This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Exercise 16.2Q1. Find the mean of the first five natural numbers. |
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| 2. |
The curved surface area of a right circular cylinder ofheight 14 cm is 88 cm.liameter of the base of the cylinder. |
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| 3. |
The circumference of the base of a cylinder is 88 cm and its height is 30 cm. Find the volume of thecylinder |
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| 4. |
curved surface area of a right circular cylinder of height 14 cm isdiameter of the base of the cylinder88 cm Find the |
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Answer» Height (h) of cylinder = 14cmLet the diameter of cylinder be d.Curved Surface Area of Cylinder = 88cm square2πrh = 88 cm squareπ dh = 88 cm square. (d = 2r)22/7 × d × 14 = 88 cmd = 2 cmTherefore,the diameter of the base of the cylinder is 2 cm |
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| 5. |
The circumference of a circle is 88 cm. Its diameter is |
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| 6. |
23 x^{2} y^{2} ) \times\left(-5 x^{3} y^{5}\right)=? |
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| 7. |
\left(23 x^{2} y^{2}\right) \times\left(-5 x^{3} y^{5}\right)=? |
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| 8. |
3 x + 5 = 23 |
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Answer» 3x+5=233x=23-5=18so x=6 |
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| 9. |
SHORT ANSWER-II TYPE PROE7. If x = 3+2/2, find t |
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Answer» your answer is write but I am not understanding your answer is write but I am not understanding |
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| 10. |
Writeanarithmeticsequencewithcommondifference6.Isthedifferenceofanytwoterms be 50 Why? |
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Answer» 1, 7,13,19,25,31........No the difference can't be 50, it can only be a multiple of 6 and 50 is not a multiple of 6. |
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| 11. |
((-8)/44)*(text*(((-17)/11)*(f*(r*(m*o))))) |
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| 12. |
1. Find the value of (64)12 x (125)11/21/3 |
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Answer» (64)1/2×(125)1/3(8^2)1/2×(5^3)1/38×5=40 |
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| 13. |
11.F+ 10 and 3p+2or what value of p are 2p, pin A.P? |
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Answer» all three are in A.P. so 2(p+10)=2p+3p+22p+20=2p+3p+2so 3p=18so p=6 |
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| 14. |
ion 3.. Two arithmetic progressions have the same common difference. The difference between their 100term is 100, what is the difference between their 1000th term.n BC into two narts equal in area& XY AC. |
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| 15. |
hat ie the common difference s7 |
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Answer» Terms are 1 21 ----- , 1----- , 2.. 3 3 4/3 , 5/3 , 2.... D = 5/3 - 4/3 = 1/3 |
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| 16. |
4. LCM of (23 x 3 x 5) and (2* x5x7) is 1 |
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| 17. |
6. (a) Find the simple interest on Rs.15000 at 5% per annum for 8months |
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| 18. |
6 x + 25 - \frac { 1 } { 9 } x = 1.8 - 0.75 x - \frac { 1 } { 3 } |
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Answer» options Lo ledu |
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| 19. |
State and prove ptolemy's theorem. |
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Answer» Ptolemy's theorem states the relationship between the diagonals and the sides of a cyclic quadrilateral. It is a powerful tool to apply to problems about inscribed quadrilaterals. Ptolemy's Theorem states thatIf a quadrilateral ABCD is inscribable in a circle, then the product of the measures of its diagonals is equal to the sum of the products of the measures of the pairs of the opposite sides:AC. BD = AB. CD + AD. BC |
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| 20. |
Why are rational numbers closed undermultiplication? |
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Answer» Product of two rational number is also a rational number,So rational number closed under multiplication. thus,multiplying two rational numbers produces another rational numbers |
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| 21. |
T eI कौन सी धनशशि 'पर साधारण ब्याज से 6| तो में अ्कबिक की, दर से 150क ब्याजA.5000% b.7500 wS ©.10000% * d.15000% | |
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Answer» SI = P×R×T/100150 = (P × 4 × 6/12)/100P = 7500 |
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| 22. |
6. (a) Find the simple interest on Rs15000 at 5% per annum for 8months |
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Answer» 8 months= 8/12 years |
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| 23. |
1. a) Iam round and flat. Who am 1?b) I have 2 short sides and 2 long sides. Who am 1?c) I have 3 sides. Who am I? |
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Answer» b) rectangle c) triangle |
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| 24. |
of the spectators wereAt a cricket test match 2 of the spea covered place while 15000 were infind the total number of spectaaopen.Me 15000 were in |
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Answer» 21,000 is the correct answer of the given question |
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| 25. |
3 7 x 107 x 1255-5 Ă 6-6 |
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| 26. |
15000 %2B 500*15000 |
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Answer» 15000+15000 × 500=15,000,000 |
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| 27. |
Give reasons for the following statements:(i) {2, 3, 5, 7, 9, 11)#{r:x is a prime number, x< 12)(ii) {1, 64, 125)#1 x : x is a perfect square and perfect cube, x<125) |
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Answer» i) prime numbers less than 12 = 2,3,5,7,11 The set has 9 which is a non - prime number. Hence it is true ii) Perfect square and perfect cube less than 125 = 1,64 The set has 125 which is not a perfect cube. Hence it is true |
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| 28. |
. Give reasons for the following statements:(0) (2. 3, 5, 7,9, 11) x : a is a prime number, x< 12)(ii) {1,64, 125)(x:a is a perfect square and perfect cube and x<125) |
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Answer» i) the sets are not equal because 9 is not a prime. ii) the sets are not equal because 125 is not perfect square |
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| 29. |
3-7 x 10-7 x 125c)-5-6 |
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| 30. |
((125*x^(-3))/((x^(-6)*(25*5^(-3)))))^2 |
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Answer» 5^8;x^6 the correct answer of the given question |
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| 31. |
17. In the given figure, 4BAD-7575°Find the values of x and y |
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| 32. |
State and Prove closed Graph Theorem. |
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Answer» Inmathematics, theclosed graph theoremis a basic result which characterizescontinuous functionsin terms of theirgraphs. There are several versions of the theorem. The closed graph theoremIn point-set topology For any functionT:X→Y, we define thegraphofTto be the set Inpoint-set topology, the closed graph theorem states the following: IfXis atopological spaceandYis acompactHausdorff space, then the graph ofTis closed if and only ifTiscontinuous. Msc paper |
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| 33. |
1. Three angles of a quadrilateral are 75 90° and 75. Find the measurethe fourth angle |
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Answer» let fourth one be x. then, 75+90+75+x=360 (sum of angles in quadrilateral is 360 degree) -> 240+x=360-> x=360-240-> x=120 |
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| 34. |
MATHEMATIOConstrauct a triangle of sides 4 cm, 5 cm and 6 cm and then a triangle similar to itwh2sides are - of the corresponding sides of the first triangle.Construct a trinnal |
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| 35. |
5, 12, 13, 50, 141 - after next digit. |
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Answer» it should be 23in the place of 137…….+11……….+27……….+91………+347………+4……..+16……….+64………+256answer will be 452 how |
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| 36. |
(a) t57.) If the sum of the lengths of bases of a trapezium is 12 cm and area is 141 cm2, tenits altitude will be |
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Answer» Area of trapezium = 1/2(sum of bases)*altitude 14.1 = 1/2(12)*altitudeAltitude = 14.1/6 = 2.35 cm |
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| 37. |
1. Expand the following: |
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Answer» Using trignomertric identity,(a+b)²=a²+b²+2abWhere a=2a and b=1 (2a+1)²=4a²+1+4a |
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| 38. |
1. Three angles of a quadrilateral are 75°, 90° and 75°. Find the measure ofthe fourth angle. |
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Answer» As we all know that the sum of all interior angles of a quadrilateral =360° So , let us take the 4th angle as X.. Then:- 75°+90°+75°+X=360°240°+X=360°X = 360°-240°X= 120° so the 4th angle will be 120° |
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| 39. |
EXERCISE 10A1. Three angles of a quadrilateral are 75°, 90° and 75° Find thethe fourth angle. |
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Answer» 75+90+75+x = 360 x = 360-240 x = 120° |
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| 40. |
EXERCISE 10A1. Three angles of a quadrilateral are 75°, 90° and 75°. Find the measure ofthe fourth angle. |
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Answer» Sum of all the four angles of a quadrilateral is 360°. Let the unknown angle be x°.75+90+75+x=360240+x=360x=120 The fourth angle measures 120°. it may help |
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| 41. |
Find the valueof . Ich log(x+3) log(x-3) = log 27 |
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| 42. |
(the following are closed eurves? Which of them are simple?ich(iii)(iv) |
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| 43. |
Given d = 5, S" 75, find a and a9. |
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Answer» By applying the formula Sn = n / 2 + ( 2a + ( n - 1 ) × d 75 = 9 / 2 + (2a + ( 9 - 1 ) × 5 75 = 9 / 2 + ( 2a + 40 ) 75 × 2 / 9 = 2a + 40 50 / 3 = 2a + 40 50 / 3 - 40 / 1 = 2a by taking LCM we will get - 70 / 3 = 2a a = - 70 / 3 × 2 a = - 35 / 3. a9 = a + 8d = -35 / 3 + 8 × 5 = - 35 / 3 + 40 = -35 + 120 / 3 = 95 / 3. |
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| 44. |
12.5% of a number is 75, Find thenumber. |
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| 45. |
Which of he following mumbers heve1at the units placea 12105e 219141d 143 |
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Answer» question is not clear. ok |
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| 46. |
MATHEMATESCo2202. Construct a triangle of sides 4 cm, 5 cm and 6 cm and then a triangle similar to itwhosSt0sesides areof the corresponding sides of the first triangle. |
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| 47. |
(1) 179 (2) 197(3) 219(4) 221 |
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| 48. |
7 1यदि 15 कलमों का मूल्य 219 रु० हो, तो 25 कलमों का मूल्य क्यकक किक |
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| 49. |
2.ABC and ADC are two right triangles with common hypotenuse AC. Prove thCADa CBD3. |
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| 50. |
404. The perimeters of circular ends of a bucket are respectively 220 cm and 88 cm. If the height of theAns: 80.081bucket is 40 cm. How much water can it hold? |
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Answer» Radius will be2πR=220R=220/2π=35cm2πr=88r=88/2π=14cmHencevolume will be 1/3π(R^2+Rr+r^2)h=80.08litres kaise kaise bnaye ho bhaiya please explain |
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