This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
In Fig. 1, P QzΔΧΥΖ is 32 cm2, then find the area of thequadrilateral PYZQ교 :=3, if the area ofPYQZ |
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| 2. |
Simplify:48 + [25 -{20-(11-16+ 2 x 4)}]=?(A) 40(C) 62(B) 32(D) 58 |
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| 3. |
A = \left[ \begin{array} { l l l } { 0 } & { 1 } & { 2 } \\ { 1 } & { 2 } & { 3 } \\ { 3 } & { 1 } & { 1 } \end{array} \right] |
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| 4. |
find medians of 31 ,48 ,51 ,25 32, 9 ,33 |
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Answer» 9, 25, 31, 32, 33, 48, 5132 is the median no this is not possible how do this? this is wrong |
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| 5. |
(45/16)^3*((6/15)^3/(25/32)^2) |
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Answer» the answer would be 1458/625 the answer is 1458/625 the correct answer is 1458/625 |
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| 6. |
1. ABCD is a quadrilateral in which P. Q, R and S aremid-points of the sides AB. BC, CD and DA(see Fig 8.29). AC is a diagonal. Show that:0 SR IIAC and SRAC(ii) PQ = SR(ii) PQRS is a parallelogram.Fig. 8.29 |
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| 7. |
1. ABCD is a quadrilateral in which P, Q, R and S aremid-points of the sides AB, BC, CD and DA(see Fig 8.29). AC is a diagonal. Show that:SR AC and SRAC(ii) PQ=SR(i) PQRS is a parallelogram.Fig. 8.29 |
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| 8. |
ABCD is a quadrilateral in which P, Q, R and S aremid-points of the sides AB, BC, CD and DA(see Fig 8.29). AC is a diagonal. Show that:1."(i)SRI AC and SR =-AC(ii) PQ SR(ii) PQRS is a parallelogram.Fig. 8.29 |
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| 9. |
\cos 6 x = 32 \cos ^ { 6 } x - 48 \cos ^ { 4 } x + 18 \cos ^ { 2 } x - 1 |
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Answer» cos6x=cos[2(3x)]=2cos^2(3x)-1 cos2x=2cos^2x-1 =2[cos(3x)]^2-1 cos3x=4cos^3x-3cosx =2[4cos^3x-3cosx]^2-1 (a-b)^2=a^2+b^2-2ab =2[16cos^6x+9cos^2x-24cos^4x]-1 =32cos^6x-48cos^4x+18cos^2x-1 |
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| 10. |
38. In given fig, AB | CD, Prove that p+q-r 180° |
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Answer» extend the line EF and let it meet CD at Hthen in triangle FGH<FHG=180-p<GFH=180-q<FGH=rsum of angles in triangle is 180so,<FHG+<GFH+<FGH=180180-p+180-q+r=180p+q-r=180 |
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| 11. |
5. Write postulate of playfair and explain it. |
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Answer» The playfair axiom states that In a plane, given a line and a point not on it, at most one line parallel to the given line can be drawn through the point. |
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| 12. |
What is an axiom? Give an example |
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Answer» Axioms or Postulate is defined as a statement that is accepted as true and correct.Ex : Examples of axioms can be 2+2=4, 3 x 3=4 etc. In geometry, we have a similar statement that a line can extend to infinity. This is an Axiom because you do not need a proof to state its truth as it is evident in itself. |
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| 13. |
State play fair's axiom |
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| 14. |
Why straight angle id 180Is it prove or axiom |
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Answer» start with the 90 degree right angle JKL. If we continue to bend JK all the way down to a straight line, that would be twice of 90, or 180. Continue bending JK all the way back to KL, and you have a complete circle, 360 degrees. Now, why is there such an odd number as 360 degrees in a circle? Basically, because it was observed thousands of years ago (about 2400 BC) that it takes 360 days for the Sun to make one complete yearly cycle. A thousand years later, the Egyptians divided each day into 24 hours, and another thousand or so years later the Babylonians subdivided the hour into 60 minutes and the minutes into 60 seconds. Obviously we know now that it actually takes 365 1/4 days for the earth to revolve around the sun. But I'm perfectly happy without 365 1/4 degrees in a circle. |
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| 15. |
D) 212ne graph of y=p(x) is given for some polynomial p(x). The no. of Zeroes ofp(x) in givenfig isU. Tâ˛Yxl5A) 3B) 4C) 1D) 0 |
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Answer» As this graph is cutting the x axis 4 times so 4 zeroes are there |
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| 16. |
EXERCISE 2.1l. The graphs of y =p(x) in Fignumber of zeroes of p(x), in each case.are given in Fig. 2.10 below, for some polynomials p(x). Find the(iii)(iv)IV(vi) |
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| 17. |
6. (i) Calculate the area of quad. ABCD, given in Fig. (i).(ii) Calculate the area of trap. PQRS, given in Fig. (ii).S 8 cm17 cmP 8 cmT 8 cm |
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| 18. |
4. In Fig. 6.17, if x +y w+, then prove that POQ is a line.Fig. 6.175.In Fig. 6.18, POQ is a line. Ray OR is perpendicular to line PQ.OS is another ray lying between rays OP and OR. Prove thatFig. 6.18It is given that LXYZ = 64° and XY is produced to point P. Drawa figure from the given information. If ray YQ bisects ZZYP, findZXYQ and reflex ZQYPIf OP bisects LB0C and 0Q <AOC, show that LP0Q-90°. In thegiven Fig. 6.197.Fig. 6.19 |
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Answer» Which question? 4 Given : x + y = w + zTo prove : POQ is a line.Proof : We know that;x + y + w + z = 360०then, x + y + x + y = 360०(given)2x + 2y =360०2 (x + y) =360०x + y = 180०(linear pair)Therefore, POQ is a line. Hence, Proved! 4&5 solve |
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| 19. |
Fig. 6.16In Fig. 6.17, POQ is a line. Ray OR is perpendicularto line PQ. OS is another ray lying between raysOP and OR. Prove thatIt is given that XYZ = 64° and XY is producedto point P. Draw a figure from the given |
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| 20. |
19. In Fig. 3. given,3. If the area of AXYZ is 32cm2, then find the area of the quadrilateralP QZPYZQFig. 3d at 0and R |
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| 21. |
How much pure alcohol must be added to 400 mL of a 15% solution to make itsstrength 32%? |
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Answer» इघूरा अघूरा जवाव |
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| 22. |
35. How much pure alcohol must be added to 400 mL of a 15% solution to make itsstrength 32%? |
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| 23. |
25. Apharmacist needs to strengthen a 15% alcohol solution to one of 32% alcohol. Howmuch pure alcohol should be added to 800 m of 15% Solution? |
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| 24. |
what is axiom |
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Answer» An axiom or postulate is a statement that is taken to be true, to serve as a premise or starting point for further reasoning and arguments. The word comes from the Greek axíōma 'that which is thought worthy or fit' or 'that which commends itself as evident. |
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| 25. |
State "PLAYFAIR" axiom. |
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Answer» In geometry,Playfair's axiomis anaxiomthat can be used instead of the fifth postulate of Euclid (the parallel postulate): In a plane, given a line and a point not on it, at most one line parallel to the given line can be drawn through the point. |
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| 26. |
State corresponding angle Axiom ? |
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Answer» TheCorresponding AnglesPostulatestatesthat, when two parallel lines are cut by a transversal , the resultingcorresponding anglesare congruent . The converse is also true; that is, if two lines and are cut by a transversal in such a way that thecorresponding anglesformed are congruent , then l ∥ m . |
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| 27. |
the compound interest of 18000 at ayears. Findrate of 10% per annum for a period of 1when interest is added half yearly?2 |
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| 28. |
| Anjali can complete a job in 10 daysBany can do it in 5 days. In howI days can the job be done it theywork together?many |
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| 29. |
14 How much pure alcohol be added to 400 ml of a 15% solution to make itsstrength 32%? |
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| 30. |
If cos θ _ sin θV2 sin θ .then cos θ + sin θ |
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| 31. |
if (cosθ + sin θ)v 2 cos θ, show that (cose-sin θ)-V2 sin θ |
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| 32. |
. .0(1) 70How much pure alcohol be added to 400 ml of a 15% solution to make it's strength 32%:(1) 190...1 |
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| 33. |
A 60-litre solution of alcohol and water contains 20 litres of alcohol. How much alcohol must be addedto produce a solution of 50% alcohol? |
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| 34. |
20. If cos θ + sin θ = V2 cos θ, prove that cos θ-sin θ2 sin θ. |
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| 35. |
5X5t 2-14รท901 t 4000 x 1 |
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Answer» (5×5)+2-(14÷901)+(4000×1)=25+2-(0.0155)+4000=4026.98 good |
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| 36. |
A 60-litre solution of alcohol and water contains 20 litres of alcohol. How much alcohol must be addedto produce a solution of 50% alcohol?100 ton of |
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Answer» Suppose we need to add X litres of alcohol to the solution. So, overall quantity of alcohol = X + 20 litres. But adding the alcohol increases volume of the solution also.So, total volume of solution = 60 + X So, we have the following equation: X+20/(X+60) = 50/100=> 2X + 40 = X + 60=> X = 20 LTherefore, to get a solution of 50% alcohol, we need to add 20 L of alcohol. 20 l of alcohol is needed to get 50% solutions 20l of alcohol........ 20 litre is right answer.... |
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| 37. |
Using Field axiom, prove the following:1. -(-a) a, a E F |
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| 38. |
) Principal4000, Rate of interest 85% and period2*1/2 years |
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| 39. |
In the given Fig. (f), DEF is a straight line. What is the value of y?The word POLYGreekA 128135° |
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| 40. |
\int \frac { x ^ { 3 } + 3 } { x ^ { 3 } - 3 x } d x |
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| 41. |
oo) Find the degree of the poly nomials given below:(iii)Il1 0 |
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Answer» 1) 52)83)04)n5)5(since it is 2+3) thanks but can it be done with method U need to find highest power term in an expressionIf the term contains more than one variable u need to add their powers to get their degree(like in 5th part) |
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| 42. |
2ĎFind the principal value of Sin (Sin |
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| 43. |
DATEd.a polyhas lo ta |
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Answer» Using Euler's formula V - E + F = 2 where V is the number of vertices, E is the number of edges and F is the number of faces. Given, V = 8 and F = 10 so the equation becomes 8 - E + 10= 2 18 - E = 2 E = 16 So number of edges in polyhedron are 16 f+v=e+2 10+8=e+218=e+2 e=18-2e=16 |
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| 44. |
Prove the identity+ cow: 1 + tane+ cotθ |
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| 45. |
t )17. Find the principal value of sinV2 |
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| 46. |
Find the principal value of:() sin" ((i) cos" (MB |
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Answer» ii. is the correct answer (i) If θ be the principal value of sin^−1 x then - π/2 ≤ θ ≤ π/2. Therefore, If the principal value of sin^−1(-1/2) be θ then sin^−1(-1/2) = θ ⇒ sin θ = - 1/2 = sin (-π/6) [Since, - π/2 ≤ θ ≤ π/2] Therefore, the principal value of sin^−1(-1/2) is (-π/6). (ii) If the principal value of cos^−1 x is θ then we know, 0 ≤ θ ≤ π. Therefore, If the principal value of cos^−1(- √3/2) be θ then cos^−1(- √3/2) = θ ⇒ cos θ = (- √3/2) = cos π/6 = cos (π - π/6) [Since, 0 ≤ θ ≤ π] Therefore, the principal value of cos^−1(- √3/2) is π - π/6 = 5π/6.
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| 47. |
EXAMPLE 3.7SBTEB 2003, SBTEB 2006, SBTEB 2010, saTEFind the derivative of sin z using first principal. |
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Answer» I didn't understand first principal explain plz Derivative by first principlerefers to using algebra to find a general expression for the slope of a curve. It is also known as the delta method. The derivative is a measure of the instantaneous rate of change, which is equal to This expression is the foundation for the rest of differential calculus: every rule, identity, and fact, follows from this. expression is which I have used in solving question and what a function denote foe what is use of h and x which function....... x is variable and h is limit for which we are solving yes thnx what is limit limit is h tending to zero can u differentiate sin x by your method or easy and simple way |
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| 48. |
Find the derivative of the following using first principal f(x)=tanx |
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Answer» By first principle if f[x]=tanx F'[x]= f[x+h]-f[x]/x+h-x at Lth tends to 0 F'(x) = tan(x+h)-tanx/h By simple trigonometry tan(x+h)=tanx+tanh/1-tanxtanh Thus, f'(x) = tanx+tanh-tanx+tan^2xtanh/(1-tanxtanh) h =tanh(1+tan^2x)/(1-tanxtanh) h But Lt (tanx)/x. =1, 1+tan^2x=sec^2x h~0 Hence f'(x) =sec^2x(1)/(1-tanxtanh) = sec^2x Thanks |
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| 49. |
EXAMPLE 3.8SBTEB 2004, SBTEJ 2005, SBTEJ 2008, $81E)2Find the derivative of cose using first principal. |
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| 50. |
the amount and compound interest by using the formula i interns'scompounded annually:(i)Principal-7 1 4000, Time-2 years, Rate7% pa- |
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