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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Q.1. If 7 kg onions cost 140 rupees, how muchmust we pay for 12 kg onions? |
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Answer» answer is 12multiplied by 20 is 240 the cost of 7 kg onions=140 the cost of 1 kg onions=140/2 =20the cost of 12 kg onions=12×20=240ans:we pay 240 ruppes for 12 kg onions |
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| 2. |
1/117 kg onions cost 140 rupees, bow me |
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Answer» 240 is the right answer 240 is the correct answer of the given question cost of 7 kg = Rs 140cost of 1 kg = 140/7=20cost of -12kg= 20 x 12 = Rs 240 ₹240 is a right ans. |
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| 3. |
Practice Set 371. If 7 kg onions cost 140 rupees, how much must we pay for 12 kg onions |
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Answer» 7kg onion cost=1401kg onion cost=140/7 =20so, 12kg onion cost=12×20 =240 answer 240 is correct answer |
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| 4. |
Tina had 25 m long cloth she cuts for 50 cm length of cloth from this this is for making a curtain . how much cloth is Left with her |
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Answer» good |
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| 5. |
Determine the value of p and q so that the prime factorisation of2520 is expressible as 23 x 31x q x 7. |
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| 6. |
i sin 2A 2 sin A is true when A- |
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| 7. |
1e. In Fig. 13.12, you see the frame of a lampshade. It is to becovered with a decorative cloth. The frame has a basediameter of 20 cm and height of 30 cm. A margin of 2.5 cmis to be given for folding it over the top and bottom of theframe. Find how much cloth is required for covering thelampshade.Fig. 13.12 |
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| 8. |
10. In Fig. 13.12, you see the frame of a lampshade. It is to becovered with a decorative cloth. The frame has a basediameter of 20 cm and height of 30 cm. A margin of 2.5 cmis to be given for folding it over the top and bottom of theframe. Find how much cloth is required for covering thelampshade.Fig. 13.12 |
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| 9. |
2. Determine the value ofpandqsothattheprimefactorisationof2520 is expressible as 23 x 3#x q x 7. |
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Answer» how do know about the of p and q I can not understand |
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| 10. |
Determine the values of p and q so that the prime factorisation of 2520 is expressible as |
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Answer» Prime factors of 2520= 2*2*2*3*3*5*7= 2^3*3^2*5*7 Then value of p and qp = 2, q = 5 |
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| 11. |
making the tank.. In Fig. 13.12, you see the frame of a lampshade. It is to becovered with a decorative cloth. The frame has a basediameter of 20 cm and height of 30 cm. A margin of 2.5 cmis to be given for folding it over the top and bottom of theframe. Find how much cloth is required for covering thelampshadeFig. 13.12 |
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Answer» Superb.. |
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| 12. |
making the tank.of10. In Fig. 13.12, you see the frame of a lampshade. It is to becovered with a decorative cloth. The frame has a basediameter of 20 cm and height of30 cm. A margin of 2.5 cmis to be given for folding it over the top and bottom of theframe. Find how much cloth is required for covering thelampshade.Fig. 13.12 |
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| 13. |
12making the tank.10. In Fig. 13.12, you see the frame of a lampshade. It is to becovered with a decorative cloth. The frame has a basediameter of 20 cm and height of 30 cm. A margin of 2.5 cmis to be given for folding it over the top and bottom of theframe. Find how much cloth is required for covering thelampshade.Fig. 1t no competition f |
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| 14. |
10 In Fig. 13.12, you see the frame of a lampshade. It is to beovered with a decorative cloth. The frame has a basediameter of 20 cm and height of 30 cm. A margin of 2.5 cmis to be given for folding it over the top and bottom of theframe. Find how much cloth is required for covering thelampshadeFig. 13.12nate in a comnetition for making and |
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| 15. |
Fig. 13.12. you see the frame of a lampshade. It is to bered with a decorative cloth. The frame has a basediameter of 20 cm and height of 30 cm. A margin of 2.5 cm/is to be given for folding it over the top and bottom of thee. Find how much cloth is required for covering theInFig. 13.12lampshade. |
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| 16. |
(ii) sin 2A 2 sin A is true when A-(B) 30°(C) 450(D) 60 |
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| 17. |
1. The sum of first two terms of an infinite G.P. is 5 and each term is three times the sum of thesucceeding terms. Find the G.P.C D KA7İth common ratio r ( | r | < 1), each term bears a constant ratio |
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Answer» remaining solution |
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| 18. |
10. In Fig. 13.12, you see the frame of a lampshade. It isto becovered with a decorative cloth. The frame has a basediameter of 20 cm and height of 30 cm. A margin of 2.5 cmis to be given for folding it over the top and bottom of theframe. Find how much cloth is required for covering thelampshade. |
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| 19. |
10. In Fig. 13.12, you see the frame of a lampshade. It is to becovered with a decorative cloth. The frame has a basediameter of 20 cm and height of 30 cm. A margin of 2.5 cmis to be given for folding it over the top and bottom of theframe. Find how much cloth is required for covering thelampshade. |
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| 20. |
(iii)sin 2A = 2 sin A is true when A = |
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Answer» Given, sin2A=2sinAwe know that sin2A=2sinAcosA so, 2sinAcosA=2sinA divide with 2sinA on both sides, we get cosA=1cosA=cos0 Therefore, A = 0° |
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| 21. |
b) A heap of a rice is in the form of a cone of diameter 12 mt and height 8 mt.Find its volume? How much canvas cloth is required to cover the heap?(Use T 3.14) |
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Answer» Diameter to the base of a cone is = 12 mandheight of cone = 8m we have to find:volume of cone = ? solution:-According to givendiameter of base = 12 m=> radius of base = 12 / 2 = 6 m we know that;volume of cine is = 1/3 ×π×r²×h => 1/3× 22 / 7× 6²×8 => 36×22×8 /21 => 6336 / 21 = 301.71 m³ Answer |
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| 22. |
The height of a circular cylinder is 20 cm andthe diameter of its base is 14 cm. Find:(i) its volume(i) its total surface area |
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| 23. |
The height of a circular cylinder is 20 cm andthe diameter of its base is 14 cm. Find:(i) its volume(ii) its total surface area |
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| 24. |
The height of a circular cylinder is 20 cm andthe diameter of its base is 14 cm. Find:(i) its volume(ii) its total surface area1. |
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| 25. |
\frac { \sqrt { 3481 } - \sqrt { 2025 } } { \sqrt { 3481 } + \sqrt { 2025 } } |
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| 26. |
find the sq.root of each of the following no.by prime factorisationQ-2025 |
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| 27. |
(&=(6) जि (6/व7* ६ ८7रत्रथ्ट्4 दि mt In 1. अ 0/4 ¢ 4 :\‘/ /¥ nel ry s AETEYN८ है/§पिन . i Leoth & b/ v Lry |
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Answer» Length=5x, breadth=3xCost of 1 m=24Rsperimeter for 9600Rs=9600/24=400m Perimeter=2(5x+3x)400/2=8x200/8=xx=25 Length=125m, breadth=75m |
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| 28. |
(Fig. 2)A wooden article was made by scooping out a hemisphere from each end of a solid cylinder, as shown in Figthe height of the cylinder is 10 cm and its base is of radius 3.5 cm. Find the total surface area of the article.(Fig. 3)ORA heap of rice is in the form of a cone of base diameter 24 m and height 3.5 m. Find the volume of the ricemuch canvas cloth is required to just cover the heap? |
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| 29. |
में से प्रत्येक के लिए रचना का औचित्य भी दीजिए:[. 6 ठाए त्रिज्या का एक वृत्त खींचिए। केंद्र से 10 ८0 दूर स्थित एक बिंदु से वृत्त पर स्पर्श रेखा Ry |की रचना कीजिए और उनकी लंबाइयाँ मापिए। |L o >>“ चकेल्ीय जे के किसी बिंदु से T *4 |
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| 30. |
u Jugal !13. Ramu bought 2 m 70 cm cloth for his shirt and 2 m 60 cm cloth for his pviamas. Find thetotal length of cloth bought by him. |
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Answer» Length of cloth for his shirt = 2 m 70 cmLength of cloth for his pyjamas =2 m 60 cmTotal length of cloth bought = 5 m 30 cm |
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| 31. |
sin 2A = 2 sin A is true when A |
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Answer» sin(2A) = 2 sin(A)2 sin (A) cos(A) = 2 sin(A)cos (A) = 1soA = 0° |
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| 32. |
मदन नर S e Y /4 /4&7 of Light कह 4 jlnf”"j/‘ o 140 /fiy प्र 24lets ©n के y-axels ot ८ %' A cand 4 7jtaf&c ८० ््द «४ ८दनल्छ- न it € 53) G- z/! alf“४: ot 4 WJ- S g e qr%’j,PN |
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| 33. |
rms is . Find tUP Diploma 199oTSum of the first two terms of a decreasing GP. is and sum of infinite tecommon ratio and the first term. |
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| 34. |
|x 3 71| 10. यदि 2 x 2 = 0 का एक मूल x =-9 है,176xतो दूसरे दो मूल है(A) 2,7(B) 2,-7(C) -2, -7 (D) -2,7 |
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| 35. |
51.If we rotate a right angled triangle of height 10 cm and base 6 cm about its base we get(I) cone of height 6 cm and base diameter 10 cm.(2) cone of height 10 cm and base diameter 6 cm.(3) cone of height 10 cm and base diameter 12 cm.(4) cone of height 6 cm and base diameter 20 cm. |
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| 36. |
TIONI (Area of A Trapezium and A Polygon)2025ILLUSTRATIVE EXAMPLESind the area of the pentagon ABCDE shown in Fig. 20.40, if AD8AH-6 cm, AG -4 cm, AF 3 cm, BFem, CH-3 cm and EG -2.5 em.crn.,Fig. 20.40 |
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| 37. |
If $ A+B=90^{\circ}, $ then prove that $ \sqrt{\frac{t a n A \text { tan } B+t a n A \cot B}{\sin A \sec B}-\frac{\sin ^{2} B}{\cos ^{2} B}}=\tan A $ |
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Answer» LHS = root tan a tan b + tan a cot b/sin a sec b - sin^2 b/cos^2 a = root tan a tan(90-a) + tan a cot(90-a)/sin a sec(90-a) - sin^2(90-a)/cos^2 a = root tan a.cot a + tan a.tana/sin a.cosec a - cos^2 a/cos^2 a = root 1+tan^2 a/1 - 1 = root tan^2 a = tan a. |
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| 38. |
27. If tan A = n tan B and sin A = m sin B. Prove that :2cos A = mp-1 |
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| 39. |
\tan n=\frac{5}{6} \text { and } \tan 13=\frac{1}{11}A+B=\frac{\pi}{4} |
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| 40. |
७ 2४07 >ुड020 7000 7 नरe o£71=0087VEOV~DAOYV ‘& LE9 |
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Answer» Angle DOC + angle BOC = 180(linear pair )DOC = 180-125angle DOC = 55DOC + DCO +ODC = 180(sum of all angle )angle DCO = 180-125DCO = 55Angle OAB = OCD (Alternate an.)OAB = 55. |
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| 41. |
neer 18 77 cm6. The diameter ofthe wheel of a car is 70 em. How many revolutions will it make to travel1.65 km? |
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| 42. |
is. Ramu bought 2 m 70 em cloth for his shirt and 2 m 60 cm cloth for his pytamas13.total length of cloth bought by him. |
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| 43. |
End the zelo ot P(x): 2x47 |
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Answer» What is the value of x P(x): 2x+7 =2x+7=0 2x=-7x=-7/2= -3.5 |
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| 44. |
7Inman 713. Find the HCF of 252525 and 363636. |
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Answer» 10101 is the HCF of 252525 and 363636 Answer: 10101 is the H.C.F. of 252525 and 363636. 252525/5=50505/5=10101; 363636/6=60606/6=10101 |
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| 45. |
Find the area of this park using both ways. Can you suggest soof finding its area?28 cm111. Diagram of the adjacent picture frame has outer dimensions 2and inner dimensions 16 cm × 20 cm. Find the area of eathe frame, if the width of each section is same. |
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| 46. |
(a) Find the value of 'x' and 'y'if71 I 10 7(b) Sonig ld |
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| 47. |
nu the vatue of k for which solutions of the following pair of linear equations f unique so: 3x-3y-5 |
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| 48. |
4 identify the numerical coefficients of terms (other than constants)in the following6) 5 32(iv) 100m+ 1000n) p+7p i)12a+0. b(vi) 3.14Identify terms which ronta) 1+1+P+() x + 2xy + 3yix) 0.1 y +0.01s.(a) |
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Answer» 1. -3 2. 1,1,13. 1,2,34. 100,1000 Thanks for the answers 🐒 |
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| 49. |
2. ....2. ¥ 'S Mci&dfij I/)7\0{; . ot P)\yc[,u/g,}—— न e } [5 4९25 thiactin |
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| 50. |
कक न कह के कक B e रूc> o o o ८ (seco— c, o) = Grore। Ll ot (p\mh =कि £ i |
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