This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
9) A shopkeeper gains 25% by selling tiesat R155 a piece. How much profit willshe make by selling 200 of them? |
|
Answer» VV good |
|
| 2. |
1.A man got a 10% increase in his salary. If his new salary ist 1,54,00, find |
| Answer» | |
| 3. |
a v = 9b, z = 27C 3 xbe yaTuj 411466747.026yfa x = 34, y = gbab = 1 at abc =(a) ?(c) 277IST 27(d) 0 |
|
Answer» given x^a=y______(1) (X^ab)^c=X, , X^abc=X, abc=1, bases are same. |
|
| 4. |
Shreya's age ist gears more than two timesSarla's age. If 3 years bence,Sarla's agewill be 19 years more than Shreya's agethen find their present ages |
|
Answer» rushbh haveliya Jaykishanrushabh Havaliya Jaykishan |
|
| 5. |
If the compound interest on a certain sum at 162% for 3 years ist 1270, find thesimple interest on the same sum at the same rate and for the same periocd.19. |
| Answer» | |
| 6. |
240Profit = 22Profit = 3105Loss = * 220Loss = 202. Find the SP when :(a) CP = 250,(b) CP = 720,(C) CP = 1550,(d) CP = 790,Find the CP when :(a) SP = 1250,(b) SP = * 400,(C) SP =* 1250,(d) SP=* 1800,7990, a trader gains 10%. Find the cost piite bindingProfit = * 250Profit = 335Loss = 3150Loss = 3 325 |
|
Answer» sp = 1256, profit = 250; 1256 - 250 = 1006= cp 2.(a)CP=Rs250 Profit=Rs22 solution: profit=SP-CP so,SP=profit+CP =Rs22+Rs250 =Rs272 3.(a)SP=Rs1250 profit=Rs250solution: profit=SP+CP so,CP=SP-profit =Rs1250-Rs250 =Rs1000 |
|
| 7. |
1. By selling a table for Rs. 330 a trader gains 10%. Find thecost price of the table. |
|
Answer» Given: sp=330 rsgain%=10%Formula: (sp-cp)/cp*100= gain %Solution10= (330-cp) /cp*100330/cp-1=10/100330/cp=11/10cp=(330*10)/11cp=300Therefore cost price = 300 rs |
|
| 8. |
7"By selling chair for Rs 1440, a trader gains 20%. Find the cost price of the chair |
| Answer» | |
| 9. |
By selling 25 metres of cloth atrader gains the selling price of 5metres of cloth. The gain percentof the trader in % is(1) 25%(3) 28%(2) 20%(4) 29% |
| Answer» | |
| 10. |
(on selling an exhaust fan foroF7350, a man gains of its cost price. Find the cost pr73of the fan.Mohit sold a watch to Karim at a gain of 10% and Karim sold it to Rahmat a gain of 4%. IfRahim pays 14800 for it, for how much did Mohit purchase it?ureroa ins I 0% the wholesale dealer 15%, and the retailer 25% then what is |
|
Answer» According to the problem given , Selling price of the exhaust fan = S.P = Rs 7350 Let the cost price of the exhaust fan ( C.P ) = Rs x Gain = 1 / 6 of C.P = x / 6 We know that , Cost price = Selling Price - Gain x = 7350 - x / 6 x + x / 6 = 7350 ( 6x + x ) / 6 = 7350 7x / 6 = 7350 x = 7350 × ( 6 / 7 ) x = 1050 × 6 x = 6300 Therefore , Cost price of the exhaust fan = x = Rs6300 Let C.P of watch For Mohit = xMohit Sold It At a profit of 10%So,S.P of Mohit = x + 10x/100 = 110x/100 = 11x/10S.P of Mohit = C.P for KarimNo, Karim sells it at a profit of 4%So S.P of Karim = 11x + 11x * 4 ------ ------------ 10 10 * 100 = 1100x + 44x / 1000 S.P Of karim = C.P of RahimBut Rahim Pays 14300 for it Therefore, 1144x /1000 = 14300x = 14300 * 1000/1144x = Rs12500 Therefore, Mohit Buys The Watch For Rs 12500 |
|
| 11. |
124. Pradeep invested 20% more than Mohit. Mohit invested10% less than Raghu. If the total sum of their investmentis 17,880, how much amount did Raghu invest?1600279377000 |
|
Answer» 6000 is correct. |
|
| 12. |
1. What should be added to 3891 102. Mohit bought an MP3 player for20598. Safina bought thesame MP3 player but paid 1999 more than Mohit. How muchmoney did Safina pay? |
| Answer» | |
| 13. |
10. A committee of 8 is to be selected out of 6 males and &females, In how mait be formed so that the males may not be out-numbered? |
|
Answer» There are 5 possible ways |
|
| 14. |
10. Acommittee of 8 is to be selected out of 6 males and 8 females. Ia how sanormed so that the males may not be out-numbered ? |
| Answer» | |
| 15. |
Mohit sold a watch to Karim at a gain of 10% and Karim sold it to Rahim at a gain of 4%. IfRahim pays18,14300 for it, for how much did Mohit purchase it? |
| Answer» | |
| 16. |
or the lafl18."Mohit sold a watch to Karin at a gain of 10% and Karim sold it to Rahim at a gain of 4%. IfRahim pays 14300 for it, for how much did Mohit purchase it? |
| Answer» | |
| 17. |
sanya ordered 45 ice cream for her birthday . Only 33 were used.How many ice creams were lift. |
|
Answer» 12 ice cream will remain 12 ice cream will remain 12 nos ice cream will remain 12 ice cream Will remain45-33= 12then the answer is 12 Sanya left with 12 ice creams as 45-33 = 12 hence, she has 12 ice creams now Saunya ordered ice cream = 45Used ice cream = 33ice cream lift= 45-33 =12 Sanya ordered 45 ice creams 33 were usedTherefore the ice creams she was left with=45-33=12Sanya was left with 12 ice creams |
|
| 18. |
6, If the sum of all interior angles of a polygon is 8640°, find the number of sides. |
| Answer» | |
| 19. |
| 196प्राथमिक गणित7. एक व्यक्ति किसी वस्तु का 8640 रु० में खरीदता है एवंलाभ लेकर बेच देता है। यदि उसने उसे 10,000 रु0 मेंउसे कितना अतिरिक्त लाभ होता?६० में बेचा होता |
|
Answer» nine hundred on tenthousand |
|
| 20. |
The Mr. Clean company has cleaned 28 houses this week. If this number representsof the total number of houses they clean each week, how many total houses will thecompany clean by the end of the week?1. |
|
Answer» Let the total number of houses cleaned=x40% of x=28(40/100)*x=28x=(28*100)/40x=70 Therefore, the total number of houses cleaned=70 |
|
| 21. |
Mary used 600 mlice creams to make milk shake for 4 people. How much ice-cream will sheneed to make milk shake for 10 such people? |
|
Answer» 600 ml used for 4 people so for 10 people (10×600)/4 = 1500 ml thanks 600litres/4= 150150 multiply by 10 =1500litres |
|
| 22. |
In a garden, the ratio of mango and almond trees is 5:8. If8 trees each of mango and almond are planted then theratio of the trees will be 43:64. Find the number of treesof mango and almond in the garden.(A) Mango-35 and Almond -56(B) Mango-30 and Almond -58(C) Mango-34 and Almond -55(D) Mango-30 and Almond -48 |
| Answer» | |
| 23. |
10 August 2017 SSC CGLरू0 60500 को A, B तथा C में इस प्रकार बॉटा जाता है।कि \ का भाग 3 तथा C के कुल भाग का 2/9 है, तथाB का भाग A तथा C के कुल भाग का 3/7 है। C काभाग (रू0 में) कितना है?The sum of Rs. 60500 is distributed Among A, B & Cin such a way that amount of A is 2/9 of the totalamount of B and C and the amount of B is 3/7 of thetotal amount of A & C. Find the amount (in Rs.), of C.(a) 29850(b) 30120(c) 31350(d) 37250।1।/17''/'/'/:।। |
|
Answer» d right answer bhai please like |
|
| 24. |
L 5% of an amount is? 600, then total amount is: |
|
Answer» 5% of X is 600x=600/0.05=12000 |
|
| 25. |
21. A, B and C divide an amount amongstthemselves in the ratio of 4:7:9 respectively.If B's share in the amount is 2989 what is thetotal amount?(a) 9820(b) 8540(c) 2720(d) 7 864010 tudents is 18 y |
|
Answer» Let the ratio be 4x:7x:9xIf, 7x=2989X=2989/7=427 rsTotal ratio=4x+7x+9x=20xSo,total amount=20x=20*427=rs8540Answer is (b) answer B is the right answer I am right so please tell me iam is a unique it the Heidi |
|
| 26. |
If the radius of base of a cylinder is doubledand the height remains unchanged, its curvedsurface area becomes:7.doubledthree timeshalfno change |
|
Answer» Letrandhbe the radius and height of original cylinder respectively. Curved surface area of original cylinder, S1= 2πrh If the radius of base of cylinder is doubled, then New radius,R= 2r Curved surface area of new cylinder, S2= 2π(2r)h= 2 × 2πrh= 2 S1 ∴ Curved surface area of the new cylinder is twicethe curved surface of the original cylinder. give me by step by step please give me by step wise |
|
| 27. |
23. If the length of a rectangle is increased by 25percent and the width is decreased by 20percent, then the area of the rectangle(a) increases by 9%(c) remains unchanged (d) increases by 10%(b) decreases by 5% |
| Answer» | |
| 28. |
Areafollowing statements is true ?(a) A remains unchanged(c) A is decreased by 0.1%of a rectangle is A. If its length is reduced by 10% and its breadth is increased by 10% then which of the(b) A is decreased by 1(d) A s increased by 0.1% |
|
Answer» suppose initial length and breadth is 1 so area is 1now new length is 0.9 and new breadth is 1.1so area=(1.1)(0.9)=0.99so decrease in percentage=(1-0.99)×100=1% |
|
| 29. |
find the simple interest and amount on.1. Find the san.4500 for 2years atyears at 7% per annum |
|
Answer» SI=862.5amount=3637.5 22425 is the correct answer 1st take formula of simple simple interest and then add simple interest and the interest right answer is si=5175amount=5175-4500=675 first take P multiply R multiply T divide by 100 then add interest and principle right answer is =5175 amount =5175-4500=675 |
|
| 30. |
63. A sum of Rs. 10000 is borrowed at the rate of interest15% per annum for 2 years. Find the amount to be paid atthe end of 2 years |
|
Answer» 4ooo rupees is right answer |
|
| 31. |
6011Find the width of the courtyard.41. The area of a rectangular gtoactangular ground remains unchanged if length is increased by 3m and Dreatsdecreased hv. 2m. If length is decreased by 2 m and breadth is increased by 3m, area increaseby 5 m 2 Find the length and breadth of the ground.72. The sides of indlad trianale containini thoni |
| Answer» | |
| 32. |
778 ^ { \circ } = 1 |
| Answer» | |
| 33. |
7. If the radius of base of a cylinder is doubledand the height remains unchanged, its curvedsurface arca becomes:three timesdoublede halfno change |
|
Answer» Let old radius = r1 New radius = r2 = 2r1 —(1) Height of both (reduced and original cylinder) = h Similarly CSA of cylinder = 2πrh Therefore, ratio of reduced to original cylinder area= r1/r2 =r1/(2r1) = 1/2 |
|
| 34. |
eprice of petrol goes up by 10%. By how much per cent must a motorist reduce theconsumption of petrol so that the expenditure on it remains unchanged? |
| Answer» | |
| 35. |
Probability of solving specific problem independently by A and B are andrespectively. If both try to solve the problem independently, find the probablitythat(6) the problem is solved (i) exactly one of then solves the problen.(ii)exactly one of them solves the problem. |
| Answer» | |
| 36. |
The rate for a 1.20 m wide carpet is 40 per metre, find the cost of coveringa hall 45 m long and 32 m wide with this carpet. Also find the cost ofcarpenting the same hall if the carpet, 80 cm wide is at 25 per metre. 4 |
|
Answer» lengthoffloor=45m breadthoffloor=32m areaoffloor=length×breadth=45×32=1440m² widthofcarpet=1.2m lengthofthecarpet=14401.2=1200m Totalcost=Rs(40×1200)=Rs48000 widthofcarpet=80cm=0.8m Lengthofcarpet=14400.8=1800 Totalcost=25×1800=Rs45000 |
|
| 37. |
Find the principal when simple interest at 5% pa for 15 years is2,500 |
|
Answer» given S.I.=2500r=5%t=15yearsP=?S.I.=P*r*t/1002500=P*5*15/100P=2500×100/75P=10000/3=3333.33 you are so intelligent thank you |
|
| 38. |
12) Find the sum of money which amountsto 4640 at 8% simple interest pa. at theend of 2 years. |
| Answer» | |
| 39. |
Find the simple interest and the amount when1. Principal - 6400, rate - 6% pa. and time - 2 years. |
| Answer» | |
| 40. |
rekha took a loan from Yusuf at the rate6% per annum SI. She returned乏7000 toYusuf after 2 years. Find the amount she tookas loan.Karim took a loan of 1500 at the rate ofinterest same as the number of years. If he paid375 as interest at the end of the loan period,find the number of years. |
|
Answer» please give answer of second question also |
|
| 41. |
Find the simple interest and the amount when:1. Principal = 6400, rate = 6% pa. and time-2 years. |
| Answer» | |
| 42. |
rupees 7000 is borrowed at 3.5 % rate of interest P A for 2 years find the amount to be paid the end of second year |
|
Answer» we know thatP*T*R/100= simple interest7000*3.5*2/100= 70*3.5*2=490 rupees will be interestthen amount to be paid will be7490 |
|
| 43. |
te the following table.NumberRoot of the powPower of the root5 Square root of cube(22s) Cube of square root of 22(45)5(81)-(100)(21) |
| Answer» | |
| 44. |
(1) the square root of 0.6254(2) the cube root of 0.6254 |
|
Answer» i) (0.6254)² = 0.39112516ii) (0.6254)³ = 0.244609675064 |
|
| 45. |
1 the least number that must be added to 1300 so as to get a posquare root of the perfect square.1 the least number that must be subtracted to 6412 so as to getthe square root of the perfect square.1 the square root by long division method.7956 (ii) 11025 (iii) 6889 (iv) 1764I the square root of the following decimal numbers:2.89 ii) 1.96 üü) 67.24 iv) 31.36 v 2.0164the square root of each of the following fractions:21) 77864365 423rue or False:595 |
| Answer» | |
| 46. |
PLUSroot of this number.Find the least number which must beeast number which must be added to 6203 to obtain a perfect square.Also, find the square root of the number so obtained.perfect square. Find the square root |
| Answer» | |
| 47. |
(a) There are 6 marbles in a box with numbers from1 to 6 marked on each of them :-(1) What is the probability of drawing a marblewith number 2'? |
|
Answer» total chances =6chances for 2=1probability=1/6 |
|
| 48. |
Q.14 Find the angle between hour-hand andminute-hand in a clock ati) ten past elevenii) twenty past seveniii) thirty five past oneiv) quarter to sixv) 2:20 vi) 10:10 |
|
Answer» i)36 degreesii) 100 degreesiii) 72 Degiv) 36 Degv)36 Degvi)36 deg 1) 36 degrees2) 100 degrees 3) 72 degrees 36 degree72 degree100 degreeis the right answer 36degrees100degrees72degrees 5 is the correct answer option iii is the correct answer 1) 36degrees . 2) 100 degrees . 3) 72 degrees is correct answer |
|
| 49. |
MUTL) TUNC UT Liese17. The ages of A and B are presently in the ratio of 5:6. Sixyears hence this ratio will become 6:7. What was B's age 5years ago?25 years 2) 30 years 3) 36 years 4) 31 years |
|
Answer» Let age of A = 5xLet age of B = 6x After 6 yearsAge of A = 5x + 6Age of B = 6x + 6 As per given condition(5x + 6)/(6x + 6) = 6/7 7*(5x + 6) = 6*(6x + 6)35x + 42 = 36x + 3636x - 35x = 42 - 36x = 6 Therefore, B age 5 years ago= 6x - 5= 6*6 - 5 = 36 - 5= 31 years (4) is correct option |
|
| 50. |
Ivikas is three years older thanDeepika six years ago. Vakansage doos four times DeepitalsEege. And the ages & Deepikaand Vikas. |
|
Answer» Let deepika age be x yearsVikas age = x + 36 years ago:Deepika age = x - 6Vikas age = x+3-6 = x-3As per the question, vikas age is 4 times the deepika agex - 3 = 4(x-6)x-3 = 4x - 243x = 21x = 7Deepika age = 7 yrsVikas age = 7+3 = 10 Let deepika age be x yearsVikas age = x + 36 years ago:Deepika age = x - 6Vikas age = x+3-6 = x-3As per the question, vikas age is 4 times the deepika agex - 3 = 4(x-6)x-3 = 4x - 243x = 21x = 7Deepika age = 7 yrsVikas age = 7+3 = 10 Let deepika age be x yearsVikas age = x + 36 years ago:Deepika age = x - 6Vikas age = x+3-6 = x-3As per the question, vikas age is 4 times the deepika agex - 3 = 4(x-6)x-3 = 4x - 243x = 21x = 7Deepika age = 7 yrsVikas age = 7+3 = 10 hope this will help you like my answer and Mark it as best answer the age of Deepika and vikas is 7 and 10 respectively... the age of deepika and vikas is7 and 10 respectively... |
|