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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
-3/4p=24 |
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Answer» -3/4p = 244p = -3/244p = -1/8p = -1/32 |
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| 2. |
4p^2-9^2 |
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Answer» (2p)^2- (3q)^2(2p+3q)(2p-3q)by applying a^2-b^2= (a+b) (a-b) |
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| 3. |
1) Find the sum of following polynomials.A) 2p3+q3-14pq-2q and -p3-10q3+9p2q+2pq-12p+12q-18 |
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| 4. |
(12p-(42-(30p) |
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Answer» correct answer is p = 1 |
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| 5. |
3. A klogram of apples cost 16 1/4 Watis the cost of 3 1/5kg of apples? |
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Answer» Cost of 1 kg apple is ₹ 65/4Cost of 16/5 kg apple is ₹ (65/4) × (16/5)= ₹52 |
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| 6. |
8344Apples are sold at 48per kg What is the cost of 3 kg of apples?3 |
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Answer» Cost of 1kg=(48*5+4)/5=240/5=48RsCost of 15/4kg=48*15/4=180Rs |
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| 7. |
5. The cost of 3/4 kg apples is Rs130. Find the costof 1 kg apples. |
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Answer» aw3some |
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| 8. |
The cost of5 oranges and 3 apples is Rs. 30 and the cost of 2 orangesof an orange and an apple.and4applesisRs.26.Findthecost |
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Answer» let cost of one orange=x cost of one apple=y so, according to question, 5x+3y=30...............(1) second equation: 2x+4y=26 2x=26-4y x=13-2yput the value of x in equation 1.so , >> 5(13-2y)+3y=30 >> 65-10y+3y=30 >> 7y=35 >> y=5 so, x=13-10=3 so, x=3 and y=5 cost of one orange= rs.3 cost of apple= rs.5 |
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| 9. |
3p®+4p-5-6p° +2p’ -8p-2+6p |
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| 10. |
1. Apples are sold at 2 48 per kg What is the cost of 3 kg of apples? |
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| 11. |
Draw the graphs for the following tables of values, with suitable scales on the axes(a) Cost of applesNumber of apples 1 2 3 4 5 Cost (in Rs ) 5 10 15 20 25 |
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| 12. |
p^2+8p+ 16 |
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Answer» p² + 8p + 16 p² + 2 ×(4p) + 4²(p+4)² |
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| 13. |
3. The cost of 2 kg of apples and lkg of grapes on a day was found to beR 160. Afiemonth, the cost of 4 kg of apples and 2 kg of grapes is 300. Represent the sialgebraically and geometrically. |
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| 14. |
(8p® - 4p?) न थीं |
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Answer» 8p^3-4p^2 = 2p^2( 4p-2) So dividing by 2p^2= 4p-2 |
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| 15. |
the HCF of two number is 1 upon 5 of their LCM is the product of the two number is 720 find the LCM |
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Answer» HCF * LCM = Product of two numbers(1/5) * LCM = 720 LCM = 720*5 = 3600 |
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| 16. |
(c) Subtract 4p'q -3pg 5pa - 8p + 7q - 10 from |
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Answer» (18 - 3p - 11q + 5pq - 2pq^2 + 5p^2q)- (4p^2q - 3pq + 5pq^2 - 8p + 7q - 10)= (5-4)p^2q + (-2-5)pq^2 + (-3+8)p +(-11-7)q + (18+10)= p^2q - 7pq^2 + 5p - 17q + 28 ans |
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| 17. |
express -5 upon 98 as a rational numbers with denominator |
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Answer» -3/7 is the correct answer of the given question -3/7 is the correct answer |
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| 18. |
9.Factorise: 8p12p q+ 6pq |
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| 19. |
5upon 10=x upon 15 |
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Answer» 5/10= x/150.5= x/1515*0.5= x= 7.5please like the solution 👍 ✔️ |
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| 20. |
4213/3125 |
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Answer» 1.34816 is correct answer 1.34816 is the correct answer by me 1.34816 is correct answer |
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| 21. |
5^x=3125 |
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Answer» if 5^5=3125 then 5^(5-3=2) = 125 Given:5^x=31255^x=5^5Since base are equal x=5now 5^(x-3)= 5^(5-3)=5²=25 |
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| 22. |
\frac { 13 } { 3125 } |
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| 23. |
37. If Red part in the following pie chartis 40, what is White part?YellowBlue8White4Red82(1) 2010(2) 5(4) 12 |
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| 24. |
4x upon 5 = 12 |
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Answer» 4x/5 =12 4x=12×5 x=60/4x=15 4x = 12×54x = 60x = 60/4=15/1x= 15/1 |
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| 25. |
Find the equation of the straight line upon which the length of the perpendicularfrom the origin is 2 and the slope of this perpendicular is12 |
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| 26. |
multi inverse of 1 upon 10 |
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Answer» 1/10* 10= 1 so it will be the answer to that question |
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| 27. |
cos (taninverse x)=sin(cot inverse 3/4) |
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Answer» cos(tan⁻¹x)=sin(cot⁻¹3/4)Let, cot⁻¹(3/4)=yor, coty=3/4(=perpendicular/base)Using Pythagorus's theorem,hypotenuse=√(p²+b²)=√(3²+4²)=√25=5∴, siny(=p/h)=3/5∴, sin(cot⁻¹3/4)=siny=3/5cos(tan⁻¹x)=3/5or, tan⁻¹x=cos⁻¹(3/5) let, cos⁻¹(3/5)=zor, cosz=3/5=base/hypotenuse∴, perpendicular=√5²-3²=√16=4∴, tanz=p/b=4/3∴, tan⁻¹x=zor, x=tanzor, x=4/3 |
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| 28. |
find the discriminant of the equation 3 x square - 2 X + 1 upon 3 equal to zero and hence find the nature of its roots |
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Answer» 3X^2 - 2X + 1/3 = 0Discriminant = b^2 - 4acIn given equationb = - 2, a = 3, c = 1/3 Then,Discriminant = - 2*-2 - 4*3*1/3 = 4 - 4 = 0 Since discriminant is 0 roots are equal |
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| 29. |
13/3125 |
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Answer» correct answer is 0.00416 0.00416 is correct answer 0.00416 is the correct answer of the followingso, please accept me as best. |
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| 30. |
133125write the decimal expansion of the rational number |
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Answer» Solution:-3125 = 5*5*5*5*5 = 5⁵13/3125= 13/5⁵= (13*2⁵)/(5⁵*2⁵) {Multiplying the numerator as well as the denominator with 2⁵}= (13*32)/(10⁵)= 416/10⁵= 0.00416 |
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| 31. |
\frac 13 3125 |
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Answer» iska answer ye h 13 ÷ 3125 = 0.00416 |
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| 32. |
8 A tano = T7l & cosec” § —sec’ ©T cosec” 8 + sec’ § |
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| 33. |
6. sec 30+sec 45° +sec 60cosec30°+ cosec 450 + cosec 60 |
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| 34. |
write the multiplicative inverse of -12 upon 9 |
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Answer» -12/9 is the given fractionit's multiplicative inverse will be -9/12 |
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| 35. |
if tan theta is equal to 1 by root 3 find the value of sin theta + cos theta upon sin theta minus cos theta |
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| 36. |
(1) 1217(2) 3125(3) 13\begin{array}{l}{\frac{12}{625}} \\ {\frac{9}{1600}}\end{array} |
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Answer» 42/52=21/26=0.807726/65=2/5=0.4 |
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| 37. |
150 50 50 £ 50 0 5 50 50 50 Solved छिदाृ। €५ (२८२२८२२०२८२८२२८०२७३Find the distance between the points P(-1, 1) and Q (5,-7 )S शा 2 2 ew e R |
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| 38. |
Some More Important Ce down the decimal expansion13312517nal number in Q(ii)6 3515 /() 50 which have terminating |
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Answer» 13/3125=0.0099217/8=2.125 |
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| 39. |
13312517.Write the decimal expansion of the rational number |
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Answer» Solution:-3125 = 5*5*5*5*5 = 5⁵13/3125= 13/5⁵= (13*2⁵)/(5⁵*2⁵) {Multiplying the numerator as well as the denominator with 2⁵}= (13*32)/(10⁵)= 416/10⁵= 0.00416 |
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| 40. |
\frac { \sin 50 ^ { \circ } } { \cos 40 ^ { \circ } } + \frac { \csc 40 ^ { \circ } } { \sec 50 ^ { \circ } } - 4 \cos 50 ^ { \circ } \csc 40 ^ { \circ } |
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Answer» Thanks brother Thanks |
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| 41. |
(40^circ*cosec)/sec(50^circ) %2B sin(50^circ)/cos(40^circ) - 4*cos(50^circ*(40^circ*cosec)) |
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Answer» -2 the correct answer of the given question -2 is the correct answer -2 is the right answer |
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| 42. |
50+50 |
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Answer» 100 in question of answer the answer is hundred(100) the answer of your question is 100 |
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| 43. |
. A particle completes 40 vibrations within 2.5seconds. Calculate its frequency? |
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| 44. |
8. A man sold an article for 6270 and lostof the cost price. Find the cost price.21 |
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| 45. |
8sin x - cos xdx21-2 sin x cos* x2 |
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| 46. |
int (a sin (x) +b cos (x) ) /(c cos (x) + dsin (x) ) dx |
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| 47. |
dx*Integral((2*sin(x) %2B 3*cos(x) %2B 4)/(3*sin(x) %2B 4*cos(x) %2B 5), x) |
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| 48. |
Aditya and Manav purchased one scooter each for the same price. Aditya sold itlostor 18,400 and8%. At what price should Manav sell it to have a profit of 6%? |
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| 49. |
Exercise 3.21. Use 'ODMAS' rule to simplify the folloa. 80- of 70 + 40 = 4 - 3 x 6 |
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Answer» =80-7+10-18=90-25=65is the correct answer |
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| 50. |
0. Aditya and Manav purchased one scooter each for the same price. Adtya sold it for Rs 18400 andlost 8%. At what price should Manav sell it to have a profit of 6%? |
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Answer» Price of scooter = CP CP =[100 / (100 – Loss %)] * SP= (100/92)*18400= 20,000 Required Profit % = 6% Therefore, 6 = (profit/CP) *100 Profit = (6*20000)/100 = 1200 Then SP for Manav = CP + Profit = 21200 |
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