Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

dydx, when x-a cos t, y a sin t.

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2.

EXERCISE9.5Use a suitable identity to get each ofthe following products.(x+3)(x+3)(2y +5) (2y+5)

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3.

26. Use suitable identity to get each of the following products.i) (2y+ 5) (2y +5)i) (6x + 7) (6x -7)

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1)(2y+5)(2y+5)=(2y+5)^2(a+b)^2=a^2+b^2+2abhence4y^2+25+20y2)(6x+7)(6x-7)(a+b)(a-b)=a^2-b^2hence(6x)^2-7^2=36x^2-49

Thanks

4.

1. Find the following by using Identity-l.(i)(2x + 5)2(ii)(8x + 3y)2liv)(7pq + 4ab)2(v) (0.2x +1.5y)22. Evaluate the following by using Identity-I.() (101)2(iv) (203)2(ii) (52)2(v) (410)2

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(2x+5)² = 4x²+10x+25

Find the following by using by identity 1 (8x+3y) 2

5.

Using identity, find the value of the following(0) 25x +60xy +36y, ifx--1,y-24.Itsing identity, evaluate the foll

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thanks a lot

But not sure

6.

Evaluate the following by using Identity-.

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7.

Evaluate the following by using Identity-I(0) (101)2

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1)(101)²=(100+1)²=100²+1+2×100×1=10000+201=10201

2)(52)²=(50+2)²=50²+2²+2×50×2=2500+4+200=2704

8.

Worksheet 21. Simplify:(i)1 5x2xx2

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x^3 is the correct answer of the given question

9.

Downloaded from www.studiestoday.comName 11 dellaRoll No.(Class-VT)IMath SA-ITWorksheet - 8Class VIChapter - 7 (Fractions)1. Fill in the blanks by using >,<or in the following to make correct statements,²0102.Match the following:0Mixed FractionProper FractionImproper fractionShape the figures for the fraction given below it.3./1/4ΔΔΔΑAAAA 7/12AAAA3/45.Write next three fractions equivalent to6.Simplify:7. Draw at number line8. Write in unending order.9. Write 15 in simplest form.Downloaded from www.studiestoday.com

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(1) a = <b=<c= =(2) I = improper fractioii = proper fraction iii = mixed fraction

like please

10.

Worksheet 3Find the square root of each of the following by prime factorisation.Š 225(ii) 441(i) 529(iv)(v) 7744 (vi) 8281 (vii) 4096(viii)4000028900

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11.

3. हल कीजिए श् =cos (x +y).dy _Solve == = cos (x+y).

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Like if you find it useful

12.

10. A carpet of size 5 m x 2 m has 25 cm wide red border. The inner part of the carpetis blue in colour. Find the area of blue portion. What is the ratio of the areas of redportion to blue portion?o55 m

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Please like the solution 👍 ✔️👍

13.

6. Findyog (cos xdydx

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14.

If y=sin x, then dy is equal to1 + COS Xdx

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this is not correct answer

this is not correct answer

15.

\left. \begin{array} { l } { f ( x ) = x - 2 , g ( x ) = x ^ { 2 } + 3 x + 1 } \\ { f ( x ) = \frac { 1 } { x } , g ( x ) = \frac { x - 2 } { x + 2 } } \end{array} \right.

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put the value of x in given equation

1) fog(x) = (x²+3x+1)-2 = x²+3x-1 gof(x) = (x-2)²+3(x-2)+1

2) fog(x) = x+2/x-2. gof(x) = 1/x-2/(1/x+2) = 1-2x/(1+2x)

16.

7= —, evaluate:8in6) (1-sin 6)

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hit like if you find it useful

17.

12. Find (r + y) = (x - y), if13. Evaluate (x + y) * (ty), if x = and y=

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12)x=2/3 ; y= –1/4(x+y)=2/3+(-1/4)=2/3-1/4=5/12x+y= 5/12 ✔x-y=2/3-(-1/4)=2/3+1/4=11/12x-y=11/12✔

therefore (x+y)÷(x-y)=(5/12)÷(11/12)=(5×12)/(12×11)=5/11✔✔or(x+y)÷(x-y)(2/3-1/4)÷(2/3+1/4)=5/11

(2)x=–2/5 ; y=3/4(x÷y)= -(2/5)÷(3/4)=-(2×4)/(5×3)=–8/15✔xy=–2/5 × 3/4=–6/20=–3/10✔

therefore (x÷y) × XY=(–8/15 )× (–3/10)=4/25✔

or(x÷y)× xy(-2/5÷3/4)× (-2/5)×3/4=4/25

18.

\lim _{x \rightarrow 0} \frac{\sin a x}{b x} \quad, \quad \gamma_{4}, \lim _{x \rightarrow 0} \frac{\sin a x}{\sin b x}, a, b \neq 0

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sinx/x=1 iyea formula to mujeh Kahi nahi mila tha friend!iye formula kis series ka hea??

19.

\lim _{x \rightarrow 0} x^{2} \sin \frac{1}{x}=0

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20.

12. 67 +33 +33 +67 is an example of(a) closure property(c) commutative property(b) associative property(d) distributive property

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(c) commutative property

commutative property (c)

21.

Find $\lim _{x \rightarrow 0} f(x)$ and $\lim _{x \rightarrow 1} f(x),$ where $f(x)=\left\{\begin{array}{cc}{2 x+3,} &amp; {x \leq 0} \\ {3(x+1),} &amp; {x&gt;0}\end{array}\right.$

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22.

\lim _{x \rightarrow 0}\left(\frac{x^{2}}{e^{x}}\right) ;(0, \infty)

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lim x-> 0 (x^2/e^x)=(0)^2/e^(0)=0/1=0

23.

Example 6 in Fig. 6.27,AB lI CD and CD l EF. Also EA LAB, If 4 BEF 55°, findthe values of a, y and z

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1

2

24.

\lim _{h \rightarrow 0} \frac{\sqrt{x+h}-\sqrt{x}}{h}, x \neq 0

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by taking h=0 we will get 0/0 form so using L'hospital rulelim h->0 1/2root(x+h) - 1/2root(x)=1/2root(x)-1/2root(x)=0

Bdiya blue pen say likh kar bhejo

25.

1. In the above example, cΔ ABD first and then fir2. Can you construct a quacm, PS-7.5 cm, PR = 8EXERCISE 4Construct the following quadrilat(i) quadrilateral LIFT1.LI 4 cmIF = 3cmTL-2.5 cmLF 4.5 cmIT 4 cm

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26.

\lim _ { x \rightarrow 0 } \frac { \sin a x } { \sin b x } , a , b \neq 0

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27.

3. Evaluate:(0(0.04)

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0.008 is the answer. If any doubt, check it in the calculator.

Thank you. Have a nice day.

all comment is right bro answer is 0.008

28.

Evaluate(I) 8 !

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8! = 8×7×6×5×4×3×2×1 = 40320

29.

Evaluate :(8)

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30.

8(Evaluate:) \int_{2}^{8}|x-5| d x

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31.

Evaluate : 5P3 and P(8, 5)

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nPr=n!/(n-r)!5P3=5!(5-3)!=5!/2!=5*4=20

P(8,5)=n!/(n-r)!=8!/(8-5)!=8!/3!=8*7*6*5*4=6720

32.

If log(x+y/3)=1/2 log(log x+ log y) then find the value of X/Y-Y/X

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log [ ( x + y )/3] = 1/2 ( logx + logy)

2× log[ ( x + y )/3 ] = log x + log y

log [ ( x + y ) / 3 ]^2 = log xy

{ since i ) n log a = log a^n

ii ) log a + log b = log ab }

Remove log bothsides,

[ ( x + y ) / 3 ]^2 = xy

( x + y )^2 / 3^2 = xy

x^2 + y^2 + 2xy = 9xy

x^2 + y^2 = 9xy - 2xy

x^2 + y^2 = 7xy

Divide each term with xy

x^2 / xy + y^2 / xy = 7xy / xy

x / y + y / x = 7

x/y+y/x=7njsee h Texas o Saturday

33.

If log,x log,16, then find x.

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logx/log2= 2 logx=2×log2logx=log4x=4

34.

17. In the figure given below, p lI q and r li s. Find the values of x, y and z.l1x +560°136°- 8y

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11x + 5 = 60(corresponding angles)11x = 60 - 5 = 55 x = 560 + 2z = 180 2z = 180 - 60 2z = 120 z = 602z = 136 - 8y(vertically opposite angle)120 = 136 - 8y 8y = 136 - 120 = 16 y = 2

35.

find the value of x if 3 log 2+1/3 log 27-log4=log x

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The numbers log 2, log (2x − 1) and log (2x + 3) are in A.P.

∴log (2x−1)−log 2 = log (2x+3)−log (2x−1)⇒log (2x−12)=log (2x+32x−1)⇒2x−12=2x+32x−1⇒(2x−1)2=2(2x+3)⇒22x+1−2.2x=2.2x+6⇒22x−4.2x−5=0

Let 2x=y.⇒y2−4y−5=0⇒(y−5)(y+1)=0⇒y=5 or y=−1∴2x=5 or 2x=−1 (not possible)Taking log on both the sides, we get: log 2x=log5⇒xlog2=log5⇒x=log 5 log 2=log2 5⇒x=log2 5

36.

What is the zero of the zero polynomial ?

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The constantpolynomialwhose coefficients are all equal to 0. The correspondingpolynomialfunction is the constant function with value 0, also called thezeromap. Thezero polynomialis the additive identity of the additive group ofpolynomials

values that makes our function = 0

37.

Find the zero of the zero polynomial.

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A zero polynomial is a polynomial which has no variables. So it is not possible to find the zero of a zero polynomial.

38.

VistilExponents(Name31Evaluate :. Evaluate : 0° -6° 03-5 x10-5x125Simplify :5-2 X6-5372Evaluate : *T*x0+(3)

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39.

1. Evaluateul)2. Evaluate:3 (33. Evaluate

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625/81 is the correct ansswer

40.

Sum of zero 8/5, product of zero=3/5

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Any Equation having zeroes a and b can be written as(x-a)(x-b) = x² - (a+b)x + abx² - 8x/5 + 3/5 = 0multiply by 55x² - 8x + 3 = 0

41.

EvaluateEvaluate0-6*

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=(3³-2³) ÷4³= (27-8) ÷4³= 19/64

42.

हि. 2y 4 y_)_L_\+‘~L——cui

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(x² - 2xy + y²) - z²

( x - y)² - z²

( x - y - z) ( x - y + z)

43.

\frac { 4 x - 5 x ^ { 2 } + 6 x ^ { 3 } } { 2 x } \quad ( 11 ) y ^ { 2 } ( y - y ^ { 3 } )

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44.

3. Evaluate (2)3. EvaluateA.

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(-2/3)^-3= (-3/2)^3= -27/8

= (4/27)^-2= (27/4)^2= (-27/8)/(45.56)-3.3/45.56-0.07

45.

EvaluateEvaluate cuwit 8 d.

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46.

225 x (-4)

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225×(-4)=-900 answer

47.

iIfy=x", find 7dx

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48.

ii.Ify=tan? (log x), find out

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cosec x is the correct answer of the given question

49.

Ify=al/2 log: sx.find dydx

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50.

3. Why is excreiol all U3How does transpiration help in the ascent of sap in plantsits various events.

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Evaporation of water molecules from the cells of a leaf creates a suction which pulls water from the xylem cells of roots.

Thus,transpiration helpsin the absorption and upward movement of water and minerals dissolved in it from roots to the leaves