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Diameter is 49 cmSo, radius is 49/2 cmCircumference is 2× pi × rcircumference = 2 × 22/7 × 49/2Circumference = 154 cm

sorry but I cannot understand show another method sir

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9x+6=2x7x=-6so x=-6/7

Let the cost price of each cassette be rs.10cost price of 130 casts = 130*10=1300by selling , he gained sp of 5 cassettestherefore , cost price of 130 cassettes = selling price of 125 cassettessp of 5 cassettes = 1300/125×5= 52he gained Rs. 52 on selling 130 cassettesgain℅= gain/total cp * 100= 52/1300*100= 4℅

to proof: AP = BPBy const.=draw radius from A to O and from B to OProof : In ΔAOP and ΔBOP AO = BO(radius of circle) angleAPO=angleBPO(each=90°) OP=OP (common) ΔAOP≈ΔBOP(by SAS) by cpct AP=BP

A) A+C+= B+D is the right answer

10+15+30+55+68+38=235

STATEMENT :- In a triangle if the square of a side is equal to the sum of the squares of other two side then the angle opposite to the first side is a right angle..

In triangle XRQ XQ²+QR²=XR²(2/3PQ)²+QR²=XR²4/9PQ²+QR²=XR² (1)BY Pythagoras THEOREM IN TRIANGLE PYRPQ²+QY²=PY²PQ²+(2/3QR)²= PY² (2)BY PYTHAGORAS PQ²+4/9QR²=PY²IN TRIANGLE PQRPQ²+QR²=PR² (3)PYTHAGORAS THEOREMAdding 1 and 24/9QR²+QR²+4/9PQ²+PQ²=XR²+PY²13/9 QR²+ 13/9 PQ ²= XR²+PY²1/9(13QR²+13PQ²) = XR²+PY²13(QR²+PQ²) =9(XR²+PY²) FROM 3 WE GET 13PR²=9(XR²+PY²)

xy-pq+qy-px=xy-px+qy-pq=x(y-p)+q(y-p)=(x+a)(y-p)

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Radius = 10 cm height = 21 cm

l =√r² +h²l =√10² + 21²l = √100 + 441l = √541l = 23.25 cm

cloth required = Curved surface area of one conical cap = πrl= (22/7)×(10)×23.25= 73.07 cm ²

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Let the cost price of each cassette be rs.10cost price of 130 casts = 130*10=1300by selling , he gained sp of 5 cassettestherefore , cost price of 130 cassettes = selling price of 125 cassettessp of 5 cassettes = 1300/125 * 5= 52he gained Rs. 52 on selling 130 cassettesgain℅= gain/total cp * 100= 52/1300*100= 4℅

option (ii) is the correct answer

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thanks jkr a Xdxd VCUXX schooluv j

option (iii) is the correct answer

ii) 30%&10% is the correct answer

option 2nd is the correct answer

2 is the right answer

let the actual price be X

so, first discount is 20% , so the price becomes x-(20%ofx) => x-0.2x = 0.8x

now of the price of 0.8x , another 15% discount is there.. so, again the price drops to

= 0.8x -(15% of 0.8x) = 0.8x-0.12x = 0.68x

so, total discount on initial price is = (x-0.68x)×100%/x = 0.32*100 = 32%

Adding the two equations2x=22 x=1111+y=10 y=-1

given,a/(x-a) + b/(x-b) = 2c/(x-c)[a(x-b)+b(x-a)]/(x-a)(x-b) = 2c/(x-c) (x-c)[a(x-b)+b(x-a)] = 2c(x-a)(x-b)

ax^2 – 2abx + bx^2 - acx + 2abc – bcx = 2cx^2 – 2bcx – 2acx + 2abc ax^2+ bx^2 - 2cx^2 = 2abx – acx – bcx (a+b-2c)x^2 = x(2ab – ac – bc)(a+b-2c)x^2 - x(2ab – ac – bc) = 0 x[(a+b-2c)x - (2ab – ac – bc)] = 0 x = 0 or (a+b-2c)x - (2ab – ac – bc) = 0 x = 0 or (a+b-2c)x = (2ab – ac – bc) x = 0 or x = (2ab – ac – bc) / (a+b-2c) thus the 2 roots of the given equation are x = 0 and x = (2ab – ac – bc) / (a+b-2c)

Value will bex⁽²⁺⁶⁾/x⁵x⁽⁸⁻⁵⁾x³

P(x) = x^2 + x - 7

Then,P(-1) = (-1)^2 + (-1) - 7 = 1 - 1 - 7 = 0 - 7 = - 7

Given diameter of the circle = 20 units

Radius of the circle = d/2 = 20/2 = 10 units

Given center of a circle is (2x - 1, 3x + 1)

Given that circle passes through (-3, -1),

So, distance of (-3, -1) from the center of the circle should be equal to radius

of the circle

Hence, √(2x + 2)² + (3x + 2)² = 10

Squaring on both sides, we get

(2x + 2)² + (3x + 2)² = 100

13x² + 20x - 92 = 0

13x² -26x + 46x -92 = 0

13x(x - 2) + 46(x - 2) = 0

(13x + 46)(x - 2) = 0

Hence, x = 2 or -46/13

the diameter of the circle =20 units

as this is an isosceles triangle, YP and RZ eill be the midpoint of XY and YZ respectively so the triangle is symmetric across the line QSY hence XR = PZ so XY=2PY, Applying Pythagoras theorem we get XR= 10√5, so XR+PZ=20√5

आपका उत्तर बरोबर हैमुझे अच्छा लगा

first draw oa and ob as tringle

the answer is incorrect

Buy of land =4800002/5*480000=192000 rsloss=6%100-6/100*192000=180480

total gain =10%100+10/100*480000=528000

sp=528000-180480=347520

cp of remaining part of land =3/5*480000=288000

gain% of remaining part of land= sp-cp/cp*100

<=>347520-288000/288000*100=20.6 %

1.

(x - 7)³

x³ - 7³ - 21x ( x - 7)

x³ - 343 - 21x² + 147x

(p+7) (p-4)P^2-4p+7p-28P^2+3p-28

First do factorization

p^2 = p*pp^5 = p*p*p*p*pp^7 = p*p*p*p*p*p*p

HCF is highest common factor which isp*p = p^2

The u

Thanks for the answers

Thanks guys for the answers

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