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two numbers are coprime when their HCF is 1 thereforea) 14 and 37 are coprime as their HCF is 1 because 37 is prime number.b) 35 and 36 are coprime as hcf is 1.35= 7×536= 6×6

Option2 is the correct answer.

option number 3 is correct because sec is opposite of cos

Binary fission

1. The unicellular splits into two equal daughter cells by cess division

2. Nucleus and cytoplasm divide simultaneously.

3. Many different patterns of division transverse and longitudinal.

Example :Ambeoa

Multiple fission

1. Unicellular organisms divide into many daughter cells.

2. First the nucleus divides into many nuclei and then each nuclei is surrounded by cytoplasm and the daughter nuclei are released by rupture of parent cell.

3. No definite pattern of division.

Example :Malaria parasite.

1. 2+8 = 10, 10+8 = 18, 18+8 = 26

similarly

5+9 = 14, 14+9 = 23, 23+9 = 32

So the next number is 26+8 = 34

2. When the number is divided by 18, it leaves a remainder of 7.

When the number is divided by 21, it leaves a remainder of 10.

When the number is divided by 24, it leaves a remainder of 13.

Observing the constant difference of 11 between divisor and remainder:

We can conclude that if 11 is subtracted from the LCM of 18, 21 and 24, then it will leave a remainder of 7 when divided by 18, a remainder of 10 when divided by 21 and a remainder of 13 when divided by 24.

When 11 is subtracted from any multiple of LCM, it will give the same result.

Now,

18 = 2 × 3 × 3

21 = 3 × 7

24 = 2 × 2 × 2 × 3

∴ LCM of 18, 21 and 24 = 504

So, any number of the form (504n – 11) will give the required remainders, when n is an integer.

But, this number also has to be divisible by 23.

Using trial and error method, for n = 6:

We find that: 504n – 11 = 504 × 6 – 11 = 3024 – 11 = 3013

congrats excellent

12 = 4 × 3 so 12 is a multiple of 4

10p is correct answer.

10p =💯p=100/10p=10

10 is the correct answer.

10p is correct answer.

10 paisa is the right answer

the value of p is 10

10p=100p=100÷10p=10

10 is the correct answer of this question

10p=100p =100/10p=10

P=10.....................

p= 10 is the right answer

10 is the correct value of p

volume of the remaining part of the solid = (pi)r^2 h - 1/3 (pi)r^2 h

= 2/3 (pi) r^2 h

Density is given as 10gm/cm3 ,meaning mass of every 1cm3=10gms

It is given that mass of remaining portion = 24.64kg = 24640gms

then,2/3 * 22/7 *r^2 *24* 10 =24640r^2 = 49r = 7

Slant height of cone l= sqrt[(24)^2 + (7)^2] = sqrt(625) = 25

surface area of the remaining portion = 2 pi r h + pi r^2 + pi r l= pi*r(2h + r + l)= 22*7/7(2*24 + 7 + 25)= 22(48 + 32)= 22(80)= 1760 cm^2

Cost of painting per 440 cm^2 = Rs 3Cost of painting 1760 cm^2= 1760*3/440= 4*3= Rs 12

no answer got me

thank u

5x + 2x =17×1/2kg=>7x=35/2kg=>x=5/2kg5x= 5/2*5= 25/2 kgzinc= 2x= 5/2*2= 5kg

Now after adding 1.250 kg of zinc

=> zinc becomes

=> 5 + 1.250 = 6.250 kg= 25/4

New ratio becomes

copper : zinc =25/2:25/4

= 2 : 1

10/100×40 = 4then 10%=420%=5

In geometry, a triangular prism is a three-sided prism; it is a polyhedron made of a triangular base, a translated copy, and 3 faces joining corresponding sides. A right triangular prism has rectangular sides, otherwise it is oblique. ... These three faces are parallelograms

price of 5 m fabric= Rs 210then the price of 1 m fabric=RS 210/5= Rs 42therefore the price of 2 m fabric= Rs 42×2=Rs 84

Cost 5 m fabric is Rs 210Cost of 1 m fabric is Rs 210/5 = Rs 42Cost of 2 m fabric is Rs 42 × 2 = Rs 84

THANKS

Area of rectangle =l*b=500*3.5=1750cm²

Radius of circular wire= 10.5 cmCircumference of circular wire = 2×22/7×10.5=>66 cmAs the rectangle is made up of same piece of wire then circumference of circle is equal to perimeter of rectangle

Perimeter of rectangle =2(l+b)=> 66=2(20+b)=> 66/2=20+b=> 33= 20+b=> 33- 20= b=> 13 = bTherefore breadth of the given rectangle is 13 cm.

Perimeter of rectangle=2(length+breadth)=2(11.25+7.5)=2(18.75)=37.5 cm

thanks

slope of the line is equal to the tangent of the angle it makes from the horizontal axis.(i) tan(0°)=0(ii)tan(60°)=√3(iii)tan(45°)=1(iv)tan(90°)= vertical line(v)tan(120°)=tan(90°+30°)=-√3(vi)tan(150°)= -1/√3

2)(i) tan⁻¹(1)=45°(ii)tan⁻¹(1/4)(iii)tan⁻¹(3)(iv)tan⁻¹(0)=0°

250 metres 12.5 seconds500 metres 25 seconds

Consider one window:area of a rectangle = length x widthArea = 1.2 x 4.2 = 5.04 m^2area of semicircle = (pi x radius^2)/2Area = (pi x 2.1^2)/2 = 6.93 m^2 (2 decimal places)Total area = 5.04 + 6.93 = 11.97 m^22 windows = 2 x 11.97 m^2= 23.94 m^2

Let H be the height of the cylinder and of the cone let r be the radius of cylinder and cone let n be the number of cones that can be fill the cylinder then, n x volume of cones=volume of cylinder n x1/3 (πr^2H)=πr^2H n=3Hence 3 cones should be filled the cylinder.

ratio of area of similar triangles=(ratio of side of triangle)^2=(4/9)^2=16/81

option c is correct bcz BC2/QR2 = 64/36

Dimensions of a room are 4 m , 3.5 m, 3 m

Volume of cuboid = l× b× h

Volume of room= 4 m × 3 .5 m ×3 m

= 42 m³

in litres = 42*1000 = 42000 litres

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BOC=60° and triangle BOC is equilateral triangle

Given,diameter=3cmradius=3/2 cmheight of the model=height of the two cones+ height of the cylinder12=2×2+h12-4=hh=8cmvolume=πr²h+2(1/3 πr²h)=22/7 ×3/2 ×3/2 ×8 +2(1/3 (22/7×3/2×3/2×2))=22×3×3×8/2×2×7 +2(1/3 (22×3×3×2/2×2×7))=56.57+2(1/3 × 14.14)=56.57+2(14.14/3)=56.57+2(4.71)=56.57+9.42=65.99m³air occupied=65.99m³

A balloon is in shape of a Sphere.So, In a Sphere, Diameter= 6mRadius= 6/2= 3mVolume of Sphere= 4/3× π × ( radius)³= 4/3 × 22/7 × 3³= 4/3 × 22/7 × 27= 36× 22 / 7= 792/7 = 113.14 m³

Volume of the balloon with diameter 6 m=(4/3)πr³=(4/3)×3.14×(6/2)³=113.04 m³