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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
64 factors prime number |
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Answer» 64=2×32=2×2×16=2×2×2×8=2×2×2×2×4=2×2×2×2×2×2 |
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| 2. |
a. 2197 133. The volume of acubical box is 110592 cm. Find the length of each side of theboxb. 46656 |
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| 3. |
- Find the percentage of pure gold in 22-carat gold, if 24-carat gold is 100% pure.Hint. 22-carat gold contains 22 parts out of 24 parts.2ojopercentage of pure gold in it = 5x10024 |
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| 4. |
22. Find the percentage of pure gold in 22-carat gold, if 24-carat gold is 100% pure,Hint. 22-carat gold contains 22 parts out of 24 parts.percentage of pure gold in it = ( 22 x 100%=912 %.24 |
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| 5. |
3.Find the percentage of pure gold in 22-carat gold, if 24-carat gold is 100% pure. |
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| 6. |
C gets..Find the percentage of pure gold in 22-carat gold, if 24-carat gold is 100% pure. |
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| 7. |
A bag contain five black seven red and three white balls.A ball is drawn from the bag at random.Find the probability that the ball drawn is 1 red 2 black or white 3 not black |
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| 8. |
Ex.2. Three urns contain balls as follows:urn I: 1 white, 2 red and 3 blackurn II : 2 white, 3 red and 1 blackurn III: 3 white, 1 red and 2 blackAn urn is chosen at random and two balls are drawn from it. If one ball is red andthe other is white, what is the probability that the balls come from um II |
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| 9. |
A bag contains five black seven red and three white balls. A ball is drawn from the bag at random. Find the probability that the ball drawn is 1 red 2 black or white 3 not black |
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| 10. |
dactćśCIRCLESn an equilateral triangle, prove that the centroid and centre of the cr22centre) coincide.15.25circum-circlecumarde |
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Answer» Thank you very much........ |
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| 11. |
multiplicative inverse ofI w(vi) (2-5 ÷ 2² ) x 2-2 C2 |
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Answer» (1/2)-5=2×2×2×2×2=32 |
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| 12. |
_ { p \rightarrow 0 } \frac { \sqrt { 4 + p } - \sqrt { 4 - p } } { p } |
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| 13. |
EXERCISE 7.2L. Find the cube root of each of the following numbers by prime factonio0 64(v) 15625(ix) 175616(ii) 512(vi) 13824(x) 91125(ii) 10648(vi) 110592 |
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| 14. |
find the cube root of following numbers by prime factorization method the numbers are 27000 15625 13824 110592 46656 175616 91125 |
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Answer» cube root of 27000=(30)^3=30; 15625=(25)^3=25; 13824=(24)^3=24, 110592=(48)^3=48; 46656=(36)^3=36; 175616=(56)^3=56 ; 91125=(45)^3=45; 1) 27000/3=9000/3=3000/3= =1000/2=500/2=250/5=50/5=10/2=5; 2)15625/5=3125/5=625/5= 125/5=25/5=5; 3) 13824/2=6912/3=2304/2= 1152/2=576/2=288/2=144/2=72/2=36/2=18/2=9/3=3; 4) 110592/2=55296/2= 27648/2=13824/2=6912/2= 3456/2=1728/2=864/2 = 432/2=216/2=108/2=54/2= 27/3=9/3=3; |
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| 15. |
Find the LCM of 175616 |
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| 16. |
er If the cube root of 175616 ist50 then find the valtue of175.616+ Vo.175616+V0.000175616 |
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Answer» cuberoot(175.616)+cuberoot(0.175616)+cuberoot(0.000175616)=5.6+0.56+0.056=6.216 |
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| 17. |
\lim _ { p \rightarrow 0 } \frac { \sqrt { 4 + p } - \sqrt { 4 - p } } { p } |
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| 18. |
cube root of 175616 |
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Answer» =2x2x2x2x2x2x2x2x2x7x7x7 =2 x 2 x 2 x 7 =56 Answer = 56 is the cube root of 175616 |
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| 19. |
درfind AB and BA0.24 - IfA=21B=0 |
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| 20. |
\log _ { 2 } p = q \text { and } \log _ { 4 } r = p \text { prove that } \log _ { 4 } p = p q |
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| 21. |
Q10. (a + b)2 (a - b)2 is possible, if:a) ab-0b) ba-0c) both a and bd) of the above |
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| 22. |
โ0 cicles ofradi 5 ㎝ and 3 cm intersect at two points and the distance betweentheir centres is 4 cm. Find the length of the common chord.1e segments of |
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| 23. |
There are 6 green, 5 red and 4 blue identical balls in a bag. One ball is drawnat random from the bag. The probability that the ball drawn is not red is |
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Answer» given the balls are 6 green 5 red 4 blue..total = 6+5+4 = 15 balls now probability that the ball drawn is not red is = {6+4}/15 = 10/15 = 2/3. |
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| 24. |
Vi25vi |
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Answer» 2/5÷ 1(1/2)= 2/5÷(3/2)= 2/5×2/3= 4/15 |
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| 25. |
u1 Dislie BIE ४५ 1० 6109 - O UBY 2 ‘- = 6 509 B “2T |
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Answer» tan theeta- cot theeta |
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| 26. |
EXERCISE 6.1What will be the unit digit of the squares of the following numbers?(i) 81(iv) 3853(vii) 99880(ii)272(ili) 799(v) 1234 -(vi 26387(vi) 52698VI)(ix) 12796 6 (x) 55555 |
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Answer» 1)12)43)14)95)66)97)48)09)610)5 |
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| 27. |
ey BIE Lk 1 दा न विवि पड इक 1 16 lagh kephieh kBदे (V-UOTRS) १६-७७ |
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| 28. |
oy lakgee BIEदा e ok © L6 7SPAYES Tei Uk Jumb piin पे R € e 6T X e |
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| 29. |
QetfFind the satue 5. i) t722 2 in 18? (ncos8 biknse0:sin 180 (vi)cos36 (vi)sin54 |
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| 30. |
6. Find the additive inverse of each of the following:(iii) -18(vi) -16(vi) 5(vii)(viii) 0 |
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Answer» find additive inverse |
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| 31. |
8.ft (If) P(A)-0.4, P(B)-0. 8, P(BA)-0.6(find), |
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| 32. |
\frac{2^{p-8} \times 8^{q-4}}{2^{p-11} \times 8^{q-5}} |
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| 33. |
factorise6 p + 8 p^2 - 4 p^3 |
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Answer» 6p + 8p² -4p³2p( 3 + 4p -2p²) |
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| 34. |
p ^ { 3 } + 8 q ^ { 3 } \text { if } p + 2 q = 8 \text { and } p q = 6 |
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| 35. |
21. Cost of 105 envelopes is Rs 35. How many envelopes can be purchased for Rs 10 |
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Answer» Number of envelopes in ₹35=105Number of envelopes in ₹1=105/35=3 Number of envelopes in ₹10=3*10=30 cost of 105 envelopes is 350 rupees. how many envelopes can be purchased for 100 rupees |
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| 36. |
3. If three apples cost Rs 15, how much doesone apple cost? How much do two applescost? How much do 10 apples cost? |
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Answer» Cost of three apples is ₹15cost of one apple is ₹15/3 = ₹5so cost two apples is ₹5 × 2 = ₹10cost of 10 apples is ₹5 × 10 = ₹50 |
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| 37. |
Jhcle,topoisefind the cost of many articles, we multiplyarticles, to find the cost of one article, we dvide.know methe cost of manytoe knowLet's Do3 the correct option:15. What is the cost of three pens?(b) 15many 10 paise coin makes a rupee ?(b) 102) 30(c) 45(d) 60(c) 20(d) 2al5742 is:he sum of 252 andhi o92) 994(d) 984 |
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Answer» 45 because cost of one pen is 15if we multiply 3 with 15then we get the answer |
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| 38. |
the cost of 5 dolls or 6 balls is 15. What will ne the cost of 10 dolls and 18 baals? |
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Answer» Which of the following can not be used for measurement of time cost of 10 dolls= 30and cost of 18 balls= 3×15= 45 cidxudifpgiEtt62din Hi pyar www1234567t 22din Hi 75 is the ans 10, 18 we add to get 30 15 ×5 =75 cost of 10 dolls:30cost of 18 balls:3×15=45 |
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| 39. |
1.Calculate the HCF 013 x 5 and 32 Ă 52. |
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Answer» 3^3×5=135ie in the simplest form....3×3×3×5=135 3^2×5^2=225in simplest form.....3×3×5×5 Therefore HCF=135=3×3×3×5225=3×3×5×5taking the common factorHcf=3×3×5= 45 |
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| 40. |
9. 5.5 of (2.25 06) 0.75 013 |
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| 41. |
me roorle0.0no+013kapressasarational |
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| 42. |
UV mpe LULUWD I WirewWrite short notes on :i) Users of accounting information.ii) Concepts in accounting.09:17:42 |
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Answer» The accounting process provides financial data for a broad range of individuals whose objectives in studying thedata vary widely. Three primary usersof accounting information were previously identified, Internal users, External users, and Government/ IRS. Each group uses accounting information differently, and requires the information to be presented differently. Accounting supplies managers and owners with significant financial data that is useful for decision making. This type of accounting in generally referred to as managerial accounting. Some of the ways internal users employaccounting informationinclude the following: Assessing how management has discharged its responsibility for protecting and managing the company’s resources Shapingdecisions about when to borrow or invest company resources Shaping decisions about expansion or downsizing Accounting conceptrefers to the basic assumptions and rules and principles which work as the basis of recording of business transactions and preparingaccounts. Thisconceptassumes that, foraccountingpurposes, the business enterprise and its owners are two separate independent entities. |
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| 43. |
150(iv) 18 - 3p - 11q+5p9 – 2pq- + 5p?q #4pʻq- 3pq + 5pq? - 8p + 74 -10 07 EZTETI |
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Answer» 18-3p-11q+5pq-2pq^2+5qp^2 -4qp^2-3qp+5pq^2-8p+7q-10=8-11p-4q+2pq+3pq^2 |
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| 44. |
All the carbon bonds in a saturatedhydrocarbon electrons. |
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Answer» They share electronsall the carbon bonds in a saturated hydrocarbon share electrons because covalent bond takes place here are they are neither ready to loose nor ready to gain electronshence, each carbon atom forms 3 single bonds with 3 hydrogen atoms and 1 single bond with the other carbon atom |
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| 45. |
рди рдиреА iLk sfj |
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| 46. |
4p - 7 = 1 |
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Answer» 4.12 is the right answer p= 33/8 is correct answer 33/8 is the correct answer 4p-7=9.54p=9.5+74p=16.5p=16.5/4 1. in fraction p= 165/40 = 33/82. In mixed fractionp= 4 and 1/83. in decimalp= 4.125 p equals to 4.125 amswer this question answer is 5/8. 4p- 7= 19/2 4p = 19/2 + 7 4p = 33/7 p =33/28 33/8 is the right answer (19÷2)+7=33÷2 = 33÷8 4p-7=19/2 , 4p=19/7+7, 4p=68/7 ,p=68/7×4 ,p=17/7 4p*2-7*2=198p-14=198p=19+148p=33P=33/8 p = 33/8 is the correct answer right answer is 33/8 hoga 4p-7=19/24p=19/2+74p=19+14/2=33/2p =33/2into4=p 33/8 p=33/8 is the right answer p=8.25 is right answer 4p-14=194p=17+144p=31p=31/4 4p - 7=19/24p=19/2 + 74p=19/2 +14/24p=33/2p=33/2×4p=132/2p=66 the value of p is 33/2 4p-7=19/2 8p-14=198p=19+148p=33p=33/8 right the correct answer -12 33/8 is the correct answer..... 4p-7=19/22(4p-7)=198p-14=198p=19+148p=33p=33/8 33/2 is a correct answer the answer of this question is P=47 16.5/4 is the answer p=33/8 is the correct answer 33/8 hoga yr iska answer bhai 4p= (19/2+7)=(33/2)p=33/4 33/8 right answer i know it is correct answer 4p-7=19/24p=19/2-74p=5/2p=5/8 4p=19/2+7 4p=33/2p=33/8 4p=19/7+74p =19+14/24p=33/2p=33/2/4p=4.125 p= 33/8 is the answer of the question p = 33/8 is the best answer of the question p = 33/8 is the answer p = 33/ 8 is unique answer p=33/8 is correct answer |
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| 47. |
LK d-1io ) |
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Answer» In mathematics, a ratio is a relationship between two numbers indicating how many times the first number contains the second. For example, if a bowl of fruit contains eight oranges and six lemons, then the ratio of oranges to lemons is eight to six. Please hit the like button if this helped you out |
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| 48. |
/13 Lk 21४ 1% ०४). पथ हट ‘d=.gLushk 81. |
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| 49. |
CHXT+ X 5 [४2% रोड डि2 «लि5 * [४2% ९ डि22] 5०205 98. |
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| 50. |
If 2x__ = 4 , then find the value of 27x3-0138x3 |
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Answer» Like my answer if you find it useful! thank u Like my answer if you find it useful! |
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