This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The side of a square field is 60 m long. What will be the length of a fence going all around it?e metal wire are to be usc |
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Answer» length will be equal to the perimeter hence perimeter of a square is 4xside=4*60=240m |
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| 2. |
-SolvebyFormula methodinARB13] me ages of| years the product onme 19 & 15 respectivelytheir ages is 480.19-6-5Tespih |
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Answer» Given,Age of A = 19 yearsAge of B = 15 years Let in x years product of ages will be 480 Then,(19 + x)*(15 + x) = 48019*15 + 19x + 15x + x^2 = 480x^2 + 34x - 195 = 0x^2 + 39x - 5x - 195 = 0x(x + 39) - 5(x + 39) = 0(x - 5)(x + 39) = 0x = 5, - 39 Negative value not possible Therefore, on adding 5 to each 19 and 15 product will be 480 |
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| 3. |
Fill the boxes using(1,3,5,7,9,11,13,15)You can also repeat the numbers |
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Answer» 11+13+3! 3!=3×2×1=611+13+6=30so the answer is 11+13+3! |
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| 4. |
The expanded form of log 15 is |
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Answer» log 15=log(3×5)Using product law of logarithm we get log(3)+log(5) |
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| 5. |
Expanded form of (-a b)^{4} is |
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Answer» (-1)(-1)(-1)(-1)*a*a*a*a*b*b*b*b=a*a*a*a*b*b*b*b |
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| 6. |
How much distance a man walks in goingtimes around a square field of side 35 m? |
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Answer» perimeter of a square = 4*35 = 140 m Like my answer if you find it useful! |
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| 7. |
Write (3a+4b+ 5c) in expanded form |
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Answer» (3a + 4b+ 5c)2= (9a2+ 16b2+ 25c2+ 2(12ab +20bc + 15ca) As (a+b+c)2= a2+ b2+ c2+ 2(ab + bc+ ca)= 9a2+ 16b2+ 25c2+ 24ab + 40bc + 30ca |
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| 8. |
Mental Maths Corner1. Tick (v) the correct answer.(a) The perimeter of a triangle whose sides are 6 cm, 5 cm and 4 cm is(i) 30 cm (in) 15 sq. cm(iii) 15 cm(iv) 15 m |
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Answer» the answer is 15 centimetres the answer is ( 3)15 centimetres . perimeter of the triangle is sum of all the sides so (6+5+4)cm=15 cm the answer of the question is (iii) 15 cm PERIMETER OF TRIANGLE =SUM OF ALL SIDESO 6 + 5 + 4 CM = 15 CM perimeter of a triangle is sum of all sides that is 6+5+4=15centimeters the answer is 15 centimetres please like me 🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗 Perimeter is option 3 , 15 cm 3rd is your answer ol the 3 one that's 15 centimetres |
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| 9. |
2. Write the expanded form of 123.987. |
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Answer» 100000+20000+3000+900+80+7 100+20+3+9/10+8/100+7/1000 100+20+3+9/1000+8/100+7/10.please like my answer |
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| 10. |
2. Theexpandedformof[38-B 73. ... |
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| 11. |
A horse is tied with a rope 7 m long to one corner of a square field of side 17 m. Find thegrass that the horse can graze. (Take Ď ) |
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Answer» Length of rope tied to the centre of the Square=7 mSide of square=17 mTo find,(i) Area grazed(ii) Area ungrazedATQ,(i) Area grazed= Area of circle with r=7 m=πr²=22/7*(7)²=22*7=154 m²Now,Area ungrazed=Area of square-Area grazed=[(a)²-154] m²=[(17)²-154] m²=[289-154] m²=135 m² |
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| 12. |
\begin{array} { l } { \text { If } \frac { 3 + \sqrt { 5 } } { 4 - 2 \sqrt { 5 } } = p + q \sqrt { 5 } , \text { where } p \text { and } q \text { are rational } } \\ { \text { numbers, find the values of } p \text { and } q . } \end{array} |
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| 13. |
19. Find the value(s) of p for which the points (p 1,2p-2). (p-1. p) and (p -3, 2p-6) arecollinear.OR |
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| 14. |
(a)The distance around a circular region is called its |
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Answer» The distance around a circular region is called it's circumference. if radius of the circular region is given as R Then circumference will be 2πR |
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| 15. |
Q30) four hours 24 min - how many minutes?1) 2402) 2443) 2644) 364 |
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Answer» One hour = 60 minutes4 hours = 60*4 = 240 minutes 4 hours 24 min= 240 + 24 = 264 minutes (3) is correct option 1 hour = 60min4 hour = 4 X 60 = 2404 hour 24 min = 240+24 =264 if 1hour=60minut then 4 hour=4.60=240minut then 240+24=264minut |
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| 16. |
write the following numerals in expanded form 356782 |
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Answer» 356782 = 300000 + 50000 + 6000 + 700 + 80 + 2 |
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| 17. |
2. Write the expanded form of the following numbers.a) 12312b) 43821 |
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Answer» I don't know (a)12312=10000+2000+300+10+2(b)43821=40000+3000+800+20+1 ans 10000+2000+300+10+2 |
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| 18. |
Write the following in expanded form:(a) 5.3(b) 12.89(c) 10.05 |
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Answer» (a) 5+(3/10)(b) 10+2+(8/10)+(9/100)(c) 10+(5/100) |
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| 19. |
hasthe greaterareddlllDlength 80 m. Which plot7.50metre, how much would it cost for grass to be laid on the field leaving a bare path 4 m wide allthe field?per squarearound13. A rectangular field is 60 m wide and its perimeter is 320 m. If laying of grass costsm What is the area of unshaded region? |
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Answer» B=60mp=320mnow,2(l+b)=320l+60=160l=160-60l = 100mnow,new length =100-(2×8)=84mnew bredth=60 -16=44marea=84×44=3,696 m squrecost =3,696×7.5=27,720 |
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| 20. |
Walking around the edge of a circular fountain, Ram noticesthat its circumference is 66 m. Find the area of the fountainregion. |
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| 21. |
)Write the expanded form of the following1) 0.8752) 25.18 |
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Answer» 1) 0.875 = 8/10 + 7/100 +5/10002)25.18 = 25 + 1/10 + 8/100 |
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| 22. |
cos 2A = cos2 A2 A- sin |
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Answer» Given A = 30° LHS: cos 2A= cos 2*30= cos 60°= 1/2 RHS: cos^2 A - sin^2 A= cos^2 30 - sin^2 30= (root(3)/2)^2 - (1/2)^2= 3/4 - 1/4= 2/4 = 1/2 Hence proved |
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| 23. |
iii) Prove that:23a24Cos 2A1+Sin2A |
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Answer» We have to prove that Cos2A/1+sin2A=tan(π/4-A) Solution:-As shown in attachment... Formula used :Cos 2x = cos²x- sin²x Sin²x +cos² x =1Sin 2x = 2sin x cos x And (1-tan x)/(1+tan x) = tan (π/4 -x)please like the solution 👍 ✔️ |
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| 24. |
(m)‘Y 800 पाई केVus+ " v 500 |
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Answer» LHS =cosA/(1+sinA) +(1+sinA)/cosA ={cos²A +(1+sinA)²}/cosA.(1+sinA) ={cos²A+1+sin²A+2sinA}/cosA.(1+sinA) use sin²∅ +cos²∅ =1 =(1+1+2sinA)/cosA(1+sinA) =2(1+sinA)/cosA(1+sinA) =2/cosA =2secA = RHS |
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| 25. |
Find out the distance between the points (p,q+r) and(q,p+r). |
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Answer» bhai distance formula lga ke solve krdo n The. distance between. the two point is. 2p-2q p -q √2 is a write answer 2p-2q is the distance between two points A and B (v+v)/distance speed equal distance between points the distance between.the two point is.2p-2q 2(p-q) and2(q-p)is the distance between both points .the value of both is same but sign is negative ,so we can neglact negative because the distance always measured in postive never be negative (+/-)√2(p-q) this is your answer √ (q+r-p-r)^2 + ( q-p)^2 = √2 • ( q-p ) The answer is p+q/2,q+p+2r/2 √2 p-q square root over ( q-p)²+(q-p)²=1.414×(q-p) it's like thisassume distance=x,x²=[p-q]²+[(q+r)-(p+r)]²x²=(p-q)²+(q-p)²x²=2(p-q)²x=√2(p-q)² Use the distence formula of pint line The answer will be √2(p-q). distance between two point is (p-q)√2 underroot 2 (p-q) is the answer for the given question use distance frula and then compare them using distance formula the answer is 2p-2q for the following question (p - q)√2 unit is the correct answer the distance between the two points is 2p-2qplz assign my answer as the best answer |
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| 26. |
उप,14 tan” 30° (i) sin 60° (i) cos 60° "G sin30°(iii) tan 60° |
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| 27. |
The line segment joining the points (3, -4) and (1, 2) is trisected at the points p and q. If theco-ordinates of P and Q are (P,-2) aresecively. Find the value of P and Q |
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| 28. |
9६(४ ण्थ- )V Uisव्यप्थ o Vs |
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| 29. |
gus v s0d + gs0d Vs = (g + v)uws () 5 |
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Answer» LHS:sin(A + B) = - cos (A + B + pi/2) = - cosA cos(B + pi/2) + sinA sin (B + pi/2) = cosA sin B + sin A cos B = RHS Hence proved |
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| 30. |
4 The dot plot shows how long it takes the24 students in Brayden's class to brushtheir teeth each morning. Each dotrepresents one studentTime Taken to Bruno Tooth1 1 2 2 3 3 4 4MinutesHow many students in Brayden's class take2 to 4 minutes to brush their teeth eachmorning?F 14 G 16H 22 J 23 |
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Answer» Count the dots in 2, 2 1/2, 3, 3 1/2, 4Number of students = 22 |
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| 31. |
\left. \begin{array} { l } { \text { Three points } ( p + 1,1 ) , ( 2 p + 1,3 ) \text { and } ( 2 p + 2,2 p ) \text { are collinear if } p = } \\ { \text { (a) } \quad - 1 } & { \text { (b) } 1 } & { \text { (c) } 2 } \end{array} \right. |
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Answer» p =2 is a right option |
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| 32. |
school3t-La |
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Answer» thank's |
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| 33. |
Find number for following expanded formsA))0x10^2+ 0x10^3+ 0x10^3+5x10^5+ 9x10^6B) 0x10^1+ 9x10^4+ 2x10^2+1x10^5+ 0x10^7(-5/3)^-3 x (1/3)^2 =?If 2^P+ 2^P+1 =24, find the value of p. |
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Answer» a) 0+0+0+500000+9000000 = 9,500,000 a)0+0+0÷500000+9000000%9,500,5000 |
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| 34. |
. The region around a magnet where its magnetic influence can be felt is called its magnetic |
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| 35. |
हि () AABC Hsin का मान होगादब% दर जज -छि व- (i) sin3 +sin (i) sinyAkt bte (i) cos रु (ivy & & कोई नहीं |
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Answer» In a ∆ , A + B + C = 180° A + B = 180 - C (A + B)/2 = 90 - C/2 sin [ (A + B)/2] sin ( 90 - C/2) cos (C/2) iii) option |
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| 36. |
find a value of A when cos 2A= sin3 A |
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| 37. |
L m— मेनका 2- 0 + 3« सर A (ना 9 B (3,“) C‘US J)LA _. |
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| 38. |
23. If sin3the value of Ge cos60), where 30 and (- ) are both acute angles, find |
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| 39. |
3. In an AP: la), if common difference is 3, find a37-1 |
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Answer» Given : d = 3 a(37) - a(15) a + 36d - ( a + 14d) a + 36d - a - 14d 22d 22 × 3 66 |
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| 40. |
Vs YS0o+] vus7 5 v +vso:)+[ 1Y) 2A01g |
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| 41. |
Find the area of the triangle formed by the points (P+), (2P+1. 3)and(2P+2, 3P) and show that the points are collinear if P-2 or- |
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Answer» Like my answer if you find it useful! |
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| 42. |
twist to lebrush aside Calpurnia's fears and leaveulUQ8. Why is Decius more successful in persuading Caesar than(Textual)ld iust anpeal to Caesar's emotionsCalpurnia? |
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Answer» Ans :- Decius Brutus is a great flatterer. Heis more successful in persuading Caesar than Calpurnia because his argument appeals to Caesar’s pride.While Calpurnia wishes that Caesar stay at home after seeing horrible dreams, Decius Brutus interprets the dreams lucky and fortunate. According to him, they signify Caesar’s power and influence. He gives Caesar’s ego a boost. Caesar is totally carried away by his words and decides to go to the Capitol. |
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| 43. |
4) The line segment joining the points A(2, 1) and B(5, 8) is trisected at the points P and Q suchthat P is nearer to A. If P also lies on the line given by 2x -y+k0, find the value of k. |
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| 44. |
13. If the points A (0, 2) is equidistant from the pointsB (3, P and C (P, 5), find P. Also, find the lengthof AB. |
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| 45. |
27. In Figure 17, determine the value ofx1. In thetwo strother afind the138°Fig. 17 |
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Answer» because both given are vertically opposite angle so ,x+x = 1382x = 138x = 69 |
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| 46. |
. Determine the angJ U, Find a value of A when cos 2Asin3 A.10no |
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Answer» cos2A = sin3A==> cos2A = cos(90 - 3A) ==> Either 2A = 90 - 3A or 2A = -(90 - 3A)==> 5A = 90 or 2A = -90 +3A==> A = 18 or A = 90. These are the solutions from 0 degrees to 360 degrees. WhySin3A to cos(90-3A) to convert |
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| 47. |
Determine a and b, if/7+vS-./7-5=a+/35b-15 Find the coo |
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Answer» So 2√5 =a+b√35 a= 0 2√5 = b √7. √5 b= 2/√7 |
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| 48. |
17. If (p 1)th term of an AP is twice the(q+ 1Ixh term, prove that 3p lth term istwice the (p+ 1th term |
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| 49. |
6In Fig. 5.20, find the value of x and hence determine the values of ZAOC, COD(x + 29)Fig. 5.20 |
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Answer» x+x+29+x-17= 1803x= 197-293x= 168x= 56 x+x+29+x-17=1803x=197-29 3x=168x=56 answer The sum of the angles are =180°So,x+(x+29)+(x-17)=180°3x+12=180°3x=180°-12°3x=168°x=168/3x=56° |
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| 50. |
S Find(a) Do you see any order in the digits ofH TO2 3 4the two numbers being added? Writeascending or descending against each.234:7 65:+7 65mn(c)What is 1 more than the above sum? What is special about this number? |
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Answer» a) 234 - ascending 765 - descending b) It is a special 3-digit number having all digits as 9 c) It is 1000 right ascending descending |
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