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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
D A wooden anicle was made by wspngout a hemisphere from each end of a silidcylinder, as shown is Fig I311 Ifehright of the cylinder is 10 cm, and ibase is of radius 3.5 om, fiad the lealwrface ares of the article |
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| 2. |
find the area of triangle two sides are 42 cm, 34 cm & 20 cm in length. hence find the height corresponding to the long side |
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Answer» Semiperimeter (s) = (42 + 34 + 20 ) / 2So it is = 96 / 2 = 48 cm. Using herons formula = (√s )(√s-a )(√s-b) (√s-c)By substituting s and a , b , c i.e the given sides.We have√48 ×√6 ×√14 ×√28So √(4 × 6 × 2) ×√6 ×√(7 × 2) ×√(7 × 4)Simplifying the numbers we have area = 4 × 6 × 2 × 7 = 336 cm²Hence area is 336 cm² Now height corresponding to longest side implies that base is 42 cm and area remains same So area of triangle is 1/ 2 b × h336 = 1/ 2 × 42 × HHENCE H = 16 cm |
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| 3. |
-6*longdiv*(x %2B x^3 %2B 4*x^2 - 1) %2B x^2 |
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| 4. |
Find the area of the triangle whose sides are 42 cm, 34 cm and 20 cm in length. Hence, findthe height corresponding to the longest side. |
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| 5. |
the area of a triangle whose sides are 34 cm, 20 cm and 42 cm. Hence, find thelength of the altitude corresponding to the shortest side.3 Find |
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| 6. |
2*(longdiv*(2*x^2 %2B 3*x %2B 1)) %2B x |
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Answer» Quotient is 2x-1 and remainder is 3 (x+2)(2x-1)=2x^2+3x+1 |
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| 7. |
what is the total number of candidates appear in an examination, if 32% isfail and the number of passed candidates are 270 more than the numberof fail candidates?(A) 750(E) of these(B) 750(C) 800(D) 900 |
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| 8. |
12. In a triangle ABC, if AB = AC and AB is produced to D such that BD = BC, findZACD: LADC |
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| 9. |
Find the sum of first 24 terms of the list of numbers whose nth term isa_n = 3 + 2n |
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Answer» Dhanmesh kindly post question separately... not in the reply to any answer. |
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| 10. |
艮lg. 6.43Fig 644, the side QR of Δ PQR is produced toa pornt S If the bisectors of PQR and4 PRS meet at point T. then prove thatlig.6.446.8 SummaryIn this chapter, you have stüdied the loi |
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| 11. |
Q. 18. The sum ofthe 4th and 8th termsof an A.P. is 24 and the sum of the 6th and10th terms is 44. Find the first three termsof the A.P. |
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Answer» 1 2 3 |
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| 12. |
.Ajokerscapisintheformofa right circular cone of base radius 7 om and height24 cm. Find the area of the sheet required to make 10 such caps |
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| 13. |
The largest sphere is curved out of a cube of side 10.5cm. Find the volume of sphere |
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| 14. |
areĂ ol a tap10 cm and its height is 4 cm. Find the length of the oulel pai aner side3. Length of the fence of a trapezium shaped field ABCD is 120 m.lBC-48m, CD 17 m and AD-40 m, find the area of this field. SideAB is perpendicular to the parallel sides AD and BC. |
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| 15. |
Find the area of the largest circle that can be cutof a square board of side 42 cm. |
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Answer» As the side of the square is 42 cmThe diameter is also equal to 42 cmTherefore the radius=42/2=21 cm=> Area= πr^2=22/7×(21)^2=>1386 cm^2 |
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| 16. |
Example 15: Find the sum of first 24 terms of the list of numbers whose nth term isgiven by |
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Answer» The nth term is an=3+2n so by using this we can find the value of terms like a1=5,a2=7,a3=9and a24=51now the first term is 5 and the last term is 51 and the difference is 2by using the formula for sum of n terms i. esn =n/2(2a+(n-1)d)so s24=24/2(10+23*2) i. e 672 ans. |
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| 17. |
le-14. Find the sum of first 24 terms of the list of numbers whose nth term is given bya,-342n |
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| 18. |
If the surn of first n terms of an A.P is given by Sn = 3m2 + 5n, find the nth term ofthe AP |
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Answer» Sn=3n^2+5nTO FIND:nth termwe have to find value of a&d i.efirst term &common difference put n=1S1=3(1)^2+5(1)s1=3+5s1=8putn=2s2=3(2)^2+5(2)s2=12+10s2=22now,a=t1=s1a=t1=8t2=s2-s1=22-8t2=14a=8tn=8+(n-1)14....(substituting value)tn=5+14n-14tn=14n-11As a resultthe nth term is 14n-11 |
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| 19. |
6. In the given figure, ABCD is a quadrilateralin which AB AD and BC DC. Prove that(i) AC bisects A and C, (ii) BE = DE,(ili) ZABC LADC. |
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| 20. |
pai is rational or irrational |
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Answer» pi is an irrational number. |
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| 21. |
0㨠theem A pai20 |
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| 22. |
6. Two sides of a parallelogram are in the ratio 5 : 3·If its perimeter is 64 cm, find the lenof its sides. |
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| 23. |
hecommon base and tde wo pai |
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Answer» Although quadrilateral MNRS and quadrilateral PQRS are on the same base SR but they are not the same parallel |
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| 24. |
therhönbus6. The area of a rhombus is equal to the area of a triangle havingbase 24.8 cm and thehombus is 22 cm, find the16.corresponding height 16.5 cm. If one of the diagonals of the rlength of the other diagonal. |
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| 25. |
Find the area of a parallelogram PQRS, if PR 24 cm and QU ST 8 cm.8 cm8 cm24 cm9 cm |
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Answer» Area of PQRS = Ar(PRS) + Ar(PQR) = 1/2 × PR × ST + 1/2 × UQ × PR = 2 × 1/2 ( 8 × 24) = 192 cm² |
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| 26. |
Compute the area of trapezium PQRS.24 om24 cm24 cm |
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Answer» Find value of RT using pythagoras theoram26x26 = 24x24 + RTxRTRTxRT = 100RT = 10 cmArea of trapezium = 1/2(42+24)10= 1/2x66x10= 33x10= 330 cm |
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| 27. |
Jl eecth side oiand theem. find thecorresponding height 16.5 cm. If one of the diagonals of the rhombus is 22length of the other diagonal16. The area of a rhombus is equal to the area of a triangle having base 248 em |
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| 28. |
3.The sides of a triangle are 16 cm, 12 cm and20 cm. Find:(i) area of the triangle(ii) height of the triangle, corresponding tothe largest side |
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| 29. |
. Prove that the diagonals of a rhombusintersect each other at right angle. |
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| 30. |
EXAMPLE 12term.Ifs,, the sum offirst n terms ofan лљ.ла., is given bys,-5m+3m, thenfinditspICBSE2009 |
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| 31. |
Ifthe sum offirst n terms which are in GPiş a(r+1),then the number of terms isfirst term and r is the common ratio)Where a is the |
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| 32. |
. Construct a parallelogram ABCD, in which diagonal AC 3.8 cm, diagonal BD 4.6 cmand the angle betweenAC and BD is 60° |
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| 33. |
the given figure, ABCD is a quadrilateral-shaped field inwhich diagonal BD is 36 m, AL BD and CM丄BD such thatAL = 19 m and CM-11 m. Find the area of the field.2. In |
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| 34. |
10. In the adjoining figure, ABCD is a quadrilateralin which diagonal BD = 14 cm. If ALL BD andCML BD such that AL = 8 cm and CM = 6 cm,find the area of quad. ABCD |
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| 35. |
Construct a quadrilateral ABCD in which sides A8-4cm, BC = 5 cm,CD = 4.5 cm,AD 5.5 cm and diagonal AC 7.5 cm. Measure diagonal BD. |
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Answer» thank u so much.. |
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| 36. |
2. In the given figure. ABCD is a quadrilateral-shaped field inwhich diagonal BD is 36 m. AL 1 BD and CM BD such thatAL = 19 m and CM = 1 1 m. Find the area of the field.1un.IM |
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| 37. |
1. Construct a quadrilateral ABCD, in which AB -5 cm, BC -4.5 cm, CD-6 cm, AD-3.5 cm anddiagonal BD6.5 cm |
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Answer» ABCD. Is. a. Quadri. AB 5., |
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| 38. |
1. Find the area of a triangle whose base and altitudes are 8cm and 5cm. |
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| 39. |
Construct a parallelogram ABCD in which BC-5 em, CD 3 cm and diagonal BD 6 cm. |
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| 40. |
9. 10% वार्षिक दर से 3 वर्ष के लिए किसी धनराशि के चक्रवृद्धि ब्याज तथा साधारण ब्याज का अन्तर ₹ 620v तो वह धनराशि कितनी होगी? (बैंक पी०ओ० परीक्षा, 2010) |
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Answer» यदि मिश्रित और साधारण ब्याज के बीच का अंतरतीन साल काहै, तोअंतर = 3 x P (R) (/ (100) 100 + P (R / 100) and।यहाँ भी, P = मूल राशि, R = ब्याज की दर Let the sum be Rs.x. then S.I.=(x*10*3 / 100) = 3x/10C.I = [x(1+10/100)^3 -x] = 331x/1000331x/1000 - 3x/10 = 620=> 31x/1000 = 620=> x = 20,000 |
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| 41. |
ABCD is a rhombus whose diagonals intersect at O. If AB 10 cm, diagonal BD 16 cm, then find thelength of other diagonal AC. |
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| 42. |
\cos ^{3} 10^{0}+\cos ^{3} 110^{0}+\cos ^{3} 130^{\circ}=\begin{array}{ll}{\text { A) } \frac{3}{4}} & {\text { B) } \frac{3}{8}}\end{array} B \frac{3 \sqrt{3}}{8} \quad \text { D) } \frac{3 \sqrt{3}}{4} |
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Answer» Cos³ x + Cos ³ ( 120-x )+Cos³ ( 120+ x ) = (3/4)Cos 3x____________________________ According to the problem given , x = 10 , Cos³ 10 + Cos³ 110+Cos³130 = Cos10+ Cos³ (120-10)+ Cos³ (120+10) = ( 3/4) Cos (3×10) = (3/4)Cos30° = (3/4)×(√3/2) = (3√3)/8 |
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| 43. |
The area of a triangle whose base and altitude are 5 cm and 4 cm |
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Answer» answers Area of triangle is 1/2 × base × height1/2 × 5 × 4 = 10 cm |
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| 44. |
\begin{array} { l } { 1,0,3,2,5,6 , ? } \\ { \text { (a) } 9 } \ text { b } 8 \\ { \text { (c) } 10 } & { \text { (d) } 7 } \end{array} |
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Answer» 2 parallel series going1,0,1+2=3,0+2=2,3+2=5,2+4=6,5+2=7so next term is 7 |
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| 45. |
18. Find the area if triangle whose base is 12 cm and height 5 cm. |
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Answer» Like if you find it useful |
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| 46. |
( 6 x ^ { 2 } + 8 x - 9 ) \text { and } ( - 3 + 5 x - 3 x ^ { 2 } ) \text { from } 10 |
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| 47. |
7*longdiv |
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Answer» 158 is the best answer 158 is correct answer this question 158 is the right answer 158 is your right answer. 158 is correct answer The answer is 1106/7=158 158 is the correct answer |
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| 48. |
2*(8*longdiv) |
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Answer» 9 is the right answer 9 is the best answer me Given division is 18 ÷ 2 = 9. 9 is the right answer |
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| 49. |
8*(4*longdiv) |
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Answer» 48.4255319 is the right answer |
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| 50. |
9 \longdiv { 8 1 } |
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