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c is the correct answer

c) 2 is the right answer of the following

x= 3, 1/2 is the right answer

x=1/2,3 is the correct answer

x= 1/2,3 is correct answer

x=3 and 1\2 is the correct answer

x=1/2,3 is the correct answer

x=3, 1/2 is correct answer.

x= 3, 1/2 is the correct answer

x=1/2and 2 is the correct answer

Solution:-The given integers are 3, 4, 5, 5 and 8.Mean = (3 + 4 + 5 + 5 + 8)/5= 25/5Mean = 5Median = 5 and Mode = 5 (Mode is the most frequently occurring value)After adding 4 integers, mode is increased by 1,Therefore, the new mode is 6.Since, the mode is most frequently occurring value, there 6 must be added at least three times.So, the new set of integers will be 3, 4, 5, 5, 6, 6, 6, 8 and x.Let the 4th integers be 'x'.And the new mean is 6.6 = (3 + 4 + 5 + 5 + 6 + 6 + 6 + 8 + x)/9(43 + x)/9 = 643 + x = 54x = 54 - 43x = 11So, greatest of the four integers that are added is 11.

5a(2-a) + 6a²+12a= 10a - 5a² +6a² +12a= a² +22a= a(a+22)Please hit the like button if this helped you.

1 - 64/113 ÷ 1 - 49/113

= 49/113 ÷ 64/113

= 49/64

RHS= 1+sin theta/cos theta

2*tan²45+cos²30-sin²60=2*(1/2)+(3/4)-(3/4)=1

correct answer is D 75√2

humein hindi nahi ati

thanks

A1 , A2 are inserted bw a,b ...

total terms now are 4 ...

let common difference is d then

a+(n-1)d = b

a+(4-1)d = b

3d = b-a .................1

second term is A1 = a+d

third term is A2 = a+2d

A1+A2 = 2a+3d = 2a+b-a (by using 1)

=a+b

now if A1,A2 are Gm's bw a,b then

arn-1= b

ar3= b

r3= b/a ............2

2nd term is A1 = ar

third term is A2 = ar2

A1A2 = a2r3= ab (by using 2)

now A1+A2/A1A2 = a+b/ab

Area of triangle = 1/2 × base × height

= 1/2 × 9 × 4.5

= 20.25 m²

ye polynomial ka question hai

answer is 11.... because let the touching point of both the circle be R and then PR+RQ =PQ.6.3+4.7=11cm

The middle number is the product of numbers obtained by adding numbers opposite to each other.Therefore answer will be(2+1) x (6 +6) = 36.

wrong answer that concept not in any some

85% of 500 is 425 so girls are 425 boys= 500-425= 75

25/30-4/28= 5/6-1/7= (35-6)/42= 29/42

length: 2m =200cm:height=200cm

diameter: 1.4cmradius: 0.7cm

volume: πr^2h:22/7×0.7×0.7×20022×7×2:22×14:300cm^2

the volume of the cylinder is 300cm^2

S=a(r^n-1)/(r-1)S10=3(2^10-1)/(2-1)S10=3(2^10-1)

Total weight of his purchase=5kg 400 gram+2 kg 20 gram +10 kg 850 gram=18 kg 270 grams

320/500=32/50=16/25=(4*4)/(5*5)=0.64

Let the angle bex

We know that supplement of an angle = 180-x

Complement =90- x

Supplement = 4(complement)

180-x =4(90-x)

180-x= 360–4x

3x =180

x=60

Hence the angle is 60

Supplement =120; Complement = 30

thanks you

x=2 is the right answer

thanku

part 1

part 2

<1=<5 (corresponding angle)120-2x=4x120=4x+2x120=6xx=120/6x=20<1=<5=20

thanxxx

red line is x + 2y = 5Blue line 3x + 5y = 13

Arre solve toh karo

So point of intersection is x = 1 and y = 2, which is solution.

electron=(-) , proton=(+)(2.) 6-6=0 no charge(3.) 9-12=(-3) ,3 electrons(4.) 4-8=(-4) , 4 electrons(5.) 7-6=(+1), 1 proton.

Its right !!!! Absolutely right !!!

Generally lanthanides and actinides have electron configurations that follow the Aufbau rule. There are some exception, in a few of the lanthanide and actinide elements.

The electronic configuration of the lanthanoids is4f1-145d0-16s2

Lanthanum, the d-block element preceding this series, has the electronic configuration [Xe]5d16s2.

The reason why gadolinium has a 5d1arrangement is that this leaves a half-filled 4f subshell, Lutetium has a 5d1arrangement because the f subshell is already full.General electronic configuration of actinoids is5f1-146d0-17s2

The difference in energy between the 5f and 6d orbitals is small for the first four elements, thorium, protactinium, uranium and neptunium, the electrons in these elements and their ions may occupy the 5f or the 6d levels, or sometimes both.

The reason why curiumhas a 6d1arrangement is that this leaves a half-filled 5f subshell, Lawrencium has a 6d1arrangement because the f subshell is already full.

[Rn]5f^(1-14)6d^(0-1)7s^2

Sum=1/3Product=-1/3

Equation=x²-Sx+Px²-x/3-1/3=0

3x²-x-1=0

Sum of zeroes is q-1/q=q^2-1/qand product is -1hencepolynomial is x^2+(sum of roots)x-(product of roots)=x^2+(q^2-1/q)x+1

speed is 80 km/h so in 45 min covered distance is 60 km. speed is increased by 10 so new is 90km/h so to cover 60 km require time is 40 min.

formula

what is the formula of this question and answers

Let the radius of the bigger circle be 'R' and the radius of the smaller circle be 'r'.It is given that R=5cm=OB and r=3cm=OD and AB is the chord whose length we have to find.AD=BD and OD⊥AB(radius is perpendicular to a chord and it divides the chord into two equal parts)therefore, ΔODB is a right angled trianglewhere, OD²+BD²=OB² (3)²+BD²=(5)² 9+BD²=25BD²=25-9BD²=16BD=4cm Since AD=BD=4cm therefore, AB=AD+BD AB=4+4 AB=8cm