Explore topic-wise InterviewSolutions in Current Affairs.

Given,Principal amount P = 2400,Rate of Interest R = 5%, Simple Interest SI = 240, Time period = T

We know,SI = P*R*T/100240 = 2400*8*T/100T = 240/(24*8) = 10/8T = 5/4 = 1 1/4

Therefore, In 1 year 3 months I will earn Rs 240 as interest on amount of Rs 2400.

Sum of angles of various sector in pie diagram is 360°.

Reason: Due to circular shape

as four are white and total sectors are sixhence4/6=2/3 is the probability.

open above image to have a look at the solution it is not blur.

First angle, a = 8°nth angle, an = 72°let the common difference = d

sum of angles = 360°⇒ (n/2)[a + an] = 360⇒(n/2)[8+72] = 360⇒(n/2)[80] = 360⇒ 40n = 360⇒ n = 360/40⇒ n = 9

72 = 8+(n-1)d⇒ 72 - 8= (9-1)d⇒ 64 = 8d⇒ d = 64/8⇒ d = 8°

a₃ = a + (n-1)d⇒a₃ = 8 + (4-1)×8⇒a₃ = 32

n = 9angle of fourth sector = 32°

Draw right angle triangle ABC,

draw medians. AD, BE, CF. Now Join DF.Since D and F are midpoints of sides AB and BC, DF will be parallel to AC and is equal to 1/2 AC.

ADF, ABE, AFC are all right angle triangles.

LHS = 2 (AD² + BE² + CF² ) = 2 [ (AF² + DF²) + (AB² + AE²) + (AF² + AC²) ] = 2 [ (AB²/4 + AC²/4) + (AB² + AC²) + (AC²/4 + AB²/4) ] = 2 [ BC² /2 + BC² ] = 3 ( BC² ]

Mr. George asker her why she was absent for yesterday's presentation?

(B) 130°

Given:AB=CDto prove:PB=PDconst: draw OE and OQ perpendicular on AB and CD respectivelyproof:given AB and CD are two equal chords of the same circle.OE=OQ(equal chords of a circle are equidistant from the center.)now in triangle OEP and OQP,OE=OQOP=OP(common)angle OEP = OQP =90 degree,by constructiontherefore triangle OEP = OQP (RHS congruency)EP = QP (CPCT)also AE=EB=1/2 AB and CQ=QD=1/2CD (the line joining the center of the circle is perpendicular to the chord and bisects the chord.)Now AB = AC implies AE = EB= CQ=QD ....(1)therefore EP-BE =QP - BEEP - BE = QP - QD (FROM 1)BP = PDhence proved

thanks yrr

tq very much

OK better answer

convex quadrilateral

convex wuadrilateral

thank you very much

1)area of parallelogram= base × height = 7×4=28cm^22)area=(5)(3)=15cm^2

sec p = x – tan p

squaring both the sidesबर्ग लेने पर

sec^2p = x^2– 2* x* tan p + tan^2p

sec^2p –tan^2p =x^2– 2* x* tan p

x^2– 2* x* tan p – 1 = 0

2* x* tan p =x^2– 1

tan p = (x^2– 1) / 2 x

0.2 is the correct answer

value of x will be 1/5. It can be obtained by solving trignomwtric relation.

1/5 is the correct answer

cot x = 5/12

Then,Value of 1 + tan^2 x - sec^2x= 1 - (sec^2 x - tan^2x)= 1 - 1= 0

(d) is correct option

xsin³∅ + ycos³∅ = sin∅. cos∅x.sin³∅ + cos²∅.(ycos∅) = sin∅.cos∅use xsin∅= ycos∅ in above

xsin³∅ + cos²∅.xsin∅ = sin∅.cos∅ xsin∅( sin²∅ + cos²∅) = sin∅.cos∅ xsin∅ = sin∅.cos∅ x = cos∅ so, y = sin∅

now we know, sin²∅ + cos²∅ = 1 put sin∅ = y cos∅ = x

hence, x² + y² = 1

Here's the answer you are looking for

Curved surface area of a cone is = πrl

where r = radius = 40cm

and l = slant height

Substituting the values,

1640 = π (40) (l)

l =1640/22/7x40

l = 13cm (approx)

10 open rectangular district when measured from outside is 1.35 metre long 1.08 board and 80 CM Deep and is it made of iron which is 1.5 cm find the capacity of the Christian and the volume of the iron used

Given:radius= 5 cm.Height= 40 cm.

To find: Total surface area of a cylinder.

Solution:Total suface area : 2 pi r (r+h).2 × (3.14) × 5 × 45.1413 sq.cm.

thank you sir

LHS

( cosecA - cotA )²

= ( 1/ sinA - cosA/sinA )²

= ( 1 - cosA/ sinA )²

= ( 1 + cosA )²/ sin²A

= ( 1 - cosA )²/ 1 - cos²A

= ( 1 - cosA ) ( 1 - cosA )/ ( 1 + cosA ) ( 1 - cosA )

= 1 - cosA / 1 + cosA

.°. RHS

Like my answer if you find it useful!