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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
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13) On Tuesday Shanice bought five hats. OnWednesday half of all the hats that she hadwere destroyed. On Thursday there wereonly 17 left. How many did she have onMonday? |
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Answer» Answer: She had had29hats on Monday. Explanation: Assuming we have been told about all activities involving Shanice's hats: Letmrepresent the number of hats Shanice had on Monday. She bought5hats on Tuesdaywhich would bring the number of hats she had tom+5 Half of her hats were destroyed on Wednesday,so on Thursday she would havem+52hats. We are told this number equals17 So,(m+5)/2=17 m+5=34 m=29 Hit like if you find it useful |
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| 2. |
73. In the figure. OACB represents a quadrant of circle of radius 3.5 em with centre O. 3Calculate the area of auardrant OACB.Also, calculate the area of shaded portion DACB, if OD < 2 cm also Take π2 cm3.5 cm A |
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| 3. |
3) On Tuesday Shanice bought five hats. OnWednesday half of all the hats that she hadwere destroyed. On Thursday there wereonly 17 left. How many did she have onMonday? |
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Answer» Answer: She had had29hats on Monday. Explanation: Assuming we have been told about all activities involving Shanice's hats: Letmrepresent the number of hats Shanice had on Monday. She bought5hats on Tuesdaywhich would bring the number of hats she had tom+5 Half of her hats were destroyed on Wednesday,so on Thursday she would havem+52hats. We are told this number equals17 So,(m+5)/2=17 m+5=34 m=29 Hit like if you find it useful |
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| 4. |
पर e 1. 1.1(XVI)a_*.b_*_X = a 3 b % X X# 0, की (8710) |
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Answer» HIT THE LIKE BUTTON IF YOU ARE SATISFIED |
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| 5. |
(xvi) 3(x+6) = 24 |
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Answer» 3x+18=243x=24-183x=6x=2is the answer 3(X+6) = 24X+6 24/3X+6 = 8-6X=2X=2 is the correct ans. 3x=6X=2 is the right answer 3(x+6)=24 One solution was found : x = 2 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 3*(x+6)-(24)=0 Step by step solution : Step1: Equation at the end of step1: 3 • (x + 6) - 24 = 0 Step2: Step3: Pulling out like terms : 3.1 Pull out like factors: 3x - 6=3•(x - 2) Equation at the end of step3: 3 • (x - 2) = 0 Step4: Equations which are never true: 4.1Solve:3=0 This equation has no solution.A a non-zero constant never equals zero. Solving a Single Variable Equation: 4.2Solve:x-2 = 0 Add2 to both sides of the equation:x = 2 One solution was found : x = 2 2 is the right answer 3x+18=243x=24-183x=6x=2 is the right answer of this question x=2 is the correct answer 3x+18=243x=24-183x=6x=6 ÷3 =2 is the answer
3(X+6)=24X=2 is the right answer |
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| 6. |
A1) 4x+3y=18 )Brr2y= 5 ()समीकरण (1) में 3 से तथा समीकरण (2.R, | A S o भर ~ W |
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Answer» please like my answer if you find it useful |
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| 7. |
5.From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut andalso a circle of diameter 2 cm is cut as shown in Fig. 12.23. Find the area of the remainingportion of the square. |
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| 8. |
(2) 2y + 2 = 2 2 2Niu |
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Answer» sorry par mai app ki help nahi kar sakthi hu y= 8 is the correct answer of the given question y=8 is the correct answer |
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| 9. |
4Q25: From each of the two op1.4 cm is cut. Another circle of radius 4.2 cm is also cut from the centre as shown in figure. Find theposite corners of a square of side 8 cm, a quadrant of a circle of radiusarea of the shaded portion. I Use Ď-'71 |
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| 10. |
From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cmis cut and also a circle of diameter 2 cm is cut as shown in figure. Find thearea of the remaining portion of the square.Ans. |
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| 11. |
Fig. 12.23com each corner of a square of side 4 om a quadrant of a circle of radus Ialso a circle of diameter 2 cm is cut as shown in fig. 12.253. Find the area ofcircle of diameter 2 cm is cut as shown in Fig. 12.23ortion of the square. |
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Answer» thanks |
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| 12. |
AILare left with Hele the number of stamps ads with Abhay. Use x forwith Abhay are 2 less than thrice theThe number of stampsfrat has. Find a rule to determine the numstamps with Virat.stankdetGivUse x for nu |
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Answer» let no of stamps with virat be X and Abhay be yhence3x-2=y |
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| 13. |
3, Mahesh spent 84 % of his income for dailyexpenses. He donated 5% for social causes. Hewas left with 9350 at the end of the month. What(3 marks)was his monthly income?Solution: |
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| 14. |
The line 2x+3y 12 meets the x-axis at A andaxis at B. The line through (5, 5) perpendicularAB meets the x- axis , y axis and the AB at Cand E respectively. If O is the origin of coordinatthen the area of OCEB is6.(b) squnits232(a) 23 sq. units |
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| 15. |
A big contains 3 red balls and 5 black balls. A ball is drawn at random frorn the bag.What is the probability that the ball drawn is (0) red? (ii) not red? |
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| 16. |
2. Write the coordinates of the point, such that the line 5x -3y 18 meets y-axis. |
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Answer» line meets y axis that is x=0so 5(0)-3y=18y=-6then the coordinates are (0,-6) |
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| 17. |
x+2y+1=62x - 3y - 12 =12 |
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Answer» X=9y=-2is the best answer x+2y=6-1=5----(1)×32x-3y=.12+12=24-(2)×23x+6y= 154x-6y=48by adding 7x=63x= 63/7=9putting the value of x in eq1x+2y=59+2y=52y= 5-9= -4y= -4/2= -2 x=9y=-2is the best answer X=9. y=-2 is the answer of this question x=9;y=-2 is the best answer x + 2y + 1 = 6x + 2y = 5. --------(1) 2x - 3y - 12 = 122x - 3y = 24 ------(2) Subtracting (1) and (2),2x - 3y - 2x - 4y = 24 - 10-2y = 14y = -7And, x = 5 - 2y x = 5 - 2 × -7 = 19 x = 19 |
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| 18. |
raw graph of the equation 3(x + 2y)-2(x + 3y)-3.Also tind the point where the line meets x-axis |
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Answer» First we simplify the equation 3(x + 2y) - 2 ( x + 3y) = 3 3x + 6y - 2x - 6y = 3 x = 3 Intersection with x axis is at x = 3 |
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| 19. |
Solve the following simultaneous equations(i) 2x-3y = 12; 5x + 3y = 9. |
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| 20. |
xy-4x+3y-12 |
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Answer» Factorization :xy - 4x + 3y - 12x(y - 4) + 3 ( y -4)(x + 3) ( y - 4) |
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| 21. |
LLLLLL8. Sum of two integers is -30. If one of them is 15,find the other integer. |
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Answer» x+15= -30x= -30-15x= -45 Let the other integer be x, Sum of that integers = -30 15 + x = -30 x = -30 -15 x = -45 Hence, other integer is -45 the answer of your question is -45 Given,Sum of two integers = -30,One number = 15,Other number = -30-15, = -45. |
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| 22. |
3.Find the equation of the line which passess through the point (5,6) and makes inter epaon the axes which are equal in magnitude but opposite in sign |
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| 23. |
ORA bag contain 5 black and o red balls Detwrnine the no of ways inwhich 2 black and 3 red halis con be selored.P.T0. |
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Answer» Total number of black ball =5 Total number of red ball =6 No of ways of selecting 2 black balls =5C2 ⇒5!/2!3! ⇒5×4×3!/2×3! ⇒10⇒10 No of ways of selecting 3 red balls =6C3 ⇒6!/3!3! ⇒6×5×4×3!/3×2×3! ⇒20 Total no of ways of selecting 2 black and 3 red ball =10×20 = 200 Like my answer if you find it useful! |
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| 24. |
7. In how many ways four men and three women may sit around a round table if all the women aretogether? |
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| 25. |
centre (0, 2) and radius 2 |
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| 26. |
4. There were three candidates in an election. They received 687905 votes, 495093756 votes respectively. The number of invalid votes was 13849. If 25467 pesvote. find how many votes were registered. |
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| 27. |
ira,ßarethe zeroes ofr,px +q,find the value of(+2)(+2) |
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LLLLLL LLLLLLLL4. There were three candidates in an election. They received 687905 votes, 495000ey. I ne number of invalid votes was 13849. If 25467 persons did notvote. find how many votes were registered. |
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| 29. |
2 o 1)न.| 3f2f® A1 ol |
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| 30. |
lfanBC ~ ΔΡΟR and AB: PQ 2:3, then fill in the blanks.A(Δ ABC) AB: 22ira ABC-A POR. A ( Δ ABC)-80. A (A POR) 125, then fill inangles |
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| 31. |
29. What is the product of the complex numbers (-3f +4)and (3f + 4)?A. 1B. 7C. 25E. 7+ 241 |
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Answer» (4+3i)(4-3i) =(4)^2-(3i)^2=16-9i^2=16+9=25 |
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| 32. |
Represent -2/11 , -5/11 , -9/11 on the number line |
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Answer» Answer is this pic Answer is this pic Ikshu is right. |
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| 33. |
\frac { - 9 } { 11 } \div \frac { 5 } { 16 } = \frac { 5 } { 16 } \div \frac { - 9 } { 11 } |
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| 34. |
3÷11 × 9÷7 +9÷3 × 11÷3 +4÷3 - 3÷11 |
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Answer» 12.411255411 is the answer 12.4112554113 is the answer for this question 12.411255411 is the answer |
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| 35. |
\frac { 9 } { 11 } - \frac { 5 } { 11 } |
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Answer» d) ( 9/11)-(5/11)=4/11 |
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| 36. |
If 1 + 9 + 11 = 1, Then what is the value of12 + 11 + 9 = ? |
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Answer» 10 asEquation 1 + 9 + 11 = 1 can be derived fromOne (o) + nine (n) + eleven (e) = one = 1 Similarly for equation,12 + 11 + 9 Twelve (t) + eleven (e) + nine (n) = ten (10) |
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| 37. |
1 \frac { 9 } { 11 } - \frac { 5 } { 11 } |
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| 38. |
There are 500 children in a school. For a P.T. drill they have to stand in such aanner that the number of rows is equal to number of columns. How manychildren would be out in this arrangement |
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| 39. |
There are 500 children in a school. For a P.T. drill they have to stand in such a mannerhat the number of rows is equal to number of columns. How maut in this arrangement?any children would be left |
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Answer» let the students in a row be x the column are equal to number of row=x*x=x square total students=500 students that would be left out = 500-x square(nearest square) =500-484 =16 students |
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| 40. |
।2।28. 9-8-5x0-6 +5-3 का मान क्या होगा?(1) 11-9 (2) 10-90 (3) 10:98(4) 10:99 |
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Answer» 9 - 8.5 * 0.6 ÷ 5 + 3 = 9 - 8.5 *.12 + 3 = 9 - 1.02 + 3 = 12 - 1.02 = 10.98 (3) is correct option |
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| 41. |
11 10 99 10 1112 13 14BSEB. 2017 A |
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Answer» A+B = (20 20 20 20 20 20)please like the solution 👍 ✔️👍✔️ |
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| 42. |
11!-10!/9! |
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| 43. |
\frac { 11 ! - 10 ! } { 9 ! } |
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Answer» (11!-10!)/9!=(11×10×9!-10×9!)/9!=11×10-10=110-10=100 |
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| 44. |
of all two digit natural numbers which whens a right triangle, right angled at C and D is thedivided by 3 yield 1 as remainder.16.) In Fig.1, ABCmid-point of BC. Prove that ABAD-3AC17. Point P divides the line segment joining the pointsA(2, 1) and B(5,-8) such that AP =豆. If P lies on the line 2x-y+k0, find the mnAB 3 |
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Answer» ABC is a right angled at B and D is the midpoint of BC. In ∆ABD AD²= AB²+BD²…………(1)[By Pythagoras theorem] In ∆ ABCAC²= AB²+BC²…………(2) From equation (1) AD²= AB²+ (BC/2)²[D is the midpoint of BC] 4AD²= 4AB²+ BC²BC²= 4AD²-4AB²…………….(3)Using the value of BC² in eq. 2 AC²=AB²+4AD²-4AB² AC²=AB²-4AB+4AD²AC²= 4AD²-3AB² |
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| 45. |
in 2 years ?1. At what rate per cent will a sum of 4,00as compound interest inyield 1,324 as compound in3 years ? |
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Answer» 5. is the correct answer of the given question |
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| 46. |
Construct a line segment OP=7cm and divide it in the ratio 3 :5. |
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Answer» Let ratio be xSo, parts are 3x and 5xAccording to question,3x + 5x = 78x = 7x = 7/8 = 0.875So, parts are 3 × 0.875 = 2.625 cm and 5 × 0.875 = 4.375 cm.So, draw two parts 2.625 cm and 4.375 cm |
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| 47. |
7. Complete each one of the following magic square192numbers a, b, c, is it true that (a + b) + c = a + C DCollowing magic squares by supplying the missing numbers.(11) 16 215,1018 /(iii)29151216(iv)18 17 414 111016Write (Tifo |
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Answer» In a magic square, the sum of each row is equal to the sum of each column and the sum of each main diagonal. By using this concept, we have:(i) 4 9 2 3 5 7 8 1 6 (ii) 16 2 12 6 10 14 8 18 4 (iii) 2 15 16 5 9 12 11 6 13 8 7 10 14 3 4 17 (iv) 7 18 17 4 8 13 14 11 12 9 10 15 19 6 5 16 |
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| 48. |
Write the first four square numbers. |
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Answer» If you find this solution helpful, Please give it a 👍 |
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| 49. |
Write the first four square numbers |
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Answer» If you find this solution helpful, Please give it a 👍 |
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| 50. |
¢ शी _QuantlionN Ceriidn dum 0 %fiomy A eon diided sinde ¥Tl an e ; ko 5V पु He | put P(rd i T 252the एप amount 150}\ B ०0. ।.... . _ 1, | () +he > |
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Answer» Let 5:8 be = 5x and 8x5x =2501x =250/58x=250/5*88x =4008x+5x =250+40013x=650Ans=650 |
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