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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
(-6) \times(-5) \times(-7) \times(-2) \times(-3 |
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Answer» 30×14×(-3)=30×(-42)=-1260 |
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| 2. |
\sqrt{\frac{2 \times 6 \cdot 0 \times 10^{-21}}{2 \times 1 \cdot 7 \times 10^{-27}}} |
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| 3. |
\frac { ( - 8 ) ^ { - 2 } \times 5 ^ { - 3 } \times ( - 7 ) ^ { - 4 } \times 24 } { ( - 5 ) ^ { - 7 } \times 28 ^ { - 3 } \times 164 } |
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| 4. |
3share = =\frac{3}{17} \times 1,275 |
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Answer» basic multiplication3/17*1275=3*75=225 |
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| 5. |
\frac{137 \div 17 \times 3.99}{4.02 \times 3.98}=? |
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| 6. |
3' istimes larger than 3353 is times larger than 5217 is times larger than 17510 is times larger than 5'. |
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Answer» 1)3 times2)5 times3)7^2 times4)17^2 times5)5^6 times |
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| 7. |
25 + 15 - 0 \times ( 22 \times 15 \text { of } 17 ) \div 20 + \overline { 6 - 2 } |
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Answer» 25+15-0x(22*15*17)÷20+425+15-0+440+4=44 |
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| 8. |
किंवाजर वर्मसमीकरण 82: + 027 ८० चे एक g N g e m रिद्ध कस की,S3p* =16 ac. |
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| 9. |
\frac{6}{17} \times \frac{34}{15}-\frac{6}{35} \text { of } 2 \frac{1}{3} |
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Answer» by BODMAS rule(6×2)/15+6/35×7/3=4/5+2/5=6/5 |
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| 10. |
\frac { 6 } { 17 } \times \frac { 34 } { 15 } - \frac { 6 } { 35 } \text { of } 2 \frac { 1 } { 3 } |
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| 11. |
16.a^{2} \times b^{3} \times b^{4}“ का मान होगा = |
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Answer» a2×b7 is answer of is his quesruon |
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| 12. |
Bnove that--(\vec{a}-\vec{b}) \times(\overline{a} \times b)=2(a \times b) |
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| 13. |
4. The length of the shadow of a tower onthe plane ground is 3 times the heightof the tower. The angle of elevation of sun151) 302) 453) 60:4)90ositions of the |
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Answer» option a is the correct answer of the given question Answer:2)30° Explanation; Ans. (a) is correct answer of the given question |
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| 14. |
Find the sum of(I) 153 and -302(ii) -489 and-324 |
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Answer» 1. 153 +(-302) = -1492. -489 + (-324) = -813 |
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| 15. |
-35+Find the area of the following figure:2(a)3027 am |
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| 16. |
\sqrt { 0.03 \times 3 \times a = 3 \times 0.03 \times \sqrt { b } , \text { then } \frac { a } { b } } |
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Answer» take square both the sides0.03×3×a=(3×0.03)^2×bso a/b=(3×0.03)^2/(3×0.03)=3×0.03so a/b=0.09 |
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| 17. |
A = \{ a , b , c \} \text { and } B = \{ 1,2 \} , \text { then } A \times B = |
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| 18. |
1/+1321. (a) What loss is caused due to the use of plasticof plastic ?(b) What is recycling ? explain. |
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Answer» Recycling is the process of converting a waste material, such as glass, plastic, paper or metal, into a material that can be used for the same or alternative purpose. It is part of the waste hierarchy – reduce, reuse, recycle. |
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| 19. |
\left| \begin{array} { r r r } { x } & { 4 } & { - 4 } \\ { 3 } & { - 2 } & { 1 } \\ { - 2 } & { - 4 } & { 1 } \end{array} \right| = 0 |
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Answer» x(-2*1+4) -4(3+2)-4(-12-4) = 0=> 2x-20+64 = 0=> x-10+32= 0=> x= -22 |
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| 20. |
= \quad z - 9 + 5 \times 21 |
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Answer» 12×5+6-2=(12×5)+6-2=60+6-2=64 is the answer 64 is the answer for this question.. |
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| 21. |
109 \times 21 \times 302 |
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Answer» 109×21×302=691278 is the product of those 3 numbers |
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| 22. |
\sqrt [ 3 ] { \frac { - a ^ { 6 } \times b ^ { 3 } \times c ^ { 21 } } { c ^ { 9 } \times a ^ { 12 } } } |
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| 23. |
\left. \begin{array} { r } { 43 } \\ { \times 21 } \\ \hline \end{array} \right. |
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Answer» 43x21=903 903 is the value 43*21=903. |
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| 24. |
Solve this questioXx + y = 25 |
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Answer» 16,9 is the correct answer of the given question |
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| 25. |
Sunil takes 5 days more than Anil to complete a certain work. 4 days after starting thegork. Anil lefi the work. The remaining work was done by Sunil in 5 days. Find howmany days each will take to complete the work |
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Answer» Let Anil takes x number of days to complete the work ⇒ 1 day = 1/x of the work Sunil takes 5 more days than Anil to complete the work ⇒ x + 5 days ⇒ 1 day = 1/(x + 5) of the work Together: 1 day = 1/x + 1/(x + 5) 1 day = (x + 5 + x)/x(x+5) 1 day = (2x + 5) / (x² + 5x) of work doneFind 4 days of work done: 1 day = (2x + 5) / (x² + 5x) 4 days = 4(2x + 5) / (x² + 5x) 4 days = (8x + 20) / (x² + 5x) of work done Find the amount of work left to be done: Work left = 1 - (8x + 20) / (x² + 5x) Work left = (x² + 5x - 8x - 20) / (x² + 5x) Work left = (x² - 3x - 20) / (x² + 5x) Solve x: Give that Anil needs 5 days to complete the rest of the work (x² - 3x - 20) / (x² + 5x) ÷1/(x + 5) = 5 (x² - 3x - 20) / (x² + 5x) × (x + 5) = 5 (x² - 3x - 20) /x = 5 x² - 3x - 20 = 5x x² - 8x - 20 = 0 (x - 10) (x + 2) = 0 x = 10 or x = -2 (Rejected, number of days cannot be negative) Find the number of days each take to complete the work Anil = x = 10 days Sunil = x + 5 = 10 + 5 = 15 days i didnt understoood some steps i understood it nicely |
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| 26. |
4(1)Sunil takes 5 days more than Anil to complete a certain work. 4 days after starting thework, Anil left the work. The remaining work was done by Sunil in 5 days. Find howmany days each will take to complete the work. |
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Answer» sunil take 5day mor |
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| 27. |
The diameter of a wheel of a cycle is 70 cm. Find out the distance covered by it after200 revolutions.in tho ratio of their circumferences? |
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Answer» Diameter of the wheel =70 cmRadius = d/2=70/2=35 cmFor 1 revolution the wheel moves = circumference of the wheel= 2*pi*r=2*22/7*35 =2*22*5=220cmFor 200 revolutions it moves =200×220=44000 cm |
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| 28. |
ing questions : (Any One)Sunil takes 5 days more than Anil to complete a certain work. 4 days after sarting thework. Anil left the work. The remaining work was done by Sunil inmany days each will take to complete the work.All kings, queens and accs5 days. Find how(2) |
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Answer» Let Anil takes x number of days to complete the work ⇒ 1 day = 1/x of the work Sunil takes 5 more days than Anil to complete the work ⇒ x + 5 days ⇒ 1 day = 1/(x + 5) of the work Together: 1 day = 1/x + 1/(x + 5) 1 day = (x + 5 + x)/x(x+5) 1 day = (2x + 5) / (x² + 5x) of work done Find 4 days of work done: 1 day = (2x + 5) / (x² + 5x) 4 days = 4(2x + 5) / (x² + 5x) 4 days = (8x + 20) / (x² + 5x) of work done Find the amount of work left to be done: Work left = 1 - (8x + 20) / (x² + 5x) Work left = (x² + 5x - 8x - 20) / (x² + 5x) Work left = (x² - 3x - 20) / (x² + 5x) Solve x: Give that Anil needs 5 days to complete the rest of the work (x² - 3x - 20) / (x² + 5x) ÷1/(x + 5) = 5 (x² - 3x - 20) / (x² + 5x) × (x + 5) = 5 (x² - 3x - 20) /x = 5 x² - 3x - 20 = 5x x² - 8x - 20 = 0 (x - 10) (x + 2) = 0 x = 10 or x = -2 (Rejected, number of days cannot be negative) Find the number of days each take to complete the work Anil = x = 10 days Sunil = x + 5 = 10 + 5 = 15 days Answer: Anil takes 10 days and Sunil takes 15 days to complete the work |
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| 29. |
Q.5Solve the following questions (Any one):(04)Sunil takes 5 days more than Anil to com plete a certain work. 4 days after starting thework, Anil left the work. The remaining work was done by Sunil in 5 days. Find howmany days each will take to complete the work.1) |
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Answer» Let Anil takes x number of days to complete the work ⇒ 1 day = 1/x of the work Sunil takes 5 more days than Anil to complete the work ⇒ x + 5 days ⇒ 1 day = 1/(x + 5) of the work Together: 1 day = 1/x + 1/(x + 5) 1 day = (x + 5 + x)/x(x+5) 1 day = (2x + 5) / (x² + 5x) of work done Find 4 days of work done: 1 day = (2x + 5) / (x² + 5x) 4 days = 4(2x + 5) / (x² + 5x) 4 days = (8x + 20) / (x² + 5x) of work done Find the amount of work left to be done: Work left = 1 - (8x + 20) / (x² + 5x) Work left = (x² + 5x - 8x - 20) / (x² + 5x) Work left = (x² - 3x - 20) / (x² + 5x) Solve x: Give that Anil needs 5 days to complete the rest of the work (x² - 3x - 20) / (x² + 5x) ÷1/(x + 5) = 5 (x² - 3x - 20) / (x² + 5x) × (x + 5) = 5 (x² - 3x - 20) /x = 5 x² - 3x - 20 = 5x x² - 8x - 20 = 0 (x - 10) (x + 2) = 0 x = 10 or x = -2 (Rejected, number of days cannot be negative) Find the number of days each take to complete the work Anil = x = 10 days Sunil = x + 5 = 10 + 5 = 15 days |
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| 30. |
. Sive the following questions : (Any One)4unil takes 5 days more than Anil to complete a certain work. 4 days after starting thework, Anil left the work. The remaining work was done by Sunil in 5 days. Find howmany days each will take to complete the work.(1) S |
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Answer» Let Anil takes x number of days to complete the work ⇒ 1 day = 1/x of the work Sunil takes 5 more days than Anil to complete the work ⇒ x + 5 days ⇒ 1 day = 1/(x + 5) of the work Together: 1 day = 1/x + 1/(x + 5) 1 day = (x + 5 + x)/x(x+5) 1 day = (2x + 5) / (x² + 5x) of work done Find 4 days of work done: 1 day = (2x + 5) / (x² + 5x) 4 days = 4(2x + 5) / (x² + 5x) 4 days = (8x + 20) / (x² + 5x) of work done Find the amount of work left to be done: Work left = 1 - (8x + 20) / (x² + 5x) Work left = (x² + 5x - 8x - 20) / (x² + 5x) Work left = (x² - 3x - 20) / (x² + 5x) Solve x: Give that Anil needs 5 days to complete the rest of the work (x² - 3x - 20) / (x² + 5x) ÷1/(x + 5) = 5 (x² - 3x - 20) / (x² + 5x) × (x + 5) = 5 (x² - 3x - 20) /x = 5 x² - 3x - 20 = 5x x² - 8x - 20 = 0 (x - 10) (x + 2) = 0 x = 10 or x = -2 (Rejected, number of days cannot be negative) Find the number of days each take to complete the work Anil = x = 10 days Sunil = x + 5 = 10 + 5 = 15 days Answer: Anil takes 10 days and Sunil takes 15 days to complete the work. |
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| 31. |
Mamta can alone complete a part of assignmentin 8 days. Work done by Sunil alone in one day ishalf of the work done by Mamta alone in one day.In how many days can the assignment becompleted, if Mamta and Sunil work together?Options:A. 5.33 daysB. 16 daysC. 24 daysD. 4 days |
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Answer» the correct answer is C right answer 24 days option (c)is the right answer A is the correct answer option c is the correct answer assignment is completed in 24 days A is the right answer |
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| 32. |
ong 3-I (Short Answer Type Questioi) 04704(ii)0.572(iii) 1.63 |
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Answer» thanks |
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| 33. |
hcf 1064 |
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Answer» 5 is the correct answer Factors of 1064 =1, 2, 4, 7, 8, 14, 19, 28, 38, 56, 76, 133, 152, 266 5 is the right answer 5 is the right answer 5isthe right answer....... 5 is the correct one find the correct answer and like my answer 5 is the right answer five is the correct answer and like my answer |
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| 34. |
() AnsweranyonequestioC) Find the probability that a leap year, selected at random will contain53 sundays. |
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| 35. |
वि कि oo & का की. ब्ग्जुSa-p L if ~=~ fings o |
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Answer» a/b=7/45a-b/b=5a/b-1/1=5*7/4-1=35/4-1=35-4/4=31/4 |
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| 36. |
18,000 ; Second year 20,500 ; Thirdas : First yearCalculate the value of Lood will on the basis Uluweights 1, 2 and 3 respectively to the profit for 2014, 2015 and 205. A firm earned net profits during the last four years as : First yearyear 25,500; Fourth year 28,000; Fifth year *23,000.Goodwill of the firm is valued at 10% less than thrice the average profit onCompute the value of Goodwill.an thrice the average profit of the preceding five years.or average profit. |
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Answer» Average profit of last 5 years= (18000 + 20500 + 25500 + 28000 + 23000)/5= 115000/5= 23000 Therefore,Goodwill of firm= 3*23000(1 - 10/100)= 69000(9/10)= 6900*9= Rs 62100 ye commerce ka question h |
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| 37. |
A and B are partners in a firm and share profits in tho ratio of 3: 2. Ifthe profit of the year is 6,500, distribute the profit. |
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Answer» Let A gets 3x and B gets 2x , where x is a constant. according to question, 3x+2x =6500 => 5x =6500=>x =1300 Therefore, A gets 3x = Rs 3900 from the profit and B gets 2x = Rs 2600 from the profit. |
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| 38. |
9. Umesh set up a small factory by investing40.000. During the first three successive yearshis profits were 5%, 10% and 15% respectively. Ifeach year the profit was on previous year's capital,calculate his total profit. |
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| 39. |
1. Tand my friend Mala together have started a business with capitals of 15000 and25000 respectively. If we make a profit of 16,800 in a year, let us see that the profitshare shall we each get? |
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Answer» I : mala15000 : 2500015 : 253 : 5sum of ratio= 3+5=8I get = 3×16800/8 = 3×2100 = 6300. ₹mala get =5×16800/8 = 5×2100 = 10500 ₹ 2100*3=6300, and 2100*5= 10500 |
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| 40. |
की A= ;& = के = +f A 2 1l B 4l and |Y d (A +BY = A2 4£ B fing |
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| 41. |
Fing the faclonial |
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| 42. |
18=H.fing |
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Answer» 4+4=83+3=64+9=13answer is this |
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| 43. |
Fing the no- of ways SECTORof ways of rearrangingteatters of the "woid VECTOR, |
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Answer» No of ways will be!6= 720thanks No of ways isVECTOR-42 |
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| 44. |
4. If the rate of VAT increased bythen Spel an article goeitebe Fluo- fing the marretDocce of the article. |
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Answer» sjakakaksjsheiwowoqoqoqowo |
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| 45. |
5. The diagonals of a rhombus are 7.5 cm and 12 cm, Fingits area. |
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| 46. |
theoremFactorise 3-9-5Ii I and y are two positive real numbers such that 15--84 and Sry-2ny-24, thenevaluate 5x-2ydenre welfare Association planned to make a rectanguiar playground for chilidren in their colonylation hrnwsen all angies of a rectangies |
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| 47. |
opkeeper marks his goods at 40% above the cost price but allows a discount of 5%for cash payment to his customers. What actual profit does he make, if he receives Rs1064 after paying the discount?14 |
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| 48. |
1. Two soldiers A and B in tthe top of a hill. The angle of elevation of the intruder from A and B to the ground level in theeastern direction are 30° and 45o respectively. If A and B stand 5 km apart, find the distance of theintruder from Bwo different underground bunkers on a straight road, spot an intruder at |
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Answer» 1 2 |
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| 49. |
Theorem-4 : If a, m, n are positive real numbers and a # 1, thenloga-loga m -loga n |
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Answer» Let logaM = x ⇒ ax= M and logaN = y ⇒ ay= N Now ax/ay= M/N or, ax - y= M/N Therefore from definition we have, loga(M/N) = x - y = logaM- logaN[putting the values of x and y] Corollary:loga[(M × N × P)/R × S × T)] = loga(M × N × P) - loga(R × S × T) = logaM + IogaN + logaP - (logaR + logaS + logaT) The formula of quotient rule[loga(M/N) = logaM - logaN]is stated as follows:The logarithm of the quotient of two factors to any positive base other than I is equal to the difference of the logarithms of the factors to the same base |
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| 50. |
2. Suppose a. b are positive real numbers such that avatbb-183. avbba 182.Find ab).+5v/a = 182 |
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