This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
1 what is sphese |
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Answer» Sphere is a round three dimensional object with no vertices that completely look like a ball. |
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| 2. |
((cos(360^circ - theta)*cot(90^circ - theta))*sin(180^circ - theta))/(((sin(-theta)*tan(180^circ %2B theta))*tan(theta %2B 90))) |
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| 3. |
1. A park, in the shape of a quadrilateral ABCD, has 900, AB 9 m, BC 12CD 5 m and AD 8m. How much area does it occupy? |
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| 4. |
(QuestionalL. Simplify: |
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| 5. |
2/ 9 Spem ajfi Sl zeroes f He P2 J,(mm:‘a/( Gulkm Al 2. रच... |
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| 6. |
(b)a (a, a + 1) + 5 and find its value for (1) a = 0, (ii) al(iii)a =-1Simplifye |
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Answer» +1 Kha sa aya |
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| 7. |
OLAd. of these15 If y = 2logx, then dy isdxzlogx---log 2b. 2031 109. 22logs.log, 22logxc. |
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| 8. |
A park in the shape of a quadrilateral ABCD has C 90°, AB 9 m, BCCD 5 m and AD 8m. How much area does it occupy?12 m. |
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Answer» Page 1 |
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| 9. |
1. A park, in the shape of a quadrilateral ABCD, has C-90° AB9 m, BC 12CD5 m and AD-8 m. How much area does it occupy? |
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| 10. |
EXERCISE 12.2park, in the shape of a quadrilateral ABCD, hasCDd5 m and AD = 8 m. How much area does it occupy?Ca 90. ABo 9 m, BC |
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| 11. |
Write the following polynomial in standard form:m3 +4 +3m. |
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Answer» PLEASE LIKE THE SOLUTION |
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| 12. |
Write the following polynomial in standard form :m3 +4+3m. |
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| 13. |
(3) Write the following polynomial in standard form:m3 +4 + 3m. |
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Answer» Standard form: m³ + 3m + 4 |
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| 14. |
2the following polynomials in standard form.(ii) Ty+(i) m3 +3 + 5m |
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Answer» standard form is ax^3+bx^2+cx+dhence1m^3+0m^2+5m+3 |
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| 15. |
(3) Write the following polynomial in standard formm3 +4+3m. |
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Answer» In standard form :m³ + 0m² + 3m + 4 |
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| 16. |
(b) cost-sin 02-3.調, I |
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| 17. |
Find the Sustace asea ol a sphese alodius 3.S n |
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Answer» byyaaa alla 4cut aindhi |
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| 18. |
9( ol ik A X¢ 6 (IA)o Sk |
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Answer» 9^(-3)*16^(1/4)/6^(-2)*(1/27^(-4/3) 16=2^4; 16^(1/4)=2^1=227=3³; 27^(-4/3)=3^(-4)=81 =-729*2/36*1/81=-1/2 |
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| 19. |
sin 360 |
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Answer» 0 is correct answer. 0 is the right answer 0. . the question answer is 0 |
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| 20. |
ol oeâ=N|=n2 |R A6. |
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Answer» please like if the solution helped you. |
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| 21. |
3) IIN+a+b/3 find the value of a and BOla2+3w |
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| 22. |
1.536. Find the value of7. Find on number line.8. Simplify92alal |
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Answer» 2 👌 |
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| 23. |
1 Convert each of the following fractions into a percentage.OLA(b) |
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Answer» 4/5= 1.0 ,111/25 = also do the same as number one ok😄 |
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| 24. |
1.EXERCISE 12.2A park in the shape ola quadrilateral ABCD has/C=90". AB -m.BC 12.D=Snyd AD = $m. How much area daca it occupy? |
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Answer» say enlarge the point is not cut say in |
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| 25. |
he Sides ola ight angle taioogla |
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| 26. |
tan 6Um---) . ही =1+ sec Ocosec O/1-—cot® 1-tan6 |
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Answer» GIVEN:- tanθ/(1 - cotθ) + cotθ/(1 - tanθ) => tanθ/(1 - 1/tanθ) + (1/tanθ)/(1 - tanθ) => tan²θ/(tanθ - 1) - 1/tanθ(tanθ - 1) => 1/(tanθ - 1) { tan²θ - 1/tanθ } => 1/(tanθ - 1) { (tan³θ - 1)/tanθ) [as, a³ - b³ = (a - b)(a² + b² + ab) => {(tanθ - 1)(tan²θ + 1 + tanθ)}/{(tanθ - 1)(tanθ)} => tanθ + cotθ + 1 => sinθ/cosθ + cosθ/sinθ + 1 => (sin²θ + cos²θ)/sinθ . cosθ + 1 => 1/sinθ . cosθ + 1 => cosecθ . secθ + 1 please like the solution 👍 ✔️👍✔️ |
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| 27. |
Eind he Inseq raCOSolacosa |
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| 28. |
2 IF thee of elivaion of aclod foom a pontmlere above helahe is oc and he aale oeef hctions Doau a Sutablediaqm eam fos to poblem |
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| 29. |
) 2(ii) ;—y—*'z— =1.a B. 2014; H.P.B. 2013¢« B. 2013 ; H.B. 2011) 2R R 5X %Kerala B. 2017) e (P.B. 2014 §( k |
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| 30. |
2r (z-x-y) and 2y (z-y -x) |
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Answer» 2x(z-x-y) + 2y(z-y-x) = 2x(z-x-y) + 2y(z-x-y) = (2x+2y)(z-x-y) = 2(x+y)(z-x-y) |
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| 31. |
is the angle between them. Then a + bLet a and b be two unit vectors andis a unit vector if |
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| 32. |
For the travelling harmonic wavex, 2 cos 2 (10-0.008x+0.35)where r and y are in cm andatoscillaiory motion of two points sepaie seconds. The phase differencents separated by a distance f 0.5 m is(a)(c)0.8 π(d π(b) 0.6 π(d) 0.2 π |
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Answer» a b |
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| 33. |
. Write two different vectors having same magnitude. |
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| 34. |
2. Write two different vectors having same magnitude. |
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| 35. |
3 Fig. 12.3 depicts an archery target marked with its fivescoring regions from the centre outwards as Gold, Red, Blue.Black and White. The diameter of the region representingGold score is 21 cm and each of the other bands is 10.5 cmwide. Find the area of each of the five scoring regions. |
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| 36. |
3. Fig. 12.3 depicts an archery target marked with its fivescoring regions from the centre outwards as Gold, Red, BlueBlack and White. The diameter of the region representingGold score is 21 cm and each of the other bands is 10.5 cmwide. Find the area of each of the five scoring regions. |
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| 37. |
3. Fig. 12.3 depicts an archery target marked with its fivescoring regions from the centre outwards as Gold, Red, Blue,Black and White. The diameter of the region representingGold score is 21 cm and each of the other bands is 10.5 cmwide. Find the area of each of the five scoring regions. |
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| 38. |
Additional QuesllU1. There are 20 apples in a carton. How manyapples will 'c number of cartons have?K&U |
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Answer» apples in 1 carton = 20 Hence, apples in c cartons = 20*c = 20c apples |
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| 39. |
Fig. 12.3 depicts an archery target marked with its fivering regions from the centre outwards as Gold, Red, Blue,Black and White. The diameter of the region representingscore is 21 cm and each of the other bands is 10.5 cmind the area of each of the five scoring regions. |
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| 40. |
areasan archery target marked with its fivethe centre outwards as Gold, Red, Blue,and White. The diameter of the region representingis 21 cm and each of the other bands is 10.5 cmBlack andwide. Find the area of each of the five scoring regions. |
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| 41. |
If the sum of two unit vectors is a unit vector, show that the magnitude of their difference is,/3 |
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| 42. |
Ir a,b,č are unit vectors such that a+bätbč 0, find |
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Answer» a+b+c = 0 take dot product with (a+b+c) both sides... (a+b+c). (a+b+c) = 0 a.a + a.b+a.c + b.a + b.b+ b.c+c.a+c.b+c.c = 0 2(a.b+b.c+c.a) +|a^2|+ | b2|+ | c2|= 0 ...........(a.b =b.a , b.a=a.b , c.a=a.c , ..) 2(a.b+b.c+c.a) = -3 .....(since mode a = mode b = mode c = 1 ) a.b+b.c+c.a = -3/2 |
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| 43. |
In the given figure, O is the centre ofthe circle and LDAB 50°. Calculatethe values of x and y. |
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| 44. |
8. If the sum of two unit vectors is a unit vector provethat the magnitude of their difference is V3 |
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| 45. |
3. एक त्रिभुज ABC की दो भुजाएँ AB औरBC तथा माध्यिका AM क्रमशः एक दूसरेत्रिभुज की भुजाओं PQऔर QR तथा माध्यिका ।PN के बराबर हैं (देखिए आकृति 7.40)। B-दर्शाइए कि(i) AABM=A PON(ii) AABC=APQRMmdenआकृति 7.40 |
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Answer» I) is the correct answer (i) is the correct answer |
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| 46. |
I1. The slope of a line is double of the slope of another line. If tangent of the anglestbetween them is,find the slopes of the lineserefopon th |
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| 47. |
16. AD bisects ZCAB. If ZCAD (8x + 6)° andLDAB= (x +20)", what is the value ofx?|(a) 10°(c) 4°(b) 2°(d) 12° |
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| 48. |
6. एक आयताकार श्यामपट्ट की लम्बाई 3 मी. और चौड़ाई 2 मी. है। श्यामपट्टका परिमाप ज्ञात कीजिए।Som 73 |
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| 49. |
9. By selling a sofa set for 10,2401,incurred a loss of 20%. If he wanted.nake a profit of 8%, at what price sh 00he have sold it?hocea for |
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Answer» SP = 10240 LOSS = 20% CP = 10240/0.8 = 12800 PROFIT = 8% SP = 12800*1.08 = 13824 If you find this answer helpful then like it. |
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| 50. |
Prove that the tangents drawn to a circle at the two ends of a diameterare parallel. |
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Answer» thank you so much one more question I have plzz answer it |
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