Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The value of a for which the sum of the squares of the roots of the equationX - (a - 2)x-a-1=0 assumes the least value is:(A) O(B) 1(C) 2(D) 3 |
|
Answer» (D) 3 is the correct answer to this question. |
|
| 2. |
then show that a b and t'R1Section D16) Let Xe universal set, for the non-empty sets A and sverity thar20i.(AUB)'ΖΑ'ПВ,ii.(AnB),AUB'where X:(1,2,3,4,5,6,7 |
| Answer» | |
| 3. |
19. If (C3, then the least value- 1)of n is(a) 3(c) 7(b) 4(d) 8 |
| Answer» | |
| 4. |
(3) (AUB)A)A4 If A and B are two sets such that n(A) 32n(B) 28 and n(AUB) 50, then n(An B) will be48 Ans.( |
| Answer» | |
| 5. |
In the given figure, triangles ABC and DCB are right-angled at A and D respectively and AC DB.Prove that AABC ADCB. |
| Answer» | |
| 6. |
In the given figure, triangles ABC and DCB are right-angled at A and D respectively andProve that AABC & ADCB. |
| Answer» | |
| 7. |
13. (a) Solve:2 cos0 = 1 - sin(b) In any AABC, show thatCowc)Rial + babc14. (a) Find the vertex, focus and directrix of the parabola(x + 8)2 = 24 (y - 31).(b) Find the equation of the cllipse which passes through thepoints (-2,1) and (-1,3) with axes as coordinate ages. |
|
Answer» mujhe answer pta nhi |
|
| 8. |
ng appropriate properties find. |
| Answer» | |
| 9. |
Prove the follouwingSec A) an |
| Answer» | |
| 10. |
sECTTON AQuestions number 1 to 6 carry 1 mark each.Q1. In AABC, 4B -90° and BD 1 AC. If DC-7 cm and AD -3 cm then find the length of[Ans. BD 21 cm [Hint: Solve by using pythagoras theorem |
| Answer» | |
| 11. |
0.4. Solve the following : (Any 3)In AABC, Ray BD bisects ZABC and Ray CE bisects ZACB.If seg AB1.seg AC, then prove that EDII BC. |
| Answer» | |
| 12. |
CDA(AABC)A (ABCDQ2 (B) Solve the following questions. (Any Twol)AB 1Find(1)In the adisining figure for the right angled triangles ABC and RCD, |
| Answer» | |
| 13. |
o. Meena has a basket of fruits.Shehas40mangoesand20apples.whatIsthepercentage of fruits of each type ? |
| Answer» | |
| 14. |
16. AABC ~ΔDEF. Area of AABC64Cm2 and area of ADEP-121 cmBC.ORIn 'AABC, DE 1 BC, AD = x+1, DB = x-1, AE = x+3 and CE-x. find x.12 |
|
Answer» Like if you find it useful |
|
| 15. |
find 10 percent of 230 |
| Answer» | |
| 16. |
20)Construct a pair of tangents to a circle of radius 5cm which$0 Dual Rear CameraVivo V9clined to each other at an angle of 60° |
| Answer» | |
| 17. |
A fammer buys used tractor for Rs 12000. He pays Rs 6000 cash and agreespay the balance in annual instalments of Rs 500 pluy12% interest on themount. How much will the tractor cost him? 04 |
|
Answer» thanks |
|
| 18. |
122+223++11°(n + 1)MTI27. A farmer buys a used tractor for Rs 12000. He pays Rs 6000 cash and agrees topay the balance in annual instalments of Rs 500 plus 12% interest on the unpaidamount. How much will the tractor cost him?mHansRs 400 cash and agrees to |
| Answer» | |
| 19. |
A farmer buys a used tractor for Rs 12000. He pays Rs 6000 cash and agreepay the balance in annual instalments of Rs 500 plus 12% interest on theamount. How much will the tractor cost him? 04 |
|
Answer» tanks |
|
| 20. |
2f. Afarmer buys a used tractor for Rs 12000. He pays Rs 6000 cash and adpay the balance in annual instalments of Rs 500 plus 12% interest on theamount. How much will the tractor cost him?npaid28. Shamshad Ali buys a scooter for Rs 22000 He as P 400 |
|
Answer» by the way I had asked Q27 |
|
| 21. |
suumita pays to buy the chain. [ Rs 27,1781calculatea dinning table set is Rs 14,500. Discount offered is 10% the Vat Charged ishe s P? Ans : Rs 690 |
|
Answer» Discount = 14500 - 14500*10/100 = 14500-1450 = Rs.13050 Tax = 13050*10/100 =1305 Total = Rs. 14355 thanks for answering |
|
| 22. |
CaRaghav buys a shop for Rs. 1,20,000. He pays half of amount in cash and agrees to pay the balain 1 2 annual instalments of Rs 5000 each. If the rate of interest is 12% and he pays with theinstalments the interest due on the unpaid amount, find the total cost of the shop. |
| Answer» | |
| 23. |
Sakshi had 23 fruits. She ate 15fruits. How many fruits are left? |
| Answer» | |
| 24. |
A vendor soldof fruits to motorists andtostudents. He also soldof the remaining fruits toothers. If the vendor was left with 168 fruits, how manyfruits were sold to students?2016 No.14] |
|
Answer» Just add allSo2/5+1/4= 0.40+0.25= 0.65Now 3/7 of 0.65 = 0.27Now 1-(0.65+0.27)= 0.07So 0.07 = 168 |
|
| 25. |
basket, 40% ofthe fruits are apples and the rest are mangoes. If there are 12 mangoes, how manyfruits are there in the bag?ju |
|
Answer» 40% are apples hence rest 100-40=60% are mangoeshence 60/100*X=12..if X is the total number of fruitshenceX=12*100/60=20 fruits |
|
| 26. |
6) Out of 230 fruits sold 10 were apples and 31 13)of these were green apples. How manyapples were sold? How many green appleswere sold? How many other fruits were sold?14) |
|
Answer» thanks |
|
| 27. |
pose you have 9999 apples andkes 7189 apples from you. How9999 apples and your sisterfrom you. How many applesdo you have now?JinsA fruit seller has 11078 fruits in his shop. Ifhe sells 3829 apples, 3281 banana and 2569mangoes, then how many fruits are left with |
|
Answer» (1) Number of apples left = 9999 - 7189 = 2810 ANS... ER. RAVI KUMAR ROY (2) Number of fruits left = 11078 - ( 3829+3281+2569) = 1399 ANS.... 11078-3829-3281-2569=1399 9999-8189=180, 11078-3829-3281-2569==6537 koi ek galti karde to sab usi ka copy kar kar ke galat answer hi post karte raho, Kya kahu tum logo ko... 1. 2810 and2. 1399. ans. 1.28102.1399. . 1399 fruits are left 2810 Apple I have 1399. fruits left with fruit seller |
|
| 28. |
seen angie of the triangleIf one angle of a triangle is equal to the sum of the other two, show thatthe triangle is right angled.1 |
| Answer» | |
| 29. |
9. The base and height of a triangle are in the ratio 3:4 and its arca is 96 cm. Find its base and height. |
|
Answer» suppose base is 3x and height is 4x area is 96 cm*cm 1/2*base*height = 96 1/2*3x*4x = 96 6x*x=96 x*x = 16 x = 4 base = 12 cm height = 16 cm |
|
| 30. |
Base of a triangle is 9 and height is 5. Base of another triangle is 10 and heightis 6. Find the ratio of areas of these triangles. |
| Answer» | |
| 31. |
(I) Base of a triangle is 9 and height is 5. Base of anothertriangle is 10 and height is 6. Find the ratio of areas ofthese triangles. |
|
Answer» Given: b1 = 9 ; h1= 5b2=10 ; h2=6Solution:Area = (b*h)/2A1=(9*5)/2=22.5 unit sqA2=(19*6)/2=30 unit sqratio=22.5:30=3:4Therefore the ratio of their areas = 3:4 |
|
| 32. |
1. Base of a triangle is 9 and height is 5. Base of another triangle is 10 and heightis 6. Find the ratio of areas of these triangles. |
|
Answer» Area of triangle with base = 9 and height = 5A1 = 1/2*base*height = 1/2*9*5 = 45/2 Area of triangle with base = 10 and height = 6A2 = 1/2*base*height = 1/2*10*6 = 60/2 Ratio of area of trianglesA1: A2 = 45/2:60/2A1: A2 = 3:4 |
|
| 33. |
1 ^ { 2 } + 2 ^ { 2 } + \ldots \ldots + n ^ { 2 } = \frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } |
| Answer» | |
| 34. |
1+2+3+\ldots \ldots+n=\frac{n(n+1)}{2} |
| Answer» | |
| 35. |
1 ^ { 3 } + 2 ^ { 3 } + 3 ^ { 3 } + \ldots \ldots + n ^ { 3 } = [ \frac { n ( n + 1 ) } { 2 } ] ^ { 2 } |
| Answer» | |
| 36. |
1.3 + 2.4 + \ldots + n ( n + 2 ) = \frac { n ( n + 1 ) ( 2 n + 7 ) } { 6 } |
| Answer» | |
| 37. |
81 ^ { x - 2 } = 27 ^ { x + 1 } |
|
Answer» convert them to same base:81=(3)^427=(3)^3 so,3^[4(x-2)]=3^[3(x+1)]the base is equal so the powers should be equal. 4(x-2)=3(x+1)=>4x-2=3x+3=>4x-3x=3+2=>x=5 (answer) wrong |
|
| 38. |
(c) 120 cm11. A cube of edge 5 cm is cut into cubes, each ofedge 1 cm. The ratio of the total surface area ofone of small cubes to that of the large cube is(a) 1 125 (b) 1:5 (c) 1 625 (d) 1 25 |
| Answer» | |
| 39. |
21. Two cubes of 5 cm each are kept togetherjoining edge to edge to form a cuboid Findthe surface area of the cuboid so formed. |
|
Answer» Side of cube =5cm Length of cuboid=5+5=10cmBreadth=5cmHeight=5cm Surface area=2(lb+bh+hl)=2(10*5+5*5+5*10)=2(50+25+50)=2(125)=250cm² |
|
| 40. |
How many 5 cm cubes can be obtained from a cubewhose edge is 20 cm. |
|
Answer» Total edge = 20Edge of a single cube = 5No. of cubes required = 20/5 = 4 |
|
| 41. |
0. 12. How many balls of diameter 0-5 cmcan be made by melting a cube of edge 11 cm? |
|
Answer» 20328 balls 20328 is correct no. of balls the correct answer is 20328 |
|
| 42. |
An edge of cube is 5 cm. what is the volume of cube? |
|
Answer» good |
|
| 43. |
9.log (1/81) to the base 9 is equal to |
|
Answer» We know that ____________________1) 1 / aⁿ = a ⁽⁻ⁿ⁾ 2 ) log aⁿ = n log a 3 ) logₐ(a) = 1 ___________________ 1/81 = 1 / 9² = 9⁽⁻²⁾ log ( 1 / 81 ) = log [ 9⁽⁻²⁾] = ( -2 ) log₉(9) = -2 |
|
| 44. |
What is the value of (cos2 67-sin2 23°) 2 |
|
Answer» value of (cos^2 67 - sin^2 23) We know,cos(90-x) = sin x Using this identity cos^2 67 - cos^2 (90-23)= cos^2 67 - cos^2 67= 0 I have used © instead of thetasin © = cos 90-©(cos^2 67° - sin^2 23°)butsin ©= cos 90-©sin 23 = cos 90-23therefore sin 23 = cos 67put this value of sin 23 in equationcos^2 67° - cos^2 67 = 0 |
|
| 45. |
a)Use graph paper for this questionThe point (4, 5) is reflected in the origin to get the image Pi) Write down the coordinates of Pii) If M is the foot of the perpendicular from P to the y axis find the coordiili) If N is the foot of the perpendicular from Pl to the y axis find the coordiv) Write the special name of the figure PMP'N |
| Answer» | |
| 46. |
( - \operatorname sin ^ 2 23 ^ \circ ) ? |
|
Answer» Like if you find it useful |
|
| 47. |
\cos ^ { 2 } 67 - \sin ^ { 2 } 23 ^ { \circ } |
| Answer» | |
| 48. |
1+\frac{1}{(1+2)}+\frac{1}{(1+2+3)}+\ldots+\frac{1}{(1+2+3+\ldots n)}=\frac{2 n}{(n+1)} |
| Answer» | |
| 49. |
81 + x 6 + z ^ { x } ( 1 ) |
| Answer» | |
| 50. |
9*81^x=27^(-x %2B 2) |
| Answer» | |