Explore topic-wise InterviewSolutions in Current Affairs.

Like if it is useful

(କ) ସୁଦର୍ଶନ ଠିକ୍ ଉତ୍ତର।

Given: A triangle ABC in which AC² = AB² + BC²To Prove: angleB = 90°.

Construction: We construct a APQR right-angled at Q

such that PQ= AB and QR = BC

Proof: Now, from APQR,

we have, PR² = PQ² + QR² [Pythagoras Theorem, as angleQ = 90°] or, PR²= AB²+ BC²

[By construction] ...(i) But AC²= AB² + BC 2 [Given] ...(ii)

So, AC² = PR² [From (i) and ii AC = PR ...(iii) Now, in triangle ABC and TrianglePQR, AB = PQ [By construction] BC = QR [By construction] AC = PR [Proved in (iii)]

hit the like 👍✔️✔️ if you have understood

3Median= Mode+2mean3Median = 18 + 2(24)3Median = 18 + 483Median = 66Median = 22

Find The Mode of 2'2;2;3;3;4;5;5;6;8

angle=radius108=108π/180=3π/5

3π/5=Arc/159πcm=Arc28.28cm=Arc

Applying section formula , Let λ is the ratio by which P divides the line joining A and B.x = (λx₂ + x₁)/(λ + 1) here , x = 4 , x₁ = 2 , x₂ = 6 Now, 4 = (6λ + 2)/(λ + 1)4(λ + 1) = 6λ + 2 4λ + 4 = 6λ + 2 2 = 2λ ⇒ λ = 1 Hence, p divides the line AB into 1 : 1 ratio.

Now, for y - co - ordinate y = (λy₂ + y₁)/(λ + 1) m = (1 × -3 + 3)/(1 + 1) = 0Hence , m = 0

Ley M(x, y) is mid point of line joining points P(-4, 2) and Q(8, 6)

Then,x = (-4 + 8)/2 = 4/2 = 2y = (2 + 6)/2 = 8/2 = 4

Therefore coordinates of midpoint are (2, 4)

(C) is correct option

Circumference of base of cylinder = 2πr =132cm.

=2×22/7×r

r = 132×7/2×22

r = 21cm

volume of cylinder = πr²h

22/7×21×21×22cm³

=30492cm³

thanks

Amount collected by each student = Total amount collected/ Number of students = 1510784/638= Rs 2,368

Hence, each student collected Rs 2,368.

First we have to divide 337875 by 255

then will get answer as 1325

therefore answer is ..1325 student..

total number of students =2786contribution from each student =500 Rs.total contribution from 2786 students are 2786×500=13,93,000 Rs.plz like my answer thanks

class 9 of which school

A is true But is the false is the best answer

(b) A is true, B is false is the correct answer

as it satisfies Pythagoras theorem hence it is at 90°

what is y

pls send me the value of x

(2/3)X=X-202X=3X-60X=60 ans.

x=60 is correct answer

find the number of 2

find the number of 2

find a correct answers is 2

(2/3)×=×-202×=3×-60×=60

ye kya ha dimag ma nhi aa rha ha

City in Afghanistan is the right answer.

EVERY STUDENT HAS A PLAN FOR THEMSELVES AT KUNDUZ! Affordable plans for...

this right answer 4. 150m

Given ratio of pop songs to rock songs is 5:4

Let number of pop songs = 5nNumber of rock songs = 4n

As number of pop songs downloaded = 405n = 40n = 40/5 = 8

Therefore, number of rock songs downloaded = 4n = 4*8 = 32

thank you very much

Equivalent weight = atomic weight/ valency

Therefore, valency = 26.89/8.9

= 2.99 or 3

Exact atomic weight = equib=valent weight x valency

= 8.9 x 3

= 26.7 g

Thus the exact atomic weight = 26.7 gm.

mass no

option D is correct answer according to Pythagoras theorem

We are provided with a Δ PQR such that <P = 90°. Thus, we know that QR is the hypotenuse of this triangle.

PR and PQ are the other two sides.

Applying Pythagoras Theorem to Δ PQR,

h² = a² + b²

QR² = PR² + PQ²

PR² = QR² - PQ²

INΔPQR ,PQ=QR...GIVEN

∴∠R=∠P [ANGLES OPPOSITE EQUAL SIDES]

⇒1/2 PQ=1/2 QR

⇒PL=MR

IN ΔMRN AND ΔLPN

PL=MR

∠R=∠P

PN = NR [N IS THE MIDPOINT OF PR]

∴ΔMRN≅ΔLPN [SAS]

⇒MN=LN [C.P.C.T]

PQ=QR

L,MN are midpoints of PQ,QR,PR respctively

⇒PL=PQ=QM=MR.............................(i)

and ∠QPR=∠QRP(angles opp. to equal sides)......................................(ii)

Step-by-step explanation:

in ΔLPN and Δ MNR

PL=MR(from (i))

∠LPN=∠MRN(from (ii))

PN=NR( N is midpoint)

∴ΔLPN≅ΔMNR(By SAS congruency)

⇒LN=MN(corresponding sides)

Hence Proved

thnqs Sir..

sorry

thnqs mam..

x^2 - x - 72 = 0x^2 - 9x + 8x - 72 = 0x(x-9) + 8(x-9) = 0(x+8)(x-9) = 0x= -8;9

(9x³+3x²-2x+4)-(10x³-4x+11)= (9-10)x³ + 3x² +(-2+4)X +(4-11)= -x³ +3x² +2x -7Please hit the like button if this helped you

Let us assume difference in consecutive terms in first AP = x

difference in consecutive terms in second AP = y.

10th term in both APs are 2+(10-1)x and 7+(10-1)y

i.e. 2+9x and 7+9y.

21st terms in both APs are 2+20x and 7+20y.

Since the differences of consecutive terms are same,

7+9y-(2+9x) = 7+20y-(2+20x)

9(y-x) = 20(y-x)

That means y-x = 0.

Implies y = x.

The difference between consecutive terms in both APs is same.