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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
) निम्नलिखित युगपत समीकरण है(13:22. 3X X |
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| 2. |
EXERCISE 2CGive the prime factorization of each of the following numbers:1. 122. 183. 484. 56 |
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| 3. |
Resolve the Following practions into partial Fraction.22+32. 50+6(x+1)(x-3)(270) (1-2) |
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Answer» 2) is the correct answer |
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| 4. |
2 ita,y, g are in A.P., Ithen prove that) y + ,xy,are in A.P(i)are in A.P(iv) (x-z)2 =4(y2-XZ)(v) xy + yz + zx = |
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| 5. |
find dy/dx of ytanh^-1{(x^2 -1)/(x^2+1)} |
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| 6. |
(İİİ)引37F寸村邗VITず37虱虱动 T 9 히豜邗訓虱礻ㄒㄒˊ研訓市37葡 |
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| 7. |
D.Evaluate the following for x2, y2 and1. x2y'z2,,32. ry3. 22X10 |
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Answer» You have already done the question |
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| 8. |
Exercise 18 (B)Find the area of the shaded portion in each case.24m3mii)22m-20m18mmounted onto a frame of external dime |
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| 9. |
1. Prove that the following points are collinear(İ) (-2, 3, 5); (1, 2, 3); (7,0,-1) (NCERT)(iii) (6,-7,-1); (2-3, 1); (4-5, 0)|(iv)(-1,4-2): (2,-2, l); (0,2-1)VIt |
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| 10. |
Exercise 18 (c)3. The lengths of the sides of a tiangular sarden are 42 , 38 m andzFind its penimeterar fiskd is 285m If bwo of its sides are 9% mae |
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Answer» Perimeter of a triangle= Sum of all sides=42+38+25=105 m |
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| 11. |
Who is the largest bird which live in water |
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Answer» Dalmatian Pelican is one of the heaviest flying water bird in the world. They are native to Europe and South Asia. This large bird grows up to a length of 6 ft. and weigh between 12 and 14 kg. The wingspan of an adult Dalmatian pelican measures up to 9 ft. They look exactly like great white pelicans. But Dalmatian pelicans are larger. The largest livingbird, a member of theStruthioniformes, is the ostrich (Struthio camelus), from the plains ofAfricaandArabia. A large male ostrich can reach a height of 2.8 metres (9.2 feet) and weigh over 156 kilograms (344 pounds).[1]A mass of 200kg (440lb) has been cited for the ostrich but no wild ostriches of this massive weight have been verified.[2]Eggs laid by the ostrich can weigh 1.4kg (3.1lb) and are the largest eggs in the world today. Wandering Albatross Eggs laid by the ostrich can weigh 1.4 kg (3.1 lb) and are the largest eggs in the world today. The largest living bird by wingspan is theWandering Albatross(Diomedea exulans) of the sub-Antarctic oceans. kori bustard ........ ibises is the correct |
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| 12. |
| Solve : (PS)= 2 and:=-2 3-+ = 3 andry-25.x+yX- y-and-y-2and-1-10-2y.y1ਦੇF|23+) |
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Answer» 2/x + 3/y = 13 ----(1) 5/x - 4/y = -2 ------(2) If we substitute 1/x = a and 1/y = b , we get the following pair of linear equations: 2a+3b=13 -----(3) 5a-4b = -2 -----(4) Coefficients of b are 3 and 4 and their LCM is 12 . Using the elimination method . Equation (3) × 4 8a+12b=52 Equation (4) × 3 15a-12b=-6 'b' terms have opposite sign , so we add the two equations. 23a = 46 => a = 46/23 => a = 2 Substitute the value of a in equation (3), we get => 2×2 +3b =13 => 4 + 3b = 13 => 3b = 13 - 4 => 3b = 9 => b = 9/3 => b = 3 But 1/x = a = 2 => x = 1/2 1/y = b = 3 => y = 1/3 |
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| 13. |
EXERCISE 181. Take a point O on your notebook and draw circles of radii 4 cm. 5.3 cm and 6.2 cm, eachhaving the same centre O.ntsp0Ruch that P lies in the |
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| 14. |
V2(2+43) _)f’(”’V3(V3+1) रायN 3-4% gU x=2, y=3 SA¢ 26 W oH,B B olcn s SRumiinx L x+d D Ry |
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| 15. |
1. Satural Causes of risk arela) Seasonal changesc) Natural calamities(b) Geographical chang(d) All of above |
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Answer» option d) all of above |
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| 16. |
Solve eachof the following pairs of equations by reducing them to a pair of linear equations.5-223x+y=2.xyr-yx-I y-26ry |
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| 17. |
EXAMPLE 6lfaand β are the zeros ofthe quadratic polynomía!f(x)-x.px+q, thenfind thvalues of (i)α2+D2 (ii) +αβ |
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| 18. |
Example 6: Savita and Hamida are friends. What is the probability that both willhave (i) different birthdays? (ii) the same birthday? (ignoring a leap year). |
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Answer» 1 2 |
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| 19. |
7. If radius of circleis 13 cm, and length of its one chord is 10 cm, then find thelength of the chord from the centre.olution-- |
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Answer» Radius=13cmchord=10cm1/2chord=5cmdistance=√13^2-5^2=√169-25=√144=12cm |
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| 20. |
: Factorise 6xy - 4y+ 6 - 9x. |
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| 21. |
8x-3y=12, 5x=2y+7 |
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Answer» 8x - 3y = 12 ....(1) 5x - 2y = 7 ......(2) 2 × eq (1) - 3 × eq(2) 16x - 6y = 24-15x + 6y = -21 x = 3 So, 15 - 2y = 7 8 = 2y y = 4 thanks |
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| 22. |
Example 6. If the pth term of an A.P. be q and the gth term be p; prove that the[M.D.U. 2017(p +q)th term is zero. |
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Answer» pth term is q so a+(p-1)d = q qth term is p so a+(q-1)d = p so (p+q)th term is a + (p+q-1)d = a + pd + qd - d = 0 |
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| 23. |
12x-3x5,thenxbelongsto |
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| 24. |
Add the polynomial 3x + 7y , 8x - 3y |
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| 25. |
13x + 71 5, then x belongs to |
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| 26. |
EXERCISE 18ake a point O on your notebook and draw circles of radii 4 cm, 5.3 cm and 6.2 cm, eachving the same centre O |
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| 27. |
\left. \begin{array} { l } { | 2 x - 3 | < | x + 5 | , \text { then } x \text { belongs to } } \\ { ( a ) ( - 3,5 ) } \\ { ( - 2 / 3,8 ) } \end{array} \right. |
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Answer» lets go through options(a) if we take -1 which is in the range|2x-3|=|-2-3|=|-5|=5|x+5|=|-1+5|=45 is not less than 4 so this is wrong(c) if we take -1 which is in the range|2x-3|=|-2-3|=|-5|=5|x+5|=|-1+5|=45 is not less than 4 so this is wrong(d) if we take -1 which is in the range|2x-3|=|-2-3|=|-5|=5|x+5|=|-1+5|=45 is not less than 4 so this is wrong(b) If we take any value from the range (5,9) it will satisfy the condition. So B is the right answer. sorry but the correct ans is c |
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| 28. |
Solve eachingpairs of equations by reducing them to a pair of linear equationi)26x-1 y-223ry3iv) 6x+3y 6xy42x + 4y 5xyFree Distribution by T.S. Gvernment |
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Answer» 4 th same as before pls send the anss |
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| 29. |
EXERCISE - 4.3m to a pair of limesSolve each of the following pairs of equations by reducing them to a pair ofx+y = 2XY*)=6iv)6x+3y=6xy492x + 4y= 5xy52V)x+yX-Y+//Free Distribution by AB |
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Answer» 1/ x-1=k, 1/ y-2=a; 5k+ a=2_(1), 6k-3a=1; 3(5k+a=2); 15k+3a=6/9k=5; k=5/9; 6k-3a=1; 5(5/9)+a=2; 25/9+a=2; a=2+25/9= 18+25/9=43/9; 1/x-1=5/9; 1/x=5/9+1=5+9/9=14/9; x=9/14;; 1/y-2=43/9; y-2=9/43; y=9/43+2= 9+86/43=95/43 x+y= 2xy ----(1)x-y= 6xy -----(2)2x= 8xy1= 4yy= 1/4putting the value of y in eq 1x+y= 2xyx+1/4= 2x×1/44x+1/4= 2x/44x+1=2x4x-2x= -12x= -1x= -1/2 iv) 6x + 3y =6xy; 2x+4y=5xy; 4( 6x + 3y =6xy)= 24x +12y=24xy; 3(2x + 4y =5xy); 6x +12y = 15 xy;; 24x+12y =24 xy; __________________ 18x=9xy; y=18x/9x=2; 6x + 3y=6xy; 6x+3(2)=6xy; 6x+6=6(2)x; 6x+6=12x; 6x=12x/6=2x; 6x-2x=4x; x=1/4 1/Vx=a; 1/Vy=k; 2a+3k=2; 4a-9k=-1; 2(2a+3k=2); 4a+6k=4 /3k=3; k =3/3=1; 4a-9(1)=-1; 4a=-1+9; 4a=8; a =8/4=2; 1/Vx=1/1; 1/Vy=1/2 |
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| 30. |
(iii) 8x + 3y = 14,method)3x+y=5(Useolution |
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Answer» 8x + 3y = 14 ......(1) 3x + y = 5 .....(2) From (2)y = 5 - 3x So, put in (1) 8x + 3 ( 5 - 3x) = 14 8x + 15 - 9x = 14 x = 14 - 15 = -1 x = -1 So, y = 5 - 3 × (-1) = 5 + 3 = 8 |
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| 31. |
Factorise 6xy-4y+6-9x |
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| 32. |
Factorise the following:(i) 3ax - 6xy + 8by – 4ab |
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Answer» 3ax-6xy+8by-4ab=3x(a-2y)-4b(-2y+a)=(3x-4b)(a-2y) (3X-4b) (a-2y) 3ax-6xy+8by-4ab=3ax-4ab-6xy+8by=a(3x-4b)-2y(3x-4b)=(3x-4b)(a-2y) |
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| 33. |
3.Factorise the following using appropriate identities:(i) 9x2 + 6xy + 12(ii) 4y2 – 4y + 1 |
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Answer» (1) 9x^2 + 6xy + y^2= (3x)^2 + 2*(3x)*y + y^2= (3x + y)^2= (3x + y)(3x + y) (2) 4y^2 - 4y + 1= (2y)^2 - 2*(2y)*1 + 1^2= (2y - 1)^2= (2y - 1)(2y - 1) |
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| 34. |
onThe factors are the thExample 3: Factorise 6xy-4y + 6-9xesame (as they have to be), although they appear in different |
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Answer» 6xy - 4y + 6 - 9x2y ( 3x - 2) -3 ( 3x - 2)(2y - 3) ( 3x - 2) |
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| 35. |
Hencetnetolalnumberofstudentsin the classis400.·2. Two candidates A aind B contest an election. A gets 46% of the valid votes and is defeated by 1600votes. Find the total number of valid votes cast in the election. |
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Answer» A gets 46 % so B gets 54 %Difference between them = 8% = 1600There 100 % valid votes = (1600/8)x 100 = 20000. Thanks |
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| 36. |
(b) x2-6y2 +3xy +5 from 4xy +5x y(d) 6xy-7-11xy from -6xy+7+10yx |
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| 37. |
x2+6xy+9y2 |
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| 38. |
ur OrVUDes Feceived by each.At an election between two candidates, 68 votes were declared invalid. The winning candidatesecures 52% of the valid votes and wins by 354 votes. Find the total number of votes polled.The salary ofMrs Santa is 2000 per m |
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Answer» Invalid votes = 68 winner = 52% of valid votes loser = 48% of valid votes (52-48)% =4 % =354 1% = 354/4 100 % = 35400/4 = 8850 no of valid votes = 8850 invalid votes = 68 total votes polled = 8850 + 68 = 8918 Thanks |
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| 39. |
6xy-4y+6-9x |
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Answer» 6xy- 4y + 6 - 9x = 6xy - 9x - 4y + 6 = 3x(2y-3) - 2(2y-3) = (3x-2)(2y-3) |
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| 40. |
MCQ - VIIake I whole?5What fraction of the cake was |
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Answer» =1/9 + 8/9 =9/9 =1 |
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| 41. |
If(x + [x]2 then x belongs to |
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| 42. |
If x -31-4 <2, then x belongs to |
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| 43. |
Solve for x and y: 8x -3y5xy, 6x-5y-2xy by the method ofion. |
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Answer» 8x-3y=5xy6x-5y=-2xy Multiply equation 1 with 5 and equation 2 with 3 40x-15y=25xy18x-15y=-6xy Subtract 22x=31xyx(22-31y)=0x=0 y=22/31 |
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| 44. |
Write T'for true and 'F' for false in each of the following:(1) 0 is neither positive nor negative.385) On the number line-10 lies to the right of -6.(iv) 0 is an integer.(v) 15-15.(vi) |-40 + 40 = 0. |
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| 45. |
3 Factorise: 2x-7x-15 |
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| 46. |
3. Factorise:i) 4a2-25 |
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Answer» Ans :- 4a^2 - 25 = (2a)^2 - 5^2 = (2a - 5) (2a + 5) |
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| 47. |
3. Factorise: 2x -7x-1:5 |
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Answer» If you find this solution helpful, Please give it a 👍 thanks |
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| 48. |
3/ Factorise.(i) x2 +xy+8x+8y |
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Answer» x² + xy + 8x + 8y x( x + y) + 8 ( x + y) (x + 8)(x + y) |
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| 49. |
3. Factorise.(0 x + xy+ 8x+ 8y |
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Answer» x² + xy + 8x + 8y x ( x + y) + 8 ( x + y) ( x + 8) ( x + y) |
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| 50. |
Out of 125 votes, 95 are valid. What per cent of votes is not valid? |
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