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Prime factorization of 235445 is 7 * 7 * 31 * 31 * 5

Since the prime factor 5 does not occur in a pair, so 235445 is not a perfect square.

In order to make it a perfect square, it must be divided by 5.

So, 235445/5 = 47089

Square root of 47089 = 217 * 217= 217

It should be multiplied by 5

Is my answer right ?

Factors of 1100 are,

1100=5*5*2*2*11

Since, 11 does not forms a pair therefore 11 should be multiplied to 1100 to make it a perfect square.

1100*11=12100

Now,

12100=5*5*2*2*11*11

√12100=5*2*11

√ 12100=110

x=90°y=50°z=50°these are the answers

x=90y=45 z=44:is the best answer

Laws of indicesa^m*a^n=a^m+na^m/a^n=a^m-nhence2^x/2^2*3^2x/3^6=36now2^x/4*9^x/3^6=362^x*9^x=36*4*3^618^x=104976now 18^4=104976hencex=4

tan2theta= 2 tan theta/ 1-tan^2 thetathis is the formula

1100×11=12100110 is the square root of 12100.

a = 11 d = 8 - 11 = -3 suppose -150 is nth term of AP -150 = a+(n-1)d -150 = 11 + (n-1)(-3) -161 = (n-1)(-3) so n-1=161/3 so n = 164/3 which is not possible so -150 is not a term.

The no. is 11.1100×11=12100 which is a perfect square.sq. root of 12100 is 110.

sir that no. is not,180 it's 1100

We have to find a no. by which 1100 must be multiplied so the product obtained is a perfect square.that no. is 11let's see:-1100×11=12100.√12100 is 110.

1

2

3

Use quadratic formula with a=4, b=-154, c=126.

x=−b±√b2−4ac/2a

x=−(−154)±√(−154)2−4(4)(126)/2(4)

x=154±√21700/8

x=774+54√217orx=774+−54√217

Applying BODMAS= 40+20-3060-3030

4u(u+2)u= 0u+2= 0u= -2product = (-2)*(0)= 0

15000

tan30=50√3/x

1/√3=50√3/x

150=x

√3=50√3/y

y=50

total distance covered =x+y=200m

.2km

time=2/60hr

speed=6km/hr

Here,

a = 11

d = 8 - 11 = - 3

Let - 150 be the nth term of the given A.P.

We know that,

an = a + (n - 1)d

⇒ - 150 = 11 + (n - 1) - 3

⇒ - 150 = 11 - 3n + 3

⇒ (- 150) + (- 14) = - 3n

⇒ - 3n = - 164

⇒ 3n = 164

⇒ n = 164/3

So, it is clear that n is not an integer.

Therefore, - 150 is not a term of the given A.P.

For an AP 11, 8, 5, 2.... First term a = 11, Common difference d = 8-11 = - 3

Ley - 150 is nth term of an APThen,-150 = a + (n-1)d-150 = 11 + (n-1)*(-3)-161 = - 3n + 3n = 164/3n = 5.43

If - 150 is term of an AP then value of n should be positive integer. Which is not true in this case.

Hence, - 150 is not a term of an AP

Thanks

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1200 = 2*2*2*2*3*5*5

since only 3 is not in pair.hence 3 is the required number by which 1200 should be decided to make it perfect square ..

1200/3 = 400 A perfect square

for 2nd question answer is 3....as if it divided by 3 then 400 is quotient.. which is a perfect square of 20

1200/2=600/2=300/2=150/3=50/5=10/5=2

1200/2=600/2=300/2=150/3=50/5=10/5=2

we will have no time

x^3 - 2x^2 - x + 2= x^3 - x^2 - x^2 + x - 2x + 2= x^2(x - 1) - x(x - 1) - 2(x - 1)= (x - 1)(x^2 - x - 2)= (x - 1)(x^2 - 2x + x - 2)= (x - 1)(x(x - 2) + 1(x - 2))= (x - 1)(x + 1)(x - 2)

Please post complete question by image for easyness

How can we take common in this question plz answer

please like my answer if you find it useful

thanqs

-1.95 is the best answer

-1.95

correct answer for this question

x= -1.95 is the correct answer of the given question

-1.95 is the correct answer

-1.95 is correct answer

-1.95 is the right answer

-1.95is the correct answer

-1.95 is correct answer.