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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
14x^2 + x- 3 |
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Answer» 14x*x + x - 3 = 14x*x + 7x - 6x - 3 = 7x(2x+1) -3(2x+1) = (7x-3)(2x+1) |
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| 2. |
b.2x2 - 9x- 5 by 2x + 1 |
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| 3. |
14x^2 +X-3 |
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Answer» 14x^2+x-314x^2+7x-6x-37x(2x+1)-3(2x+1)(2x+1)(7x-3) thanks... |
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| 4. |
p(x)=14x³-5x²+9x-1;g(x)=2x-1 find this by remainder theorem |
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| 5. |
14x-10x=24 then x=? |
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Answer» x=6 is the right answer 14x-10x=244x=24x=24/4=6 |
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| 6. |
29 Solving the following inequation, write the soluline.- 3 (x â 7) > 15 â 7x > *2,XER |
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Answer» X should be greater than equal to 2 by intersection of following |
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| 7. |
Solve for x: 4x-9 + 14x+9 =5+17. |
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Answer» 4x-9+4x+9=25+78x=32x=32/8x=4 By squaring both sides4x-9+4x+9=25+79 is in +&- so that cutso 8x=32.: x=32/8.: X=4 X= 4 is the correct answer of this question x = 4 is the best answer. x = 4 is the correct answer. X=4 is the correct answer. |
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| 8. |
Theme :Solving Mystery of messed up fieldsin Rehman's Field, if angles are in the ratio 3:5:1:3, find all the angles. |
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Answer» Thanks |
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| 9. |
6. Find the values of p for which the quadratic polynomial 4x2 + px + 3 has equal zeroes.7. Without solving the polynomial, find the value of m for which the roots are equal: |
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Answer» TanA=1=SinA/Cos A; SinACosA=1/1=1 (2x+1)(2x+3)ai tai hoba answer |
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| 10. |
3Mixed Problem SolvingSolve using addition, subtraction, multiplication or division.52 pencils are put into boxes, 9 in each box. How manyboxes are needed? How many pencils will be left over?a |
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Answer» answer fast |
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| 11. |
5||2014 !Tithi : Aasad Krishna (Sasti)Sunrise : 5:13 a.m. Sunset: 6:47 p.m.urtParties name,Stage Next Date2-27-- ५ ( कन छक्या३]] |
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Answer» 2^3-2^(3-1)=8-4=4 so,n=3 n^n=3^3=27 |
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| 12. |
olun.ProductVoduct is less thanPractice Zone 3State whether the product obtained is greater orsactually solving them.ater or smaller than the fraction46a. 5*1336/Division of Fractions |
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Answer» a=24/65b=70/18c=45/72d=6/12 Hello harsh I am your friend kunal so you multiply 4and6 and then 5×13 and answer will be in numinator dinominator firm and your answer is 24÷65 |
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| 13. |
1. 3 feet = 36inches2. 5 yards = 180 inches3. 4 yards = 12feet72 inches = _yardsRedProblem Solving WomConor has a roll of fence that is aof fence to go around a flower bd the flower bed? Fx |
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Answer» 72 inches = 2 yards. 72 inches = 2 yardssince 72/36= 2Formula : 1 Yardis equal to36 inches. |
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| 14. |
Factorise the fo |
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Answer» There is a common factor of 3 in each of the 2 terms which can be taken out.hence 3x - 12 = 3(x - 4) |
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| 15. |
foCutorube the |
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| 16. |
The solution of (7x2 + 14x)-(x+2)(a) 7x (x+2)Q.6(b) 7(x+2)(c) 7x |
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| 17. |
sin 2xx0 2x2+ x11 lim |
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| 18. |
Evaluate lim Sin(a+x)+sin(a - x) - 2 sin a80x.sinx |
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| 19. |
An internal angle of an equilateral surface is132° more than its exterior angle. Find thenumber of sides in the equilateral surface. |
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Answer» The answer is 15 Let exterior angle be x Then, Interior angle = x+132 Now, Interior angle +Exterior angle = 180 or, x + x + 132 = 180 or, 2x = 48 or, x = 24 So, number of angles = 360/exterior angle = 360/24 = 15 Correct Ans of this question = 15 |
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| 20. |
how many type of polynomial. |
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| 21. |
how many type soil can divided? |
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Answer» soil can be Divided in to three partstop soilsub soilbedrock soul can be divided into three parts,1=Top Soil 2= Sub Soil 3= BedRock |
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| 22. |
5. Prove that the angle betucen the internal bisectorangte and the external bisector of the other s equal to ohalt ob the vesbcal angle |
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| 23. |
Evaluate lim Sin auc |
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| 24. |
(hyp)(Opp)m)(ad]) |
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| 25. |
The area of a square plot is 6084 m2. Find the length of the wire which can go fourtimes along the boundaryof the plot. |
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| 26. |
Write L.H.S and R.H.S of the following simple equations.(i) 2x 10(ii) 4z+1 8(v) 14 27-y(vii) 7m 14(ii) 2x-3 9(iv) 5p +3 2p+9IV(vi) 2a- 3 5(vii) 8-q+ 5 |
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Answer» kimdly crop the question you want to ask i) LHS = 2x, RHS = 10ii) LHS=2x-3, RHS=9iii) LHS=4z+1, RHS=8iv) LHS = 5p+3, RHS = 2p+9v) LHS = 14,RHS = 27-yvi) LHS =2a-3, RHS = 5vii) LHS = 7m, RHS =Mviii) LHS = 8=q, RHS = +5I hope it helps......................... |
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| 27. |
Write L.H.S and R.H.S of the following simple equations.(i) 2x 10(ii) 4z+1 8(v) 14 27-y(vii) 7m 14(i) 2x-3 9(iv) 5p +3 2p 9(vi) 2a - 3 5(vii) 8 q+ 5 |
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Answer» 1)LHS=2x rhs-102) LHS=4z+1rhs-83)lhs=14rhs=27-y4)lhs=7mrhs=145)LHS=2x-3rhs=96)LHS=5p+3rhs=2p+87)LHS=2a-3rhs=5 |
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| 28. |
3 men or 5 boys can complete a task in 10days. How long will 2 men and 10 boys taketo complete the same task? |
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Answer» like karo karo karo please like karo 2 men and 10 boys complete the task 12 days 10 days is the best answer please like my answer then I like your answer too all of you 2 mens and 10 boys complete the same task in 10 days 3 mean or 5 boys task complete in 10 days 2 men and 10 boys task complete in 14 days |
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| 29. |
two trains leaves have a railway station at the same time the first train travels due west and second is due north the first train travels 5km/h faster than the second train if after two hours they are 50km apart find the average speed of each train |
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| 30. |
to the cling the of the sides of a triangle are8C m 12 รง'm and lbc.m. Find the height deals fordiits the longest side2. the height of an equilateral triangle measwa12. c.m. find the area of triangle correct to2. Felaces of deciane. Iuse VE = 1,7327.3. Robe of an isosceles trionale is 3/2 times eachof eqbal sides. If it's perimeter is 28 cmFind oves, and height of the triangle.1. If perimeter of an ensial tringle is equal stahite dren. Find the area of the equilateral tringle.The perimeter of a rhombus is 100.com andone of its shorter diagonal is to cm lang.Find the length of other diagonal and cred ofMhambusthe lenath of the adiacent sides of a bordelaParallasram are respectively 48 cm and 36cm.one of it's diagonal its 44 cm. Find the area ofthe bbralloram |
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Answer» 1. 30 cm, 2.50cm, 3. 63cm 4.73m |
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| 31. |
3 men or 6 boys can complete awork in 8 days. In how many days 4 men and 4 boyswill complete the same work? |
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Answer» Men x boys x days= worknow 3m= 6bm= 2bnow 4 men = 8b6 boys can do in 8 days1 boy wll do in 8/68 will do = 64/6 |
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| 32. |
3 men or 5 women can do a work in 12 days.How long will 6 men and 5 women take tofinish the work?(S.S.C. 2006) |
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Answer» Three men can complete the work in 12 days.Thus, one man can complete the work in 36 days.Rate of work done by one man in 1 day =136Similarly, rate of work done by one woman in 1 day = 15×12=160 Now, six men will do 636, i.e., 16 unit of work in a day.Five women will do 560, i,e., 112unit of work in a day.∴ Total work done in 1 day= 16+112 = 14 unit Thus, six men and five women will take 4 days to complete the work. The work can be completed in 4 days. |
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| 33. |
A length ofa bacteria enlarged 50,000 times attains a length of5 cm. What is the actual length of the bacteria?Ifthe length isenlarged 20,000 times only, what would be its enlarged length? |
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Answer» Very very very thanks 👏👍💖 2 is the enlarged area of the bacteria. very very very thanks 👏👍💖 |
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| 34. |
16., if 3 men with 4 boys can ear a Rs.2100 in 7 days, and 11 men with 13 boys can earn Rs.8300 in 8 days, in what timewill 7 men with 9 boys earn Rs.11000?(a) 16 days(b 17 days(c) 18 days(d) 20 days |
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Answer» Let m and n be the money earned by a boy and a man in 1 day. Then, we have 3m + 4n = 2100/7 ⇒3m + 4n = 300 ----------[1] And 11m + 13n = 8300/8 ⇒11m + 13n = 1037.5 –------[2] Solving [1] and [2], we get We get m = 50 and n = 37.5 Now we need to find k where ⇒ k(7m + 9n) = 11000 ⇒ k(7 × 50 + 9 × 37.5) = 11000 ⇒ 687.5 × k = 11000 ⇒ k = 11000/687.5 ⇒ k = 16 |
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| 35. |
can youhare tringle withto internal right angle Cye and No) - |
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Answer» yes we have a triangle with internal angle of 90 degree Yes is the correct answer no because sum of all angle of triangle is 180 but if we have 2 angles of 90° then the sum of only 2 angle will be 180 which is not possible |
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| 36. |
how many type of tringle |
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Answer» Ans :- Equilateral triangle. The Equilateral triangle shown on the left has three congruent sides and three congruent angles. ... Isosceles triangle. The Isosceles triangle shown on the left has two equal sides and two equal angles. Scalene Triangle. The Scalene Triangle has no congruent sides. ... Acute Triangle. ... Obtuse Triangle. |
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| 37. |
The angles of a quadrilateral are in the ratio 2:3:4:6. Find the measure of each offour angles |
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Answer» Let the angles be, 2x,3x,4x,6x we know that the sum of all the angles of a quadrilateral is 360 degree ⇒2x+3x+4x+6x=360 ⇒15x=360 ⇒x=360÷ 15 ⇒x=24 thereforethe angles are- 2x⇒2*24=48 degree 3x⇒3*24=72 degree 4x⇒4*24=96 degree 6x⇒6*24=144 degree |
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| 38. |
The angles of a quadrilateral are in the ratio 2:3:4:6 Find the measure ofeach of thefour anglesbe se |
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| 39. |
13. Find the sum of the first 15 multiples of 814. Find the sum of the odd numbers between 0 and 50. |
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| 40. |
14. The area of a square plot is 6084 m2. Find the length of the wire which can go fourtiealong the boundary of the plot. |
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| 41. |
5. A quadrilateral has all its four angles equal. Find the measure of each angle |
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| 42. |
2.If both a and b are rational numbers, then find thevalues of a and b in each case.V81=a+bV313+11V2 + 5312-215V-a-bo |
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Answer» ans. |
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| 43. |
9. If 2 men or 4 women can reap a field in 44 days, how longwill 3 men and 5 women take to reap 3/4 of the field?a) 10 days b) 8 daysc) 12 days d) of these |
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| 44. |
A length of a bacteria enlarged 50,000 times attains a length of5 cm. What is the actual length of the bacteria? If the length isenlarged 20,000 times only, what would be its enlarged length? |
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| 45. |
A photograph of a bacteria enlarged 1,00,000 times attains a length of 4 cm. What isthe actual length of the bacteria? Ifwould be its enlarged length?the photograph is enlarged 25000 times only, what |
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| 46. |
A photograph of a bacteria enlarged 50,000 timesattains a length of 5 cm as shown in the diagram.What is the actual length of the bacteria? If thephotograph is enlarged 20,000 times only, whatwould be its enlarged length? |
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| 47. |
Asphotograph of a bacteria enlarged 50,000 timesattains a length of 5 cm as shown in the diagram.What is the actual length of the bacteria? If thephotograph is enlarged 20,000 times only, whatwould be its enlarged length? |
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Answer» If 50000x magnification gives bacteria of length 5cm :. 1x magnification (normal view) will give5/50000=1/10000=0.0001 cm If the magnification was 20000x only then the enlarged length would be 20000×0.0001=2×1=2cm |
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| 48. |
If the measure of three angles of a quadrilateral are 84°,67and 1 3 1 , find the measure of fourth angle. |
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Answer» quadrilateral so addition of all 4 angles is 360so fourth angle is 360 - 84 - 67 - 131 = 78 |
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| 49. |
A photograph of a bacteria enlarged 50,000 tmesattains a length of 5 cm as shown in the diagramWhat is the actual length of the bacteria? Ifthphotograph is enlarged 20,000 times only, whawould be its enlarged length? |
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| 50. |
3. Among two supplementary angles, the measure of the larger angle is 36° more than themeasure of the smaller. Find their measures. |
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