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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Using Euclid's Division algorithm, find the greatest number that divides 445.572 and 03remainder 4, 5 and 6 respectively.es 445, 572 and 699 leaving |
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Answer» i think that HCF wll be 63 |
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| 2. |
25. Find the greatest number which divides 615 allu Juu26. Find the greatest number which divides 2011 and 2623, leaving remainders 9 and 5respectively.con louring remainders 4 5 6 |
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Answer» Clearly, we have to find the number which exactly divides2011−92011−9and2623−52623−5.So, the required number is the HCF of 2002 and 2618. ∴ The required number is 154. |
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| 3. |
6. Find the largest number which divides 630 and 940 leaving remainders 6 and 4respectively. O |
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| 4. |
6. Find the largest number which divides 630 and 940 leaving remainders 6 and 4respectively. | |
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| 5. |
LAUIVISIOIE Uy 20, 20, 30.I6. Find the largest number which divides 630 and 940 leaving remainders 6 and 4respectively.yde1.. |
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| 6. |
The area of a triangle is 5 squarc units.Two of its vertices are (2, 1), (3, -2) andthe third vertex lies on the line y -x+ 3.The third vertex can be |
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| 7. |
25. The area of a triangle is 5. Two of its vertices are (2, 1) and (3, -2). The third vertexlies on y x + 3. Find the third vertex. |
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| 8. |
If (0,0) and (3, v3) are two vertices of anequilateral triangle, then find third vertex. |
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| 9. |
4x2 + 16x-9= 0 |
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| 10. |
itude of a right triangle is 7cm less than its base Ifthe her two sidesypo |
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| 11. |
unte positive integers. sum of whose squares is 365alritude of a right triangle is 7cm less than its base Iftheother two sides.hypoteniuse ismage industry prodi |
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| 12. |
find the volume of right circular cone withr=60mandh= 7cm |
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Answer» Volume of cone= 1/3 x πr²h= 1/3 x 22/7 x 6 x 6 x 7= 264 cm³ |
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| 13. |
do side 7cm ,24cm, 25cm, form right angled triangle ? |
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Answer» This is enough explanation for your question |
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| 14. |
13. If ¥3-1 = x + y V3, find the value of x and yV3+1 |
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Answer» I can do it sir do u want to answer by me it is very easy may answer sir X=4 ,y=-2 is the correct answer of the given question |
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| 15. |
)If sides of triangle are 7cm, 24cm, 25cm. Determine it is a right triangle or not. |
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| 16. |
Date:/tay |
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Answer» --π/3is correct answer -π/3 is the correct answer of the given question |
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| 17. |
the hypotenuse of a right triangle is 25cm and its perpendicular distance is 7cm find the length of the base |
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| 18. |
Find the curved surface area and total surface area of a right circular cylinder with radius 7cm and height 15cm |
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| 19. |
Differentiate te following functions with respect to x ta(b(i) y = 7-7+--x+10 (ii) y=xt.4x |
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| 20. |
Factorise: 16x-25y |
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Answer» 16x² - 25y²(4x)² - (5y)²(4x - 5y) ( 4x + 5y) |
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| 21. |
If x = 2 - V3, find the value of ( x - |
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| 22. |
If x = 2 -V3, find the value of (x - |
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Answer» x = 2 - √3--( 1 ) 1/x = 1/( 2 - √3 ) = ( 2 + √3 ) / [ ( 2 - √3 )(2 + √3 ) ] = ( 2 + √3 ) / [ 2² - ( √3 )² ] = ( 2 + √3 ) / ( 4 - 3 ) = 2 + √3 ----( 2 ) x - 1/x = 2 - √3 - ( 2 + √3 ) = 2 - √3 - 2 - √3 = - 2√3 ---( 3 ) Therefore , ( x - 1/x )³ = ( - 2√3 )³ = - 24√3 |
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| 23. |
s 2 AIf two zeroes of the polynomial x4-603-26x2 + 138x-35 are 2 ± V3, find other zeroes. |
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| 24. |
(a)16x -81 |
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Answer» 16x*x*x*x - 81 = (4x*x-9)(4x*x+9) = (2x-3)(2x+3)(4x*x+9) |
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| 25. |
factorise 16x-144x3 |
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Answer» =16x-144x³=x(16-144x²) =x(4²-12x²) =x(4-12x) (4+12x) |
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| 26. |
B)-V3:0<A+B£90 ;A>B, find A and B3.İftan (A-B)-V3 and tan (A |
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| 27. |
V. If x = (2 + V3), find the value of x2 +1. |
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Answer» ans.14. |
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| 28. |
mple 29 : Ifx = 2 + V3, find the values of:1(i) x2 x2 |
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Answer» (i)If x= 2+ √3then1/x=2-√3 (by rationaliztion) then (x+1/x)² = X²+(1/X)² +2(x)(1/X) i.e, (2+√3 +2-√3)² = x²+(1/x)²+2=4² - 2 = x² +(1/x)²i.e, 14 is the answer similarly solve for the second part but (a + b) whole square is not equal to a square + b square....and I tried but I can't solve the second part..plzz send me in hand written note.... |
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| 29. |
2 The ratio of the length of a rod and its shadow is 1 :V3. Find the altitude of the sun. |
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| 30. |
(7-4) cm, find x.28. The angles of a triangle are 4xยบ, (2x + 30) and (5x - 15). Find the angles and then showthat the triangle is an equilateral triangle.Find the cost nrice of the article. |
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| 31. |
\left. \begin{array} { l } { ( x ^ { 2 } y ) ^ { 3 } = x ^ { 2 } y ^ { 3 } = x ^ { 8 } y ^ { 3 } } \\ { ( 5 x + 3 y ) ^ { 2 } = 25 x ^ { 2 } + 9 y ^ { 2 } } \end{array} \right. |
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Answer» (x^2y)^3=x^2*3y^3=x^6y^3(5x+3y)^2=25x^2+30xy+9y^2 |
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| 32. |
antbya the j bn tay = b solve bycross multiplication method |
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| 33. |
7. Simplffy the following25 x t453 x 10 xt 8 |
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Answer» (25*t^-4)/(5^-3*10*t^-8)= (5)^2*t^[-4+8]]/(5^[-3+1]*2)= (5)[2+2]*t^4/2= 5^4*t^4/2= 625/2*t^4 |
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| 34. |
5.6. In the fig, a ABC is an equilateral triangle. Find & BEC |
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Answer» As given triangle ABC is equilateralSo,<BAC = 60° <BAC + <BEC = 180°[In cyclic quadrilateral sum of opposite angles is 180] <BEC = 180 - 60 = 120° |
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| 35. |
3845 x 5 x 782 + 769 x 25 x 218 |
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Answer» 3845*5*782+769*25*218=15033950+4191050=19225000 સ્ટેપ કેમ આવે ? |
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| 36. |
i) 218 5 आप 1 ॥रेथु 05 न रथ तक इन © |
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| 37. |
find the ibu. If (0coordinates of its third vertex.3) and (0, 3) are the two vertices of an equilateral triangle, find theCBSE 2014] |
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| 38. |
verteX.26. Find the third vertex of a triangle, iftwo of its vertices are (2, 1) and (3,-2) and centroid is at theongin. |
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| 39. |
Y o P 7= °d %o YI |
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Answer» Let add x So, -4/5 + x = 19/30 x = 19/30 + 4/5 x = (19 + 24)/30 x = 43/30 yessssssssssssssssssssssssssswe |
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| 40. |
If x and y are inverscly proportional, find the values of x. x2 y and ya in the tablegiven below:8 xi 16 x2 80yi45 2 y2 |
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| 41. |
EXAMPLE 1. Evaluate:(i) J 16x |
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| 42. |
\begin{array}{l}{\text { EXAMPLE 1 Evaluate: }} \\ {\text { (i) } \int_{1}^{2} x^{2} d x} \\ {\text { (iii) } \int_{0}^{1} \frac{1}{\sqrt{1+x}+\sqrt{x}} d x}\end{array} |
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| 43. |
he points (x, y), (collinear, ifThe points (, ). (i, Vi) and ( -x, y yi) areyi) and (x x y yi) areD.x+xy + y! |
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| 44. |
15. Evaluate the following:-ding3845 Ă 5 x 782 + 769 x 25 x 218 |
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Answer» 3845×5×782+769×25×218=15033950+4191050=19225000 |
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| 45. |
yiIn Fig. 6. 16, ifx + y = w + z, then prove that AOBis a line.A.Fig. 6.16 |
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| 46. |
Find the value of k if2. y a 1 is a solution of the equation 2yi |
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| 47. |
6-j Solve the following pair of equation for x and y 7+5-74 and 7w5-218 |
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Answer» send me solution plz in this question... thankx... |
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| 48. |
Find the value of following using properties (3485 x 5 x 782 769 x 25 x 218493 x 8+ 493+2 |
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Answer» 3845 × 5 × 782 + 769 × 25 × 218 = 3845 × 5 × 782 + 769 × 5 × 5 × 218 = 3845 × 5 × 782 + 3845 × 5 × 218 = 3845 × 5 × (782 + 218) = 19225 × 1000 = 19225000 given that3485×5×782+769×25×218=17425×782+19225×218=13626350+4191050=17817400 |
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| 49. |
Find the value of following using properies) 3485 x 5 x 782 + 769 x 25 x 218493 x 8 + 493 + 232277 (648-39)140 x (30 x (-9) = (140 x 30) x (4) |
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Answer» 3845 × 5 × 782 + 769 × 25 × 218 = 3845 × 5 × 782 + 769 × 5 × 5 × 218 = 3845 × 5 × 782 + 3845 × 5 × 218 = 3845 × 5 × (782 + 218) = 19225 × 1000 = 19225000 given that3485×5×782+769×25×218=17425×782+19225×218=13626350+4191050=17817400 |
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| 50. |
If the ratio of the roots of ax^2 + bx + c=0, (a!=0) is equal to the ratio ofthe roots ofx2 + x+1-0, then(a) b=(a+c)/2(b) b^2=ac(c) 2/b=1/a +1/c(d) none of these |
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Answer» so option B is rightas |
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