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Let the common term be x.Boys=2x Girls =3x2x=16x=8 So Number of girls =3×8 =24 girls

thanx

TheCartesian coordinate system. The coordinateplane can be used to plot points and graph lines. Thissystemallows us to describe algebraic relationships in a visual sense, and also helps us create and interpret algebraic concepts.

x + y = 10 and given that x = Z

so, (x=z) + y = 10=> z +y = 10

a(1/b+1/c) + c(1/a+1/b)=a(c +b)/bc + c(a+b)/ab={a²(c +b) + c²(a+b)}/abc={a²c +a²b + c²a+c²b)}/abc={a²c+ c²a +a²b +c²b)}/abc={ac(a+c) +a²b +c²b)}/abc={ac(2b) +a²b +c²b)}/abc Since a,b,c are in AP hence a+c=2b={2abc +a²b +c²b)}/abc=b{2ac +a² +c²)}/abc=b{(a+c)²)}/abc={(a+c)²)}/ac={(a+c)(a+c))}/ac=(2b)(a+c))}/ac Since a,b,c are in AP hence a+c=2b=(2b)(1/c+1/a)hence a(1/b+1/c), b(1/c+1/a), c(1/a+1/b) are in A.P if a,b,c are in AP

Ans :- Captain James Cook

In 1642, Dutchman Abel Tasman discovered Van Dieman's Land, now named Tasmania, before returning on another voyage in 1644, when he passed the coast of Australia naming it Nova Hollandia (New Holland). Navigator and astronomerCaptain James Cookset out in 1768 on the HM Bark Endeavour bound for Tahiti.

I'm guessing you asked about river system of Australia.

The Murray–Darling basin is a large geographical area in the interior of south-eastern Australia. Its name is derived from its two major rivers, the Murray River and the Darling River. The basin, which drains around one-seventh of the Australian land mass, is one of the most significant agricultural areas in Australia. It spans most of the states of New South Wales and Victoria, the Australian Capital Territory, and parts of the states of Queensland (lower third) and South Australia (south-eastern corner). The basin is 3,375 kilometres (2,097 mi) in length, with the Murray River being 2,508 km (1,558 mi) long. Most of the 1,061,469 km2 (409,835 sq mi) basin is flat, low-lying and far inland, and receives little direct rainfall. The many rivers it contains tend to be long and slow-flowing, and carry a volume of water that is large only by Australian standards.

Let the terms be a,b,c and da=a,b=a+d(common difference),c=a+2d,d=a+3d..

To prove :(a+d)×(a+2d)=a(a^2+3ad)+2d^2

Multiply 2nd and 3rd terms(a+d)×(a+2d)=a^2+3ad+2d^2=a(a^2+3ad)+2d^2

LHS=RHSHENCE PROVED.

AUB= { a e i o u}thanks

average=(110+122+120+116+112)/5=580/5=116 cm

Let one number is x and other be 3x

Difference=263x-x=262x=26x=26/2=13

Numbers are 13 and 39

how did 39 come??

267.75 is the correct answer

Total length =63m1 piece =4.25mNo.of pieces=63/4.25=14

If speed of the boat be x and stream speed be y

from the given question,

24/(x-y) + 28/(x+y) = 630/(x-y) + 21/(x+y) = 6.5

Taking 1/(x-y) as X and 1/(x+y) as Y24X + 28Y = 630X + 21Y = 6.5

solving for X and Y==>X = 1/6 and Y = 1/14

so x-y = 6 and x+y = 14hencex = 10 kmph and y = 4kmph

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18km/h , is that answer?

Speed of boat in still water, x = 6 km/h

Let speed of the stream = y km/h

Downstream speed =(6+y)km/h

Upstream speed =6−ykm/h

According to Question

3(Distance/6+y)=(Distance/6−y)=>3/6+y=1/6−y

6+y=18−3y

4y=12

y=3

∴Speed of stream = 3 km/h.

2 km/h. is it the ri8 ans ??

Let the speed of the boat in still water be X km/hr and the speed of the stream be Y km/hr.

Therefore,

Speed upstream = (X-Y) km/hr

And,

Speed downstream= (X+Y) km/hr.

Time taken to cover 16 km upstream =16/(X-Y) hrs.

Time Taken to cover 24 km downstream = 24/(X+Y) hrs

Total Time Taken to cover to both distance=6 hours.

Therefore,

16/X-Y + 24/X+Y = 6.…...(1)

Again,

Time Taken to cover 12 km upstream= 12/(X-Y) hrs

Time Taken to cover 36 km downstream = 36/(X+Y) hrs.

Total Time Taken to cover both Distance =6 hours.

Therefore,

12/X-Y + 36/X+Y = 6.........(2)

Putting 1/(X-Y) = U and 1/(X+Y) = V in equation (1) and (2). we get,

16U + 24V = 6 => 8U + 12V = 3......(3)

12U +36V = 6 => 2U + 6V = 1.......(4)

On multiplying (4) by 4 and subtracting (3) from it , we get,

12V =1

V = 1/12

Therefore,

1/X+Y = 1/12

X+Y = 12.......(5)

On multiplying (4) by 2 subtracting it from (3) we get,

4U = 1

U = 1/4

Therefore,

1/X-Y = U

1/X-Y = 1/4

X-Y = 4.....(6)

On adding (5) and (6) , we get,

2X= 16

X = 16/2 = 8

On subtracting (4) from (5) , we get,

2Y = 8

Y = 8/2 =4

Hence,

Speed of the boat in still water = 8 Km/ hr

And,

Speed of the stream = 4 km/hr.

a cylindrical vessel open at the top has a base diameter of 21 cm and height 14 cm. find the cost of tin plating its inner part at the rate of rs.5 per 100 cm cm

SI = P*R*T/100

For P= 1200, T= 3SI1= 1200*R*3/100 = 36R

For P = 1000, T= 3SI2 = 1000*R*3/100 = 30R

Given,SI1 - SI2 = 5036R - 30R = 506R = 50R = 50/6R = 25/3 = 8.3

Rate of Interest = 8.3%

Length of inner side =146-3=143breadth of inner side=116-3=113height of inner side=83-3=80

tsa of a cuboid=2(lb+bh+lh)-lb =2(143x113+113x80+80x143)-143x113 =2(16159+9040+11440)-16159 =2(36639)-16159 =57119cm^2cost of painting 1000cm^2 = Rs 2then the cost of painting 57119 cm^2 = (57119×2)/1000= 114238/1000=114.238 rs

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Source of fresh water are rain water, ground water like well , bore well etc ,river,lakes,artificial reservoir like dam , tanks

Main source is rain water , which replenish ground water,and other water bodies like ponds,lakes etc

10p + 10 = 10010p = 100 - 1010p = 90p = 90/10p = 9

my sister is good at singing dancing and cooking

>is the right answer

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correct answer is <

< is the right answer

Let AO=HCD=OB=60mA'B=AB=(60+H)m

In triangke AOD,tan30'=AO/OD=H/OD

H=OD/√3OD=√3 H

Now, in triangle A'OD,tan60'=OA'/OD=(OB+BA')/OD√3=(60+60+H)/√3 H =(120+H)/√3 H=>120+H=3H 2H=120 H=60m

Thus, height of the cloud above the lake = AB+A'B =(60+60) = 120m

Let AO=HCD=OB=60mA'B=AB=(60+H)m

In triangke AOD,tan30'=AO/OD=H/OD

H=OD/√3OD=√3 H

Now, in triangle A'OD,tan60'=OA'/OD=(OB+BA')/OD√3=(60+60+H)/√3 H =(120+H)/√3 H=>120+H=3H 2H=120 H=60m

Thus, height of the cloud above the lake = AB+A'B =(60+60) = 120m

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P= 5000, t= 1 1/2 , r= 16%A=p(1+r/100)^t(1+1/2r/100) = 5000{(1+16/100)^1(1+16/2/100)= 5000{116/100)(108/100)= 5000×116×108/100×100=6264₹interest= A - P = 6264 - 5000 = 1264 ₹

5000*32*16/100=62246224-5000=1224

thanks bro

(l+m)² -4lm l² + m² +2lm -4lml²+m² -2lm(l-m)²

Let unit place digit be x and ten place digit is (12 - x)

Then,Original Number = 10*(12 - x) + x

If digits are reversedThen number will be equal to10x + 12 - x

As per given condition10x + (12 - x) = 10*(12-x) + x + 18

9x + 12 = 120 - 9x + 18

18x = 126

x = 126/18 = 7

Therefore,Original Number = 120 - 9*7= 57