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1.65-1.52=.13cm is ritika taller than her mother.....

height of mother = 1 m 52 cm = 152 cm

height of Ritika = 1 m 65 cm = 165 cm

Ritika is taller then her mother = 165 - 152 = 13 cm. (ANS)

Height of Ritika's mother=1m 52cmHeight of Ritika =1m 65cmHeight by which Ritika istaller by her mother =1.65 - 1.52=0.13Answer = 13 cm

Summary: Ritika is 13cm taller by her mother.

Ritika's mother = 1m 52cm tallRitika = 1m 65cm 1m 65cm - 1m 52cm ____________ 0m 13cm ( Ans )Ritika is 13 cm taller than her mother.

13 cm tall is ritika more than her mother

1.65-1.52=13 cm is correct answer.

count the numbers between 52cm and 65cm we get 13 cm so this is the answer

thank you

2:3=28:4217:21=34:4211:14=33:425:7=30:4228:42 < 30:42 < 33:42 < 34:422:3 < 5:7 < 11:14 < 17:21

-n/m01/2 is the correct answer of the given question

Range is the difference.

Let the cubic polynomial be p(x)

It's zeros are 3,2,-1

So the factors will be (x-3),(x-2),(x+1)

A cubic polynomial will at most have three zeros

So by multiplying all its three factors, we will get the polynomial

(x-3)(x-2)(x+1)

=(x²-2x-3x+6)(x+1)

=(x²-5x+6)(x+1)

=x³+x²-5x²-5x+6x+6

=x³-4x²+x+6

Minor change in one line of address might not cause trouble. Aadhar card number will be used to verify name and date of birth. Make sure it is correctly entered. While filling any form name and date of birth should not have errors.

what's the number to Notre Dame Victory Square weather Oconomowoc Wisconsin today

image nh aa ri yrrr

perpendicular=45 mbase=45√3 mAngle of elevation (A)tanA=perpendicular/hypotenuse=45/45√3=1/√3A=30°

Cost of pen is x and notebook is y.3x+y=72y=183x=72-183x=54x=18.So, cost of one pen is 18.

the cost of 3pens and a notebook is = 72the cost of notebook is = 18now, we will subtract (72 - 18). we get 54, which is the cost of 3 pen

cost of 3 pen = 54. (above mention)cost of one pen = 54 ÷ 3 = 18.The cost of one pen is Rs 18.

model value is that value which has highest frequency.here the age is 90

x= [x]+{x}

[x] -x = -{x}

so, so f(x) = √-{x}

which is always defined when {x} = 0

so, range will be {0}

a) range = largest no. - smallest no. = 30 - 19 = 11b)mean = sum of observations /no. Of observations = (21+25+24+26+28+19+30+27+29+21) /10 = 250/10 = 25

Mode of given data can be defined as a number having maximum frequency

For given data no. 3 have max frequency as it repeated 4 times so Mode is 3

yes it is correct answer

here s and r is replaced by a and b, you can change a and b as s and r.

thanks

Given equation4x - (2/3)y = 7 meets y axisWhen x = 0

Then put x=0 in given equation we get4*0 - (2/3)y = 7y = - 7*3/2 = -21/2

Coordinates are (0, - 21/2)

for any angle, the value of sin^2∅ + cos^2∅ = 1 as it is an identity, whatever value you may substitute in the place of ∅ in the above identity you will get 1

15)

15)

16)

Let the largest even number=x

x+(x-2)+(x-4)+(x-6)=234x-12=234x=35

x=35/4

Therefore, the largest even number=35/4

Numbers are as x,x+2,x+4 largest=x+4 smallest=x

so, 3x-7=2(x+4)3x-7=2x+83x-2x=8+7x=15

therefore,first no.=x=15second no.=x+2=15+2=17third no.=x+4=15+4=19

15,17,19 ans

Consecutive odd numbers (x=smallest): x, x+2, x+4

3x-7 = "three times the smallest … decreased by 7"

2(x+4) = "twice the largest"

These two things are equal: 3x-7 = 2(x+4)

3x-7 = 2x+8

x = 15

Ans: the 3 numbers are 15, 17, and 19

Let the number be a,b,c ; a be the smallest and c the greatest

Given a×b×c =224& c = 7a ---- e1

We know that if a,b, c are in A.P then 2b=a+c (arthimetic mean formula)2b=a+7a (given c=7a)2b = 8ab=4a ---- e2

a×b×c= 224a× 4a × 7a =224 (from e1 and e2)28a^3 = 224a^3= 224÷28a^3= 8a^3=2^3a=2

b= 4a= 4×2= 8c=7a= 7×2= 14

The numbers are 2,8,14.

Consecutive odd numbers (x=smallest): x, x+2, x+4

3x-7 = "three times the smallest … decreased by 7"

2(x+4) = "twice the largest"

These two things are equal: 3x-7 = 2(x+4)

3x-7 = 2x+8

x = 15

----

Ans: the 3 numbers are 15, 17, and 19

Let number of pages in 1st part is x and number of pages in 2nd part is y.

because total number of pages in algebra textbook is 1382 .so, x + y = 1382.......(1)

a/c to question, second part of the book has 64 pages more than 1st part .e.g., y = 64 + x .........(ii)

put equation (ii) in equation (i), => x + 64 + x = 1382 => 2x + 64 = 1382 => 2x = 1382 - 64 = 1318 => x = 659

put x = 659 in equation (ii), y = 64 + 659 = 723.

hence, number of pages in 1st part is 659number of pages in 2nd part is 723

Let the total no. of pages in 1st part be x then, According to the question no. of pages in 2nd part =64+xnow, Total no. of pages book has = 1382x + x + 64 = 13822x = 1318x = 659hence 1st part of book has x= 659 pagesAnd 2nd part has x + 64 = 659 + 64=723 pages********Accept As Best 👍💯******

In a circle diameter passes through the centreNumber of times a particular value in data occurs is called it's frequency0/8 is a fraction but it's value is zero.

so ab =1 Ans

Let the roots be p, q, rGiven p and q are 0sum of roots=-b/ap+q+r=-b/a0+0+r=-b/ar=-b/a

Put x = 3 in the given polynomials.27a + 36 + 9 - 4 = 27 + 12 - a 28a = -2 a = -1/14

Roots of given polynomial is in AP let P- r , P, and P+ r are the roots of

f( x) = ax³ + 3bx² + 3cx + d

sum of roots = -coefficient of x²/coefficient of x³

P -r + P + P+ r = -( 3b/a)

3P = -( 3b/a)

P = -b/a -----------(1)

sum of products of two roots = ( P -r)×P + P×(P+r) + (P-r)(P+r) = coefficient of x/coefficient of x³

P² -Pr + P² +Pr + P² -r² = 3c/a

3P² - r² = 3c/a ------------------(2)

again ,

products of all roots = -constant /co-efficient of x³

(P-r)×P× (P+r) = - d/a

P³ - Pr² = -d/a ----------(3)

now,

equation (1) put in eqn (2) ,

3(-b/a)² -r ² = (3c/a)

r² = 3(b²/a²) -3(c/a) ----------(4)

eqn (4) and (1) put in eqn(3)

(-b/a)³ -(-b/a)( 3b²/a² -3c/a ) = -d/a

-b³/a³ +b/a(3b²/a² -3c/a ) = -d/a

-b³/a³ +3b³/a³ -3bc/a² = - d/a

2b³/a³ -3bc/a² = -d/a

2b³ -3abc = -da²

2b³ -3abc + a²d = 0

hence, proved

thanks alot sir

Smallest number in the range = 21

Largest number in the range = 60

The range of the data set is calculated by subtracting the smallest number from the largest number.

so here,

Range = largest number - smallest number

Range = 60 - 21

Range = 39

Hence,

The range of the data is 39

Range = Largest number- Smallest number = 60-21 =39

Answer:(III) FrequencyExplanation:

Frequency of avalue(observations) is defined by thenumber of timesthe value occursin agiven data set.

Therefore, thenumber of times a particularobservationoccursis a given data setis called its frequency.