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2x*x - 7x - 15 = 2x*x - 10x + 3x - 15 = 2x(x-5)+3(x-5) = (2x+3)(x-5)

2x^2 - 7x - 15 = 2x^2 - 10x + 3x - 15= 2x(x - 5) + 3(x - 5)= (2x +3)(x - 5)

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HCF of 3m+6n+12mn=33(m+2n+4mn)This is correct.

3m^2 + 9m + 6=03m^2 + 6m + 3m + 6=03m(m+2) + 3(m+2)=0(3m+3)(m+2)=0m = -1, -2

it is a factorisation question

2x^2-(10-3)x-15=02x^2-10x+3x-15= 02x(x-5)+3(x-5)=0(2x+3)(x-5)=0x= 5 and x= -3/2are the zeros of this quadratic

Every set is a member of power set so that, A ∈ P(A) Given that P (A) = P (B) So that A ∈ P(B) A is a element of power set of B so that, A ⊂ B ... (1) Similarly we can prove that B ⊂ A ... (2) From equation (1) and (2) we get, A = B

8x-3/3x =2; 8x-3=6x; 8x-6x-3=2x-3; 2) 9x/7-6x=15; 9x=15(7-6x); 9x=105-90x; 9x+90x=105; 99x=105;

8x-3/3x=2,; 8x-3=6x; 8x-6x-3; 2x=3; ; 2) 9x/7-6x=15; 9x=15(7-6x); 9x=105-90x; 99x=105; x=105/99=35/33; 3)z/z+15=4/9; 9z=z+15(4); 9z-z=60; 8z=60; z=60/8=30/4=15/2;;

3y+4/2-6y=-2/5; (3y+4)(5)=(-2)(2-6y); 15y+20=-4+12y; 15y-12y=-4-20; 3y=-24; y=24/3=-8; 5) 7y+4/y+2=-4/3; 7y+4(3)=y+2(-4); 21y+12=-4y-8; 21y-4y=-8-12; 17y=-20; ; y=20/17

8x-3=6x or 8x-6x=3 or 2x=3 or x=3/2

the answer of this is8x-3____ 3x

1. 8x - 3/ 3x = 2 8x × 3x = 2 + 3 24x = 5 x = 24/5 x = 4.9

2. 9x / 7 - 6x = 15 9x × 6x = 15 -7 54x = 8 x = 54 / 8 x = 6.75

3. z / z + 15 = 4/9 z^2 = 4/9 - 15 z^2 = 4/9 - 135/9 z^2 = -131/9 z = -131/49/z z = -131/49

4. 3y+4 / 2-6y = -2/5 3y×6y / -4+2 = -2/5 18y / -2 = -2/5 18y = -2/5 ×-2 18y = 4/5 y = 4/5/18 y = 4/5×18 y = 72/5 y = 14.4

please solve cross multiplication.

4800*2.5/100 + 75*20/100 -950/10120+15-95=45

Factorization:

3m² + 9m + 6

3m ² + 3m + 6m + 6

3m ( m + 1) + 6 ( m + 1)

(3m + 1) ( m + 1)

Antibiotics work by decreasing the amount of bacteria present, while probiotics work by increasing and diversifying the amount of bacteria.

the answer is 2 years

the answer is 2years

If the given two lines are parallel, then their slopes are equal.

Then, equation of lines in standard formy = mx + c

2x + 3y = 7y = - 2/3x + 7/3......(1)

(a-1)x + (a + 1)y = 3a+1y = [(1 - a)/(a + 1)]x + (3a+1)/(a+1)

Hence,(1 - a)/(a + 1) = - 2/33 - 3a = - 2a - 22a - 3a = 3 - 2-a = 1a = - 1

Therefore value of a = - 1

value of a is 5 you are wrong

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mast jai

यदिa1/ a2= b1/ b2= c1/ c2तब बहुत हल होगेअतः2/(a-b)=3/(a+b)2/3= (a-b)/(a+b)2(a+b)= 3(a-b)2a+2b=3a-3b-a=-ba=b---(1)अतः3/(a+b)=-7/3a+b-23(3a+b-2)=-7(a+b)9a+3b-6= -7a-7b

as a= b9a+3a+7a+7a= 626a= 6a=b= 6/26

16(a-b)³ -24(a-b)²8(a-b) [2(a-b) -3]8(a-b) (2a - 2b -3)

16(a-b)³ -24(a-b)²8(a-b) [2(a-b) -3]8(a-b) (2a - 2b -3)

thanku

(a) 90° is the right answer

90• is the correct answer of the following

90° is the correct answer...

2a+5a+3a=180a=180/10a=18°c=5ac=5×18c=90° answer

90° is the best answer

90° is correct answer.

a 90 is the right and correct answer

a =40° and b = 100°.

yes the d option is right as-1+4/7=-3/7

4/7 is the correct answer of the given question

4/7 is the answer of the following

4/7 is answer that is questions

3/7 is the correct answer of the given question

Lowest form for this one is 3/7

suppose multiplicative inverse is x so (-13)(x) = 1 so x=-1/13

a-1/a=7take square in both the sidesa^2-2+1/(a)^2=49so a^2+a^(-2)=51

again take square in both the sidesso a^4+2+a^(-4)=2601so a^4+a^(-4)=2599

please tell me the concept of +1

bro please elebrate i cant understand i have my exam at 12:30

thanks

x^2-36=(x)^2-(6)^2=(x+6)(x-6)

By using algebraic identity,

a² - b² = ( a + b ) ( a - b )

We find the factors.

************************

x² - 36

= x² - 6²

= ( x + 6 ) ( x - 6 )

x^2*6^2(x + 6) (x - 6)

x=6,-6 are the correct solutions

X2-32x*x+8*-4(x+8)(x-4)

(x+6)(x-6)=x2-36,x2-6x+6x-36

x*x=x^22*3*2*3=36this can be done

By using identity2x²-36(x-6)²x²-2.x.6+6²(x-6)(x-6)

x square - 36 x square - 6squarethe formula is a square - b square(a+b) (a-b) this answer is (X+6) (x-6)

(a-b)=(a+b)(a-b)(x)^2 (6)^2(x-6) (x+6)

(x-6)(x+6) is the correct answer h

(x-6)² is the correct answer believe in scholr

x^2-36(x)^2-(6)^2(x+6)(x-6)

THANKS FOR ASKING QUESTIONS.

x^2-36 =(x)^2-(6)^2=(x+6)(x-6)

x²-36x³-6²(X+6)(x-6)

we apply 3rd identity (a square - bsquare)so (x-6)(x+6)

(A-B) (A+B) A=xB=6(X-6) (X+6)

x²-36(x)² - (6)²(x+6) (x-6)

by using identity a^2-b^2 = ( a+ b ) ( a - b )x^2-36x^2 - 6^2( x+6) ( x-6)

solution (x+6)( x_6)

(x+6)(x-6) is the answer

a^2-b^2=*( a+b). (a-b) so this question answer is (x+6)(x-6)

The correct answer is x-6

(x-6) (x+6) is right answer

a²-b²=(a+b)(a-b) x²-6²(x+6)(x-6)

This question answered by (6)

=(x)² - (6)²= (x+6)(x-6)

x*x+8x+16 = x*x+2(4)(x)+4*4 = (x+4)(x+4)

x² - 2x - 99 = x² +9x - 11x - 99 = x(x+9) - 11(x + 9) = (x-11)(x+9)

4 hundred ,eighty six

2x + 3x + 20 + 3x - 20 + 2x + 10 = 360 10x + 10 = 360 10x = 350 x = 35 angles are 70,125,85,80

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please send the image clearly which you have sent now in the scholr

3x + 20 = 303x = 30 - 203x = 10x = 10/3

thank you

9. (3t+1)(3t+4) = 9t² + 12t + 3t + 4 = 9t²+15t+4

10. 90+ 4x +x = 180° ( staright line)5x = 90°x = 90°/5 = 90°

11.a² -3a -40a² +5a -8a -40a(a+5) -8(a+5)(a-8)(a+5)