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Let the book contain n pages

Then,As per given condition

4n/9 + 3/5(n - 4n/9) + 100 = n

4n/9 + 3/5 * 5n/9 + 100 = n

n - (4n + 3n)/9 = 100

(9n - 7n)/9 = 100

2n = 9*100

n = 900/2 = 450

Therefore,Book contain 450 pages

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Let the actual price of the TV be Rs. 'x' and of the fridge be Rs. 'y'.

Situation -1

By selling the TV at 5 % gain and fridge at 10 % gain, the shopkeeper gains Rs. 2000.

⇒ 5x/100 +10y/100 = 2000

⇒ x/20 + y/10 = 2000/1

Taking the L.C.M. of the denominator and then solving it, we get.

⇒ (x + 2y)/20 = 2000

⇒ x + 2y = 40000 ...........................(1)

Situation - 2

By selling the TV at 10 % gain and fridge at 5 % loss, the shopkeeper gains Rs. 1500. The loss is indicated with the negative sign.

⇒ 10x/100 - 5y/100 = 1500

⇒ x/10 - y/20 = 1500/1

Taking the L.C.M. of the denominator and then solving it, we get.

⇒ (2x - y)/20 = 1500

⇒ 2x - y = 30000 ........................(2)

Now, multiplying the (1) by 2, and then subtracting 2 from it, we get.

First Multiplying (1) by 2 = 2*[(x + 2y) = 40000]

⇒ 2x + 4y = 80000

Now, subtracting (2) from the above.

2x + 4y = 80000 2x - y = 30000 - + - ________________

5y = 50000__________________

⇒ 5y = 50000

⇒ y = 50000/5

⇒ y = 10000

The actual price of fridge is Rs. 10000.

Now putting the value of y = 10000 in (1), we get.

⇒ x + 2y = 40000

⇒ x + (2*10000) = 40000

⇒ x = 40000 - 20000⇒ x = 20000

Hence, the actual price of TV is Rs. 20000 and actual price of fridge is Rs. 10000.

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(1) irrational(2) rational(4) irrational(5) irrational

1 irrational2 rational3 irration4 irrational

(1) Irrational(2) Rational

(3) Irrational(4) Irrational

1) irrational2) rational3) irrational4) irrational

1. irrational 2. rational 4. irrational 5. irrational

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Given, Length of room = 5.5m, Width of room = 4m,

Width of verandah which is constructed all along outside of room = 2.25m,

Cost of cementing of verandha = Rs 200 per m2

Therefore, Length of room with verandah=5.5m+2.25m+2.25m=10m

Width of room with verandah=4m+2.25m+2.25m=8.5m

Area of room = Length×width=5.5×4=22.0m2

Area of room with verandah = Length×Width=10×8.5=85m2

Area of verandah = Area of room with verandah — Area of room

= 85m2—22m2= 63 m2

Cost of cementing of verandah = Area × RateRs.200×63=Rs.12600

In ∆ABC and ∆ABD, AC = AD (given) <BAC = <BAD ( since AB bisects <A) AB = AB ( common)therefore, ∆ABC ≈ ∆ABD ( SAS) Now, BC = BD (cpct)

2.2 cm = 22 mmVolume of cube = Volume of wire Side³ = πr²L Where L = length of wire

22³ = 22/7 x 1² x L 10648 = 22/7 L

L = 10648 x 7/22

L = 3388 mm OR 3.388 m

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Total surface area of cube=6a²=6(15)²=1350cm²

Total surface area of cuboid=2(lb+bh+hl)=2(150+200+300)=2(650)=1300cm²

Cube has more surface area by 50cm²

thanks sir

Edge of a cubical box [e]= 6 cmVolume of a cubical box [v]= edge *edge*edge = 6 cm*6 cm* 6 cm =216 cubic. cmhalf of the box is filled with sand= divide 216/2=108 cubic. cmso, volume of the sand = 108 cubic. cm

Volume of cube=13824Volume of room=2.4*2.4*2.4=13.824m^3=13824000cm^3So,no.of boxes=13824000/13824=1000Dimension of box=2.4cm

total thickness=4*39=156cmfor 6.5cm thickness156/6.5=24 books

total thickness covered=39*4=156cmhence for 6.5cm thickness156/6.5=24 books

It

will be (0,5) as we know that in coordinates we first keep x and then y, i.e., (x,y). So the point on y-axis will be (0,x) , here we have supposed the point on y-axis as x. As the nearest point is given (-2,5), so the nearest point will be 5 . Thus the answer is (0,5)..

thanks

,

Price of 150 eggs =2.50×150 = 375No. of eggs broken =20Eggs left= 150-20=130Then cost of remaining eggs =130×3=390So profit = SP-CP =390-375 = 25So profit% = Profit/CP × 100 =25/375 ×100 =20/3 - (Answer)

it's not correct

what will be the answer

it's not correct

Please tell me the answer

abhinav see your subtraction is wrong it's 15 then alright

Now answer will be 4%.

Tell me is it right?

Total C.P.=150×2.5=375now 20 were broken so remaining are 130so total S.P.=130×3=390so profit=(390-375)/375×100= 1500/375=4%

Please tell. Me the answer

Space research is scientific study carried out using scientific equipment in outer space. It includes the use of space technology for a broad spectrum of research disciplines, including Earth science, materials science, biology, medicine, and physics

Thetelexnetwork was a public switched network of teleprinters similar to a telephone network, for the purposes of sending text-based messages.

The "telex" term refers to the network, not the teleprinters; point-to-point teleprinter systems had been in use long beforetelexexchanges were built in the 1930s.

2/9 = approximately 0.222...

2/3 = 0.667 ( approx)

8/2 = 4

8/2 > 2/3 > 2/9

In ∆ POS and ∆ROQ

PS = RQ

angle P = angle Q

angle SOP = angle ROQ

By AAS rule ∆POS is congurent ∆QOR

No,all the angles of a quadrilateral cannot beacute angles.

As, sum of theangles of a quadrilateralis 360°.

So, maximum of threeacute angles willbe possible.

Thankyou so much I love this app

the total sum of a triangle is 180° so each side of the ∆ will be 60°.......(60+60+60=180)

if the triangle is equilateral then the angle of the triangle is 60°and the sum of the anles of the triangle is 180°

please like my answer I request you please like

their are two types of triangles one is 30-60-90degree triangle and second is 45-45-90 degree triangle .also measure of each angles of an equilateral triangle is always 60 degree.And Sum of the measure of all angles of A triangle is 180 degree.

the total sum of a triangle is 180° so each side of the ∆ will be 60° .....(60+60+60=180)

the measure of the angle of the triangle is 180

sum of measure of all angles of a triangle is 180°

The sum of 60°....(60+60+60=180) be the answer

It covers 60 km in an hour

60 km is the distance covered by the car in one hour

√(1+27/196) = 1+x/13

=> x/13 +1 = √223/14=> x/13 = √223/14 -1 => x = 13(√223/14) -13 => x = 0.866 = √3/2.

speed of the car is 157.5/2.5 = 63 km/h

Total no. of students=40No. of students preferring parathas=15Therefore, percentage of atudenta that prefer parathas=(15/40)×100=(3/8)×100=3×12.5=37.5%

Area of slate = 35*20 = 700 cm^2Area of outer region = (35+5)*(20+5) = 40*25 = 1000 cm^2

Area of wooden frame = 1000-700 = 300 cm^2

speed =distance / time=48/10=4.8

wrong ans.

Since, the height of a sphere is the diameter, the cone and cylinder have height 2r.

ThenCurved surface area of Sphere= 4πr²

Curved surface area of cylinder = 2πr(2r) = 4πr²

Curved surface area of cone = πrl

where, l = √(r2+ h2) = √( r2+ (2r)2) = √(5r2) = r√5

⇒ Curved surface area of cone = π√5r2

Now,

Ratio of CSA 'sa sphere ,cylinder and a cone = 4πr2:2πrh : πrl

= 4πr2:4πr2: πr2√5

= 4 : 4 : √5