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a) average = 78+35+69+84+54 /5

= 320/5

= 64

let the number be xx+17=54;x=37

total cp=225+15=240rssp=300gain=300-240=60gain%=60*100/240=25%

25% is a right answer

25°/° is the correct answer

total price= 225+15=240gain=300-240=60%gain= 60*100/240=25%It is correct answer.

ask only one question

Cp=200Sp=225Profit=225-200=25Profit%=(25/200)*10012.5%

Right answer is 12.5%

Profit= 25 rs% = (25/200) *100 = 12.5%

cost price = 200 rs.selling price = 225 rs.gain = selling price - cost price = 225 - 200 =25 rs.gain peecent = gain/cost price × 100 =25/200 ×100=12.5%his gain peecent is 12.5%.

225- 200 = 25

Gain % = 25/200 ×100 = 12.5%

Answer:

Rs 675

Step-by-step explanation:

Assuming triangular piece of land is Right angle triangle

Then Perpendicular on 15 m side would be p

Area = (1/2) * Base * height

=> (1/2) * 15 * p = 150

=> p = 20

Hypotenuse² = Perpendicular² + Base²

=> Hypotenuse² = 20² + 15²

=> Hypotenuse² = 625

=> Hypotenuse = 25

Remaining two sides length = 20 + 25 = 45 m

fencing the 15 m side costs Rs. 225

1 m cost = 225/15 = Rs 15 per m

45 m cost = 45 * 15 = Rs 675

cost of fencing the remaining land = Rs 675

cost of fencing the remaining land= Rs 675.please like as best for the points

3√6or 3√2*√37.34 is the answer

In the absence of a formal identity document, adriver's licensemay be accepted in many countries for identity verification. Some countries do not accept driver's licenses for identification, often because in those countries they do not expire as documents and can be old or easily forged. Most countries acceptpassportsas a form of identification. Some countries require all people to have an identity document available at any time. Many countries require all foreigners to have a passport or occasionally a national identity card from their home country available at any time if they do not have a residence permit in the country.

But the real answer is 49750

Let sqrt(8 + 5i) = a + ib where a is real part and b is imaginary part.

squaring both sides, 8 - 5i = a² + (ib)² + 2a.ib ⇒8 - 5i = a² - b² + i(2ab)

Compare both sides , a² - b² = 8 and 2ab = -5 (a² + b²)² = (a² - b²)² + 4a²b² = 8² + (-5)² = 64 + 25 = 89 a² + b² = ±√89

Now, a² - b² + a² + b² = 8 ± √89 2a² = 8 ± √89 ⇒a² = 4 ± √(89/4) a = √(4 + √(89/4)) = 2.95 find b=0.84

Then, a and b put in a + ib a + ib is square root of 8 -5ihence, 2.95+0.84i

thanks

ans should be wrong because there is no resistance. take palcw

solving

x=2y=4 Area of triangle =1/2*base *height =4 squarevunits

your right sudhakar kumari hi

Given that :cos A = 2/5

we have to find :4 +4tan²A = ?

solution :-we know that :(1 + tan² x ) = sec²xandsecx = 1 / cos x

Here,4 + 4 tan² A = 4 (1 + tan² A)

= 4 * sec²A

= 4 / cos²A

= 4 * (5/2)²

= 4 * 25 / 4

= 25

Given that :cos A = 2/5

we have to find :4 +4tan²A = ?

solution :-we know that :(1 + tan² x ) = sec²xandsecx = 1 / cos x

Here,4 + 4 tan² A = 4 (1 + tan² A)

= 4 * sec²A

= 4 / cos²A

= 4 * (5/2)²

= 4 * 25 / 4

= 25

Momentum = mass * velocityMass = 200 g =. 2kgMomentum =.2*5 = 1kg*m/s

Vsec^2x+ cosec^2x=Vtanx^2+1^+cotx^2+1=Vtanx^2+ cotx^2+2=V(tanx+cotx)^2= tanx + cotx

bb

is it correct answer

5b-ab-ab+5a5b-2ab+5a will be the answer

4+3√5/4-3√5=a+b√4

(4+3√5)/(4-3√5)×(4+3√5)/4+3√5)

(4+3√5)^2/(4)^2-(3√5)^2

(4)^2+(3√5)^2+2×4×3√5/16-45

16+45+24√5/-29

61+24√5/-29

(61/-29)+(24√5)/-29=a+b√5

so,a=61/-29

b=24/-29

correct

Length of the fence (in metres) = Total cost / Rate = 5280/24 = 220So, circumference of the field = 220 mTherefore, if r metres is the radius of the field, then2πr = 220

or, 2 × 22/7× r = 220or, r = (220 × 7)/(2 × 22) = 35

i.e., radius of the field is 35 m.

Therefore, area of the field = πr2 = 22/7 × 35 × 35 m2 = 22 × 5 × 35 m2

Now, cost of ploughing 1 m2 of the field = Rs 0.50So, total cost of ploughing the field = Rs 22 × 5 × 35 × 0.50 = Rs 1925

A : B = 1 : 2

B : C= 3 : 5

Suppose a,b,c is x,y,z respectively

So x + y+ z = 380

x : y = 1 :2

x = y/2

y : z = 3 : 5

z = 5y / 3

So set up the equation

x +y +z = 380

y / 2 + y + 5y / 3

19y / 6 = 380

y = 120

x = y/2

x = 120 / 2

x = 60

z = 5y / 3z = 5 * 120 / 3

z = 200

So 60 + 120 + 200 = 380

Given Reactangular Park Length l = 20 m, Breadth b = 50 m

Shortest route will be equal toDiagonal of Reactangular parkThen,Shortest Distance = (l^2 + b^2)^2= (20*20 + 50*50)^2= (400 + 2500)^2= (2900)^2= 10*sqroot(29) m

According to laws of indicesa^m*a^n=a^m+nand a^m/a^n=a^m-nhence9^3*9^2=9^3+2=9^5hence9^5/9^5=1

18 is answer of the question

Hitesh reads less because (6/8)<6.

Selling price of two watchesSP = 2*1955 = 3910

Cost price of first watch = CP1Cost price of second watch = CP2

1955 = CP1(1 + 15/100)CP1 = 1955*20/23 = 85*20 = 1700

1955 = CP2(1 - 15/100)CP2 = 1955*20/17 = 115*20 = 2300

Total Cost price CP = 1700 + 2300 = 4000

Loss% = [(CP - SP) /CP]*100= [(4000 - 1955)/4000]*100= 45/40= 1.125 %

2/2=1one wholeoption C is right

2/2=1one whole(c) is the right answer

2/21one wholecorrect answer

2/2 = 1One whole is the right answer

option c is the right answer

Circumference of circle = pi × d

= 3.14 × 10 cm

= 31.4 cm

CP of 11 toffee=₹10CP of 1 toffee=₹10/11in second conditionCP of 9 toffee =₹10CP of 1 toffee=₹10/9therefore, CP of both toffees=₹10/11+₹10/9==₹200/99so, cp of 1 toffee=200/99÷2==₹100/99sp of 1 toffee =₹1(given)loss=cp-sp=100/99-1=₹1/99loss percent=1/99/100/99*100=1 percent lossans =1%