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A+B+C = piB+C = pi-A sin(B+C) = sin(pi-A)sin(B)cos(C)+cos(B)sin(C) = sin(pi)cos(A)-cos(pi)sin(A)sin(B)cos(C)+cos(B)sin(C) = sin(A)sin(B)cos(C) - sin(A) = -cos(B)sin(C)(sin(B)cos(C) - sin(A))^2 = (-cos(B)sin(C))^2sin^2(B)cos^2(C) + sin^2(A) - 2sin(A)sin(B)cos(C) = cos^2(B)sin^2(C)-2sin(A)sin(B)cos(C) = cos^2(B)sin^2(C) - sin^2(B)cos^2(C) - sin^2(A)

11/10; 10+1/2=11/2; 11/10-2/11=-8/11

11/10; 10+ 1/2=11/2 ; 11/10-2/11= -8/11

11/10; 10+1/2=11/2;11/10-2=-8/11

बिक्रीकर सहित 3300 बिक्री 10% वास्तविक मलय = 3300/1.1 = 3000

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area of triangle = 1/2× base× altitude(48×2)/12 = altitude8 cm = altitude

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S55 = 3300 [Given that]Now

Sn = n/2[2a + (n – 1)d]

∴S55 = 55/2[2a + (55 – 1) d]

∴3300 = 55/2[2a + 54d]

∴3300 = 55/2 × 2[a + 27d]

∴3300 = 55 [a + 27d]

∴3300/55= a + 27d

∴a + 27d= 60 ......(i)

Now, tn = a + (n – 1) d

∴t28 = a + (28 – 1) d

∴t28 = a + 27d

Putting the value of a+ 27d

∴t28 = 60[From (i)]

∴Twenty eighth term of A.P. is 60.

Degree of this polynomial is

8As the highest power of x is called a degree of a polynomial

Sol:1 / (√4 + √5)= [1 / (√4 + √5)] x [(√4 - √5)/(√4 - √5)]= (√4 - √5) / (√4)2 - (√5)2= (√4 - √5) / 4 - 5= (√4 - √5) / (-1)= (√5 - √4)

(1 / √5 + √6)

= [1 / (√5 + √6)] x [(√5 - √6)/(√5 - √6)]= (√5 - √6) / (√5)2 - (√6)2= (√5 - √6) / 5 - 6= (√5 - √6) / (-1)= (√6 - √5)

Similarly,(1 / √6 + √7) = (√7 - √6)(1 / √7 + √8) = (√8 - √7)(1 / √8 + √9) = (√9 - √8)

(1 / √4 + √5) + (1 / √5 + √6) + (1 / √6 + √7) + (1 / √7 + √8) + (1 / √8 + √9)= (√5 - √4) + (√6 - √5) + (√7 - √6) + (√8 - √7) + (√9 - √8)= 3 - 2= 1

( iv) octagon

option D is correct answer

option .iv. octagon is the right answer

option (4) octagon is the right answer

the correct answer is D

suppose angles are x,3x,5x,4x,5xso x+3x+5x+4x+5x=54018x=540so x=30so angles are 30,90,150,120,150

The photoelectric effect refers to theemission, or ejection, of electrons from the surface of, generally, a metalin response to incident light.Einstein proposed that the incident light consisted of individual quanta, called photons, that interacted with the electrons in the metal like discrete particles, rather than as continuous waves. For a given frequency, or 'color,' of the incident radiation, each photon carried the energy E = hf, where h is Planck's constant and f is the frequency. Increasing the intensity of the light corresponded, in Einstein's model, to increasing the number of incident photons per unit time (flux), while the energy of each photon remained the same (as long as the frequency of the radiation was held constant).

Clearly, in Einstein's model, increasing the intensity of the incident radiation would cause greater numbers of electrons to be ejected, but each electron would carry the same average energy because each incident photon carried the same energy. [This assumes that the dominant process consists of individual photons being absorbed by and resulting in the ejection of a single electron.] Likewise, in Einstein's model, increasing the frequency f, rather than the intensity, of the incident radiation would increase the average energy of the emitted electrons

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Octagon has 8 sides.

So, each side has 48.8/8

= 6.1 cm

As we knowx+y+z+130= 360100+z+130= 360z= 360-230z= 130

fog(x) = √(2x-3)gof(x) = 2√x-3

When we are asked to calculate the distance between a point and any of the axes, we calculate the perpendicular distance between them.

Therefore, the point (-3,4) is 3 units away from the y-axis and 4 units from the x-axis. This is because in case of either axes the co-ordinate of the other axis is zero.

Therefore the distance between the point P(-3,4) and x-axis is 4 units.

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1. five thousand seven hundred one

quadrilateral have 4 sides. octagon have 7 sides. pentagon have 5 sides. heptagon has 8 sides. hexagon have 6 sides.

Q-4O-8P-5Hep-7hex-6

=(sinA+cosecA)²+(cosA+secA)²

=sin²A+cosec²A+2sinAcosecA+cos²A+sec²A+2cosAsecA

=sin²A+cos²A+cosec²A+sec²A+2sinA×1/sinA+2cosA×1/cosA

=1+cosec²A+sec²A+2+2

=5+(1+cot²A)+(1+tan²A)

=7+tan²A+cot²A

Identities used:1+tan²A=sec²A

1+cot²A=cosec²A

sin²A+cos²A=1

cosecA=1/sinA

secA=1/cosA

(fog)oh=(fog)x^2=(f(3x^2+1)=3x^2+1-1=3x^2; fo(goh)=( fog)x^2=f(3( x^2)^2+1=f(3x^4+1)=3x^4+1-1=3x^4

Requisites Of Business Success

Following are the major components (requisites) required for successful business operation:

1. Establishment Of Clear-cut Objectives

Clearly defined objective helps to provide guidelines for future business activities. Long-term and short-term objectives should be established in order to achieve goals.

2. Proper Planning And Clear Policy

Proper planning helps the businessman to decide what to do and how to do different business activities. Correct and clear policy helps to perform work with minimum risk and maximum profit.

3. Sound Organization And Effective Management

This is another essential requisite for business success. Proper organizational structure and quality management helps in planning, coordinating, motivating, directing and decision making. It helps proper utilization of resources and to achieve organizational goals.

4. Dynamic Leadership

Dynamic leadership is another key factor for business success. Leader or manager with vision, courage, foresightedness, and motivating skills is needed to operate business successfully.

5. Pleasant Personality

Manager should be physically and mentally sound to handle business activities smoothly. Manager or businessman with good communication skills, intelligence, experience, and good commanding is needed for business success.

6. Adequate Capital/ Proper Financial Planning

A proper financial planning is needed to arrange adequate long-term and short-term capital to operate business. Suitable source of capital should be identified to run business smoothly.

7. Proper Location And Layout

Proper location and layout helps to reduce production and operation cost and increase efficiency of the business. Suitable location and proper layout helps to maximize profit.

8. Employees Morale

Encouraged and motivated employees play very important role in business. Success or failure of business depends on the morale of employees. Therefore, staffs should be motivated, encouraged, and properly trained to achieve organizational goals and objectives.

With the help of convection we can get heatthanksplease like the solution 👍 ✔️

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x= 11 is the correct answer of the given question

X=11is correct answer

sin20. sin 40. sin60. sin80

=> sin60[sin20.sin40.sin80]

=>√3/2[sin20.sin(60-20).sin(60+20)]

=>√3/2[sin 3(20)/4]

=>√3/2[sin 60/4]

=>√3/2[√3/2*4]

=>√3/2*√3/8

=3/16

the blue line is -2/5 , the red line is 1/5 , the yellow line is 8/3 , and the green line is 3(2/7) or 23/7.

calculate without using trigonometric table

2*cos40 - cos20 = cos40 + (cos40 - cos20) = cos40 - 2*sin((40+20)/2)*sin((40-20)/2) = cos40 - 2*sin30*sin10 = sin(90-40) - sin10 = sin50 - sin10 = 2*sin((50-10)/2)*cos((50+10)/2)=2*sin20*√3/2=√3*sin20√3*sin20 / sin20 =√3

so(1-cos^2 theta)(1-cot^2 theta)sin^2 theta* cosec^2 theta= 1

cos 60 is th right answer

sin 45° = 1/√2

cos 45° = 1/√2

A) sahi hai

Given,A = |3 2| |1 -1|

|3A| = |3(-3 - 2)| = |3*-5| = 15

(C) is correct option

(5x²-4y²)²=25x^4+16y^4-40x²y²

(a-b)²=a²-2ab+b²

sin (h^-1)x=log(X+√x^2+1)hence X=3hencesin h^-1 (3)=log (3+√10)

It is a rong

Distance between P and Q=√((x2-x1)²+(y2-y1))²=√((2-7)²+(5-5)²)=√(-5)²+0=5 units