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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Pipes A and B can Fill A Tank in 10 hours and 15 hours respectively Both can Fill it in . |
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| 2. |
7. A can finish a work in 15 days, B in 20days and C in 25 days. All these threeworked together and earned 4700. TheCDS 2012)share of C is |
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Answer» A's 1 day's work =1/15 B's 1 day's work =1/20 C's 1 day's work =1/25 A, B and C worked together. Therefore,(A+B+C)'s 1 day's work =1/15+1/20+1/25 =(20+15+12)/300=47/300 Days taken to complete work by A, B and C working together =300/47 Therefore, Share of C =1/25×300/47×4700= Rs.1200 |
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| 3. |
(a) 4r-4s+1ticpolynomial each with the given numbers ativelyorithmfor Polynomials |
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| 4. |
and Q started a business investing Rs. 85,000 and Rs. 15,000 respectively. Iatio the profit earned after 2 years be divided between P and Q respectivela) 3:4(b) 3:5(c) 15 23 (d) 17 23 (e) (B.S..E |
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| 5. |
Verify the following:() (0,7,-10), (1,6,-6)3.and (4,9,-6) are the vertices of an isosceles triangle. |
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| 6. |
9) log 2+ 16 log 16 +12 log 25-71524 |
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Answer» log2 + 16log16 - 16log15 + 12log25 - 12log24 +7log81 - 7log80= log2 + 16(4log2) - 16(log3 + log5) + 12(2log5) -12(3log2 +log3) + 7(4log3) - 7(log5 + 4log2)= log2*(1+64 -36-28) +log3*(-16 -12+28) + log5(-16+24-7)=log2* 1 + log3*(0) + log5*(1)= log2+log5= log10=1. please like the solution 👍 ✔️ |
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| 7. |
6.ABC is an isosceles triangle, nght-angled at C. Prove that ABP-2BC2 |
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| 8. |
\operatorname { log } 2 + 10 \operatorname { log } \frac { 16 } { 15 } + 12 \operatorname { log } \frac { 25 } { 24 } + 7 \operatorname { log } \frac { 81 } { 80 } = 1 |
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| 9. |
2 \operatorname { log } ( \frac { 6 } { 7 } ) + \frac { 1 } { 2 } \operatorname { log } ( \frac { 81 } { 16 } ) - \operatorname { log } ( \frac { 27 } { 196 } ) = \operatorname { log } 12 |
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| 10. |
\operatorname { log } 2 + 16 \operatorname { log } \frac { 16 } { 15 } + 12 \operatorname { log } \frac { 25 } { 24 } + 7 \operatorname { log } \frac { 81 } { 80 } = 1 |
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| 11. |
Construct an isosceles triangle whose base is 8 cm and altitude 4 cm and then anotherTtriangle whose sides are 1times the corresponding sides of the isosceles triangle.2 |
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| 12. |
ape of a square with a diagonal 32 cm and an isosceles triangle of base8 cm and sides 6 cm each is to be made of three different shades as shown inFig. 12.17. How much paper of each shade has been used in it? |
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| 13. |
Suite in the shape of a square with a diagonal 32 cm and an isosceles triangle of basend sides 6 cm each is to be made of three different shades as shown in12.17. How much paper of each shade has beenFig.8 cm |
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| 14. |
Kite in the shape of a square with a diagonal 32 cm and an isosceles triangle of basesides 6 cm each is to be mado of three different shades as shown ingiG. 12.17. How much paper of each shade has been used in it? |
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Answer» Area of shade 1 = area of shade II = 0.5*32 *16 = 256 cm^2.Area of shade III = |
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| 15. |
A kite in the shape of a square with a diagonal 32 cm and an isosceles triangle of base8 cm and sides 6 cm each is to be made of three different shades as shown inFig.12.17. How much paper of each shade has been used in it? |
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| 16. |
A kite in the shape of a square with a diagonal 32 cm and an isosceles triangle of base8cm and sides 6 cm each is to be made of three different shades as shown inFig. 12.17. How much paper of each shade has been used in it? |
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| 17. |
6. Two men can do a piece of work in 6 hours and 4 hours respectively. After the first has worked forhours, he is joined by the other. By when should the work be completed? |
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Answer» Let the first person be A and second person be B A can complete the work in 6 hoursi.e For one hour, A completes one-sixth of total work B can complete the work in 4 hoursi.e For one hour, B completes one-fourth of total work Together they do five-twelfth of total worki.e (1/6)+(1/4) = (4+6)/24 = 10/24 = 5/12 Case 1: As A worked for two hours, he would complete one-third of the work. The remaining work would be the two-third part 5/12 is the part of work which is completed together in an hour. Divide 2/3 with 5/12=> (2/3)/(5/12) = (2/3)*(12/5) = 24/15 = 8/5 So, the remaining part of the work is completed in 8/5 hours (1 hr 36 min) The total work is completed in 18/5 hours (3 hrs 36 min) |
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| 18. |
17. A cistern has two inlets A and B which can fill it in 12 minutes and 15 minutes respectivelAn outlet C can empty the full cistern in 10 minutes. If alltogether in the empty tank, how much time will they take to fll the tank completely?the three pipes are opened |
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| 19. |
6. Raza can do a piece of work in 5 days, Abdul can do the same work in 10 days and Karim can do it in 15 day!If all three work together, in how many days can they finish the job? |
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| 20. |
11.The value of log cotl+ log cot2++ log cot 89, İs-a) tan I, b) 0, c), d) tan89tr |
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Answer» log(cot1) +log(cot2) +....log(cot89)= log[cot1×cot2×cot3×.....cot88×cot89]= log[cot1×cot2×.....×tan(90-88)×tan(90-89)]= log[cot1×cot2×.....×tan(2)×tan(1)] but cotx.tanx = 1 , so here all the cot and tan will multiply to get 1 leaving the middle term cot45 = 1 so, log[cot (45)]=> log[1] = 0 |
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| 21. |
A kite in the shape of a square with a diagonal 32 cm and an isosceles triangle of base8 cm and sides 6 cm each is to be made of three different shades as shown inFig. 12.17. How much paper of each shade has been used in it? |
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| 22. |
7.A kite in the shape of a square with a diagonal 32 cm and an isosceles triangle of base8 em and sides 6 cm each is to be made of three different shades as shown inFig. 12.17. How much paper of each shade has been used in it? |
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| 23. |
- 1. किसी वस्तु की 42 रू: मैं बेचने पर 4 की हानि हौतीTRRB. HIECT TIC - 2008]पर बया. गिरी। |
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Answer» Let Cost price = CPSelling price = SP As per given conditionSP = CP(1 - 40/100)40 = CP((1 - 2/5)40 = CP(3/5)CP = 40*5/3CP = 200/3 = 66.66 If SP = 80Then,Gain% = [(SP - CP)/CP]*100= [(80 - 66.66)/66.66]*100= (13.34/66.66)*100= 20% Therefore,On selling item for Rs 80 there is profit of 20% profit of 20% when selling at RS 80 |
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| 24. |
A kite in the shape of a square with a diagonal 32 cm and an isosceles triangle of base8 cm and sides 6 cm each is to be made of three different shades as shown inFig. 8.17. How much paper of each shade has been used in it? |
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| 25. |
11. The value of log cotl'+ log cot2?+12. The line joining the points (3, 4) and (-2, -2) is divided by x axis in the ratio - a) 1: 1, b) 1:2, c) 2: 1, d) 3: 1. log cot 89 is - a) tan I, b) 0, c)l, d) tan89. |
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Answer» The given expression=log(cot1.cot2.cot3........cot89)=log(tan(90-1)tan(90-2)tan(90-3)........tan(90-44).cot45.cot46.cot47........cot89)=log(tan89.tan88.tan87.....tan46.cot45.cot46.cot47..........cot89)=log(cot45)=log(1)=0 |
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| 26. |
kite in the shape of a square with a diagonal 32 cm and an isosceles triangle oft8 cm and sides 6 em each is to be made of three different shades as showFig, 12.17. How much paper of each shade has been used in it?. A58 cmFig. 12.16Fig. 12.17 |
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| 27. |
l 12: 17:25 and its perimeter is 540cm Find izs area.6 Aa isosceles triangle has perimeter 30 cm and each of the equal sides is 12 em. Fidthe area of the triangle. |
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| 28. |
to 3/ The base ofan isosceles triangle iscm. The perimeter of the triangle is 2the RHS sWhat is the length of either of the remaining equal sides?ith a variable on beit sides the |
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| 29. |
18. In an isosceles triangle, the length of each of the equal sides is 2 more than the length of the base. If the ratioof the base to the perimeter of the triangle is 2:7, find the dimensions of the isosceles triangle |
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| 30. |
HenceEXERCISE 3.1Find the radian measures corresponding to the fotlowing degree mea()25° (ii)-47030,(iii) 240°(iv) 520° |
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| 31. |
3. Pipes A and B can fill a tank in 5 and 6 hours respectively,Pipe C can empty it in 12 hours. The tank is half full. All thethree pipes are in operation simultaneously. After how much timethe tank will be full? |
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Answer» Pipes A and B can fill the tank in 5 and 6 hours respectively. Therefore,part filled by pipe A in 1 hour=1/5 part filled by pipe B in 1 hour =1/6 Pipe C can empty the tank in 12 hours. Therefore,part emptied by pipe C in 1 hour=1/12 Net part filled by Pipes A,B,C together in 1 hour=1/5+ 1/6 −1/12=17/60 i.e., the tank can be filled in60/17=3(9/17) hours |
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| 32. |
-Jewry10 x 5 = 5U36. Three pipe A, B and C can fill an empty tank in 15 hours, 10 hours and 6hours respectively. In how much time will the tank be filled if all the threepipes work together?(3 |
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Answer» the tank will be filled in 3hrs If all the pipes work together the tank will be filled in three hours |
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| 33. |
1.80 pages can be compiled in 2 hrs. How manypages can be compiled in 12 hrs 30 min? |
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Answer» 500 pages can be compiled |
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| 34. |
orHence, x =EXERCISE 1.21.Add the followingr3 ,21-31(iv) _ and |
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Answer» 1) (-3+2)/5 = -1/52) [-8+(-3)]/11 = -11/11 = -1 |
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| 35. |
Find the value of cotl 7 cot 73" cos' 22+tan 73 see68 |
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| 36. |
An isosceles triangle has perimeter 30 em and each of the equal sides is 12 cm. Findthe area of the triangle. |
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| 37. |
An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 em. Findhe area of the triangle. |
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| 38. |
A kite in the shape of a square with a diagonal 32 em and an isosceles triangle of base8 em and sides 6 cm each is to be made of three different shades as shown inFig. 12.17. How much paper of each shade has been used in it? |
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| 39. |
42 cm What is the length of ether of the remaining equal. The base ofan isosceles triangle is em. The perimeter of the triangle isides ?d Rroblems based on speed |
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| 40. |
yurywo pipes can fill a tank in 10 hrs and 12 hrs,tivelyi Wbile a third pipe empties the fullIf all the three Pipes operategethertin how much time the tank will beoeAO hrs.fil)B. 7.5 HrsC/8 HrsD. 8.3.Hrs3e |
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Answer» 10*12*20/12*20+10*20-10*12=2400/240+200-120= 15/2=7hrs 30mins |
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| 41. |
A train is running at a speed of 75 kms/hour. How much time will it take tocover a distance of 350kms7(a) 4 hrs(c) 4 hrs 10 min(b) 5 hrs(d) 4 hrs 40 min |
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Answer» Speed of train = 75 km/hrDistance = speed x timeAs per given condition350 = 75 x timeTime = 350/75= 4.67 hrs Approximately 4 hrs 40 minutes |
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| 42. |
EXERGISE 3.3. Given a parallelogram ABCD. Complete eachstatement along with the definition or property used.AD-(iii)OC =(iv)m <DAB + m LCDA-... |
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| 43. |
EXERCISE 3.31. Given a parallelogram ABCD. Complete eachstatement along with the definition or property used.(i) AD =0C =(iv)DAB + m <CDA =m |
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| 44. |
HenceEXERCISE 3.3Given a parallelogram ABCD. Complete eachstatement along with the definition or property used.(i)(iii) OC = (iv) m LDA B + m <CDA1.AD = |
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Answer» thank u |
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| 45. |
en the value of sece cannotUsin.Acos Altan A + CDA) = 1() sin costana-cot) = 2 sinsin-1less than |
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| 46. |
24. Find the co-ordinates of the point equidistant from thregiven points A (5, 1), B (-3, -7) and C (7,-1). |
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Answer» I have also find out the same answer but the answer in our class 10 s.chand is given (2,-4) |
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| 47. |
. PORS is an isosceles tropeziumSD em.Distance between two parallelsides is 4 em, find the area ofS.3 MPORS |
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Answer» hit like if you find it useful |
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| 48. |
If 15 workers can build a wall in 48 hrs. How many workers will be required to do the samework in 30 hrs? |
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Answer» 15 workers => 48 hrs x=> 30 hrs 15×48=x×30 15×48/30=x x=24workers |
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| 49. |
1. Given a parallelogram ABCD. Complete eachstatement along with the definition or property used.(1) AD =(iii) OC = ......(ii) DCB(iv) m DAB + m 2 CDA0 |
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| 50. |
Given a parallelogram ABCD. Complete eachstatement along with the definition or property used.) A -.) DCB(iii) OCc(iv)m <DAB + mCDA = |
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