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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
ll AC - Sem and BC - 12cm. Find the length of AB.A 15m long ladder reached a window 12m high from the ground on placing.it against a wall at astance 'a'. Find the distance of the foot of the ladder from the wallstance a'. Find the distance of the foot of the lader from the wual20. A tree is broee is broken at a height of Sm from the gr12m from the base of the tree. Find the original height of the tree. |
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| 2. |
The UUUL4.Rahul walks į km from a piace p towards east and then from there 15km towards west. Wratithe position now from p?.-3-7-5inorder |
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Answer» 2/3 km towards east and 11/6 km towards west means (11/6 - 2/3) km = 7/6 km towards west.So, his position is 7/6 km or 1(1/6) km towards west from p. Hope it helps.Mark as best if you like. |
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| 3. |
On dividing ) by tl we get15mHemon, the hnight of the tent is 15 metnesAc within a cube touching all its sertical fanien made the cylier thri hrightsfind the nati of thrir selamesLet the length of each edge of theane same wsth the |
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Answer» Let the length of each edge of the cube beaunits. ∴ Volume of cube =a3cube units Since the cylinder is within the cube and it touches all the vertical faces of cube. ∴ Radius of base of the cylinder and the cone= (a/2) units Height of the cylinder and the cone =a units Volume of cylinder = πr2h=π(a/2)2x a = (22/7) x (a2/4) x a= (11/14)a3 Volume of cone = (1/3)πr2h= (1/3) xπ(a/2)2x a = (22/21) x (a2/4) x a= (11/42)a3 Consider, volume of cube : volume of cylinder : volume of cone = a3: (11/14)a3: (11/42)a3= 1 : (11/14) : (11/42)= 42 : 33 : 11 |
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| 4. |
If length, breath and height of room is 15m, 10m and 3mrespeclierly. Then find the area of the four walls. |
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| 5. |
Atank is 20m in length, 15m in breadth and 4min depth. Find the cost of cementing its floor andthe four walls at the rate of 50 per square metre.Surface Area of a cylinder |
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| 6. |
ample 1. A sum of15000 is borrowed at a rate 15% per annum for 3 years. Find the simpleurlinterest on this sum and the amount to be paid at the end of 3 vears. |
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| 7. |
Find the circumference of a circle whose diameter is(ii) 35 cnm#1) 10.5 nm(i) 14 cm |
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| 8. |
Harish started his journey at 18:40and finished at 22:20. The timetaken in completing the journey is |
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Answer» Started journey at 18:40 and finished at 22:20 Time taken = 22:20 - 18:40 = 3 hr 40 min |
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| 9. |
UMNS31. Harish started his journey at 18:40 and finished at22:20. The time taken in completing the journey is |
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Answer» Journey started at 18 : 40 and finished at 22 : 20 Then,Time taken = 22 - 18 = 4 hrs60 - (40 - 20) = 40 minutes Therefore,Total time taken for journey= 4 hrs 40 min TIME taken to finish the journey = 22:20 - 18:40 = 3 hr 40 min Initial time=18:40Final time=22:20Time taken=22:20-18:40=3:40=3hr 40min Initial time=18:40 final time=22:20=21:(20+60). The time which has taken is =(22-18):[(20+60)-40]=03:40=3h 40min this answer is 3 hours 40 minutes |
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| 10. |
10 Find the least number of square tiles required to pave the floor of a room15m 17cm iong and 9m 2em broad. |
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| 11. |
7hr 15m ÷ 15 =? |
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Answer» 1 hr =60 min 7 hr 15 m= 7×60+15 =420+15 =435435 min ÷ 15 = 29 minutes. 29 minutes is the answer of the following 1 hour =60 mintso,7 h= 7×60mint=420mint+15 mint÷15=435÷15=2929 is the best and correct answer 29 minutes is your answer 7hr 15m ÷ =?1hr =60m7hr=60*7m=420(420+15)m ÷15=435÷15=2929 is right answer |
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| 12. |
How many 6m cubes can be cut from the cuboid measuring36m x 15m x 8m? |
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| 13. |
6. A walks 10m towards East and then 10 m to his right. Then everytime turning to his lefi, he walls 5m.15m and 15m, respectively. How far is he from his starting point?30-5m(2) 10m(3) 15m(4) 20m5 |
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| 14. |
15m+4m-3=21-2m+8 |
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| 15. |
The one side of cube 15m length. Find the volume |
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Answer» Volume of cube is 15*15*15 = 3375 mcube Thanks |
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| 16. |
14. A boy reaches his school in 30 minutes by travellar is the school from his house? |
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Answer» t=30minsv=2.5km/hr=2.5/60m/mins=vts=2.5/60 * 30=2.5/2=1.25km distance=speed×timedistance=(2.5/60)km/min × 30mindistance=(25/600 × 30)kmdistance=1.25km or 1250m |
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| 17. |
xmiA 5-m-long ladder when set against the wall of a house reaches a height of 4.8 m. How far isthe foot of the ladder from the wall?Hint. x2 = 52-(4.8)2 = (5 +4.8)(5-4.8) = (9.8×0.2)- -(1.4)2196 (14 |
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Answer» thanks |
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| 18. |
puspak leaves his house at 8:20am on his motorcycle and reaches his office 40km away at 10am what is speed? |
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Answer» start from 8:20 am he will reach at 10 am so total time 1h40min = 100 min total distance = 40 km speed = 40/100 = 0.4km/min = 0.4×60 = 24km/h |
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| 19. |
pushpak leaves his house at 8:20am on his motorcycle and reaches his office 40km away at 10am what is speed ? |
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Answer» Total time taken=1.67 hoursDistance=40kmSpeed=Distance/time=40/1.67=23.95km/hour |
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| 20. |
A ladder 20 m long reaches a window of a house 16 m above the ground. The distance of the foot of theladder from the house will be:(A) 13 m(C) 14 nm7.(B) 12 m(D) 15 m |
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Answer» Use Pythagorean theorem c^2=a^2+b^2 =20^2-16^2 =400-256 =144 root144 = 12m(Ans) |
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| 21. |
6. Starting from Madhav's house, John first goes 12m to north, then 73 m to west, then 67 m to southand finally 25 m to east and reaches Mohamad'shouse. Then what is the direct distance betweenMadhav's and Mohamad's houses. |
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Answer» Like my answer if you find it useful! |
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| 22. |
1. Add or Subtract. Write each answer in simplest form:(1) +m2(5+ |
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Answer» 7/9+1/8=(56+9)/72=65/72 Ans-1 (7/8)ans-2(1/8)ans-3(195/24) 1. Ans 7/822. Ans 1/83. Ans 195/24 1. answer is 7/822. answer is 1/83. answer is 195/24 7/9+1/8=56+9/72=65/72 is the right answer ans1 :- 65/72ans2 :- 1/8ans3 :-195/24ans5 :-21.3 1)65/632)1/83)238/484)213/10 |
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| 23. |
J. Ifs unt vector glewith iwih j and an acute angle ewik,then find θ and hence, the components of a |
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| 24. |
Convert 6 radians into dezree measure. |
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Answer» if 180 degrees= pi radians, then 1 radian = 1*(180/pi) degreessimilarly, 6 radians= 6*(180/pi) degreesi.e, 6 radians= 343.774 degrees= 343.77 degrees (approx.) |
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| 25. |
\begin{array} { l } { \text { Put in the simplest form each of: } } \\ { \text { (1) } \frac { 5 } { 1 - 2 i } } \\ { \text { (2) } \frac { 2 + 3 i } { 2 - 3 i } } \end{array} |
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| 26. |
Convert 6 radians into degree measure. |
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| 27. |
Convert 6 radians into degree measure |
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Answer» 1 rad=180/pie degree6 rad=(6*180)/pie=343.949044586 degree. |
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| 28. |
4.Convert 315° into radians. |
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| 29. |
2 Convert 6 radians into degree measure. |
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| 30. |
Example 2 Convert 6 radians into degree measure. |
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Answer» thx but mujhe smjh nhi aa raha hai ki 38 kaha se aya please explain me hi |
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| 31. |
Cusluate each of the following in the simplest form:(1) sin60° cos30° + cos60° sin 30° |
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| 32. |
ratios in simplest form 1 km: 750 m |
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Answer» 1km=1000mSo, the ratio is 1000:750 which is 4:3 . |
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| 33. |
1. Express each of the following ratios in simplest form:(1) 24 40(ii) 13.5 15 |
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Answer» (I) 24/40=12/20=6/10=3/5 |
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| 34. |
2(b) Write the function y in its simplest form1 +x2 |
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| 35. |
Express the following ratio in simplest form 1) 300ml to 1L 350ml |
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| 36. |
Margarite wants to take a trip to Japan in 8 years. She knows she will need about $4,000. How much should she deposit into an account now that pays 3.5% interest, compounded daily, to meet her goal? Round to the nearest dollar. |
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Answer» x/4200=3.5/84200*3.5=1470014700/8=1837.5x=1837.5she started out with $1837.50 |
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| 37. |
express of the ratio in the simplest form 1 kl 80 l and 900 l |
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Answer» 1kl = 1000l.1kl 80l= 1080l.1kl 80l : 900l= 1080:900= 12:1Please hit the like button if this helped you |
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| 38. |
.A lader is placed against a wall such that it just reaches the top of the walladder is 1,5 m away from the wall and the ladder is inclined at an angle 60 wih uFind the height of the wall.with the |
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| 39. |
e2 Convert 6 radians into degree measure. |
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Answer» 6Rad× 180/π = 343.775Deg |
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| 40. |
A rope is 90 m long, How many pieces of 10 m each can be made from it? |
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Answer» Totally, 9 pieces of 10 m can be made from it. |
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| 41. |
A poor artist on the street makes funny cartoons for children and earns his living, Once he made a comicface by drawing a circle within a cirele, the radius of the bigger circle being 30 cm and that of smallerbeing 20 cm as shown in the ligure. What is the area of the cap given in this figure? What qualities ofthis artist are being reflected here?30-2 |
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Answer» Radius of bigger triangle is with centre O=30 cm Radius from O'=20cm difference of their radii =distance between their centres O andO' =10cm AB is a tangent if smaller circle so,/_OCA=90°=/_OCB In triangle ica AO²=AC²+CO² 30²=AC²+10² 900=AC²+100 AC=20√2 AC=CB AB=AC+CB AB=AC+CB AB=2AC AB=2*20√2 AB=40√2cm CD=30-10 =20cm Area of cap=AR of adb 1/2×AB×CD 1/2×40√2×20=400√2cm² 400×1.414 =565.6cm² |
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| 42. |
A poor artist on the strect makes funny cartoons for children and earns his living, Once he made a comicface by drawing a circle within a circle, the radius of the bigger circle being 30 em and that of smallerbcing 20 cm as shown in the figure. What is the area of the cap given in this figure? What qualities ofthis artist are heing reflected here?30- |
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Answer» Radius of bigger triangle is with centre O=30 cm Radius from O'=20cm difference of their radii =distance between their centres O andO' =10cm AB is a tangent if smaller circle so,/_OCA=90°=/_OCB In triangle ica AO²=AC²+CO² 30²=AC²+10² 900=AC²+100 AC=20√2 AC=CB AB=AC+CB AB=AC+CB AB=2AC AB=2*20√2 AB=40√2cm CD=30-10 =20cm Area of cap=AR of adb 1/2×AB×CD 1/2×40√2×20=400√2cm² 400×1.414 =565.6cm² |
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| 43. |
26. A poor artist on the street makes funny cartoons for children and earns his living. Oneehe made a comic face by drawing'a cirele within a cirele, the radius of the bigger circle being30 em and that of smaller being 20 cm as shown in the figure. What is the area of the cap given inthis figure? What qualities of this artist are being reflected here ?Capth ton hy a plane parallel to the |
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Answer» LetAandBbethecentresofthesmallerandbiggercircles,respectively.Wehave,BC=BD=BF=BE=30cm,AP=AF=20cmar(∆CDE)=?Let∆CDEbeanisoscelestrianglerepresentingthecapAs,BF=30cm⇒AB+AF=30⇒AB+20=30⇒AB=30−20=10cmSo,BP=AP−AB=20−10=10cm.....(i)Also,BE=30cm⇒BP+PE=30⇒10+PE=30⇒PE=30−10⇒PE=20cm.....(ii)Since,CDisatangenttothesmallercircleSo,BP⊥CD(Tangentisperpendiculartotheradiusatthepointofcontact)Also,CDisachordofthebiggercircleSo,CP=DP(Perpendiculardrawnfromcentretothechordbisectsthechord).....(iii)Now,in∆BPC,usingpythagorastheoremCP^2=BC^2−BP^2⇒CP=302−102−−−−−−−−√[As,BC=30cm,givenandBP=10cm,from(i)]⇒CP=900−100−−−−−−−−√=800−−−√⇒CP=20√2cmSo,CD=2CD[From(iii)]⇒CD=2(202√)=40√2cmNow,ar(∆CED)=12×CD×PE=12×40√2*20⇒ar(∆CED)=400√2cm^2 Hence,theareaofthecapis400√2cm^2. |
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| 44. |
24. A train 150m long passes a tree in 12 seconds. How long will it take to pass a tunnel 250 m long |
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| 45. |
20. A train 150 m long passes a tree in 12 seconds. How long will t take to pass a tunnel 250 m long? |
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Answer» thanks |
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| 46. |
VERFind limt-1 |
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| 47. |
n2_2limat ver-4find dimits. |
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Answer» lim x___V2 =( V2)^2-2/(V2)^2+ V2( V2)-4=2-2/2-4-4=0 |
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| 48. |
60% of the total time is 30 minutes. Find the total time. |
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Answer» Let x be the total time. 60x/100 = 30 minutes x = 30*100/60 x = 50 minutes |
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| 49. |
6EXERCISE 3.31. Solve the following pair of linear equations by the substitution method.1 x+(i 3x-y=4(i) ) 3x-y3(iv) 0.2x +0.3y-1.30.4x +0.5y 2.3Il3x5y2x+V3ăŤ0(vi)=-2 |
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Answer» given pair of linear equation isX + Y is equal to 14 1ex minus Y is equal to 4 given pair of linear equation isX + Y is equal to 14 1ex minus Y is equal to 4 |
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| 50. |
2. A distance of 800 m is covered in 30 minutes, find the speed in km/hr.3. A dog runs at a speed of 100 metre in a minute. Find its speed in km/hr. |
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