
21i) 23. 23 |
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Answer» (1) 64^1/2 = (8)^2*1/2 = 8 (2) 2^2/3 * 2^1/5 = 2^[2/3 + 1/5] = 2^[(10+3)/15] = 2^13/15 |
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| 45. |
\operatorname { tan } 22 \frac { 1 } { 2 } \pi |
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Answer» tan45=1tan2(22.5)=12tan(22.5)/(1-tan^2(22.5))=12tan(22.5)=1-tan^2(22.5)tan^2(22.5)+2tan(22.5)-1=0so tan22.5=0.55 |
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| 46. |
(23)^1/2 x (23)^3/2 |
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Answer» using law of indicesa^m*a^n=a^m+nhence23^1/2+3/2=23^2=529 |
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| 47. |
12x-y=0x-5y=0 |
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Answer» thanks |
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| 48. |
2x+5y=0 |
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Answer» 5y=-2xy=-2/5 x line with y-intersept = 0and slope is -2/5 |
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| 49. |
x+2y=16 &2x+5y=0 |
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Answer» from second equation2x+5y=02x=-5yX=-5y/2put in equation 1-5y/2+2y=16-5y+4y/2=16-y=32y=-32hence X=-5y/2=-5*-32/2=5*16=80 |
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| 50. |
(c) If 6x+5y-7-0 & 2px+5y+1-0 are parallel lines, find the value of P.(3) |
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Answer» Given 6x + 5y - 7 = 0 and 2px + 5y + 1 = 0 lines are parallel Then6/2p = 5/52p = 6p = 6/2 = 3 Value of p = 3 |
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