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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is Dispersion? |
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| 2. |
EXAMPLE 141 Calculate the formal charge oneach atoms of(i) Carbonate ion and(ii) S02 molecule |
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Answer» Carbonate:Oxy is -2. Carbon is +4 |
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| 3. |
(sp+2)(ps) * |
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| 4. |
A. 1. Define: (1) Fractions |
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Answer» fraction means parts of a hole for eg 5th part of pizza fraction of a number is the parts of the whole number numerical quantity is not a whole number a numerical quantity that is not a whole number |
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| 5. |
1. Define matrix. |
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Answer» A matrix is a collection of numbers arranged into a fixed number of rows and columns. |
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| 6. |
C)NC(d) CN m2(xiv) The temperature coefficient is negative for(a) Brass2. What is Coulomb's lom?Wei(b) Mercury(c) CuSO, solution (d) Siliver20t is (niUom. |
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Answer» Mercury has negative temperature coefficient. |
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| 7. |
1 Define the terms:(a) Mean(c) Data |
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Answer» 1.Thestatiscal mean refers to themeanor average that is used to derive the central tendency of the data in question. It is determined by adding all the data points in a population and then dividing the total by the number of points. The resulting number is known as themeanor the average. 2. data can be defined as facts or figures from which conclusion can be drawn. |
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| 8. |
(i) What do you mean by a convex quadrilateral?(ii) Define a regular polygon.3. |
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| 9. |
How many 250 ml packets can be packed from 10 liter milk? |
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Answer» pabjkwbbxj so sorry 1 l = 1000 ml = 4 x 250 mL 10 L = 40 x 250 mL Therefore, 40 packets of 250 mL can be packed. |
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| 10. |
Renu has a cumulative deposit account200 per month at 10% per annum. If sheR 6775 at the time of maturity, find the totaltfor which the account was held. |
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| 11. |
After 12 years, I shall be 3 times as oldwas 4 years ago. Find my present age.2. |
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Answer» thanks |
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| 12. |
---28. 5 years ago, Gecta's age was 3 times that of Kamla's age. 10 yearslater, Geeta's age will be 2 times that of Kamla's age. Find theirpresent anec) |
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Answer» Let present age of Geeta be x and Kamla be y. Five years agoGeeta's age = 3 (Kamla's age) (x - 5) = 3(y - 5) x - 5 = 3y - 15 x - 3y = -10 . . . . . (1) Ten years laterGeeta's age = 2(Kamla's age) (x + 10) = 2(y + 10) x + 10 = 2y + 20 x - 2y = 10 . . . . . (2) (1) - (2) -y = -20 y = 20 Substitute in (1) x - 3(20) = -10 x - 60 = -10 x = 50 Geeta's age = 50 yearsKamla's age = 20 years |
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| 13. |
The present age of a women is 3 years more than three times the age of her daughter. Three years later,the womens age will be 10 years more than twice the age of her daughter.find the height of this parallelogram |
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| 14. |
s his daughter, "Seven years ago, I was seven times as old as you were thenAlso, three years from now, I shall be three times as old as you will be." (Isn't thiinteresting?) Represent this situation algebraically and graphically-2000 later, she buys anothe |
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| 15. |
Two years ago, a man was five times as old as his son.Two years later,his age will be S more than three times the age of the son. Find thepresent ages of the man and his son.CESE 2004 |
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| 16. |
2.Rajan purchased 250 packets of blades at the rate of 8 per packet. He sold 70%of the packets at the rate of 11 per packet and remaining packets at the rate of9 per packet. Find his gain per cent. |
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Answer» Cost price of 250 packets of blades CP = 250*8 = Rs 2000 Selling price of blades SP= (70/100)*250*11 + (30/100)*250*9= 25*77 + 75*9= 1925 + 675= 2600 Therefore,Gain % = [(SP - CP)/CP]×100= [(2600 - 2000)/2000]*100= (600/20)= 30% |
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| 17. |
Rajan has750.50. He purchase fruits for 438.95. How muchmoney does he has now? |
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Answer» Money left with Rajan = 750.50 - 438.95 = 311.55 |
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| 18. |
n Rajan has 750.50. He purchase fruits for 438.95. How much money does he has now |
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Answer» Money left with Rajan = 750.50 - 438.95 = 311.55 |
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| 19. |
I06 puy-Taller Owns a field of area 1000m2. He wants to plant fruit trees in it. He has sum ofRs. 2400 to purchase young trees. He has the choice of two types of trees. Type A requires10m2 of ground per tree and costs Rs. 30 per tree and, type B requires 20m2 of ground pertree and costs Rs.40 per tree. When full grown, a type A tree produces an average of20kg of fruits which can be sold at a profit of Rs. 12 per kg and a type B tree producesan average of 35kg of fruits which can be sold at a profit of Rs.10 per kg. How many ofeach type should be planted to achieve maximum profit when trees are fully grown?What is the maximum profit? 'India is a land of farmers.' Comment. |
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Answer» aap ko ek bhi like Nahi mila mai like Kar deta hoon aap bhi mare comment ko like Kar dijiye ga |
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| 20. |
A pole has to be erected at a point on the boundary of a circular park ofdiameter 13 m in such a way that the difference of its distances from twodiametrically opposite fixed gates A and B on the boundary is 7 m. Is itpossible to do so ? If yes, at what distances from the two gates should thepole be erected ? |
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Answer» Let P be the pole to be erected and A, B be the opposite fixed gates.Given, PA – PB = 7Let PA = a, PB = bHencea – b= 7⇒a= 7 +b...(1)In right ΔPAB,AB2= AP2+ BP2(By Pythagoras theorem)132= a2+ b2169 = (7 +b)2+ b2169 = 49 + 14b + 2b22b2+ 14b – 120 = 0b2+ 7b – 60 = 0b2+ 12b - 5b – 60 = 0b(b + 12) - 5(b + 12) = 0(b + 12)(b – 5) = 0Hence b = 5 or – 12But ‘b’ cannot be negativeTherefore, b = 5⇒a= 7 +5 = 12Hence, PA = 12 m and PB = 5 m |
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| 21. |
rahul borrowed Rs 150 per month from his mother to pay for the art supplies he needed for an evening class. At the end of the course, he owed his mother Rs 600. how long was the course? |
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Answer» Rahul borrowed - 150/month Total money taken - 600 Time taken - 600/150 - 4 month's Fee of the class- 150 per monthTatal amount owed=600No.of months= 600÷1504 months |
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| 22. |
13. Sapna earns 24000 per month. She spends. She spendsof herof her Income and deposits rest of they a bank. How much money does she deposit in the bank each month |
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Answer» Money earned is Rs.24000Money spent is 7/8*24000=Rs. 21000So money deposited is Rs.24000-Rs.21000= Rs.3000 |
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| 23. |
Deepa has a 4-year recurring deposit accountin a bank and deposits 1,800 per month. Ifshe gets 1,08,450 at the time of maturity.find the rate of interest. |
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Answer» Thank you What u done that 1800×48 |
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| 24. |
37. Ruchi Saves Rs. 120 during the first month, Rs. 150 in the next month and Rs. 180 inthe thrid month. If she continues her saving in this pattern, Calculate the amounby Ruchi in 18 months. |
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| 25. |
1.6784 x 786 + 6784 Ă 214 = ? |
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Answer» 6784*786 + 6784*214=6784*(786+214)=6784*1000=6784000 |
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| 26. |
214 |
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Answer» it is a digit number it's a digital number |
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| 27. |
Re vie w Exe rcis eWrite the number name for each of the following in Indian system:a) 18460541)b) 940006 |
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Answer» a)Eighteen lac forty thousands fifty four rupeesb)Nine lac forty thousand six rupees |
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| 28. |
[(1786)2-(214)2]1) 3144000(3) 15720007.(2) 1527000(4) 3414000 |
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Answer» = (1786+ 214) (1786- 214)= (2000) × (1572)=3144000 |
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| 29. |
41. Find the equation of the two straight lines through (, 2) forming thetwo sides of a square of which 4x + 7y12 is one diagonal |
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| 30. |
Q-4A man spends on an average Rs.269.47 for the finst 7 months and Rs. 281.05 for the next 5 months.Find his monthly salary if he saves Rs.308.46 during the whole year? |
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Answer» Total spending in 12 months = Rs [269.47 × 7 + 281.05 × 5] = Rs. 3291.54 Total income = spending’s + savings = Rs. 3291.54 + Rs. 308.46 = Rs. 3600.00 ∴ Monthly salary = Rs. 3600/12 = Rs. 300please like the solution 👍 ✔️ |
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| 31. |
A person spends Rs. 1440/-in 8 months and saves Rs. 259 20 in that of 8months. Then Find out the monthly income of that person |
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Answer» Monthly income = (1440+259.20)/81699.20/8 1440 + 259.20 =1699.201699.20÷8212.4 |
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| 32. |
ollowing figures. One has been d18 m8 m8 m18 m |
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Answer» perimeter of figure is 52 perimeter of rectangle is 52 m is the best answer. Perimeter of rectangle = 18+18+8+8=52m perimeter of figure is 52answer. perimeter of rectangle = 52 is the best answer. Perimeter of retangle=2(l + b)So, perimeter of retangle=2(18+8)=52Please Mark my answer as best perimeter of figure= 2(18+8)= 2× 26m=52m perimeter of figure is 52 m Perimeter of figure is 52 m the perimeter of this figure is 52 |
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| 33. |
international system of 904204 name |
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Answer» nine lakh four thausand two hundred four Nine lakh, four thousand two hundred and four nine lakh, four thousand two hundred and four nine hundred four thousand two hundred four is the correct answer of the given question nine lakh, four thousand two and four plz like my answerans accepted as bestplz nine lakh four thousands two hundred and four nine lakh four thousand two hundred four |
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| 34. |
international system |
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Answer» international system is a metric system it is a matric system.. |
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| 35. |
Write the additive inverse of each of the following.JCI U 214 |
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Answer» 1=-2/8 is right answer |
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| 36. |
of313. Rohan is dividing 1- kg of sweets equally4among his seven friends. How much does eachfriend receive?[HOTS) |
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| 37. |
Prove that f(x) = lxl is continous at x = 0 |
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| 38. |
2, A tree breaks due to storm and the broken partbends so that the top of the tree touches the groundmaking an angle 30° with it. The distance betweenthe foot of the tree to the point where the toptouches the ground is 8 m. Find the height of thetree.epression dff the brido |
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| 39. |
Prove that f(x) = Ixl is continous at x = 0 |
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| 40. |
The number of straight lines ' y ' that connect x points is given by theequation y x-I). Hos many points does a figure have if only 15 linescan be drawn connecting them.2enn |
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| 41. |
also alh |
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Answer» Total wheat = 1745.700*15 = 22135500 grams = 22135 kg 500 grams |
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| 42. |
|T ———T__f%&éfi__! o e Lh ..i 1| |
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Answer» (1/3^3)=3^-3now(3^-3)^7=3^-21 |
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| 43. |
0 ba bLH a |
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Answer» through you multiply by 10 , but it just increase the number of steps,better to multiply by 100 as main idea is to eliminate the the repeating terms, so multiplying by 100 will eliminate the repeating terms as they are repeating after two digits |
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| 44. |
(ehlhke lh है Ifor emagh n 1 #l be/JE |NAMU AND KIA LK hi hadichik |
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Answer» π= pie, π=22/7; π=3.14 ha pie ek anurup sankhaya h π is constant it is irrational and the value of π is approximately 3.14 it is rational number |
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| 45. |
14em.fnd h rl of lh olhdragondagonelJCI cm .iho |
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Answer» Area of rhombus= (a × b)/2,where a and b are digonals,so (14×b)/2 = 98b = (98 × 2)/14b = 98/7 = 14cmSo other digonal is 14 cm |
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| 46. |
(a) The is talking(father/child) |
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Answer» The sentence can be:-The father is talking.orThe child is talking. |
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| 47. |
I Was talking to him . ( Change into future continous ) |
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Answer» I will be talking to him I will be talking to him. I will be talking to him. |
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| 48. |
The edges of a cuboid are in the ratio 1 :2: 3 and its surface area is 88 cm2. The volume dfthe cuboid is7. |
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Answer» let sides be x , 2x ,3x so,S.A = 2(lb + bh +lh) 88/2 = (x)(2x) +(2x)(3x) + (x)(3x) 44 = 2x² + 6x² + 3x² 44 = 11x² 44/11 = x² 4 = x² 2 =x now , sides are x = 2 cm (length) 2x = 4 cm (breadth) 3x = 6 cm(height) so, volume= lbh =2x 4x6 = 48 cm³ |
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| 49. |
In Δ ABC, DF/BC and AD-1 cm, BD-2cm, what is the ratio of thearea ΔABC to the area ΔADF? |
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| 50. |
Q.1 A vessel is in the form of a follow hemispheremounted by a hollow cylinder. The Diameter ofthe hemisphere is 14 cm and the total height dfthe vessel is 13 cm. Fond the inner surface areaof the vessel. |
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