This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
that he should beas to form a triangular plot. Explain Hou(s)ezium with AB I DC. A line parallel to AC intersectnca,13/ ABCD is awat Y. Prove that ar (ADX)ar (ACY)BC.you3. In Fig. sar (ADE)4.In Fig. 9 |
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| 2. |
4. The circumference of circular pond is 396 m. What is its area?5. The diameter of a wheel is 98 cm. In how many revolutions will it cover a distance of 1540 m? |
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Answer» 4) Circumference = 396 = 2*pie*r 396 = 2×22×r/7 r = 63 area = pie*r*r = 22*63*63/7 = 12474 m*m 5) Diameter = 98cm Circumference = pie*d = 22*98/7 = 308 cm = 3.08m Number of revolution to cover 1540 m = 1540/3.08 = 500 If you find this answer helpful then like it. OK |
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| 3. |
000 in a bank for 3 years at the rate of 8 p.c.p.a. at compound interest. What amount willSuhas receive from the bank at the end of the term. |
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| 4. |
as to form a triangular plt. EXplonABCD is a trapezium with AB DC. A line parallel to AC intersects AB at X and BCat Y. Prove that ar (ADX)- ar (ACY). |
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| 5. |
If a : b = 2: 3 and b:c= 4: 5; find a : b?:bc.(1) 4:9:45 (2) 16:36:45(3) 16:36:20 (4) 4:36:20 |
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Answer» 4) is the correct answer 16:36:45 (cross multiply the given product ) |
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| 6. |
4. Eind the value of k, ifr: 2, y-1 is a solution of the equation 2r + 3Ń.k. |
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Answer» 2x + 3y = k2x2 + 3x1 = k4 + 3 = kk = 7 |
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| 7. |
Find l.c.m of x^2-4 and x^2-16 |
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Answer» x²-4 and x²-16Lcm of( x-2)(x+2 and (x+ 4) (x-4)Lcm =(x²-4)(x²-16) |
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| 8. |
Example 16 : Find the discriminant of the quadratic equation 2x2-4x + 3 = 0, andhence find the nature of its rootshere (1-2 h =-4 and |
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Answer» Like if you find it useful |
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| 9. |
Find the value of k, if x= 2,y= 1 is a solution of the equation 2x + 3y= k |
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Answer» 2(2)+3(1) = k k = 4+3 k = 7 |
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| 10. |
4. Find the value of k, ifx-2,y-l is a solution of the equation 2x + 3y k |
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| 11. |
g. Find the value of k, if -2,y-1 is a solution of the equation 2x+3y-kFabrenheit to Celsius |
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Answer» putting x = 2 , y = 1 in the equation => 2(2)+3(1) = k=> 4+3 = k=> k = 7 k =7 is the answer to your question x=2,y=12x+3y=k2(2)+3(1)=k4+3=kk=7 |
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| 12. |
14. Find the value of k, if x=2 and y =2 is a solution of the equation x + 3y =k/2 |
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| 13. |
18. Find the amount that Dravid would receive if he invests8,192 for 18 months at122% per annum, the interest being compounded half-yearly. |
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| 14. |
59°sin 31°13. सिद्ध कीजिए कि-- 25 70°2, 6 —Sin 24 ~8 cos® 60°=0 |
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Answer» Sin(90°-α) = cosαcos(90°-α) = sinα so,cos70°/sin20° + cos59°/sin31° -8 sin²30°=[cos(90°-20)]/sin20° + [cos(90°-31°)]/sin31° - 8×(1/2)²=sin20°/sin20° + sin31°/sin31° - 2= 1+1- 2= 0 |
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| 15. |
789×987+123456 |
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Answer» the answer is (according to bodmas rule) 902,199 |
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| 16. |
Write as a decimal-71, 84%6.81 %9.6%2.99%6, 100%10.9%3.70%7, 13%11, 3964.58%8. 67%12.5% |
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Answer» 1).84 2).99 3).70 4).585).81 6) 1 7).13 8).679).06 10).09 11).03 12).05 |
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| 17. |
(f) 987 x 1,000 |
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Answer» (f) 987×1000=987000 |
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| 18. |
(987-43+25)-10[5+{(999÷9×3)+(8×9÷6)4}] |
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Answer» According to BODMAS, (969)-10[5+{(111*3)+(8*1.5)4}] = (969)-10[5+{(333)+(12)4}] = (969)-10[5+{333+48}] = (969)-10[5+381] = (969)-10[386] = 969-3860 = -2891 |
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| 19. |
1. Find the next term of the A.P. 7,28, 63987 |
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| 20. |
99879*67÷89+77= |
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| 21. |
s teby a protractor:Find the value of k. if r-5,y 2 is a solution of the equation 2r 3y k |
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Answer» For 2x + 3y = kGiven x = 5, y = - 2 Then,2*5 + 3*-2 = kk = 10-6 = 4 Value of k is 4 |
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| 22. |
A bag contains 15 balls, out of which some are white and the otherblack. If the probability of drawing a black ball at random from the- then find how many white balls are there in the bag. |
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Answer» No Of Balls = 15No Of Blue Balls = xNo Of Red Balls = 15 - xProbability of taking a red ball is; P(E) = 15 - x15 After 5 red balls are added,No of balls = 15 + 5 = 20No of blue balls = xNo of Red Balls = (15 - x) + 5 = 20 - xProbability of taking a red ball is; P(E) = 20 - x20 According to your question, 15 - x x 2 = 20 - x15 20 30 - 2x = 20 - x15 20 600 - 40 x = 300 - 15 x 300 =25 xx = 12 |
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| 23. |
The heights (in cm) of 20 ditterent types of plants in a house are given below:Height (in em)Number of plants59606265702an |
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| 24. |
-45 +-67 |
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Answer» -45+(-67)=-45-67=-112 is the value -45+(-67) = -45-67 = -112. |
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| 25. |
67+45×98 |
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Answer» 4477 is right answer 4477 is correct answer The right ans is 4477 4477it is right answer 6 7 + 4 5 x 98=67+4410=4477 4477 is the correct answer 67+45×98=4477 is correct answer 4477 is the right answer 67+45×9876+44104476 67+45×98=4477 is the result 4477 is A correct answer. 4477 is the right answer 4477 is the right answer. |
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| 26. |
ABCD is a trapezium in which AB I DC, BD is a diagonal and E is the mid-point of ADA line is drawn through E parallel to AB intersecting BC at F (see Fig. 8.30). Show thatF is the mid-point of BC·Er |
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| 27. |
9. 45 -6710.-13+-4 |
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Answer» -13+(-4)=-13-4=-17(-)*(-)= add with (-) sign |
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| 28. |
m cm67 4532 23 |
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Answer» 35 22
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| 29. |
Date :Page :67879135 |
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Answer» 1713 is the answer of the following 1613 is the right answer 678+935=16131613 is correct answer. 1613..........is answer 1613 is the correct answer 1613 is the correct answerthe right answer 1613 is the correct answer 161 4 is correct answer =1613 is right answer |
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| 30. |
345+678+987 |
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Answer» 345+678+9871023+9872010 |
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| 31. |
6. What number must be taken away from the sum of 67 89 678 and 1234 567 to make itequal to the difference of the given numbers? |
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Answer» Sum of 6789678+1234567=8024245Diffrence=6789678-1234567=5555111So 8024245-5555111=24689134 should be taken out from sum of both nmbr to make equal to diffrence of both |
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| 32. |
. Solve 2r +3y 11 and 2r -4y24 and hence find the value of 'm for whichy mx+3. |
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| 33. |
60% of 54 students are good in drawing how many are not good in in in drawing |
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Answer» % students not good at drawing is 100%-60% = 40% now 40% of 54 = 0.4*54 = 21.6 ≈ 22 students thank u |
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| 34. |
2. Solve 2r 3y-11 and 2r-4y24 and hence find the value of 'm' for whichmr +3 |
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| 35. |
Each letter in the word "MATH" is written on a cad and put into a bag. What is the probability of drawing the "A," keeping it (not replacing), and then drawing the "H" ? |
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Answer» Probability = possible outcomes/ Total outcomes For drawing APossible outcomes = 1Total outcomes = 4Probability = 1/4 For drawing HPossible outcomes = 1Total outcomes = 3Probability = 1/3 Probability of drawing A and then without replacing A drawing H= 1/4*1/3 = 1/12 |
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| 36. |
234/5 |
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Answer» 234/5 = 46.8 |
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| 37. |
2. A bag contains 15 white and some black balls. If the probability of drawing a black ball from the bag isthrice that of drawing a white ball, find the number of black balls in the bag. |
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| 38. |
ued 1s theepointSeli |
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Answer» kya sahi hi I am not sure...TM phir se post kro..yha p bht experts h..koi na koi answer de dega |
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| 39. |
1 In the given figure, / IIp, m I1 q and lines / and m are intersecting lines. Prove that lines p and cq |
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| 40. |
e mid point 4haorem |
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| 41. |
19/234 |
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Answer» The value of 19/234 is 0.08. with step by step method please |
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| 42. |
d the valueís) of k so that the pair of equations x + 2y 5 and+ ky + 15-0 has a unique solution. |
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Answer» X + 2y - 5 = 0 ----------(1){a=1,b=2,c=-5}3x + ky - 15 = 0 ----------(2){x=3,y=k,c=-15}Unique solution.a/x is not equal to b/y=> 1/3 is not equal to 2/k=> k is not equal to 6.No solutiona/x = b/y is not = c/z=> 1/3 = 2/k=> k = 6 |
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| 43. |
123×234 |
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Answer» Multiply=123×234=28782 |
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| 44. |
Find k so that equation has unique solution x-2y=2,3x+ky=(-5) |
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Answer» x-2y=2,3x+ky=(-5) to have a unique solution, they should meet at a single point a1/a2 should not be equal to b1/b2 ==> 1/3 =/ -2/k ==> k should not be equal to -6 how k is not equal to the -6 |
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| 45. |
234+678 |
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Answer» the correct answer is912 |
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| 46. |
-234(45)-67= |
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Answer» -234(45)-67= -10530-67= - 10597 |
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| 47. |
olve 2x + 3y = 1 1 and 2x-4y =ー24 and hence find the value of"m for whichymx+3.nrohlems and find their solution by |
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Answer» 2x+3y=112x-4y=-24(1)-(2)7y=35y=5 put in 12x+3(5)=112x +15=112x =-4x=-2 y=mx+35=-2m+32=-2mm=-1 |
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| 48. |
2. Solve 2r 3y 11 and 2r - 4y24 and hence find the value of m for whichymx 3. |
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| 49. |
2. Solve 2x+3y - 11 and 2x 4y24 and hence find the value of 'm' for whichymx+3.fontho folowin rohlems and find their solution by |
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Answer» 2x+3y=112x-4y=-24Subtract equations7y=35; y=52x=11-3y; 2x=11-15; 2x=-4; x=-2y=mx+35=m(-2)+35-3=-2m2=-2mm=-1 |
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| 50. |
2. Solve 2x + 3y = 11 and 2x-4y =-24 and hence find the value of 'm' for whichymx+3.ho follouring roblams and find their solution |
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Answer» 2x + 3y = 11 2x - 4y = -24 2x + 3y - 2x + 4y = 11 + 24 7y = 35 y = 5 2x + 15 = 11 2x = -4 x = -2 y = mx + 3 5 = -2m + 3 -2m = 2 m = -1 If you find this answer helpful then like it. |
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