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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
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1.The marked price of a pant is 1,250 and the shopkeeper allows a discount of 8%on it. Find the discount and the selling price of the pant. |
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Answer» Marked price of pant = Rs 1250 Discount by shopkeeper = 8% Thus,Discount on pant= 8/100 * 1250= 4/5 * 125= 4*25= Rs 100 Selling price of pant= 1250 - 100= Rs 1150 |
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| 2. |
A circular ground whose diameter is 35 metres, has a 1.4 m broad garden around it.What is the area of the garden in square metres? |
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Answer» thanks |
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| 3. |
DFind the solution of the EquationGirรณct coge-I sinx. 1068 |
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13. If'g and jß be two distinc rcal numbers satisfying the equationa cosx + b sinx = c, prove thatsin (α +β)"…2th2tan(α+β)=a2-b22 a ba + b()(i) |
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| 5. |
3findthe principal value of the equation sinx = |
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Answer» sin60°=sin√3/2 sin60°=π/3sin(π-π/3)=2π/3 |
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| 6. |
\begin{array} { l } { \text { If } ^ { n - 1 } C _ { r } : ^ { n } C _ { r } : ^ { n + 1 } C _ { r } = 6 : 9 : 13 , \text { then find the } } \\ { \text { values of } n \text { and } r . } \end{array} |
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Answer» thanks a lot Girija Madan |
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| 7. |
Area of a field is 6724 m2. How much wire is required to fencethe field? |
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Answer» Area= (side)^2(side)^2 = 6724 m^2side = 82 mwire required to fence the field= perimeter of the field = 4 × 82m = 328m |
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| 8. |
eA wire is bent to form a rectangle of28 m x 10mIt is again straightened and bent now to formasquare. What is the side of the square so formed? |
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Answer» The perimeter should remain constant. Perimeter of rectangle= 2(l+b) =2(28+10) =2(38)=76 Let the side of the square be a. perimeter of square is 4a. 4a=76 a=19 mSo, the side of the square is 19m. |
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| 9. |
Q.16. Find the derivative of Sinx by first principle |
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Answer» <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle displaystyle="true"> <mi>f</mi> <mo>′</mo> <mrow> <mo>(</mo> <mi>x</mi> <mo>)</mo> </mrow> <mo>=</mo> <munder> <mo>lim</mo> <mrow> <mi>h</mi> <mo>→</mo> <mn>0</mn> </mrow> </munder> <mfrac> |
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| 10. |
7.There are 2 different necklaces made of blackand white beads. The first necklace has 25 blackand 25 white beads. The second necklace has 10black and 15 white beads. Which necklace hasthe maximum percentage of black beads? |
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| 11. |
^ { 2 n } C _ { 2 } : C _ { 2 } = 12 : 1 |
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Answer» but this answer is not satisfie any doubt so put this answer in the question The solution is correct. Please check your question. The question might be 2nC3 : nC3. |
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| 12. |
C ( 2 n , 3 ) : C ( n , 3 ) = 12 : 1 |
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Answer» ²ⁿC₃ : ⁿC₂ = 12 : 1 use the concept, ⁿCₐ =n!/a!(n-a)! 2n(2n-1)(2n-2)(2n-3)!/3!(2n-3)! : n(n-1)(n-2)!/2!(n-2)! = 12 : 1 {2n(2n -1)(2n-1)/6}/{n(n-1)/2} = 12/1 {4n(2n-1)(n-1)}/3{n(n-1)}=12 4(2n-1)/3 = 12 2n - 1 = 9 2n = 10 n = 5 |
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| 13. |
14. Find the area of a square plot of land whose each side measuresmetres. |
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| 14. |
8. Find the area of a square plot of land whose each side measures 8-metres. |
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Answer» 289/4 m^2 is the area of the square plot. |
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| 15. |
78. यदि 3 : 2-2 >3, 8: ए >4:5 हो हो4 : (0 का मान ज्ञात कीजिए |
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| 16. |
Area of a square plot is 2304 m2. Find the side of the square plot. |
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| 17. |
7:Area of a square plot is 2304 m. Find the side of the square plot.18 |
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Answer» Bc answer is 576m. If you divide by4 |
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| 18. |
4. The perimeter of a square plot is 40m. Find the length of one side of this plot |
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Answer» thanks |
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| 19. |
ts placeof four digits each can be formed with the digits 0, 1,3,5,6 (assumingely, 5 and 7d up by 5 or 7w many numbers aiteinfo repeny automoblmobile licence plates can be mad if the iscrpto on eh conais |
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Answer» We have the digits, 0, 1, 3, 5 and 6. We need to make a four digit number with no repetition. We have to decide how many numbers we can choose from for each place value. The first place we can only choose from four numbers. Why? Because if we place a zero in the first place value we actually only have a three digit number. So zero cannot be used. That leaves us with 1, 3, 5 and 6. The second place we cannot use the number we used in the first place BUT we can use zero. So again we have four options. The third and fourth place values can only use whatever numbers are left. The counting principle is used for this problem. It tells us to multiply our number of outcomes for each choice to find the final number of outcomes. SO… 4*4*3*2=96 There are 96 possible four digit integers given 0, 1, 3, 5 and 6 with no repitions Like my answer if you find it useful! |
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| 20. |
Q.6find the principal value of the equation sinx2. |
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| 21. |
Q.1 Simplify the following:3 +25611-77MIRVS() Fatwa + rouva Votva |
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Answer» √11-√7/√11+√7*√11-√7/√11-√7(√11-√7)^2/11-7=11+7-2√77/5=18-2√77/5 |
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| 22. |
The estimated product of 345 and 985 is |
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Answer» 345 × 985 = 3,39,825the estimate product of 345 and 985 is 3,40,000. the estimated product of 345 and 985 is 340000is the best answer 🏆🏆🏆 estimated product =345×985=340000is the answer. estimated product=345×985=340000is the correct answer 🏆🏆🏆 The estimated product of 345&985is 340000Is the best answer 340000 is the best answer 🏆 3, 40,000 is the estimated product by given numbers. |
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| 23. |
2^sinx ➕ 2^cosx>&equal to 2√2 |
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| 24. |
side.11. A wall has dimensions 5 m, 30 cm and 3 m arelength, breadth and height of the wallrespectively. How many bricks of dimensions 20cm Ă 10 cm Ă 7.5 cm will be required to make awall?nf lenrth, breadth and height of a |
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Answer» Hit like if you find it useful! |
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| 25. |
Differentiate w.r.t x :(1) x square sinx (2) x square e x. |
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Answer» thanks Thanks mem |
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| 26. |
Differentiate following function w. r. t. x by using First Principlesinx 2 cosx 3. tan x |
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Answer» 1) |
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| 27. |
n \text { if } ^ { 2 n } C _ { 3 } : ^ { n } C _ { 3 } = 11 : 1 |
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Answer» 2nC3 : nC3 = 11:1 (2n)(2n-1)(2n-2)/(3×2×1) : (n)(n-1)(n-2)/(3×2×1) = 11 : 1 (2n-1)2(n-1):(n-1)(n-2) = 11:1 4n-2 = 11n-22 22-2 = 7n so n = 20/7 |
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^ { n } C _ { 12 } = ^ { n } C _ { 8 } \text { . then find the value of } ^ { n } C _ { 17 } |
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| 29. |
2 n C _ { 3 } : ^ { n } C _ { 2 } = 44 : 3 |
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| 30. |
^ { 2 n } C _ { 3 } : ^ { n } C _ { 3 } = 11 : 1 |
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| 31. |
If $ ^{n} \mathrm{C}_{8}=^{n} \mathrm{C}_{2}, $ find $ ^{n} \mathrm{C}_{2} $ |
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Answer» If ⁿCₓ = ⁿCᵤ then, x + u = n Here, ⁿC₈ = ⁿC₂ so, according to results , n = 8 + 2 = 10 hence, n = 10 Hence 10C2=10!/8!2!=10*9/2=9*5=45 |
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The area of a square plot is 800 m². Find the estimated length of the side of theplot. |
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| 33. |
11) Twenty-seven metres of wire can bebought for 1518.75. Find how muchwire can be bought for 1068.75. |
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Answer» thank you |
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| 34. |
5 A wire is in the shape of square of side 12 cm. If the wire is rebent into a rectangle of length 14 cm, find itsbreadth. Which figure encloses more area and by how much? |
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| 35. |
Estimated measurement(a) Length of your spoon |
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Answer» Average Length of spoon is about 5 to 6 inches |
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| 36. |
2 marks each2. Attempt the following:(1) Total surface area of a cuboidal box is 47.5 cmIf its length is 5 cm and height is 1.5 cm, find itsbreadth.Ans. |
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Answer» Let breadth of cubical box is x Then,Length l = 5 cm, Height h = 1.5 cm Volume = length*breadth*height = 5*x*1.5 Thus, 47.5 = 5*x*1.5x = 47.5/7.5x = 6.34 cm Therefore, breadth is 6.34 cm |
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| 37. |
(v) 594 x 248(iv) 523 x 7711. Find the estimated quotient forle estimated quotient for each of the following.(i) 87 - 271. Find the estimated quotient for each of the follo(ii) 98:32 |
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Answer» 87/27= as 27*3= 81so 3 and remainder= 6 98/32= 32*3= 96so quotient = 3remainder = 2 |
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| 38. |
Try ThesePrepare a table of estimated mean, deviations of the above cases. Observethe average of deviations with the difference of estimated mean and actualmean. What do you infer?Hint: Compare with average deviations) |
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Answer» Where are the cases? |
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| 39. |
5 Find the volume of a cuboid having length 5 m 20 cm, breadth 4 cm 30 cmond heigt3 m 40 cm,rsibanhume of a cube with side 1 m 60 cm. |
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Answer» length,l=5m20cm=5.20mbreadth,b=4m30cm=4.30mheight,h=3m40cm=3.40m volume=lbh=5.2*4.3*3.4 V=76.024m³ |
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| 40. |
3. Thomas bought 3 DVD's for $14.50 each, amusic CD for $9.99, and a computer game for$48. If the sales tax rate is 8.2%, what is the totalcost of Thomas' purchases to the nearest cent?A. $78.43B. $101.49C. $109.81D. $118.71 |
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Answer» Total price=14.50+9.99+48=72.49 $After sales tax:Price=72.49+8.2% of 72.4972.49+5.94= $ 78.43 |
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| 41. |
Find the volume of a box if its length, breadth and height are 20 cm, 10.5 cm gad8 cm respectively1. |
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| 42. |
(1) The area of the vertical (lateral) surfaces of a brick is 480 cm2. Its height andlength are 8 cm and 20 cm respectively. Find its breadth. |
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| 43. |
A man donates 10 aluminium buckets to an orphanage. A bucket made of aluminium isof height 20 cm and has its upper and lowest ends of radius 36 cm and 21 cm respectivelyFind the cost of preparing 10 buckets if the cost of aluminium sheet is R 42 per 100 cm2 |
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Answer» Answer: Rs 4950 Step-by-step explanation: Find the surface area of 1 bucket: Surface Area = π(R - r)√[(R - r)² + h²] Surface Area = π(36 - 21)√[(36 - 21)² + 20²] Surface Area = 375π cm² Find the surface area of 10 buckets: 1 bucket = 375π cm² 10 buckets = 375π x 10 = 3750π cm² Find the cost: 100 cm² = Rs 42 3750π cm² = 42/100 x 3750π = Rs 4950 Answer: The cost is Rs 4950 |
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| 44. |
15 From a point, 36 m above the surface of alake, the angle of elevation of a bird isobserved to be 30° and angle of depression ofits image in the water of the lake is observedto be 60°. Find the actual height of the birdabove the surface of the lake.rethe anle of elevation of the |
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| 45. |
YULJUUNIJ with short calculation:17. The length, breadth and height of a cuboidal box are 20 cm, 15 cm and 12 cm respectively. Find its total surface20 Marks)2area.LX Byly.c |
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| 46. |
Example 1 Mary wants to decorate her Christmastree. She wants to place the tree on a wooden boxcovered with coloured paper with picture of SantaClaus on it (see Fig. 13.4). She must know the exactquantity of paper to buy for this purpose. If the boxhas length, breadth and height as 80 cm, 40 cm and20 cm respectively how many square sheets of paperof side 40 cm would she require?Solution : Since Mary wants to paste the paper onthe outer surface of the box; the quantity of paperrequired would be equal to the surface area of thebox which is of the shape of a cuboid. The dimensionsFig. 13.4of the box are: |
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| 47. |
Find the time if 8000 lent at CL at 20% ato 8820; the interest being compoquarterly. |
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Answer» A = P * [1 + (r/100)]^(n/4)=> 8820 = 8000*[ 1+ 20/100]^(n/4)=> 8820/8000 = (6/5)^(n/4)=> (21/20)² = (6/5)^(n/4)=> n = 2.14 yrs Please hit the like button if this helped you |
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| 48. |
b) If (52+33)-(62-7/3)-av2+b/3, then find the values of a and b.mrime not compO |
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One side of a rectangle is 12 cmand its perimeter is 40 cm. Find its area |
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| 50. |
5. Find the smallest number, when divided by 36, 54 and 72 leaves no remaineJILLA |
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Answer» 216 is the right answer |
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